I have a string that looks like:
www.blah.com/asdf/asdf/asdfasedf/123
The string may have a slash followed by numbers, like /123 in the above example.
I want to extract the 123 from the string if it is present.
What would my regex be?
Terminate your regular expression with $ to signify the end of the line.
\/\d+$
To actually extract the number, use:
int number;
var match = Regex.Match(inputString,#"\/(\d+)$");
if(match.Success)
number = int.Parse(match.Groups[1].ToString());
You simply match a group of digits (\d+) and require the string to end after that
(\d+)$
This will match a slash followed by numbers at the end of a string and capture the numbers:
\/(\d*)$
Related
My try:
string exp1 = "\\d+G-";
string z = Regex.Match("CN=314G-VK1,OU=Grupper,OU=314,OU=Skole,OU=03Skien,DC=login,DC=sk-asp,DC=no",exp1).Value;
Console.WriteLine(z);
I want to match 314G-VK1 from the string z.
Where,
314 is decimal and it can be any number of digit. say 125632588.
G- is constant.
And VK1 can be character or decimal but length will be only 3, say er5.
How can i meet the requirements?
From my code i only get output 314G-. I tried several ways but that don't help me anymore.
You may use
string exp1 = #"\d+G-\w{3}";
See the regex demo
The \w{3} pattern will match 3 word chars, i.e. mostly letters, digits, underscores. You may precise it if need be, e.g. to only match 3 uppercase ASCII letters or digits, you may use [A-Z0-9]{3}. To also include lowercase letters, add them to the character class, [A-Za-z0-9]{3}.
Regulex regex graph:
.NET regex test results:
C# code demo:
string exp1 = #"\d+G-\w{3}";
string s = "CN=314G-VK1,OU=Grupper,OU=314,OU=Skole,OU=03Skien,DC=login,DC=sk-asp,DC=no";
string z = Regex.Match(s, exp1)?.Value;
Console.WriteLine(z); // => 314G-VK1
You are almost correct but, you just need to add [0-9a-zA-Z]{3} after G-.
string exp1 = "\\d+G-[0-9a-zA-Z]{3}";
string z = Regex.Match("CN=314G-VK1,OU=Grupper,OU=314,OU=Skole,OU=03Skien,DC=login,DC=sk-asp,DC=no", exp1).Value;
Console.WriteLine(z);
Check demo here
Try this:
string exp1 = #"\d+G-[a-zA-Z0-9]{3}"
[a-zA-Z0-9]{3} will match with 3-char alphanumeric string.
I'm trying to come up with a regular expression matches the text in bold in all the examples.
Between the string "JZ" and any character before "-"
JZ123456789-301A
JZ134255872-22013
Between the string "JZ" and the last character
JZ123456789D
I have tried the following but it only works for the first example
(?<=JZ).*(?=-)
You can use (?<=JZ)[0-9]+, presuming the desired text will always be numeric.
Try it out here
You may use
JZ([^-]*)(?:-|.$)
and grab Group 1 value. See the regex demo.
Details
JZ - a literal substring
([^-]*) - Capturing group 1: zero or more chars other than -
(?:-|.$) - a non-capturing group matching either - or any char at the end of the string
C# code:
var m = Regex.Match(s, #"JZ([^-]*)(?:-|.$)");
if (m.Success)
{
Console.WriteLine(m.Groups[1].Value);
}
If, for some reason, you need to obtain the required value as a whole match, use lookarounds:
(?<=JZ)[^-]*(?=-|.$)
See this regex variation demo. Use m.Value in the code above to grab the value.
A one-line answer without regex:
string s,r;
// if your string always starts with JZ
s = "JZ123456789-301A";
r = string.Concat(s.Substring(2).TakeWhile(char.IsDigit));
Console.WriteLine(r); // output : 123456789
// if your string starts with anything
s = "A12JZ123456789-301A";
r = string.Concat(s.Substring(s.IndexOf("JZ")).TakeWhile(char.IsDigit));
Console.WriteLine(r); // output : 123456789
Basically, we remove everything before and including the delimiter "JZ", then we take each char while they are digit. The Concat is use to transform the IEnumerable<char> to a string. I think it is easier to read.
Try it online
I'm looking for a way to search a string for everything before a set of characters in C#. For Example, if this is my string value:
This is is a test.... 12345
I want build a new string with all of the characters before "12345".
So my new string would equal "This is is a test.... "
Is there a way to do this?
I've found Regex examples where you can focus on one character but not a sequence of characters.
