I'm writing a unit test for file uploading feature of my web application. I mocked a test file, and save it in the "Test files" subdirectory of the directory that my test project resident in.
As I don't want to hard coded the file path. How can I know the directory of my project by code? I used #"..\Test files\test1.xml", but it doesn't work.
Thanks in advance!
Remember that your unit test project will be running relative from it's own bin directory, and not from the project directory. You can get the path to that bin directory using:
Assembly.GetExecutingAssembly().Location
However, the easiest thing to do is set your test files and folders to be copied to the output directory. Just click on your file in the solution explorer, hit F4, and change "Copy to Output Directory" to "Copy always" or "Copy if newer". The folder structure will automatically also be copied. Then your relative path statements will work correctly.
I beleive HttpContext.Current.Request.PhysicalApplicationPath will give you the physical directory of your application root.
I would store the name of the sub directory in the web.config file, and then use System.IO.Path.Combine(HttpContext.Current.Request.PhysicalApplicationPath,) to build the full path to the sub directory.
Just another way:
int ix = Application.StartupPath.LastIndexOf(Application.ProductName);
string s = Application.StartupPath.Remove(ix + Application.ProductName.Length + 1);
edit: After I posted it I saw that the question was for web applications, while my solution is for Windows Forms.
Related
I'm currently using fileinfo to use a xsd file in a xml validator.
I have 3 projects, a GUI, interface, project. A input project and a testproject.
Inside the input project i have a class that creates a FileInfo Object based on a path to a file that is also inside the same object:
new FileInfo(#"Xsd\Version_813\kvppt-8130.xsd")
This gives me trouble when i'm running my tests and my GUI. For example when i start my GUI, sometimes the code works and there is no problem but other times FileInfo will search the Bin/debug folder from the GUI project and the XSD isnt there.
I know that this is intended but is there a way to make this work for the unittest Project and the GUI project.
I have tried the following:
var executingFileInfo = new FileInfo(Assembly.GetExecutingAssembly().Location);
var path = executingFileInfo.DirectoryName + Path.DirectorySeparatorChar + #"Xsd\Version_813\kvppt-8130.xsd";
Return new FileInfo(path);
But this isn't the solution because it will still pick the startup project.
--- Edit:
After trying some of the suggestions in the comments i found out that my problem is a bit diffrent. I found out that if i press rebuild all before running my application, the files are always copied to their correct folder. It only fails if i just run the application.
Properties of the files are on "Copy always"
...sometimes the code works and there is no problem but other times
FileInfo will search the Bin/debug folder from the GUI project and the
XSD isnt there.
Make sure on the properties of the file (from within Visual Studio) you have "Copy to Output Directory" set to either "copy always" or "copy if newer"
I have just created a WPF application and just been wondering where is my app.config file?
I looked in the bin/Debug and bin/Release directories and there is just one file "WpfApplication1.vshost.exe" and could not find any app.config file.
All I can do is Add->New Configuratin File and this too, doesn't come in debug or Release folder.
Can anyone guide me whether I should manually copy and paste it in the debug or Release Folder?
So finally: the ANSWER
If app.config does not exist, then try creating a new one by "Add->New Item->Application Configuration File" and create a file named "App.config". After this, try rebuilding your application, the .config file specific to your project should appear in bin/Debug & bin/Release folder.
It should be getting copied into the Debug/Release folders automatically. However, you could try explicitly setting the "Copy to output directory" in the properties to Copy always and see if it appears.
After creating simple WPF project my solution look like this. App.config lies there, which is the configuration file itself
When you build your solution, which in my case is named as WpfApplication1, config file lies at WpfApplication1.exe.config in \WpfApplication1\bin\Debug\ folder.
When you build your application,it automatically gets copies to debug/Release Folder.just look for *.config file in those folders.
If you build your project you should have a file named foo.bar.exe.config in you binary directory. The app.config file itself should be visible within your solution directory.
I have my files place in a directory name XMLpackage which is located under the Root of my project
At run time i need to read the file by passing the Path.
By putting my file in debug folder i was able to read. But in this specific XMLpackage folder i can not read it.
How to do this?
Change the file property 'Copy to Output' with value other than 'Do not copy'
To get the file path try,
Path.Combine(AppDomain.CurrentDomain.BaseDirectory, "XMLpackage", "file1.xml");
Try this. Right click the file in Solution Explorer and click on Properties. Change the "Copy to Output Directory" to "Copy Always" as shown in the image.
You can access the file like
string f = System.IO.File.ReadAllText(#"XMLpackage\TableScripts.xml");
I need to read data from a file in a c# console application.
What works: new StreamReader(#"..\\..\myData.csv");
Problem:
the ..\\..\ work because my exe file is in the bin/Debug directory
When I deploy my project the path doesn't work any longer
Question:
How can I reference myData.csv regardless of the location of the exe file?
I had hoped to find a method that returns the 'root' of my console application
So far I tried the following:
Process.GetCurrentProcess().MainModule.FileName
Path.GetDirectoryName(Assembly.GetEntryAssembly().Location
Path.GetFullPath("bp.csv")
AppDomain.CurrentDomain.BaseDirectory
Directory.GetCurrentDirectory()
All of these expressions lead me to the directory of the exe file not the root.
I just started to read about isolated storage but it would be nice to have something simpler. Any suggestions / recommendations?
The simplest option is probably to add your CSV file to the solution and right-click it in VS and set the build action to "Copy if newer", which will output it together with the .exe (to the Debug or Release folder) when you build.
In the code, you can get the current location of the executing assembly like this:
string folder = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location);
And then you can combine the path with the CSV file name:
string filePath = Path.Combine(folder, "myData.csv");
Where your myData.csv will be stored ? You should have an absolute location of this file.
there are couple of options
You can place this file at the same directory where your exe is placed so you will only need to do
new StreamReader("myData.csv");
you can define file location in the App.Conig file and read that location.
you can set a path variable an read the PATH variable.
You should change your code to
new StreamReader("myData.csv");
This will ensure that the data is always read from the same folder the .exe is run from.
After that, you can create a post build step to copy the file to the deployment folder (or a subfolder) so that even in your debug environment the file will be in the correct place. The property "Copy to Output Folder" on the data file will do this as well if you just need the file to be in the output path for a project.
If you need more control, n the post build steps you can use macros like $(ProjectPath) to reference where the project files are located and $(TargetDir) to reference where the output directory will be.
I have an xml file in a WCF application that describes dependencies. It is loaded when the service facade constructor runs and works great when testing the app alone. The way our separate web testing application is setup is an endpoint in a different (mvc) project - So the relative paths are different to the xml file that we need to load. The question is what would be the best way to load that file from both projects (so that when you run the first project alone it loads the file, but then when that dll is loaded in the second project it can still find the xml file)?
You could copy it to the output directory. You can do this from Visual Studio by right clicking the file, choosing properties and changing "Copy To Output Directory" to "Copy Always".
At runtime you will be able to find the file in the current directory in both projects.
Try Server.MapPath
example:
Server.MapPath (#"~\App_Data\menudata.xml")
then you can place your file in any location relative to the root directory of your website/webservice.
I tried the "Copy To Output" with no luck - for some reason my root path was not where the output path was (which i previously thought)... So to abstract away any headaches from other developers setting up this project I did this:
var _assembly = System.Reflection.Assembly.GetExecutingAssembly();
XDocument xdoc = XDocument.Load(new StreamReader(_assembly.GetManifestResourceStream("TheNamespace.Api.TheFile.xml")));
Which of course requires the file to be an embedded resource.