Given a path and filename how can I get the Image object:
Image image = ...(filename)
You want to call the static FromFile method on the Image class.
Another alternative is to use a Bitmap object (which inherits from Image) like so:
Bitmap bitmap = new Bitmap(imagePath);
(This works for all image formats, not just *.bmp as the name might imply.)
If you're playing with images in memory, I've found that bobpowell.net has a GREAT site for GDI work in C#.
No.. I'm not related to, associated with or hired by Bob Powell. I just really enjoy his work. =)
// Get original filename with extention
string filenameWithPath = "C:\pictures\peanutbutterjellytime.jpg;
filename = System.IO.Path.GetFileName(filenameWithPath);
Also, if you're having trouble getting the path of the resource (trickiest part) you can do a :
Assembly myAssembly = Assembly.GetExecutingAssembly();
string[] names = myAssembly.GetManifestResourceNames();
foreach (string name in names)
{
Console.WriteLine( name );
}
Which shows all paths for resources.
Related
I need to check if picture is sRGB or Adobe RGB in my WEBapplication. Is there a way to know exactly what RGB does the picture have?
UPDATE:
Tried to Use Color.Context, but it's always null
code
Bitmap img = (Bitmap)image;
var imgPixel = img.GetPixel(0,0);
System.Windows.Media.Color colorOfPixel= System.Windows.Media.Color.FromArgb(imgPixel.A,imgPixel.R, imgPixel.G, imgPixel.B);
var context = colorOfPixel.ColorContext; //ColorContext is null
In System.Windows.Media also found PixelFormat and PixelFormats that can show what exact RGB type an image is.
But still I can't find a way to get System.Windows.Media.PixelFormat of an img.
How should I do this?
You'll need to use a BitmapDecoder to get the frame from there, then check the color context:
BitmapDecoder bitmapDec = BitmapDecoder.Create(
new Uri("mybitmap.jpg", UriKind.Relative),
BitmapCreateOptions.None,
BitmapCacheOption.Default);
BitmapFrame bmpFrame = bitmapDec.Frames[0];
ColorContext context = bmpFrame.ColorContexts[0];
Afterwards, you'd need to process the raw color profile (using context.OpenProfileStream()) to determine which profile it is.
If you want to write the profiles to disk to check them with an hex editor or something, you can use this code:
using(var fileStream = File.Create(#"myprofilename.icc"))
using (var st = context.OpenProfileStream())
{
st.CopyTo(fileStream);
fileStream.Flush(true);
fileStream.Close();
}
Using that method, I've extracted the raw data from both sRGB (link) and AdobeRGB (link) if you want to check them. There are magic strings and IDs at the start if you want to check but I really don't know them or know where to find a table for the common ones (the embedded profiles could be infinite, not limited to AdobeRGB and sRGB).
Also, one image might have more than one color profile.
With this method, if ColorContexts is empty, then the image doesn't have any profile.
Color.ColorContext Property
MSDN: https://msdn.microsoft.com/en-us/library/System.Windows.Media.Color_properties(v=vs.110).aspx
You might use System.Drawing.Image.PropertyItems. The property "PropertyTagICCProfile" (Id=34675=0x8773) is populated with the icc profile of the image, even if it is embedded in image data and not in exif data (or there is no profile embedded, but the image is labeled as AdobeRGB in exif: InteroperabilityIndex="R03").
byte[] iccProfile = null;
try {
System.Drawing.Bitmap myImage = new Bitmap("Image.jpg");
iccProfile = myImage.GetPropertyItem(34675).Value;
} catch (Exception) {
//...
}
How can I insert Image object into FileInfo list?
I have a list with images of this type
public List<FileInfo> _imagesList = new List<FileInfo>();
But I need to add image to this list using a method like this one:
public void AddImage(Image img)
{
}
I tried using this method
public void AddImage(string pathToImage)
{
try
{
FileInfo file = new FileInfo(pathToImage);
_imagesList.Add(file);
}
catch (Exception e)
{
MessageBox.Show("Не удалось загрузить изображение. Ошибка : " + e);
}
}
Let me explain why you can't do that. Image class does not have any references to file which was used to create that image. When you create Image instance with
Image.FromFile(filename)
File name is not stored anywhere. All you will have inside Image instance is an array of bytes which is initialized this way:
Stream dataStream = File.OpenRead(filename);
image.rawData = new byte[(int) dataStream.Length];
dataStream.Read(image.rawData, 0, (int) dataStream.Length);
So, the point is - you can't get file name from which Image was created. Actually image can be create not from file - from any stream (network stream, memory stream). Image is not related to any file, thus you can't insert it to list of FileInfo objects.
