Obtain file path of C# save dialog box - c#

I've got a save dialog box which pops up when i press a button. However i dont want to save a file at that point, i want to take the name and place it in the text box next to the button, for the name to be used later.
Can anybody tell me how to obtain the file path from the save dialog box to use it later?

Here is a sample code I just wrote very fast... instead of Console.Write you can simply store the path in a variable and use it later.
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.InitialDirectory = Convert.ToString(Environment.SpecialFolder.MyDocuments);
saveFileDialog1.Filter = "Your extension here (*.EXT)|*.ext|All Files (*.*)|*.*" ;
saveFileDialog1.FilterIndex = 1;
if(saveFileDialog1.ShowDialog() == DialogResult.OK)
{
Console.WriteLine(saveFileDialog1.FileName);//Do what you want here
}

Addressing the textbox...
if (saveFileDialog.ShowDialog() == DialogResult.OK)
{
this.textBox1.Text = saveFileDialog.FileName;
}

private void mnuFileSave_Click(object sender, EventArgs e)
{
dlgFileSave.Filter = "RTF Files|*.rtf|"+"Text files (*.txt)|*.txt|All files (*.*)|*.*";
dlgFileSave.FilterIndex = 1;
if (dlgFileSave.ShowDialog() == System.Windows.Forms.DialogResult.OK && dlgFileSave.FileName.Length > 0)
{
foreach (string strFile in dlgFileSave.FileNames)
{
SingleDocument document = new SingleDocument();
document.rtbNotice.SaveFile(strFile, RichTextBoxStreamType.RichText);
document.MdiParent = this;
document.Show();
}
}
}

Try below code.
saveFileDialog1.ShowDialog();
richTextBox1.SaveFile(saveFileDialog1.FileName, RichTextBoxStreamType.PlainText);

Related

Overwriting a text file from RichTextBox

Now if you write the text and click on the save button, OpenFileDialog will appear. If you finish something in the same document and click on the save button again, you need to select the save location again. How to make that when saving the same file you do not need to create a new file each time, and just overwrite the current one? Sorry for my English.
private void buttonSave_Click(object sender, EventArgs e)
{
SaveFileDialog sfd = new SaveFileDialog();
sfd.Filter = "Rich Text File | *.rtf";
if (sfd.ShowDialog() == DialogResult.OK)
{
richTextBox1.SaveFile(sfd.FileName);
}
else
{
}
}
It sure is, you just need to remember the last file path you saved and not display the dialog again the next time around; something like this should help:
void Main()
{
Save();
}
private string _filePath = "";
void Save()
{
var overwrite = false;
if (!string.IsNullOrEmpty(_filePath))
{
var res =
MessageBox.Show("Would you like to overwrite your last saved file?", "Overwrite?", MessageBoxButtons.YesNoCancel, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1,
MessageBoxOptions.DefaultDesktopOnly, false);
if (res == DialogResult.Cancel) return;
if (res == DialogResult.No) overwrite = false;
if (res == DialogResult.Yes) overwrite = true;
}
if (!overwrite)
{
var sfd = new SaveFileDialog();
sfd.Filter = "Rich Text File|*.rtf";
var res = sfd.ShowDialog();
if (res != DialogResult.OK) return;
_filePath = sfd.FileName;
}
// do the richTextBox.SaveFile(_filePath) here.
}
In this example it:
CHECK IF FILE PATH ALREADY SET
IF NOT THEN
ASK USER IF THEY WANT TO OVERWRITE THE LAST FILE
IF CANCEL THEN DON'T SAVE
IF YES THEN SET OVERWRITE TO TRUE
IF NO THEN SET OVERWRITE TO FALSE
END IF
CHECK IF OVERWRITING
IF OVERWRITING THEN
SHOW SAVE FILE DIALOG
IF USER DIDN'T CLICK OK THEN DON'T SAVE
IF USER CLICKED OK, SET THE NEW FILE PATH TO USE
END IF
SAVE THE FILE USING THE NOW-REMEMBERED FILE PATH
Perhaps:
private void SaveButton_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.InitialDirectory = #"C:\";
saveFileDialog1.Title = "Save text Files";
saveFileDialog1.CheckFileExists = true;
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.DefaultExt = "txt";
saveFileDialog1.Filter = "Text files (*.txt)|*.txt|All files (*.*)|*.*";
saveFileDialog1.FilterIndex = 2;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
textBox1.Text = saveFileDialog1.FileName;
}
}
Example from: http://www.c-sharpcorner.com/uploadfile/mahesh/savefiledialog-in-C-Sharp/
Might help some?
private string filePath = string.Empty;
private void SaveButton_Click(object sender, EventArgs e)
{
if (File.Exists(filePath))
{
byte[] buffer = Encoding.ASCII.GetBytes(richTextBox1.Text);
MemoryStream ms = new MemoryStream(buffer);
//write to file
FileStream file = new FileStream(filePath, FileMode.Create, FileAccess.Write);
ms.WriteTo(file);
file.Close();
ms.Close();
}
else
{
SaveFileDialog sfd = new SaveFileDialog();
sfd.Filter = "Rich Text File | *.rtf";
sfd.OverwritePrompt = false;
if (sfd.ShowDialog() == DialogResult.OK)
{
richTextBox1.SaveFile(sfd.FileName);
filePath = sfd.FileName;
}
}
}
you can use sfd.OverwritePrompt = false; property to avoid prompt messagebox if file already exists, is this what you are looking for ?

