I have several XML files that I wish to read attributes from. My main objective is to apply syntax highlighting to rich text box.
For example in one of my XML docs I have: <Keyword name="using">[..] All the files have the same element: Keyword.
So, how can I get the value for the attribute name and put them in a collection of strings for each XML file.
I am using Visual C# 2008.
The other answers will do the job - but the syntax highlighting thingy and the several xml files you say you have makes me thinks you need something faster, why not use a lean and mean XmlReader?
private string[] getNames(string fileName)
{
XmlReader xmlReader = XmlReader.Create(fileName);
List<string> names = new List<string>();
while (xmlReader.Read())
{
//keep reading until we see your element
if (xmlReader.Name.Equals("Keyword") && (xmlReader.NodeType == XmlNodeType.Element))
{
// get attribute from the Xml element here
string name = xmlReader.GetAttribute("name");
// --> now **add to collection** - or whatever
names.Add(name);
}
}
return names.ToArray();
}
Another good option would be the XPathNavigator class - which is faster than XmlDoc and you can use XPath.
Also I would suggest to go with this approach only IFF after you try with the straightforward options you're not happy with performance.
You could use XPath to get all the elements, then a LINQ query to get the values on all the name atttributes you find:
XDocument doc = yourDocument;
var nodes = from element in doc.XPathSelectElements("//Keyword")
let att = element.Attribute("name")
where att != null
select att.Value;
string[] names = nodes.ToArray();
The //Keyword XPath expression means, "all elements in the document, named "Keyword".
Edit: Just saw that you only want elements named Keyword. Updated the code sample.
Like others, I would suggest using LINQ to XML - but I don't think there's much need to use XPath here. Here's a simple method to return all the keyword names within a file:
static IEnumerable<string> GetKeywordNames(string file)
{
return XDocument.Load(file)
.Descendants("Keyword")
.Attributes("name")
.Select(attr => attr.Value);
}
Nice and declarative :)
Note that if you're going to want to use the result more than once, you should call ToList() or ToArray() on it, otherwise it'll reload the file each time. Of course you could change the method to return List<string> or string[] by -adding the relevant call to the end of the chain of method calls, e.g.
static List<string> GetKeywordNames(string file)
{
return XDocument.Load(file)
.Descendants("Keyword")
.Attributes("name")
.Select(attr => attr.Value)
.ToList();
}
Also note that this just gives you the names - I would have expected you to want the other details of the elements, in which case you'd probably want something slightly different. If it turns out you need more, please let us know.
You could use LINQ to XML.
Example:
var xmlFile = XDocument.Load(someFile);
var query = from item in xmlFile.Descendants("childobject")
where !String.IsNullOrEmpty(item.Attribute("using")
select new
{
AttributeValue = item.Attribute("using").Value
};
You'll likely want to use XPath. //Keyword/#name should get you all of the keyword names.
Here's a good introduction: .Net and XML XPath Queries
**<Countries>
<Country name ="ANDORRA">
<state>Andorra (general)</state>
<state>Andorra</state>
</Country>
<Country name ="United Arab Emirates">
<state>Abu Z¸aby</state>
<state>Umm al Qaywayn</state>
</Country>**
public void datass(string file)
{
string file = HttpContext.Current.Server.MapPath("~/App_Data/CS.xml");
XmlDocument doc = new XmlDocument();
if (System.IO.File.Exists(file))
{
//Load the XML File
doc.Load(file);
}
//Get the root element
XmlElement root = doc.DocumentElement;
XmlNodeList subroot = root.SelectNodes("Country");
for (int i = 0; i < subroot.Count; i++)
{
XmlNode elem = subroot.Item(i);
string attrVal = elem.Attributes["name"].Value;
Response.Write(attrVal);
XmlNodeList sub = elem.SelectNodes("state");
for (int j = 0; j < sub.Count; j++)
{
XmlNode elem1 = sub.Item(j);
Response.Write(elem1.InnerText);
}
}
}
Related
I have this chunk of XML
<EnvelopeStatus>
<CustomFields>
<CustomField>
<Name>Matter ID</Name>
<Show>True</Show>
<Required>True</Required>
<Value>3</Value>
</CustomField>
<CustomField>
<Name>AccountId</Name>
<Show>false</Show>
<Required>false</Required>
<Value>10804813</Value>
<CustomFieldType>Text</CustomFieldType>
</CustomField>
I have this code below:
// TODO find these programmatically rather than a strict path.
var accountId = envelopeStatus.SelectSingleNode("./a:CustomFields", mgr).ChildNodes[1].ChildNodes[3].InnerText;
var matterId = envelopeStatus.SelectSingleNode("./a:CustomFields", mgr).ChildNodes[0].ChildNodes[3].InnerText;
The problem is, sometimes the CustomField with 'Matter ID' might not be there. So I need a way to find the element based on what 'Name is', i.e. a programmatic way of finding it. I can't rely on indexes being accurate.
