RightToLeft property in Form in C# - c#

I want to move the form title, icon and close, and help buttons from left side to right side (change the layout).
I moved the form controls manually to keep background image but now I want to change the form title.
When I set rightToLeft property to yes and rightToLeftLayout to true in the form properties the background image disappears, but it uses the property "BackColor"
My code is as follows:
if (_lang == 'Arabic')
{
this.RightToLeft = RightToLeft.Yes;
this.RightToLeftLayout = true;
}
But it keeps buttons image.
So why is that?

To further Blounty's answer, the MSDN specs clearly state that BackgroundImage, Opacity and others aren't supported when using RightToLeftLayout:
http://msdn.microsoft.com/en-us/library/system.windows.forms.form.righttoleftlayout(vs.80).aspx:
Owner draw is not supported when RightToLeftLayout is set to Yes. The owner draw events will still occur, but the behavior of any code you author in these events is not defined. Additionally, BackgroundImage, Opacity, TransparencyKey, and the painting events are not supported.

BackgroundImage, Opacity, TransparencyKey, and the painting events are not supported when RightToLeftLayout is set to yes.

It is pretty easy to replace the lost functionality:
protected override void OnPaintBackground(PaintEventArgs e) {
Rectangle rc = new Rectangle(Point.Empty, this.ClientSize);
e.Graphics.DrawImage(Properties.Resources.SampleImage, rc);
}
You'll need to do a bit more work if you need to tile the image.

Related

Hidden background image C# winform in right to left layout?

I set background image to form in my project C# winform, but when set Form property to
RightToLeft=Yes and RightToLeftLayout=True
then disappear my background image.
Does anyone help me?
You can paint the image manually, by overriding the OnPaintBackground method of your form:
protected override void OnPaintBackground(PaintEventArgs e)
{
e.Graphics.DrawImage(Properties.Resources.SampleImage,
new Rectangle(Point.Empty, this.ClientSize));
}
By using background image, you have to know that it is not supported by RightToLeftLayout so you cannot use it directly in this case, but that doesn't mean that you can't implement it manually.
MSDN Reference
Owner draw is not supported when RightToLeftLayout is set to Yes. The owner draw events will still occur, but the behavior of any code you author in these events is not defined. Additionally, BackgroundImage, Opacity, TransparencyKey, and the painting events are not supported.
Referece:
[http://msdn.microsoft.com/en-us/library/system.windows.forms.form.righttoleftlayout(v=vs.110).aspx][1]
Look this:
http://msdn.microsoft.com/query/dev12.query?appId=Dev12IDEF1&l=ZH-CN&k=k(System.Windows.Forms.Form.RightToLeftLayout)%3bk(TargetFrameworkMoniker-.NETFramework%2cVersion%3dv4.5)%3bk(DevLang-csharp)&rd=true
http://msdn.microsoft.com/en-us/library/system.windows.forms.control.backgroundimage(v=vs.110).aspx
If you set RightToLeftLayout=True ,you'll not use backgroundimage.