How do a make this type of select folder dialog in C#?

So I recently tried to the FolderBrowserDialog but much to my disappointment it was not like the following screenshot:
But instead it was formatted and as I think, hard to navigate with like this:
How would I go about getting the other version where it's a dialog box asking for what folder to save to like the select file type natively, instead of what I think is this hard to navigate menu.
The CommonOpenFileDialog class from the NuGet Package "Microsoft.WindowsAPICodePack-Shell" will answer your request.
Set IsFolderPicker property to true and that's it.
using Microsoft.WindowsAPICodePack.Dialogs;
private bool SelectFolder(out string fileName)
{
CommonOpenFileDialog dialog = new CommonOpenFileDialog();
dialog.IsFolderPicker = true;
if (dialog.ShowDialog() == CommonFileDialogResult.Ok)
{
fileName = dialog.FileName;
return true;
}
else
{
fileName = "";
return false;
}
}
thats because you are using FolderBrowserDialog instead of OpenFileDialog
you can check the below
private void btnBrowse_Click(object sender, EventArgs e)
{
OpenFileDialog fileDialog = new OpenFileDialog();
fileDialog.Title = "Browse File";
fileDialog.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
fileDialog.FilterIndex = 2;
fileDialog.InitialDirectory = "c:\\";
fileDialog.RestoreDirectory = true;
if (fileDialog.ShowDialog() == DialogResult.OK)
{
txtFileName.Text = fileDialog.FileName;
}
}

OpenFileDialog only select file path

I am trying to use a OpenFileDialog to let the user select a local file that can interact with my app. The file can be in use when the user selects it as I really only want to get the file's path. My issue is that if I try doing this with a OpenFileDialog, when the user presses "open", it actually tries to open the file even though I don't call for opening anywhere. Since the file is in use, it throws an error.
Is there any way for me to present a dialog for a user to just select a file an do nothing else?
Heres my current code:
DialogResult result = this.qbFilePicker.ShowDialog();
if (result == DialogResult.OK)
{
string fileName = this.qbFilePicker.FileName;
Console.WriteLine(fileName);
}
Make sure you are using
using System.Windows.Forms;
Then the following code from MSDN will not open your file unless you explicitly uncomment the bit that opens the file :)
(Take out the bits that don't pertain to you such as the .txt filter etc)
private void Button_Click(object sender, RoutedEventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
string fileName = openFileDialog1.FileName;
Console.WriteLine(fileName);
//to open the file
/*
try
{
Stream myStream = null;
if ((myStream = openFileDialog1.OpenFile()) != null)
{
using (myStream)
{
// Insert code to read the stream here.
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
* */
}
}

Save filedialog not working

Bit of an odd one here , I'm writing an app which gives a save file option , the save file dialog is coded up as normal
SaveFileDialog ofd = new SaveFileDialog();
the dialog box comes up no problem and clicking save doesn't throw up any errors however no file is saved and I'm not sure why , any ideas ? I've googled it and can't find a similar problem
The SaveFileDialog class doesn't save anything, it prompts the user to choose a location and a file name to save the file. It is your job to save the file
This example extracted from the MSDN link above explains the concept
private void button1_Click(object sender, System.EventArgs e)
{
Stream myStream ;
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ;
saveFileDialog1.FilterIndex = 2 ;
saveFileDialog1.RestoreDirectory = true ;
if(saveFileDialog1.ShowDialog() == DialogResult.OK)
{
if((myStream = saveFileDialog1.OpenFile()) != null)
{
// Code to write the stream goes here.
myStream.Close();
}
}
}
Stream stream;
ofd.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ;
ofd.FilterIndex = 2 ;
ofd.RestoreDirectory = true ;
if(ofd.ShowDialog() == DialogResult.OK)
{
if((stream = ofd.OpenFile()) != null)
{
//FileStream might be better for you but since i don't know what you write, this will serve as an example
stream.Write(bytes,offset,count);
stream.Close();
}

Open file dialog and select a file using WPF controls and C#

I have a TextBox named textbox1 and a Button named button1.
When I click on button1 I want to browse my files to search only for image files (type jpg, png, bmp...).
And when I select an image file and click Ok in the file dialog I want the file directory to be written in the textbox1.text like this:
textbox1.Text = "C:\myfolder\myimage.jpg"
Something like that should be what you need
private void button1_Click(object sender, RoutedEventArgs e)
{
// Create OpenFileDialog
Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();
// Set filter for file extension and default file extension
dlg.DefaultExt = ".png";
dlg.Filter = "JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif";
// Display OpenFileDialog by calling ShowDialog method
Nullable<bool> result = dlg.ShowDialog();
// Get the selected file name and display in a TextBox
if (result == true)
{
// Open document
string filename = dlg.FileName;
textBox1.Text = filename;
}
}
var ofd = new Microsoft.Win32.OpenFileDialog() {Filter = "JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif"};
var result = ofd.ShowDialog();
if (result == false) return;
textBox1.Text = ofd.FileName;

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