I started to use Json.NET to convert a string in JSON format to object or viceversa. I am not sure in the Json.NET framework, is it possible to convert a string in JSON to XML format and viceversa?
Yes. Using the JsonConvert class which contains helper methods for this precise purpose:
// To convert an XML node contained in string xml into a JSON string
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
string jsonText = JsonConvert.SerializeXmlNode(doc);
// To convert JSON text contained in string json into an XML node
XmlDocument doc = JsonConvert.DeserializeXmlNode(json);
Documentation here: Converting between JSON and XML with Json.NET
Yes, you can do it (I do) but Be aware of some paradoxes when converting, and handle appropriately. You cannot automatically conform to all interface possibilities, and there is limited built-in support in controlling the conversion- many JSON structures and values cannot automatically be converted both ways. Keep in mind I am using the default settings with Newtonsoft JSON library and MS XML library, so your mileage may vary:
XML -> JSON
All data becomes string data (for example you will always get "false" not false or "0" not 0) Obviously JavaScript treats these differently in certain cases.
Children elements can become nested-object {} OR nested-array [ {} {} ...] depending if there is only one or more than one XML child-element. You would consume these two differently in JavaScript, etc. Different examples of XML conforming to the same schema can produce actually different JSON structures this way. You can add the attribute json:Array='true' to your element to workaround this in some (but not necessarily all) cases.
Your XML must be fairly well-formed, I have noticed it doesn't need to perfectly conform to W3C standard, but 1. you must have a root element and 2. you cannot start element names with numbers are two of the enforced XML standards I have found when using Newtonsoft and MS libraries.
In older versions, Blank elements do not convert to JSON. They are ignored. A blank element does not become "element":null
A new update changes how null can be handled (Thanks to Jon Story for pointing it out): https://www.newtonsoft.com/json/help/html/T_Newtonsoft_Json_NullValueHandling.htm
JSON -> XML
You need a top level object that will convert to a root XML element or the parser will fail.
Your object names cannot start with a number, as they cannot be converted to elements (XML is technically even more strict than this) but I can 'get away' with breaking some of the other element naming rules.
Please feel free to mention any other issues you have noticed, I have developed my own custom routines for preparing and cleaning the strings as I convert back and forth. Your situation may or may not call for prep/cleanup. As StaxMan mentions, your situation may actually require that you convert between objects...this could entail appropriate interfaces and a bunch of case statements/etc to handle the caveats I mention above.
You can do these conversions also with the .NET Framework:
JSON to XML: by using System.Runtime.Serialization.Json
var xml = XDocument.Load(JsonReaderWriterFactory.CreateJsonReader(
Encoding.ASCII.GetBytes(jsonString), new XmlDictionaryReaderQuotas()));
XML to JSON: by using System.Web.Script.Serialization
var json = new JavaScriptSerializer().Serialize(GetXmlData(XElement.Parse(xmlString)));
private static Dictionary<string, object> GetXmlData(XElement xml)
{
var attr = xml.Attributes().ToDictionary(d => d.Name.LocalName, d => (object)d.Value);
if (xml.HasElements) attr.Add("_value", xml.Elements().Select(e => GetXmlData(e)));
else if (!xml.IsEmpty) attr.Add("_value", xml.Value);
return new Dictionary<string, object> { { xml.Name.LocalName, attr } };
}
I'm not sure there is point in such conversion (yes, many do it, but mostly to force a square peg through round hole) -- there is structural impedance mismatch, and conversion is lossy. So I would recommend against such format-to-format transformations.
But if you do it, first convert from json to object, then from object to xml (and vice versa for reverse direction). Doing direct transformation leads to ugly output, loss of information, or possibly both.
Thanks for David Brown's answer. In my case of JSON.Net 3.5, the convert methods are under the JsonConvert static class:
XmlNode myXmlNode = JsonConvert.DeserializeXmlNode(myJsonString); // is node not note
// or .DeserilizeXmlNode(myJsonString, "root"); // if myJsonString does not have a root
string jsonString = JsonConvert.SerializeXmlNode(myXmlNode);
I searched for a long time to find alternative code to the accepted solution in the hopes of not using an external assembly/project. I came up with the following thanks to the source code of the DynamicJson project:
public XmlDocument JsonToXML(string json)
{
XmlDocument doc = new XmlDocument();
using (var reader = JsonReaderWriterFactory.CreateJsonReader(Encoding.UTF8.GetBytes(json), XmlDictionaryReaderQuotas.Max))
{
XElement xml = XElement.Load(reader);
doc.LoadXml(xml.ToString());
}
return doc;
}
Note: I wanted an XmlDocument rather than an XElement for xPath purposes.
Also, this code obviously only goes from JSON to XML, there are various ways to do the opposite.
Here is the full c# code to convert xml to json
public static class JSon
{
public static string XmlToJSON(string xml)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
return XmlToJSON(doc);
}
public static string XmlToJSON(XmlDocument xmlDoc)
{
StringBuilder sbJSON = new StringBuilder();
sbJSON.Append("{ ");
XmlToJSONnode(sbJSON, xmlDoc.DocumentElement, true);
sbJSON.Append("}");
return sbJSON.ToString();
}
// XmlToJSONnode: Output an XmlElement, possibly as part of a higher array
private static void XmlToJSONnode(StringBuilder sbJSON, XmlElement node, bool showNodeName)
{
if (showNodeName)
sbJSON.Append("\"" + SafeJSON(node.Name) + "\": ");
sbJSON.Append("{");
// Build a sorted list of key-value pairs
// where key is case-sensitive nodeName
// value is an ArrayList of string or XmlElement
// so that we know whether the nodeName is an array or not.