C# Windows Form Application Transparent button

I'm new to C#. I'd like to create an invisible button, but they are click-able in C# windows form application. Is there a way? I tried BackColor to Transparent, but that does not change the fact that it is transparent
Its simple try this.
Click the button that you want to make transparent.
Select FlatStyle from Properties and set it to popup
Now change the BackColor property to Transparent.
This will make the button transparent.
However if you want to make it transparent over a PictureBox this method wont work..
It works only on normal backgrounds and background images.
Hope it works....
buttonLink.FlatStyle = FlatStyle.Flat;
buttonLink.BackColor = Color.Transparent;
buttonLink.FlatAppearance.MouseDownBackColor = Color.Transparent;
buttonLink.FlatAppearance.MouseOverBackColor = Color.Transparent;
The answers given just make the background color of the control you want to make transparent the same as the background color of its parent. It's not true transparency and windows forms doesn't support true transparency.
Windows Forms controls do not support true transparency. The background of a
transparent Windows Forms control is painted by its parent.
https://learn.microsoft.com/en-us/dotnet/desktop/winforms/controls/how-to-give-your-control-a-transparent-background?view=netframeworkdesktop-4.8&redirectedfrom=MSDN
Reference:
Original article and code can be found at:
Displaying a ToolTip when the Mouse Hovers Over a Disabled Control
# CodeProject by tetsushmz
Code:
public class TransparentSheet : ContainerControl
{
public TransparentSheet()
{
// Disable painting the background.
this.SetStyle(ControlStyles.Opaque, true);
this.UpdateStyles();
// Make sure to set the AutoScaleMode property to None
// so that the location and size property don't automatically change
// when placed in a form that has different font than this.
this.AutoScaleMode = AutoScaleMode.None;
// Tab stop on a transparent sheet makes no sense.
this.TabStop = false;
}
private const short WS_EX_TRANSPARENT = 0x20;
protected override CreateParams CreateParams
{
[SecurityPermission(SecurityAction.LinkDemand, UnmanagedCode = true)]
get
{
CreateParams l_cp;
l_cp = base.CreateParams;
l_cp.ExStyle = (l_cp.ExStyle | WS_EX_TRANSPARENT);
return l_cp;
}
}
}
Explanation:
What you need to do is use the given control as an overlay on your disabled TextBox (that you mentioned in one of your comments). Sibscribe to the overlay control's Click event and you have yourself a click on a disabled control.
I strongly recommend against this approach and feel it is kind of a hack. You really should look for an alternative approach instead of having to use a disabled control with an overlay control on top of it.
Maybe a different UI or atleast wrap it up in a UserControl to isolate this messy logic.
Setting the background property of the button to transparent will still leave a border. If you want a completely transparent button, do one of 2 things:
Create a transparent panel and assign a method to the Click event
or preferably
Create a custom UserControl that is filled with only BackColor (set to transparent) and assign method to Click event.
public class Invisible_Button : UserControl
{
protected override void OnMouseMove(MouseEventArgs e)
{
base.OnMouseMove(e);
this.Cursor = Cursors.Hand;
}
protected override void OnPaint(PaintEventArgs e)
{
base.OnPaint(e);
e.Graphics.FillRectangle(new SolidBrush(this.BackColor), 0, 0, this.Width, this.Height);
}
}
Did you try button.Visible = false?
If all you want is to hide it, this will do the job.

How do I make a form transparent while keeping the controls fully visible?

I would like to have a form in which the controls on the form are fully visible but the form itself is invisible. If I change the form's Opacity, this makes both the form and the controls on it semi-transparent, so this doesn't work.
I can't do this by setting the form's TransparencyKey, since I have a PictureBox on the form. If the image in the PictureBox happens to contain pixels that match the TransparencyKey, they appear as openings in the form, which I don't want.
TransparencyKey is the only way to get this. Pick the right color. Color.Fuchsia has a long tradition of being the color of choice, going back to the early days of Win32 development. Assault your eye with it to see its merits.
With the caveat that I've never used it, just ran across it once, thought "neat!" and moved on...
Look into System.Drawing.Drawing2D.GraphicsPath and setting the form's Region property. I added two buttons to the basic Windows forms application:
public Form1()
{
InitializeComponent();
Rectangle r1 = new Rectangle(button1.Location, button1.Size);
Rectangle r2 = new Rectangle(button2.Location, button2.Size);
GraphicsPath gp = new GraphicsPath();
gp.AddRectangle(r1);
gp.AddRectangle(r2);
this.Region = new Region(gp);
}
I've approximated the shape of the button with a rectangle; with this code, you can see the form background color at the buttons' corners. You'll need to work out the enclosing path for each of your controls and add them to the path individually. You'll need to take into account any offset introduced by the form title bar or border style.
Update: I did some investigation and have a couple of possible approaches for the problem:
Using the GraphicsPath method, set pictureBox.Visible to False if there is no image loaded.
When you load an image into the picture box, analyze the image to get a list of all the colors in it, then randomly generate one that isn't. Set the form's BackColor and TransparencyKey properties to match this new color, Hans Passant's answer.

How do I get a disabled ToolStripButton to paint its image in colour?