Well, as a workaround, you can save Image to file. And then insert that file to list.
you can either use the method you gave, adding new FileInfo(pathToImage) or change your list so it'll contain Image items
you can use
public List<Image> _imagesList = new List<Image>();
for example. if you share more information i could help you more. this looks like an XY problem so maybe you should tell us what's the real problem
You cannot do like this, FileInfo accept one arguments in its constructor: fileName.
You should have something like this:
public List<FileInfo> _imagesList = new List<FileInfo>();
public void Main()
{
AddImage("YourImagePath1");
AddImage("YourImagePath2");
// ...
}
public void AddImage(string path)
{
_imagesList.Add(new FileInfo(path));
//var img = Image.FromFile(path); // do this if you need to load your image
}
UPDATE:
You changed your question and your code now looks like mine, what was the issue in the code you used to have?
I'm writing a program about trying different images in picturebox, but the image must correspond to the text. Plus it must come from "Resources" folder of the project.
this is what i want to do if the text "apple" displays to the screen then the image with a filename "apple" would also display in the picturebox..
I can do it in "if-else" like this
string word="apple";
if(word==apple)
pictureBox1.Image= WindowsFormsApplication4.Properties.Resources.apple;
but What if I have a thousand images, I still think there's an easy way for this,..
i'm trying this one,,
string word=label1.Text;//label1.text changes from time to time
pictureBox1.Image= WindowsFormsApplication4.Properties.Resources.word;
but I know "word" is string....It's not possible...I cannot append string to the syntax....
You can pass in a string using the GetObject method of the ResourceManager class:
string itemName = label1.Text;
this.pictureBox1.Image =
(Image)Properties.Resources.ResourceManager.GetObject(itemName);
If you open resources .Designer.cs file code , you will see something like:
internal static System.Drawing.Bitmap apple {
get {
object obj = ResourceManager.GetObject("apple", resourceCulture);
return ((System.Drawing.Bitmap)(obj));
}
}
so you can do the same thing:
string word=label1.Text;//label1.text changes from time to time
pictureBox1.Image= (System.Drawing.Bitmap)WindowsFormsApplication4
.Properties
.Resources
.ResourceManager.GetObject(word);
I have many file types: pdf, tiff, jpeg, bmp. etc.
My question is how can I change file extension?
I tried this:
my file= c:/my documents/my images/cars/a.jpg;
string extension = Path.GetExtension(myffile);
myfile.replace(extension,".Jpeg");
No matter what type of file it is, the format I specify must be with the file name. But it does not work. I get file path from browser like c:\..\..\a.jpg, and the file format is a.jpeg. So, when I try to delete it, it gives me an error: Cannot find the file on specified path'. So, I am thinking it has something to do with the file extension that does not match. So, I am trying to convert .jpg to .jpeg and delete the file then.
There is: Path.ChangeExtension method. E.g.:
var result = Path.ChangeExtension(myffile, ".jpg");
In the case if you also want to physically change the extension, you could use File.Move method:
File.Move(myffile, Path.ChangeExtension(myffile, ".jpg"));
You should do a move of the file to rename it. In your example code you are only changing the string, not the file:
myfile= "c:/my documents/my images/cars/a.jpg";
string extension = Path.GetExtension(myffile);
myfile.replace(extension,".Jpeg");
you are only changing myfile (which is a string). To move the actual file, you should do
FileInfo f = new FileInfo(myfile);
f.MoveTo(Path.ChangeExtension(myfile, ".Jpeg"));
See FileInfo.MoveTo
try this.
filename = Path.ChangeExtension(".blah")
in you Case:
myfile= c:/my documents/my images/cars/a.jpg;
string extension = Path.GetExtension(myffile);
filename = Path.ChangeExtension(myfile,".blah")
You should look this post too:
http://msdn.microsoft.com/en-us/library/system.io.path.changeextension.aspx
The method GetFileNameWithoutExtension, as the name implies, does not return the extension on the file. In your case, it would only return "a". You want to append your ".Jpeg" to that result. However, at a different level, this seems strange, as image files have different metadata and cannot be converted so easily.