SortedList<string, object> childNodeNames = new SortedList<string, object>();
// Add in all node attributes
if (node.Attributes != null)
foreach (XmlAttribute attr in node.Attributes)
StoreChildNode(childNodeNames, attr.Name, attr.InnerText);
// Add in all nodes
foreach (XmlNode cnode in node.ChildNodes)
{
if (cnode is XmlText)
StoreChildNode(childNodeNames, "value", cnode.InnerText);
else if (cnode is XmlElement)
StoreChildNode(childNodeNames, cnode.Name, cnode);
}
// Now output all stored info
foreach (string childname in childNodeNames.Keys)
{
List<object> alChild = (List<object>)childNodeNames[childname];
if (alChild.Count == 1)
OutputNode(childname, alChild[0], sbJSON, true);
else
{
sbJSON.Append(" \"" + SafeJSON(childname) + "\": [ ");
foreach (object Child in alChild)
OutputNode(childname, Child, sbJSON, false);
sbJSON.Remove(sbJSON.Length - 2, 2);
sbJSON.Append(" ], ");
}
}
sbJSON.Remove(sbJSON.Length - 2, 2);
sbJSON.Append(" }");
}
// StoreChildNode: Store data associated with each nodeName
// so that we know whether the nodeName is an array or not.
private static void StoreChildNode(SortedList<string, object> childNodeNames, string nodeName, object nodeValue)
{
// Pre-process contraction of XmlElement-s
if (nodeValue is XmlElement)
{
// Convert <aa></aa> into "aa":null
// <aa>xx</aa> into "aa":"xx"
XmlNode cnode = (XmlNode)nodeValue;
if (cnode.Attributes.Count == 0)
{
XmlNodeList children = cnode.ChildNodes;
if (children.Count == 0)
nodeValue = null;
else if (children.Count == 1 && (children[0] is XmlText))
nodeValue = ((XmlText)(children[0])).InnerText;
}
}
// Add nodeValue to ArrayList associated with each nodeName
// If nodeName doesn't exist then add it
List<object> ValuesAL;
if (childNodeNames.ContainsKey(nodeName))
{
ValuesAL = (List<object>)childNodeNames[nodeName];
}
else
{
ValuesAL = new List<object>();
childNodeNames[nodeName] = ValuesAL;
}
ValuesAL.Add(nodeValue);
}
private static void OutputNode(string childname, object alChild, StringBuilder sbJSON, bool showNodeName)
{
if (alChild == null)
{
if (showNodeName)
sbJSON.Append("\"" + SafeJSON(childname) + "\": ");
sbJSON.Append("null");
}
else if (alChild is string)
{
if (showNodeName)
sbJSON.Append("\"" + SafeJSON(childname) + "\": ");
string sChild = (string)alChild;
sChild = sChild.Trim();
sbJSON.Append("\"" + SafeJSON(sChild) + "\"");
}
else
XmlToJSONnode(sbJSON, (XmlElement)alChild, showNodeName);
sbJSON.Append(", ");
}
// Make a string safe for JSON
private static string SafeJSON(string sIn)
{
StringBuilder sbOut = new StringBuilder(sIn.Length);
foreach (char ch in sIn)
{
if (Char.IsControl(ch) || ch == '\'')
{
int ich = (int)ch;
sbOut.Append(#"\u" + ich.ToString("x4"));
continue;
}
else if (ch == '\"' || ch == '\\' || ch == '/')
{
sbOut.Append('\\');
}
sbOut.Append(ch);
}
return sbOut.ToString();
}
}
To convert a given XML string to JSON, simply call XmlToJSON() function as below.
string xml = "<menu id=\"file\" value=\"File\"> " +
"<popup>" +
"<menuitem value=\"New\" onclick=\"CreateNewDoc()\" />" +
"<menuitem value=\"Open\" onclick=\"OpenDoc()\" />" +
"<menuitem value=\"Close\" onclick=\"CloseDoc()\" />" +
"</popup>" +
"</menu>";
string json = JSON.XmlToJSON(xml);
// json = { "menu": {"id": "file", "popup": { "menuitem": [ {"onclick": "CreateNewDoc()", "value": "New" }, {"onclick": "OpenDoc()", "value": "Open" }, {"onclick": "CloseDoc()", "value": "Close" } ] }, "value": "File" }}
For convert JSON string to XML try this:
public string JsonToXML(string json)
{
XDocument xmlDoc = new XDocument(new XDeclaration("1.0", "utf-8", ""));
XElement root = new XElement("Root");
root.Name = "Result";
var dataTable = JsonConvert.DeserializeObject<DataTable>(json);
root.Add(
from row in dataTable.AsEnumerable()
select new XElement("Record",
from column in dataTable.Columns.Cast<DataColumn>()
select new XElement(column.ColumnName, row[column])
)
);
xmlDoc.Add(root);
return xmlDoc.ToString();
}
For convert XML to JSON try this:
public string XmlToJson(string xml)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
string jsonText = JsonConvert.SerializeXmlNode(doc);
return jsonText;
}
Here is a simple snippet that converts a XmlNode (recursively) into a hashtable, and groups multiple instances of the same child into an array (as an ArrayList).