You can use this code to read innertext from a specific element:
XmlDocument doc = new XmlDocument();
doc.Load("your.xml");
XmlNodeList Nodes= doc.SelectNodes("/EnvelopeStatus/CustomField");
if (((Nodes!= null) && (Nodes.Count > 0)))
{
foreach (XmlNode Level1 in Nodes)
{
if (Level1.ChildNodes[1].Name == "name")
{
string text = Convert.ToInt32(Level1.ChildNodes[1].InnerText.ToString());
}
}
}
You can often find anything in a XML document by utilizing the XPath capabilities that is available directly in the .NET Framework versions.
Maybe create a small XPath parser helper class
public class EnvelopeStatusParser
{
public XmlNodeList GetNodesWithName(XmlDocument doc, string name)
{
return doc.SelectNodes($"//CustomField[Name[text()='{name}']]");
}
}
and then call it like below to get all CustomFields which have a Name that equals what you need to search for
// Creating the XML Document in some form - here reading from file
XmlDocument doc = new XmlDocument();
doc.Load(#"envelopestatus.xml");
var parser = new EnvelopeStatusParser();
var matchingNodes = parser.GetNodesWithName(doc, "Matter ID");
Console.WriteLine(matchingNodes);
matchingNodes = parser.GetNodesWithName(doc, "NotHere");
Console.WriteLine(matchingNodes);
There exist numerous XPath cheat sheets around - like this one from LaCoupa - xpath-cheatsheet which can be quiet helpful to fully utilize XPath on XML structures.
How can I read an XML attribute using C#'s XmlDocument?
I have an XML file which looks somewhat like this:
<?xml version="1.0" encoding="utf-8" ?>
<MyConfiguration xmlns="http://tempuri.org/myOwnSchema.xsd" SuperNumber="1" SuperString="whipcream">
<Other stuff />
</MyConfiguration>
How would I read the XML attributes SuperNumber and SuperString?
Currently I'm using XmlDocument, and I get the values in between using XmlDocument's GetElementsByTagName() and that works really well. I just can't figure out how to get the attributes?
XmlNodeList elemList = doc.GetElementsByTagName(...);
for (int i = 0; i < elemList.Count; i++)
{
string attrVal = elemList[i].Attributes["SuperString"].Value;
}
You should look into XPath. Once you start using it, you'll find its a lot more efficient and easier to code than iterating through lists. It also lets you directly get the things you want.
Then the code would be something similar to
string attrVal = doc.SelectSingleNode("/MyConfiguration/#SuperNumber").Value;
Note that XPath 3.0 became a W3C Recommendation on April 8, 2014.
You can migrate to XDocument instead of XmlDocument and then use Linq if you prefer that syntax. Something like:
var q = (from myConfig in xDoc.Elements("MyConfiguration")
select myConfig.Attribute("SuperString").Value)
.First();
I have an Xml File books.xml
<ParameterDBConfig>
<ID Definition="1" />
</ParameterDBConfig>
Program:
XmlDocument doc = new XmlDocument();
doc.Load("D:/siva/books.xml");
XmlNodeList elemList = doc.GetElementsByTagName("ID");
for (int i = 0; i < elemList.Count; i++)
{
string attrVal = elemList[i].Attributes["Definition"].Value;
}
Now, attrVal has the value of ID.
XmlDocument.Attributes perhaps? (Which has a method GetNamedItem that will presumably do what you want, although I've always just iterated the attribute collection)
Assuming your example document is in the string variable doc
> XDocument.Parse(doc).Root.Attribute("SuperNumber")
1
If your XML contains namespaces, then you can do the following in order to obtain the value of an attribute:
var xmlDoc = new XmlDocument();
// content is your XML as string
xmlDoc.LoadXml(content);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(new NameTable());
// make sure the namespace identifier, URN in this case, matches what you have in your XML
nsmgr.AddNamespace("ns", "urn:oasis:names:tc:SAML:2.0:protocol");
// get the value of Destination attribute from within the Response node with a prefix who's identifier is "urn:oasis:names:tc:SAML:2.0:protocol" using XPath
var str = xmlDoc.SelectSingleNode("/ns:Response/#Destination", nsmgr);
if (str != null)
{
Console.WriteLine(str.Value);
}
More on XML namespaces here and here.