Convert file format to png
string newfilename ,
string filename = "~/Photo/" + lbl_ImgPath.Text.ToString();/*get filename from specific path where we store image*/
string newfilename = Path.ChangeExtension(filename, ".png");/*Convert file format from jpg to png*/
Alternative to using Path.ChangeExtension
string ChangeFileExtension(ReadOnlySpan<char> path, ReadOnlySpan<char> extension)
{
var lastPeriod = path.LastIndexOf('.');
return string.Concat(path[..lastPeriod], extension);
}
string myfile= #"C:/my documents/my images/cars/a.jpg";
string changedFileExtesion = ChangeFileExtension(myfile, ".jpeg");
Console.WriteLine(changedFileExtesion);
// output: C:/my documents/my images/cars/a.jpeg
I have an image in my project stored at Resources/myimage.jpg. How can I dynamically load this image into Bitmap object?
Are you using Windows Forms? If you've added the image using the Properties/Resources UI, you get access to the image from generated code, so you can simply do this:
var bmp = new Bitmap(WindowsFormsApplication1.Properties.Resources.myimage);
You can get a reference to the image the following way:
Image myImage = Resources.myImage;
If you want to make a copy of the image, you'll need to do the following:
Bitmap bmp = new Bitmap(Resources.myImage);
Don't forget to dispose of bmp when you're done with it. If you don't know the name of the resource image at compile-time, you can use a resource manager:
ResourceManager rm = Resources.ResourceManager;
Bitmap myImage = (Bitmap)rm.GetObject("myImage");
The benefit of the ResourceManager is that you can use it where Resources.myImage would normally be out of scope, or where you want to dynamically access resources. Additionally, this works for sounds, config files, etc.
You need to load it from resource stream.
Bitmap bmp = new Bitmap(
System.Reflection.Assembly.GetEntryAssembly().
GetManifestResourceStream("MyProject.Resources.myimage.png"));
If you want to know all resource names in your assembly, go with:
string[] all = System.Reflection.Assembly.GetEntryAssembly().
GetManifestResourceNames();
foreach (string one in all) {
MessageBox.Show(one);
}
Way easier than most all of the proposed answers
tslMode.Image = global::ProjectName.Properties.Resources.ImageName;
The best thing is to add them as Image Resources in the Resources settings in the Project. Then you can get the image directly by doing Resources.myimage. This will get the image via a generated C# property.
If you just set the image as Embedded Resource you can get it with:
string name = "Resources.myimage.jpg"
string namespaceName = "MyCompany.MyNamespace";
string resource = namespaceName + "." + name;
Type type = typeof(MyCompany.MyNamespace.MyTypeFromSameAssemblyAsResource);
Bitmap image = new Bitmap(type.Assembly.GetManifestResourceStream(resource));
Where MyTypeFromSameAssemblyAsResource is any type that you have in your assembly.
Code I use in several of my projects...
It assumes that you store images in resource only as bitmaps not icons
public static Bitmap GetImageByName(string imageName)
{
System.Reflection.Assembly asm = System.Reflection.Assembly.GetExecutingAssembly();
string resourceName = asm.GetName().Name + ".Properties.Resources";
var rm = new System.Resources.ResourceManager(resourceName, asm);
return (Bitmap)rm.GetObject(imageName);
}
Use below one. I have tested this with Windows form's Grid view cell.
Object rm = Properties.Resources.ResourceManager.GetObject("Resource_Image");
Bitmap myImage = (Bitmap)rm;
Image image = myImage;
Name of "Resource_Image", you can find from the project.
Under the project's name, you can find Properties. Expand it. There you can see Resources.resx file. Open it. Apply your file name as "Resource_Image".
JDS's answer worked best. C# example loading image:
Include the image as Resource (Project tree->Resources, right click to add the desirable file ImageName.png)
Embedded Resource (Project tree->Resources->ImageName.png, right click select properties)
.png file format (.bmp .jpg should also be OK)
pictureBox1.Image = ProjectName.Properties.Resources.ImageName;
Note the followings:
The resource image file is "ImageName.png", file extension should be omitted.