The Hashtable is usually accepted to convert into JSON by most of the JSON libraries.
protected object convert(XmlNode root){
Hashtable obj = new Hashtable();
for(int i=0,n=root.ChildNodes.Count;i<n;i++){
object result = null;
XmlNode current = root.ChildNodes.Item(i);
if(current.NodeType != XmlNodeType.Text)
result = convert(current);
else{
int resultInt;
double resultFloat;
bool resultBoolean;
if(Int32.TryParse(current.Value, out resultInt)) return resultInt;
if(Double.TryParse(current.Value, out resultFloat)) return resultFloat;
if(Boolean.TryParse(current.Value, out resultBoolean)) return resultBoolean;
return current.Value;
}
if(obj[current.Name] == null)
obj[current.Name] = result;
else if(obj[current.Name].GetType().Equals(typeof(ArrayList)))
((ArrayList)obj[current.Name]).Add(result);
else{
ArrayList collision = new ArrayList();
collision.Add(obj[current.Name]);
collision.Add(result);
obj[current.Name] = collision;
}
}
return obj;
}
Try this function. I just wrote it and haven't had much of a chance to test it, but my preliminary tests are promising.
public static XmlDocument JsonToXml(string json)
{
XmlNode newNode = null;
XmlNode appendToNode = null;
XmlDocument returnXmlDoc = new XmlDocument();
returnXmlDoc.LoadXml("<Document />");
XmlNode rootNode = returnXmlDoc.SelectSingleNode("Document");
appendToNode = rootNode;
string[] arrElementData;
string[] arrElements = json.Split('\r');
foreach (string element in arrElements)
{
string processElement = element.Replace("\r", "").Replace("\n", "").Replace("\t", "").Trim();
if ((processElement.IndexOf("}") > -1 || processElement.IndexOf("]") > -1) && appendToNode != rootNode)
{
appendToNode = appendToNode.ParentNode;
}
else if (processElement.IndexOf("[") > -1)
{
processElement = processElement.Replace(":", "").Replace("[", "").Replace("\"", "").Trim();
newNode = returnXmlDoc.CreateElement(processElement);
appendToNode.AppendChild(newNode);
appendToNode = newNode;
}
else if (processElement.IndexOf("{") > -1 && processElement.IndexOf(":") > -1)
{
processElement = processElement.Replace(":", "").Replace("{", "").Replace("\"", "").Trim();
newNode = returnXmlDoc.CreateElement(processElement);
appendToNode.AppendChild(newNode);
appendToNode = newNode;
}
else
{
if (processElement.IndexOf(":") > -1)
{
arrElementData = processElement.Replace(": \"", ":").Replace("\",", "").Replace("\"", "").Split(':');
newNode = returnXmlDoc.CreateElement(arrElementData[0]);
for (int i = 1; i < arrElementData.Length; i++)
{
newNode.InnerText += arrElementData[i];
}
appendToNode.AppendChild(newNode);
}
}
}
return returnXmlDoc;
}
I did like David Brown said but I got the following exception.
$exception {"There are multiple root elements. Line , position ."} System.Xml.XmlException
One solution would be to modify the XML file with a root element but that is not always necessary and for an XML stream it might not be possible either. My solution below:
var path = Path.GetFullPath(Path.Combine(Environment.CurrentDirectory, #"..\..\App_Data"));
var directoryInfo = new DirectoryInfo(path);
var fileInfos = directoryInfo.GetFiles("*.xml");
foreach (var fileInfo in fileInfos)
{
XmlDocument doc = new XmlDocument();
XmlReaderSettings settings = new XmlReaderSettings();
settings.ConformanceLevel = ConformanceLevel.Fragment;
using (XmlReader reader = XmlReader.Create(fileInfo.FullName, settings))
{
while (reader.Read())
{
if (reader.NodeType == XmlNodeType.Element)
{
var node = doc.ReadNode(reader);
string json = JsonConvert.SerializeXmlNode(node);
}
}
}
}
Example XML that generates the error:
<parent>
<child>
Text
</child>
</parent>
<parent>
<child>
<grandchild>
Text
</grandchild>
<grandchild>
Text
</grandchild>
</child>
<child>
Text
</child>
</parent>
I have used the below methods to convert the JSON to XML
List <Item> items;
public void LoadJsonAndReadToXML() {
using(StreamReader r = new StreamReader(# "E:\Json\overiddenhotelranks.json")) {
string json = r.ReadToEnd();
items = JsonConvert.DeserializeObject <List<Item>> (json);
ReadToXML();
}
}
And
public void ReadToXML() {
try {
var xEle = new XElement("Items",
from item in items select new XElement("Item",
new XElement("mhid", item.mhid),
new XElement("hotelName", item.hotelName),
new XElement("destination", item.destination),
new XElement("destinationID", item.destinationID),
new XElement("rank", item.rank),
new XElement("toDisplayOnFod", item.toDisplayOnFod),
new XElement("comment", item.comment),
new XElement("Destinationcode", item.Destinationcode),
new XElement("LoadDate", item.LoadDate)
));
xEle.Save("E:\\employees.xml");
Console.WriteLine("Converted to XML");
} catch (Exception ex) {
Console.WriteLine(ex.Message);
}
Console.ReadLine();
}
I have used the class named Item to represent the elements
public class Item {
public int mhid { get; set; }
public string hotelName { get; set; }
public string destination { get; set; }
public int destinationID { get; set; }
public int rank { get; set; }
public int toDisplayOnFod { get; set; }
public string comment { get; set; }
public string Destinationcode { get; set; }
public string LoadDate { get; set; }
}
It works....