I need to parse the following xml code in c# using system.xml. I need a list of strings containing the content of the tags User.
<Configuration>
....
<DebugUsersMail>
<User>bob#example.com</User>
<User>lenny#example.com</User>
</DebugUsersMail>
...
</Configuration>
If you can use Linq something like this is nice and simple
XDocument xmlDoc = XDocument.Load("C:\\your_xml_file.xml");
List<string> users = xmlDoc.Descendants("User").Select(xElem => (string)xElem).ToList();
You'll need to include a reference to System.Xml.Linq in your using statements to use the XDocument object.
This does however assume that there are no other User elements in the xml file that you don't want included in the list.
If you want to be more specific you could do this
List<string> users = xmlDoc.Descendants("DebugUsersMail")
.Descendants("User").Select(xElem => (string)xElem).ToList();
I found a solution:
List<string> returnList = new List<string>();
XmlNodeList node = xmlDocument.GetElementsByTagName("DebugUsersMail");
XmlNodeList childNodes = node[0].ChildNodes;
for(int i = 0; i < childNodes.Count; i++)
{
returnList.Add(childNodes[i].InnerText);
}
return returnList;
There are tons of ways to do it in C#. You can use:
XmlDocument andthen XPath and XQuery
XDocument and Linq
XmlTextReader/SAX
Regular expressions
Deserialise the XML to objects
The route to take depends a lot of what the rest of XML looks like.
This is not a homework; I need this for my unit tests.
Sample input: <rows><row><a>1234</a><b>Hello</b>...</row><row>...</rows>.
Sample output: <rows><row><a>0.0</a><b>0.0</b>...</row><row>...</rows>.
You may assume that the document starts with <rows> and that parent node has children named <row>. You do not know the name of nodes a, b, etc.
For extra credit: how to make this work with an arbitrary well-formed, "free-form" XML?
I have tried this with a regex :) without luck. I could make it "non-greedy on the right", but not on the left. Thanks for your help.
EDIT: Here is what I tried:
private static string ReplaceValuesWithZeroes(string gridXml)
{
Assert.IsTrue(gridXml.StartsWith("<row>"), "Xml representation must start with '<row>'.");
Assert.IsTrue(gridXml.EndsWith("</row>"), "Xml representation must end with '<row>'.");
gridXml = "<deleteme>" + gridXml.Trim() + "</deleteme>"; // Fake parent.
var xmlDoc = XDocument.Parse(gridXml);
var descendants = xmlDoc.Root.Descendants("row");
int rowCount = descendants.Count();
for (int rowNumber = 0; rowNumber < rowCount; rowNumber++)
{
var row = descendants.ElementAt(0);
Assert.AreEqual<string>(row.Value /* Does not work */, String.Empty, "There should be nothing between <row> and </row>!");
Assert.AreEqual<string>(row.Name.ToString(), "row");
var rowChildren = row.Descendants();
foreach (var child in rowChildren)
{
child.Value = "0.0"; // Does not work.
}
}
// Not the most efficient but still fast enough.
return xmlDoc.ToString().Replace("<deleteme>", String.Empty).Replace("</deleteme>", String.Empty);
}
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach (XmlElement el in doc.SelectNodes("//*[not(*)]"))
el.InnerText = "0.0";
xml = doc.OuterXml;
or to be more selective about non-empty text nodes:
foreach (XmlText el in doc.SelectNodes("//text()[.!='']"))
el.InnerText = "0.0";
XDocument xml = XDocument.Load(myXmlFile);
foreach (var element in xml.Descendants("row").SelectMany(r => r.Elements()))
{
element.Value = "0.0";
}
Note that this general search for "Desscendants('row')" is not very efficient--but it satisfies the 'arbitrary format' requirement.
You should take look at HTML Agility Pack. It allows you to treat html documents as well-formed xml's, therefore you can parse it and change values.