ProjectName may perhaps be more adequately understood as "Assembly name", which is to be the respective text entry on the Project->Properties page.
The example code line is run successfully using VisualStudio 2015 Community.
I suggest:
System.Reflection.Assembly thisExe;
thisExe = System.Reflection.Assembly.GetExecutingAssembly();
System.IO.Stream file =
thisExe.GetManifestResourceStream("AssemblyName.ImageFile.jpg");
Image yourImage = Image.FromStream(file);
From msdn:
http://msdn.microsoft.com/en-us/library/aa287676(v=vs.71).aspx
Using Image.FromStream is better because you don't need to know the format of the image (bmp, png, ...).
With and ImageBox named "ImagePreview
FormStrings.MyImageNames contains a regular get/set string cast method, which are linked to a scrollbox type list.
The images have the same names as the linked names on the list, except for the .bmp endings.
All bitmaps are dragged into the resources.resx
Object rm = Properties.Resources.ResourceManager.GetObject(FormStrings.MyImageNames);
Bitmap myImage = (Bitmap)rm;
ImagePreview.Image = myImage;
In my case -- I was using Icons in my resource, but I needed to add them dynamically as Images to some ToolStripMenuItem(s). So in the method that I created (which is where the code snippet below comes from), I had to convert the icon resources to bitmaps before I could return them for addition to my MenuItem.
string imageName = myImageNameStr;
imageName = imageName.Replace(" ", "_");
Icon myIcon = (Icon)Resources.ResourceManager.GetObject(imageName);
return myIcon.ToBitmap();
Something else to be aware of, if your image/icon has spaces (" ") in its name when you add them to your resource, VS will automatically replace those spaces with "_"(s). Because, spaces are not a valid character when naming your resource. Which is why I'm using the Replace() method in my referenced code. You can likely just ignore that line.
You can also save the bmp in a var like this:
var bmp = Resources.ImageName;
hope it helps!
Strangely enough, from poking in the designer I find what seems to be a much simpler approach:
The image seems to be available from .Properties.Resources.
I'm simply using an image as all I'm interested in is pasting it into a control with an image on it.
(Net 4.0, VS2010.)
I looked at the designer code from one of my projects and noticed it used this notation
myButton.Image = global::MyProjectName.Properties.Resources.max;
where max is the name of the resource I uploaded into the project.
Or you could use this line when dealing with WPF or Silverlight, especially where you have the source string already in the XAML markup:
(ImageSource)new ImageSourceConverter().ConvertFromString(ImagePath);
Where the ImagePath is something like:
string ImagePath = "/ProjectName;component/Resource/ImageName.png";
This is how I manage to create an ImageList from a Resource (.rc) file of a windows forms application:
ImageList imgList = new ImageList();
var resourceSet = DataBaseIcons.ResourceManager.GetResourceSet(CultureInfo.CreateSpecificCulture("en-EN"), true, true);
foreach (var r in resourceSet)
{
Logger.LogDebug($"Resource Type {((DictionaryEntry)r).Key.ToString()} is of {((DictionaryEntry)r).Value.GetType()}");
if (((DictionaryEntry)r).Value is Bitmap)
{
imgList.Images.Add(((Bitmap)(((DictionaryEntry)r).Value)));
}
else
{
Logger.LogWarning($"Resource Type {((DictionaryEntry)r).Key.ToString()} is of type {((DictionaryEntry)r).Value.GetType()}");
}
}
this.toolStrip1 = new System.Windows.Forms.ToolStrip();
this.toolStrip1.Location = new System.Drawing.Point(0, 0);
this.toolStrip1.Name = "toolStrip1";
this.toolStrip1.Size = new System.Drawing.Size(444, 25);
this.toolStrip1.TabIndex = 0;
this.toolStrip1.Text = "toolStrip1";
object O = global::WindowsFormsApplication1.Properties.Resources.ResourceManager.GetObject("best_robust_ghost");
ToolStripButton btn = new ToolStripButton("m1");
btn.DisplayStyle = ToolStripItemDisplayStyle.Image;
btn.Image = (Image)O;
this.toolStrip1.Items.Add(btn);