Cinchoo ETL - an open source library available to do the conversion of Xml to JSON easily with few lines of code
Xml -> JSON:
using (var p = new ChoXmlReader("sample.xml"))
{
using (var w = new ChoJSONWriter("sample.json"))
{
w.Write(p);
}
}
JSON -> Xml:
using (var p = new ChoJsonReader("sample.json"))
{
using (var w = new ChoXmlWriter("sample.xml"))
{
w.Write(p);
}
}
Sample fiddle: https://dotnetfiddle.net/enUJKu
Checkout CodeProject articles for some additional help.
Disclaimer: I'm the author of this library.
Here's an example of how to convert JSON to XML using .NET built-in libraries (instead of 3rd party libraries like Newtonsoft).
using System.Text.Json;
using System.Text.Json.Nodes;
using System.Xml.Linq;
XDocument xmlDoc = jsonToXml(jsonObj);
private XDocument jsonToXml(JsonObject obj)
{
var xmlDoc = new XDocument();
var root = new XElement("Root");
xmlDoc.Add(root);
foreach (var prop in obj)
{
var xElement = new XElement(prop.Key);
xElement.Value = prop.Value.ToString();
root.Add(xElement);
}
return xmlDoc;
}
Related
I am very new at C#. In my project I need to create a csv file which will get data from a xml data. Now, I can get data from XML, and print in looger for some particulaer attributes from xml. But I am not sure how can I store my Data into CSV file for that particular attribues.
Here is my XML file that I need to create a CSV file.
<?xml version="1.0" encoding="utf-8"?>
<tlp:WorkUnits xmlns:tlp="http://www.timelog.com/XML/Schema/tlp/v4_4"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.timelog.com/XML/Schema/tlp/v4_4 http://www.timelog.com/api/xsd/WorkUnitsRaw.xsd">
<tlp:WorkUnit ID="130">
<tlp:EmployeeID>3</tlp:EmployeeID>
<tlp:AllocationID>114</tlp:AllocationID>
<tlp:TaskID>239</tlp:TaskID>
<tlp:ProjectID>26</tlp:ProjectID>
<tlp:ProjectName>LIK Template</tlp:ProjectName>
<tlp:CustomerId>343</tlp:CustomerId>
<tlp:CustomerName>Lekt Corp Inc.</tlp:CustomerName>
<tlp:IsBillable>1</tlp:IsBillable>
<tlp:ApprovedStatus>0</tlp:ApprovedStatus>
<tlp:LastModifiedBy>AL</tlp:LastModifiedBy>
</tlp:WorkUnit>
And my Code where I am getting this value in logger.But I am not sure how can I create a csv file that stores that value in order.
Edited
namespace TimeLog.ApiConsoleApp
{
/// <summary>
/// Template class for consuming the reporting API
/// </summary>
public class ConsumeReportingApi
{
private static readonly ILog Logger = LogManager.GetLogger(typeof(ConsumeReportingApi));
public static void Consume()
{
if (ServiceHandler.Instance.TryAuthenticate())
{
if (Logger.IsInfoEnabled)
{
Logger.Info("Successfully authenticated on reporting API");
}
var customersRaw = ServiceHandler.Instance.Client.GetWorkUnitsRaw(ServiceHandler.Instance.SiteCode,
ServiceHandler.Instance.ApiId,
ServiceHandler.Instance.ApiPassword,
WorkUnit.All,
Employee.All,
Allocation.All,
Task.All,
Project.All,
Department.All,
DateTime.Now.AddDays(-5).ToString(),
DateTime.Now.ToString()
);
if (customersRaw.OwnerDocument != null)
{
var namespaceManager = new XmlNamespaceManager(customersRaw.OwnerDocument.NameTable);
namespaceManager.AddNamespace("tlp", "http://www.timelog.com/XML/Schema/tlp/v4_4");
var workUnit = customersRaw.SelectNodes("tlp:WorkUnit", namespaceManager);
var output = new StringBuilder();
output.AppendLine("AllocationID,ApprovedStatus,CustomerId,CustomerName,EmployeeID");
if (workUnit != null)
{
foreach (XmlNode customer in workUnit)
{
var unit = new WorkUnit();
var childNodes = customer.SelectNodes("./*");
if (childNodes != null)
{
foreach (XmlNode childNode in childNodes)
{
if (childNode.Name == "tlp:EmployeeID")
{
unit.EmployeeID = Int32.Parse(childNode.InnerText);
}
if (childNode.Name == "tlp:EmployeeFirstName")
{
unit.EmployeeFirstName = childNode.InnerText;
}
if (childNode.Name == "tlp:EmployeeLastName")
{
unit.EmployeeLastName = childNode.InnerText;
}
if (childNode.Name == "tlp:AllocationID")
{
unit.AllocationID = Int32.Parse(childNode.InnerText);
}
if (childNode.Name == "tlp:TaskName")
{
unit.TaskName = childNode.InnerText;
}
}
}
output.AppendLine($"{unit.EmployeeID},{unit.EmployeeFirstName},{unit.EmployeeLastName},{unit.AllocationID},{unit.TaskName}");
//Console.WriteLine("---");
}
Console.WriteLine(output.ToString());
File.WriteAllText("c:\\...\\WorkUnits.csv", output.ToString());
}
}
else
{
if (Logger.IsWarnEnabled)
{
Logger.Warn("Failed to authenticate to reporting API");
}
}
}
}
}
}
You want to write the columns in the correct order to the CSV (of course), so you need to process them in the correct order. Two options:
intermediate class
Create a new class (let's call it WorkUnit) with properties for each of the columns that you want to write to the CSV. Create a new instance for every <tlp:WorkUnit> node in your XML and fill the properties when you encounter the correct subnodes. When you have processed the entire WorkUnit node, write out the properties in the correct order.