You don't need to use a Regex:
public string GetBitBefore(string text, string end)
{
var index = text.IndexOf(end);
if (index == -1) return text;
return text.Substring(0, index);
}
You can use a lazy quantifier to match anything, followed by a lookahead:
var match = Regex.Match("This is is a test.... 12345", #".*?(?=\d{5})");
where:
.*? lazily matches everything (up to the lookahead)
(?=…) is a positive lookahead: the pattern must be matched, but is not included in the result
\d{5} matches exactly five digits. I'm assuming this is your lookahead; you can replace it
You can do so with help of regex lookahead.
.*(?=12345)
Example:
var data = "This is is a test.... 12345";
var rxStr = ".*(?=12345)";
var rx = new System.Text.RegularExpressions.Regex (rxStr,
System.Text.RegularExpressions.RegexOptions.IgnoreCase);
var match = rx.Match(data);
if (match.Success) {
Console.WriteLine (match.Value);
}
Above code snippet will print every thing upto 12345:
This is is a test....
For more detail about see regex positive lookahead
This should get you started:
var reg = new Regex("^(.+)12345$");
var match = reg.Match("This is is a test.... 12345");
var group = match.Groups[1]; // This is is a test....
Of course you'd want to do some additional validation, but this is the basic idea.
^ means start of string
$ means end of string
The asterisk tells the engine to attempt to match the preceding token zero or more times. The plus tells the engine to attempt to match the preceding token once or more
{min,max} indicate the minimum/maximum number of matches.
\d matches a single character that is a digit, \w matches a "word character" (alphanumeric characters plus underscore), and \s matches a whitespace character (includes tabs and line breaks).
[^a] means not so exclude a
The dot matches a single character, except line break characters
In your case there many way to accomplish the task.
Eg excluding digit: ^[^\d]*
If you know the set of characters and they are not only digit, don't use regex but IndexOf(). If you know the separator between first and second part as "..." you can use Split()
Take a look at this snippet:
class Program
{
static void Main(string[] args)
{
string input = "This is is a test.... 12345";
// Here we call Regex.Match.
MatchCollection matches = Regex.Matches(input, #"(?<MySentence>(\w+\s*)*)(?<MyNumberPart>\d*)");
foreach (Match item in matches)
{
Console.WriteLine(item.Groups["MySentence"]);
Console.WriteLine("******");
Console.WriteLine(item.Groups["MyNumberPart"]);
}
Console.ReadKey();
}
}
You could just split, not as optimal as the indexOf solution
string value = "oiasjdoiasj12345";
string end = "12345";
string result = value.Split(new string[] { end }, StringSplitOptions.None)[0] //Take first part of the result, not the quickest but fairly simple
I need to extract a substring from an existing string. This String starts with uninteresting characters (include "," "space" and numbers) and ends with ", 123," or ", 57," or something like this where the numbers can change. I only need the Numbers.
Thanks
public static void Main(string[] args)
{
string input = "This is 2 much junk, 123,";
var match = Regex.Match(input, #"(\d*),$"); // Ends with at least one digit
// followed by comma,
// grab the digits.
if(match.Success)
Console.WriteLine(match.Groups[1]); // Prints '123'
}
Regex to match numbers: Regex regex = new Regex(#"\d+");
Source (slightly modified): Regex for numbers only
I think this is what you're looking for:
Remove all non numeric characters from a string using Regex
using System.Text.RegularExpressions;
...
string newString = Regex.Replace(oldString, "[^.0-9]", "");
(If you don't want to allow the decimal delimiter in the final result, remove the . from the regular expression above).
Try something like this :
String numbers = new String(yourString.TakeWhile(x => char.IsNumber(x)).ToArray());
You can use \d+ to match all digits within a given string
So your code would be
var lst=Regex.Matches(inp,reg)
.Cast<Match>()
.Select(x=x.Value);
lst now contain all the numbers
But if your input would be same as provided in your question you don't need regex
input.Substring(input.LastIndexOf(", "),input.LastIndexOf(","));
I have a text file for processing, which has some numbers. I want JUST text in it, and nothing else. I managed to remove the punctuation marks, but how do I remove the numbers? I want this using C# code.
Also, I want to remove words with length greater than 10. How do I do that using Reg Expressions?
You can do this with a regex:
string withNumbers = // string with numbers
string withoutNumbers = Regex.Replace(withNumbers, "[0-9]", "");
Use this regex to remove words with more than 10 characters:
[\w]{10, 100}
100 defines the max length to match. I don't know if there is a quantifier for min length...
Only letters and nothing else (because I see you also want to remove the punctuation marks)
Regex.IsMatch(input, #"^[a-zA-Z]+$");
You can also use string.Join:
string s = "asdasdad34534t3sdf43534";
s = string.Join(null, System.Text.RegularExpressions.Regex.Split(s, "[\\d]"));
The Regex.Replace method should do the trick.
// regex to match any digit
var regex = new Regex("\d");
// replace all matches in input with empty string
var output = regex.Replace(input, String.Empty);