We have a button which allows users to 'lock' a form. Users are not permitted to 'unlock' the form, so when pressed, we want the button to be disabled, so that the user receives appropriate visual feedback.
However, the customer reports that the greyed 'lock' icon suggests to them that the form is not locked, so we would like to display the button in a pressed state, but with the icon in colour, even though the button is disabled.
How do we do that, with the absolute minimum amount of overridden painting?
Actually I disagree with the approach. Your customer might have a valid point, but I don't think they have the correct suggestion for the fix. You should look into other ways to make the form appear "locked". Changing borders or font colours, having a big padlock icon appear or change from open to closed etc. Buttons look a certain way because that's what users expect. If you have a disabled button that looks like it might be enabled, that's going to confuse users who might not then understand why they can't click it.
You can set the ToolStripButton Image as BackgroundImage
and then set the DiplayStyle to None.
The picture should stay in colour no matter what's the button Enabled value.
I was in this case few weeks ago and this question doesn't have an answer, so this is my solution 4 years later :
I'm using this solution to repaint the ToolStripButton in many cases : disabled, checked, selected
override OnPaint event or change renderer of your ToolStrip
draw your image without grey filter with this method, just set the image of the button and image's position on your button : http://msdn.microsoft.com/en-us/library/chas0s9c(v=vs.110).aspx
Two good examples who helped me :
http://tutorials.csharp-online.net/Tool,_Menu,_and_Status_Strips%E2%80%94Customizing_a_Renderer
http://jskiles1.wordpress.com/2009/08/22/33/)
ToolStrip class :
ToolStrip ts = new ToolStrip();
//[...]
ts.RenderMode = ToolStripRenderMode.Professional; //Professional is just an example
ts.Renderer = new CustomRenderer();
CustomRenderer class :
public class CustomRenderer: ToolStripProfessionalRenderer
{
protected override void OnRenderButtonBackground(ToolStripItemRenderEventArgs e)
{
if (!e.Item.Enabled) //in this case you will just have the image in your button, you need to add text etc in this if
{
//to draw the image
Graphics g = e.Graphics;
g.DrawImageUnscaled(e.Item.Image, new Point(2, 2)); //you need to specify the correct position
}
else //other cases
base.OnRenderButtonBackground(e);
}
}
The problem is to know the correct position of all elements in your ToolStripButton , that's why I drawn the ToolStripButton in every cases
Another way: don't set the button.Enabled = false at all. Just set the button.Checked = true or false and when someone clicks on the button test for the Checked state and do whatever you do. The button will then function as you want and stay colored too.

How to set/change/remove focus style on a Button in C#?