var output = new StringBuilder();
foreach (XmlNode customer in workUnit)
{
// fresh instance of the class that holds all columns (so all properties are cleared)
var unit = new WorkUnit();
var childNodes = customer.SelectNodes("./*");
if (childNodes != null)
{
foreach (XmlNode childNode in childNodes)
{
if(childNode.Name== "tlp:EmployeeID")
{
// employeeID node found, now write to the corresponding property:
unit.EmployeeId = childNode.InnerText;
}
// etc for the other XML nodes you are interested in
}
// all nodes have been processed for this one WorkUnit node
// so write a line to the CSV
output.AppendLine($"{unit.EmployeeId},{unit.AllocationId}, etc");
}
read in correct order
Instead of using foreach to loop through all subnodes in whatever order they appear, search for specific subnodes in the order you want. Then you can write out the CSV in the same order. Note that even when you don't find some subnode, you still need to write out the separator.
var output = new StringBuilder();
foreach (XmlNode customer in workUnit)
{
// search for value for first column (EmployeeID)
var node = workUnit.SelectSingleNode("tlp:EmployeeID");
if (node != null)
{
output.Append(node.InnerText).Append(',');
}
else
{
output.Append(','); // no content, but we still need a separator
}
// etc for the other columns
And of course watch out for string values that contain the separator.
Assuming that you put your XML data into List
StringBuilder str = new StringBuilder();
foreach (var fin list.ToList())
{
str.Append(fin.listfield.ToString() + ",");
}
to create a new line:
str.Replace(",", Environment.NewLine, str.Length - 1, 1);
to save:
string filename=(DirectoryPat/filename.csv");
File.WriteAllText(Filename, str.ToString());
Try this:
var output = new StringBuilder();
output.AppendLine("AllocationID,ApprovedStatus,CustomerId,CustomerName,EmployeeID");
if (workUnit != null)
{
foreach (XmlNode customer in workUnit)
{
var unit = new WorkUnit();
var childNodes = customer.SelectNodes("./*");
if (childNodes != null)
{
for (int i = 0; i<childNodes.Count; ++i)
{
XmlNode childNode = childNodes[i];
if (childNode.Name == "tlp:EmployeeID")
{
unit.EmployeeID = Int32.Parse(childNode.InnerText);
}
if (childNode.Name == "tlp:EmployeeFirstName")
{
unit.EmployeeFirstName = childNode.InnerText;
}
if (childNode.Name == "tlp:EmployeeLastName")
{
unit.EmployeeLastName = childNode.InnerText;
}
if (childNode.Name == "tlp:AllocationID")
{
unit.AllocationID = Int32.Parse(childNode.InnerText);
}
if (childNode.Name == "tlp:TaskName")
{
unit.TaskName = childNode.InnerText;
}
output.Append(childNode.InnerText);
if (i<childNodes.Count - 1)
output.Append(",");
}
output.Append(Environment.NewLine);
}
}
Console.WriteLine(output.ToString());
File.WriteAllText("c:\\Users\\mnowshin\\projects\\WorkUnits.csv", output.ToString());
}
You can use this sequence:
a. Deserialize (i.e. convert from XML to C# objects) your XML.
b. Write a simple loop to write the data to a file.
The advantages of this sequence:
You can use a list of your data/objects "readable" that you can add any other access code to it.
If you XML schema changed at any time, you can maintain the code very easily.
The solution
a. Desrialize:
Copy you XML file contents. Note You should modify your XML input before coping it.. You should double the WorkUnit node, in order to tell Visual Studio that you would have a list of this node nested inside WorkUnits node.
From Visual Studio Menus select Edit -> Paste Special -> Paste XML as Classes.
Use the deserialize code.
