The result of all of the division equations in the below for loop is 0. How can I get it to give me a decimal e.g.:
297 / 315 = 0.30793650793650793650793650793651
Code:
using System;
namespace TestDivide
{
class Program
{
static void Main(string[] args)
{
for (int i = 0; i <= 100; i++)
{
decimal result = i / 100;
long result2 = i / 100;
double result3 = i / 100;
float result4 = i / 100;
Console.WriteLine("{0}/{1}={2} ({3},{4},{5}, {6})", i, 100, i / 100, result, result2, result3, result4);
}
Console.ReadLine();
}
}
}
Answer:
Thanks Jon and everyone, this is what I wanted to do:
using System;
namespace TestDivide
{
class Program
{
static void Main(string[] args)
{
int maximum = 300;
for (int i = 0; i <= maximum; i++)
{
float percentage = (i / (float)maximum) * 100f;
Console.WriteLine("on #{0}, {1:#}% finished.", i, percentage);
}
Console.ReadLine();
}
}
}
You're using int/int, which does everything in integer arithmetic even if you're assigning to a decimal/double/float variable.
Force one of the operands to be of the type you want to use for the arithmetic.
for (int i = 0; i <= 100; i++)
{
decimal result = i / 100m;
long result2 = i / 100;
double result3 = i / 100d;
float result4 = i / 100f;
Console.WriteLine("{0}/{1}={2} ({3},{4},{5}, {6})",
i, 100, i / 100d, result, result2, result3, result4);
}
Results:
0/100=0 (0,0,0, 0)
1/100=0.01 (0.01,0,0.01, 0.01)
2/100=0.02 (0.02,0,0.02, 0.02)
3/100=0.03 (0.03,0,0.03, 0.03)
4/100=0.04 (0.04,0,0.04, 0.04)
5/100=0.05 (0.05,0,0.05, 0.05)
(etc)
Note that that isn't showing the exact value represented by the float or the double - you can't represent 0.01 exactly as a float or double, for example. The string formatting is effectively rounding the result. See my article on .NET floating binary point for more information as well as a class which will let you see the exact value of a double.
I haven't bothered using 100L for result2 because the result would always be the same.
Try
i / 100.0
because i is an int: i / 100 performs integer division, then the result, that is always 0, is casted to the target type. You need to specify at least one non-int literal in your expression:
i / 100.0
Because i is an integer and 100 is an integer...so you have an integer division
Try (decimal)i / 100.0 instead
No matter where you store it, an integer divided by an integer will always be an integer.
You need to force a floating point operation "double / double" instead of an "int / int"
double result = (double)297 / (double)315 ;
this is integer division whatever the type of variable you storing in,
so int / int = int
double result3 = ((double)i) / 100;
Because i is a int value and you divide by an integer so the result is an integer ! and so you need to divide by 100.0 to have an implicit cast in float or specify 100f or 100d
In my case I had only vars and no int
float div = (var1 - var2) / float.Parse(var1.ToString());
Related
I have some problems with my code where I think the accuracy is a bit off. I'll take out the declarations of variables from my code, so the code is as small as possible:
int a = Int32.Parse(tb_weight.Text);
double b = 0;
b = (a * 1.03) / 1000;
double g = 0;
g = (1.09 + (0.41 * (Math.Sqrt(50 / b))));
lbl_vertforce.Content = Math.Round((b * g * 9.81), 2);
So, tb_weight is a textbox where the input is made, and lets say the input is 5000, the label lbl_vertforce is showing 119,61 and according to my calculator, it should show 119,74. What is wroing here?
Doubles are not 100% precise and can vary in the least common digits. If you want exact precision you need to use Decimal type which has a bigger memory foot print, but was designed to be very precise. Unfortunately Math.Sqrt is not overloaded for Decimal and only works on doubles. I have provide code I found in another posting discussing the subject of Decimal Square roots: Performing Math operations on decimal datatype in C#?
public void YourCodeModifiedForDecimal()
{
int a = Int32.Parse(tb_weight.Text);
decimal b = 0;
b = (a* 1.03m) / 1000m;
decimal g = 0;
g = (1.09m + (0.41m * (Sqrt(50m / b))));
lbl_vertforce.Content = Math.Round((b* g * 9.81m), 2);
}
public static decimal Sqrt(decimal x, decimal? guess = null)
{
var ourGuess = guess.GetValueOrDefault(x / 2m);
var result = x / ourGuess;
var average = (ourGuess + result) / 2m;
if (average == ourGuess) // This checks for the maximum precision possible with a decimal.
return average;
else
return Sqrt(x, average);
}
You need to round g to 2 decimal places to get 119.74 in the final calculation.
g = Math.Round(1.09 + (0.41 * (Math.Sqrt(50 / b))), 2);
So I would like to calculate the percentage progress of my program as the nearest integer value
In my examples lets take
int FilesProcessed = 42;
int TotalFilesToProcess = 153;
So First I tried:
Int TotalProgress = ((FilesProcessed / TotalFilesToProcess) * 100)
This returned TotalProgress = 0
Then I tried
Int TotalProgress = (int)((FilesProcessed / TotalFilesToProcess) * 100)
This gives compiler error saying Cannot implicitly convert type decimal to int
Ive tried
Int TotalProgress = Math.Round((FilesProcessed / TotalFilesToProcess) * 100)
and get The call is ambiguous between decimal and double
and so now I've come here for help?