I think you can use Regex.Replace method in C#. I used the below regex to replace all the XML elements values:
[>]+[a-zA-Z0-9]+[<]+
This will basically match text starting with a '>'{some text alphabets or number}'<'.
I was able to use this successfully in Notepad++. You can write a small program as well using this.
I'd like to get all the element name from a xml file, for example the xml file is,
<BookStore>
<BookStoreInfo>
<Address />
<Tel />
<Fax />
<BookStoreInfo>
<Book>
<BookName />
<ISBN />
<PublishDate />
</Book>
<Book>
....
</Book>
</BookStore>
I would like to get the element's name of "BookName". "ISBN" and "PublishDate " and only those names, not include " BookStoreInfo" and its child node's name
I tried several ways, but doesn't work, how can I do it?
Well, with XDocument and LINQ-to-XML:
foreach(var name in doc.Root.DescendantNodes().OfType<XElement>()
.Select(x => x.Name).Distinct())
{
Console.WriteLine(name);
}
There are lots of similar routes, though.
Using XPath
XmlDocument xdoc = new XmlDocument();
xdoc.Load(something);
XmlNodeList list = xdoc.SelectNodes("//BookStore");
gives you a list with all nodes in the document named BookStore
I agree with Adam, the ideal condition is to have a schema that defines the content of xml document. However, sometimes this is not possible. Here is a simple method for iterating all of the nodes of an xml document and using a dictionary to store the unique local names. I like to keep track of the depth of each local name, so I use a list of int to store the depth. Note that the XmlReader is "easy on the memory" since it does not load the entire document as the XmlDocument does. In some instances it makes little difference because the size of the xml data is small. In the following example, an 18.5MB file is read with an XmlReader. Using an XmlDocument to load this data would have been less effecient than using an XmlReader to read and sample its contents.
string documentPath = #"C:\Docs\cim_schema_2.18.1-Final-XMLAll\all_classes.xml";
Dictionary<string, List<int>> nodeTable = new Dictionary<string, List<int>>();
using (XmlReader reader = XmlReader.Create(documentPath))
{
while (!reader.EOF)
{
if (reader.NodeType == XmlNodeType.Element)
{
if (!nodeTable.ContainsKey(reader.LocalName))
{
nodeTable.Add(reader.LocalName, new List<int>(new int[] { reader.Depth }));
}
else if (!nodeTable[reader.LocalName].Contains(reader.Depth))
{
nodeTable[reader.LocalName].Add(reader.Depth);
}
}
reader.Read();
}
}
Console.WriteLine("The node table has {0} items.",nodeTable.Count);
foreach (KeyValuePair<string, List<int>> kv in nodeTable)
{
Console.WriteLine("{0} [{1}]",kv.Key, kv.Value.Count);
for (int i = 0; i < kv.Value.Count; i++)
{
if (i < kv.Value.Count-1)
{
Console.Write("{0}, ", kv.Value[i]);
}
else
{
Console.WriteLine(kv.Value[i]);
}
}
}
The purists way of doing this (and, to be fair, the right way) would be to have a schema contract definition and read it in that way. That being said, you could do something like this...
List<string> nodeNames = new List<string>();
foreach(System.Xml.XmlNode node in doc.SelectNodes("BookStore/Book"))
{
foreach(System.Xml.XmlNode child in node.Children)
{
if(!nodeNames.Contains(child.Name)) nodeNames.Add(child.Name);
}
}
This is, admittedly, a rudimentary method for obtaining the list of distinct node names for the Book node's children, but you didn't specify much else in the way of your environment (if you have 3.5, you could use LINQ to XML to make this a little prettier, for example), but this should get the job done regardless of your environment.
If you're using C# 3.0, you can do the following:
var data = XElement.Load("c:/test.xml"); // change this to reflect location of your xml file
var allElementNames =
(from e in in data.Descendants()
select e.Name).Distinct();
You can try doing it using XPATH.
XmlDocument doc = new XmlDocument();
doc.LoadXml("xml string");
XmlNodeList list = doc.SelectNodes("//BookStore/Book");
If BookStore is ur root element then u can try following code
XmlDocument doc = new XmlDocument();
doc.Load(configPath);
XmlNodeList list = doc.DocumentElement.GetElementsByTagName("Book");
if (list.Count != 0)
{
for (int i = 0; i < list[0].ChildNodes.Count; i++)
{
XmlNode child = list[0].ChildNodes[i];
}
}