var workUnitsNode = customersRaw.SelectSingleNode("tlp:WorkUnits", namespaceManager);
XmlSerializer ser = new XmlSerializer(typeof(WorkUnits));
WorkUnits workUnits = (WorkUnits)ser.Deserialize(workUnitsNode);
b. Write the csv file
StringBuilder csvContent = new StringBuilder();
// add the header line
csvContent.AppendLine("AllocationID,ApprovedStatus,CustomerId,CustomerName,EmployeeID");
foreach (var unit in workUnits.WorkUnit)
{
csvContent.AppendFormat(
"{0}, {1}, {2}, {3}, {4}",
new object[]
{
unit.AllocationID,
unit.ApprovedStatus,
unit.CustomerId,
unit.CustomerName,
unit.EmployeeID
// you get the idea
});
csvContent.AppendLine();
}
File.WriteAllText(#"G:\Projects\StackOverFlow\WpfApp1\WorkUnits.csv", csvContent.ToString());
You can use Cinchoo ETL - if you have room to use open source library
using (var csvWriter = new ChoCSVWriter("sample1.csv").WithFirstLineHeader())
{
using (var xmlReader = new ChoXmlReader("sample1.xml"))
csvWriter.Write(xmlReader);
}
Output:
ID,tlp_EmployeeID,tlp_AllocationID,tlp_TaskID,tlp_ProjectID,tlp_ProjectName,tlp_CustomerId,tlp_CustomerName,tlp_IsBillable,tlp_ApprovedStatus,tlp_LastModifiedBy
130,3,114,239,26,LIK Template,343,Lekt Corp Inc.,1,0,AL
Disclaimer: I'm the author of this library.
I am trying to retrieve data from an XML file and return the parsed data in a list. Depending on what I use to access the data (Element or Attributes) I either get null (in case of Element) or something I cannot decipher (in case of Attributes).
XML Looks like this:
<DATA_RESPONSE>
<HEADER>
<MSGID>IS20101P:091317125610:98::34:0</MSGID>
</HEADER>
<DATA>
<ROW ID='IS20101P' PE_NAME='APP-029' PE_ID='4' CODE='4829' DATA='5,1,500,1' />
<ROW ID='IS20101P' PE_NAME='APPS-029' PE_ID='4' CODE='4829' DATA='4,1,500,1' />
...
</DATA>
<SUMMARY>
</SUMMARY>
<ERRORS>
</ERRORS>
</DATA_RESPONSE>
I am using the following to get the data. I read the file and store XML in a string and call a method with this string as argument:
public static Hashtable GetIDSData(string sXMLString)
{
Hashtable result = new Hashtable();
result.Add("Success", false);
result.Add("ErrorMessage", "");
result.Add("ID", "");
result.Add("PE_NAME", "");
result.Add("PE_ID", "");
result.Add("CODE", "");
result.Add("DATA", "");
xmlDoc.InnerXml = sXMLString;
XmlElement root = xmlDoc.DocumentElement;
XDocument doc = XDocument.Parse(sXMLString);
XmlNode node = xmlDoc.SelectSingleNode("DATA_RESPONSE/DATA");
if (node != null)
{
var AddressInfoList = doc.Root.Descendants("ROW").Select(Address => new
{
ID = Address.Attributes("ID")?.ToString(),
PEName = Address.Attributes("PE_NAME")?.ToString(),
PEID = Address.Attributes("PE_ID")?.ToString(),
Code = Address.Attributes("CODE")?.ToString(),
Data = Address.Attributes("DATA")?.ToString(),
}).ToList();
foreach (var AddressInfo in AddressInfoList)
{
if (string.IsNullOrEmpty(AddressInfo.Code))
{
result["Success"] = false;
result["ErrorMessage"] = "Invalid Code; code is empty.";
}
else
{
result["Success"] = true;
result["ErrorMessage"] = "";
result["ID"] = AddressInfo.ID;
result["PE_NAME"] = AddressInfo.PEName;
result["PE_ID"] = AddressInfo.PEID;
result["CODE"] = AddressInfo.Code;
result["DATA"] = AddressInfo.Data;
}
}
return result;
}
In Linq section, if I use Address.Element("ID").Value, I get null returned.
There is no namespace used in XML.
First off, the GetIDSData() method does not compile as is, because at the line xmlDoc.InnerXml = sXMLString, xmlDoc has not been defined.
I'm assuming you want xmlDoc to be an XmlDocument loaded with the contents of the sXMLString parameter, so I'm changing that line to:
XmlDocument xmlDoc = new XmlDocument {InnerXml = sXMLString};
Also, your root variable is never used, so I removed it for clarity.
Now as for the main part of your question, given your current syntax, you are calling .ToString() on a collection of attributes, which is obviously not what you want. To fix this, when you're iterating the AddressInfoList, You want to fetch the attribute values like:
ID = Address.Attributes("ID")?.Single().Value
or
ID = address.Attribute("ID")?.Value
...rather than Address.Attributes("ID")?.ToString() as you have above.
You are not selecting values of attributes. In your code you are selecting attributes. Not sure what are you trying to achieve, but here is my modified version of your code that loads all elements into DataTable
public static DataTable GetIDSData(string sXMLString)
{
DataTable result = new DataTable();
result.Columns.Add("Success");
result.Columns.Add("ErrorMessage");
result.Columns.Add("ID");
result.Columns.Add("PE_NAME");
result.Columns.Add("PE_ID");
result.Columns.Add("CODE");
result.Columns.Add("DATA");
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.InnerXml = sXMLString;
XmlElement root = xmlDoc.DocumentElement;
XDocument doc = XDocument.Parse(sXMLString);
XmlNode node = xmlDoc.SelectSingleNode("DATA_RESPONSE/DATA");
if (node != null)
{
var AddressInfoList = doc.Root.Descendants("ROW").Select(Address => new
{
ID = Address.Attributes("ID").Select(i=>i.Value) ,
PEName = Address.Attributes("PE_NAME").Select(i=>i.Value),
PEID = Address.Attributes("PE_ID").Select(i=>i.Value),
Code = Address.Attributes("CODE").Select(i=>i.Value),
Data = Address.Attributes("DATA").Select(i=>i.Value),
}).ToList();
AddressInfoList.ForEach(e =>
{
e.Code.ToList().ForEach(c =>
{
DataRow row = result.NewRow();
if (!string.IsNullOrEmpty(c))
{
row["Success"] = true;
row["ErrorMessage"] = "";
row["ID"] = e.ID.First();
row["PE_NAME"] = e.PEName.First();
row["PE_ID"] = e.PEID.First();
row["CODE"] = e.Code.First();
row["DATA"] = e.Data.First();
}
else
{
row["Success"] = false;
row["ErrorMessage"] = "Invalid Code; code is empty.";
}
result.Rows.Add(row);
});});
result.Dump();
return result;
}
return result;
}
And this is the result that you will get in your datatable.