I have a couple of buttons of which I modified how they look. I have set them as flat buttons with a background and a custom border so they look all pretty and nothing like normal buttons anymore (actually, they look like Office 2003 buttons now ;-). The buttons have a border of one pixel.
However when the button gets selected (gets the focus through either a click or a keyboard action like pressing the tab key) the button suddenly gets and extra border around it of the same colour, so making it a two pixel border. Moreover when I disable the one pixel border, the button does not get a one pixel border on focus.
On the net this question is asked a lot like 'How can I disable focus on a Button', but that's not what I want: the focus should still exist, just not display in the way it does now.
Any suggestions? :-)
Is this the effect you are looking for?
public class NoFocusCueButton : Button
{
protected override bool ShowFocusCues
{
get
{
return false;
}
}
}
You can use this custom button class just like a regular button, but it won't give you an extra rectangle on focus.
I had the same issue with the annoying double border, and stumbled across this thread looking for an answer...
The way I solved this was to set the BorderSize to 0 then draw my own border in OnPaint
Note: Not the entire button, just the border
A simple example would be:
public class CustomButton : Button
{
public CustomButton()
: base()
{
// Prevent the button from drawing its own border
FlatAppearance.BorderSize = 0;
FlatStyle = System.Windows.Forms.FlatStyle.Flat;
}
protected override void OnPaint(PaintEventArgs e)
{
base.OnPaint(e);
// Draw Border using color specified in Flat Appearance
Pen pen = new Pen(FlatAppearance.BorderColor, 1);
Rectangle rectangle = new Rectangle(0, 0, Size.Width - 1, Size.Height - 1);
e.Graphics.DrawRectangle(pen, rectangle);
pen.Dispose();
}
}
In my case, this is how I made a button that mimics a ToolStripButton, where the border is only visible when you hover over the button:
public class ToolButton : Button
{
private bool ShowBorder { get; set; }
public ToolButton()
: base()
{
// Prevent the button from drawing its own border
FlatAppearance.BorderSize = 0;
// Set up a blue border and back colors for the button
FlatAppearance.BorderColor = Color.FromArgb(51, 153, 255);
FlatAppearance.CheckedBackColor = Color.FromArgb(153, 204, 255);
FlatAppearance.MouseDownBackColor = Color.FromArgb(153, 204, 255);
FlatAppearance.MouseOverBackColor = Color.FromArgb(194, 224, 255);
FlatStyle = System.Windows.Forms.FlatStyle.Flat;
// Set the size for the button to be the same as a ToolStripButton
Size = new System.Drawing.Size(23, 22);
}
protected override void OnMouseEnter(EventArgs e)
{
base.OnMouseEnter(e);
// Show the border when you hover over the button
ShowBorder = true;
}
protected override void OnMouseLeave(EventArgs e)
{
base.OnMouseLeave(e);
// Hide the border when you leave the button
ShowBorder = false;
}
protected override void OnPaint(PaintEventArgs e)
{
base.OnPaint(e);
// The DesignMode check here causes the border to always draw in the Designer
// This makes it easier to place your button
if (DesignMode || ShowBorder)
{
Pen pen = new Pen(FlatAppearance.BorderColor, 1);
Rectangle rectangle = new Rectangle(0, 0, Size.Width - 1, Size.Height - 1);
e.Graphics.DrawRectangle(pen, rectangle);
pen.Dispose();
}
}
// Prevent Text from being set on the button (since it will be an icon)
[Browsable(false)]
public override string Text { get { return ""; } set { base.Text = ""; } }
[Browsable(false)]
public override ContentAlignment TextAlign { get { return base.TextAlign; } set { base.TextAlign = value; } }
}
Make a custom button:
public partial class CustomButton: Button
{
public ButtonPageButton()
{
InitializeComponent();
this.SetStyle(ControlStyles.Selectable, false);
}
}
That'll get rid of that annoying border! ;-)
Another option (although a bit hacktastic) is to attach an event-handler to the button's GotFocus event. In that event-handler, pass a value of False to the button's NotifyDefault() method. So, for instance:
void myButton_GotFocus(object sender, EventArgs e)
{
myButton.NotifyDefault(false);
}
I'm assuming this will work every time, but I haven't tested it extensively. It's working for me for now, so I'm satisfied with that.
There is another way which works well for flat styled buttons. Don't use buttons but labels. As you are completely replacing the UI for the button it does not matter whether your use a button control or a label. Just handle the click in the same way.
This worked for me, although not great practice it is a good hack and as long as you name the button obviously (and comment the source) other coders will pick up the idea.
Ryan
The second border which gets added is the Windows standard "default button" border. You may have noticed that if you tab through most dialog boxes with multiple buttons (such as any Control Panel properties window), the original "double-bordered" button becomes "normal," and the in-focus button becomes "double-bordered."
This isn't necessarily focus at work, but rather a visual indication of the action undertaken by hitting the Enter key.
It sounds, to me, like you don't really care about that internal working. You want the display to not have two borders -- totally understandable. The internal working is to explain why you're seeing this behavior. Now ... To try and fix it.
The first thing I'd try -- and bear in mind, I haven't validated this -- is a hack. When a button receives focus (thereby getting the double-border), turn off your single border. You might get the effect you want, and it's pretty simple. (Hook into the Focus event. Even better, subclass Button and override OnFocus, then use that subclass for your future buttons.)
However, that might introduce new, awkward visual side effects. In that vein -- and because hacks are rarely the best answer -- I have to "officially" recommend what others have said: Custom paint the button. Although the code here may be overkill, this link at CodeProject discusses how to do that (VB link; you'll need translate). You should, in a full-on custom mode, be able to get rid of that second border completely.
Certainly you can draw the button yourself. One of the state flags is focused.
So on the draw event if the flag is focused go ahead and draw the button how you like, otherwise just pass it on to the base method.
Consider implementing your own drawing code for the button. That way you have full control. In the past, I've implemented my own Control derivative that custom paints my button and implements all the button characteristics for my purposes, but you should be able to override the button's painting and do it yourself, thereby controlling how it draws in every state, including when focused.
Set the FocusVisualStyle dependency property to null in your style, and the dotted border will be gone.
From MSDN: Styling for Focus in Controls, and FocusVisualStyle
Windows Presentation Foundation (WPF)
provides two parallel mechanisms for
changing the visual appearance of a
control when it receives keyboard
focus. The first mechanism is to use
property setters for properties such
as IsKeyboardFocused within the style
or template that is applied to the
control. The second mechanism is to
provide a separate style as the value
of the FocusVisualStyle property; the
"focus visual style" creates a
separate visual tree for an adorner
that draws on top of the control,
rather than changing the visual tree
of the control or other UI element by
replacing it. This topic discusses the
scenarios where each of these
mechanisms is appropriate.
The extra border you see is defined by the FocusVisualStyle and not in the control template, so you need to remove or override the style to remove the border.
If you have a textbox and a button
then on textchange event of textbox
write button1.focus();
It will work.
You can also create an invisible button and make it active whenever you press another button.
I've had good luck merely setting the Focusable property of the button to be false:
<Button HorizontalAlignment="Left" Margin="0,2"
Command="{Binding OpenSuspendedJobCommand, Mode=OneWay}"
Focusable="False"
Style="{StaticResource ActionButton}" Content="Open Job..." />

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