Cast to double first so it doesn't compute a division between integers:
int totalProgress = (int)((double)FilesProcessed / TotalFilesToProcess * 100);
int FilesProcessed = 42;
int TotalFilesToProcess = 153;
int TotalProgress = FilesProcessed * 100 / TotalFilesToProcess;
Console.WriteLine(TotalProgress);
https://dotnetfiddle.net/3GNlVd
If you want to be more accuracy, you can use:
int TotalProgress = Convert.ToInt32(Math.Round(((decimal)FilesProcessed / TotalFilesToProcess) * 100, 0));
If the numbers are greater you will have a difference. For example
int FilesProcessed = 42;
int TotalFilesToProcess = 1530;
The result with decimals will be: 2.74%, if you use the previous methods, you would find 2%, with the formula I am proposing you will obtain 3%. The last option has more accuracy.
in my ASP.NET project i did a survey page that uses Application to save the votes. I have a problem with the making of the percentages amount. I've tried many things. here is the problematic part of my code:
double x = (count / sum) ;
double f = (count1 / sum) ;
double g = (count2 / sum) ;
double h = (count3 / sum) ;
if (sum > 0)
{
a = (int)x * 100;
b = (int)f * 100;
c = (int)g * 100;
d = (int)h * 100;
}
I used breakpoints and figured out that the problem was in the double variables: the (count/sum) equals 0 anyway.
I'm assuming count and sum are integer types.
The result of division of 2 integers is a truncated integer.
You need to cast one side of the division to a double, then the result will be double
So
((double)count)/sum
What are the datatypes of count, count[1-3] and sum? If they are integral types, then integer division is performed. This
int x = 100 ;
int y = 300 ;
double z = x / y ;
yields the value 0.0 for z.
Try something like
double h = (double) ( count3 / sum ) ;
You might also want to move your test for sum > 0 up: as coded, if sum is zero, you'll throw a DivideByZeroException before you get to your test, thus rendering your test moot.
Your count and sum variables are probably integers. Cast one of them to double:
double x = count / (double)sum;
UPDATE:
Actually, if you want the percentage as an integer, you can skip the doubles altogether:
int a = 100 * count / sum;
I need to somehow get one number before floating point and value after that floating point. Example:
Before: 212.12345;
After: 2.12345
Any Ideas?
Assuming you have:
decimal x = 212.12345m;
you can use the modulo operator:
decimal result = x % 10;
Note that the number should be represented as a decimal if you care about the accurate value.
See also: Meaning of "%" operation in C# for the numeric type double
You can do like this:
public double GetFirst(double a)
{
double b = a / 10.0;
return (b - (int)b) * 10.0;
}
try this
double x = 1;
var y = x/10;
var z = (y % (Math.Floor(y))) * 10;
Try this code
string num = "15464612.12345";
string t = num.Split('.')[0];
num = t[t.Length-1].ToString() + "." + num.Split('.')[1];
my approach was to find the number 210, and substract it....
will work for any number as well as smaller then 10.
double f1 = 233.1234;
double f2 = f1 - (((int)f1 / 10) * 10);
I can't get this to divide into a decimal. It is rounding to value 0.
private void button24_Click(object sender, EventArgs e)
{
double x = 0;
x = 1 / 2;
ans.Text = x.ToString();
}
When I debug, x is zero before it is sent to the textbox 'ans.'
I tried..and string variable is still zero..
double x = 1/5;
string displayX = x.ToString("0.0000");
It's integer division and those are the expected outputs.
double x = 1.0 / 5; // this will not perform integer division
double x = 1/5; // this does (1/5 = 0).
double x = 1D / 5; // this will not because 1 is treated as a double
You can do one of the follow:
double x = 1;
double y = 1.5;
double ans = x / y;
Replace double x = 1/5 with double x = 1.0/5 and that should fix it. Because both numbers you're dividing are integers, it still processes it as an integer, rather than as a double. When you think through logically, it makes some sense - it does the division in whatever form those numbers are and then saves it to the variable; the variable type is inconsequential to the actual equation.
(I realize there are other answers already, but hopefully this will help you see why the issue exists.)