ID = Address.Attributes("ID")?.ToString(),
You want to use Attribute(name) (without s) instead:
ID = Address.Attributes("ID")?.Value,
Im new here and my english is not good! i hope you can understand what i mean!
main:
i have a program C# convert xml to xml but with difference structure!
this mine:
<require_skill>
<skillIds>236</skillIds>
<skillIds>237</skillIds>
<skillIds>238</skillIds>
<skillIds>239</skillIds>
<skillIds>240</skillIds>
<skillIds>2039</skillIds>
<skillIds>2811</skillIds>
</require_skill>
and i want to make it like this
<require_skill skillIds="236 237 238 239 240 2039 2811"/>
this is my code:
[XmlElement("require_skill", Form = XmlSchemaForm.Unqualified)]
public RequireStigmaSkill[] require_skill;
[Serializable]
[XmlType(Namespace = "", AnonymousType = true)]
public class RequireStigmaSkill
{
//[XmlAttribute]
//public String skilllvl;
[XmlElement("skillIds", Form = XmlSchemaForm.Unqualified)]
public String[] skillIds;
}
in main program:
utility.Export<String>(item, "require_skill", requiredGen);
if (requiredGen.Count() > 0)
{
List<RequireStigmaSkill> requiredArray = new List<RequireStigmaSkill>();
foreach (string asName in requiredGen)
{
//asName as SkillStartname
List<String> forThisName = new List<string>();
foreach (ClientSkill skillGen in skills.SkillList)
{
if (skillGen.name.StartsWith(asName))
{
if (skillGen.name.StartsWith(asName))
forThisName.Add(skillGen.id);
}
}
//Did it.
var required = new RequireStigmaSkill();
//required.skilllvl = "1";
required.skillIds = forThisName.ToArray();
requiredArray.Add(required);
}
i.stigma.require_skill = requiredArray.ToArray();
}
How do I make more than 1 value in the same attribute?
I am actually not able to understand your main code so I tried to create a string as you want. Try and map it to your code and make the necessary changes if possible. The following are the steps I did:
Created a xml file and copy-pasted your input xml
Loaded the xml file and created the string. The following is the code for the same:
XmlDocument doc = new XmlDocument();
doc.Load("XMLFile1.xml");
StringBuilder builder = new StringBuilder();
foreach (XmlNode require_skill in doc.ChildNodes)
{
foreach (XmlNode skillIds in require_skill.ChildNodes)
{
builder.Append(skillIds.InnerText);
builder.Append(" ");
}
}
string attributeStr = builder.ToString().Substring(0, builder.Length - 1);
string finalStr = "<require_skill skillIds=\"" + attributeStr + "\"\\>";
You can then write this string to a file using "System.IO.File.WriteAllText" as
System.IO.File.WriteAllText("filename.xml", finalStr);
Hope this helps.
Here is the sample XML that I am receiving from the web service.
<xml xmlns:s='uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882'
xmlns:dt='uuid:C2F41010-65B3-11d1-A29F-00AA00C14882'
xmlns:rs='urn:schemas-microsoft-com:rowset'
xmlns:z='#RowsetSchema'>
<s:Schema id='RowsetSchema'>
<s:ElementType name='row' content='eltOnly'>
<s:AttributeType name='NAME' rs:number='1'>
<s:datatype dt:type='string' rs:dbtype='str' dt:maxLength='25'
rs:maybenull='false'/>
</s:AttributeType>
<s:AttributeType name='DESCRIPTION' rs:number='2' rs:nullable='true'
rs:writeunknown='true'>
<s:datatype dt:type='string' rs:dbtype='str' dt:maxLength='80'/>
</s:AttributeType>
<s:extends type='rs:rowbase'/>
</s:ElementType>
</s:Schema>
<rs:data>
<z:row NAME='JOE BLOW' DESCRIPTION='PROGRAMMER'/>
<z:row NAME='ANN SMITH' DESCRIPTION='FRONT DESK'/>
<z:row NAME='STEVE JOHNSON' DESCRIPTION='TESTER'/>
</rs:data>
</xml>
I'm not sure how to go about getting to the <rs:data> node. I eventually want to enumerate through each <z:row> and get the attributes NAME and DESCRPTION. The webservice returns this to me as a string so I load the string into an XMLDocument like this:
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(xmlString);
Now, I'm not sure if I need to use a XmlNamespaceManager in order to tel my xDoc to import the <s:Schema>
I've tried to select a single node with an XPath with no luck because of the prefix rs.
XmlNode xNode = xDoc.SelectSingleNode("/rs:data");
If there is any further information needed, please ask.
If you are taking the xml as a string try parsing it like instead of using Load()
var xml = XDocument.Parse(xmlstring);
You have to use the namespace to get hold of the data properly.
XNamespace ns = "#RowsetSchema";
foreach (var element in xml.Descendants().Elements(ns + "row"))
{
Console.WriteLine ("Name = " + element.Attribute("NAME").Value + ", " + "Description = " + element.Attribute("DESCRIPTION").Value);
}
Using xml with linq it can be done like this:
XDocument xmlDoc = new XDocument();
xmlDoc = XDocument.Parse(xml);
XNamespace ns = "#RowsetSchema";
var namesDescs = from namesDesc in xmlDoc.Descendants().Elements(ns + "row")
select new
{
name = namesDesc.Attribute("NAME").Value,
description = namesDesc.Attribute("DESCRIPTION").Value,
};
Here's some classes for handling your xml, using these extensions: http://searisen.com/xmllib/extensions.wiki
public class Test
{
XElement self;
public Test(XElement self)
{
this.self = self;
}
public RSDataRow[] DataRows
{
get
{
if (null == _DataRows)
{
_DataRows = self.GetEnumerable("rs:data/z:row", xrow => new RSDataRow(xrow)).ToArray();
}
return _DataRows;
}
}
RSDataRow[] _DataRows;
}
[DebuggerDisplay("{Name}")]
public class RSDataRow
{
XElement self;
public RSDataRow(XElement self)
{
this.self = self;
}
public string Name
{
get { return self.Get("NAME", string.Empty); }
}
public string Description
{
get { return self.Get("DESCRIPTION", string.Empty); }
}
}
You use it like:
Test test = new Test(XElement.Parse(xmlstring));
foreach (RSDataRow row in test.DataRows)
{
string name = row.Name;
string desc = row.Description;
}
I have the following xml
<Objects>
<Object>
<ViewAngle>90</ViewAngle>
<ViewMode>ThirdPerson</ViewMode>
<Top>50</Top>
<Left>100</Left>
</Object>
</Objects>
I have the following code to read this xml
XmlDataDocument doc = new XmlDataDocument();
doc.Load(xmlPath);
XmlElement root = doc.DocumentElement;
XmlNodeList nodes = root.SelectNodes("/Objects/Object");
foreach (XmlNode node in nodes)
{
if (node.InnerXml.Contains("View"))
{
string viewType=node["View"].InnerText;
//..... other stuffs
}
if (node.InnerXml.Contains("ViewAngle"))
{
string viewAngle=node["ViewAngle"].InnerText;
//..... other stuffs
}
if (node.InnerXml.Contains("ViewMode"))
{
string viewMode=node["ViewMode"].InnerText;
//..... other stuffs
}
}
Above code is working fine if my xml contains one more tag i.e. <View>3dView</View>. But if it does not contains the View tag, then it produces error.
The InnerXml.Contains() is a simple string method that checks for the sub-string is present in the string or not.
In my case the Contains("View") returns true as View is present in ViewAngle and in ViewMode that is why it is going inside the if block of View but when it tries to read the node["View"], it produces error as View node is not exists in the xml.
How to resolve this error?
You are missing the fact that XML is structured data, not string. This is completely the wrong approach:
if (node.InnerXml.Contains("View")) {
// ...
}
You want this:
XmlNode child = node.SelectSingleNode("./View");
if (child != null) {
// now do something with 'child' ...
}
Try this loop instead:
foreach (XmlNode node in nodes) {
foreach (XmlNode prop in node.ChildNodes) {
if (prop.NodeType != XmlNodeType.Element)
continue;
switch (prop.Name) {
case "View":
string viewType = prop.InnerText;
// ...
break;
case "ViewAngle":
string viewAngle = prop.InnerText;
// ...
break;
case "ViewMode":
string viewMode = prop.InnerText;
// ...
break;
}
}
}
If the View element is not present, it cannot be found. You can use the GetElementsByTagName("View") method instead. This will return null if the view element is not there.
You can make some modifications in this function and use it acordingly
XDocument xDoc=XDocument.Load(#"C:\File.xml");
Process(xDoc.Root);
public static void Process(XElement element)
{
if (element.HasElements)
{
Console.WriteLine("<" + element.Name.LocalName + ">");
foreach (XElement child in element.Elements())
{
Process(child);
}
Console.WriteLine("<" + element.Name.LocalName + ">");
}
else
{
Console.WriteLine("<" + element.Name.LocalName);
if(element.HasAttributes)
{
foreach (XAttribute attr in element.Attributes())
{
Console.WriteLine(attr.Name +"="+attr.Value);
}
}
Console.WriteLine(">" + element.Value + "</" + element.Name.LocalName + ">");
}
}
if trageting 3.5 or above u can use linq
XDocument XDoc = XDocument.Load(#"C:\UrXMLFile.xml");
var q = from b in xml.Descendants("product")
select new
{
View = (string)b.Element("View") ?? "3dView",
ViewAngle = (double?)b.Element("ViewAngle") ?? 90.0,
ViewMode = (string)b.Element("ViewMode") ?? ThirdPerson,
Top = (double?)b.Element("Top") ?? 0.0,
Left = (double?)b.Element("Left") ?? 0.0
};
So if View is not found it have a default value always. Also u can create ur class object in select new. Note: I have not compiled it.