XmlSerializer List Item Element Name - c#

I have a class PersonList
[XmlRoot("Persons")]
PersonList : List<Human>
when I serialize this to XML, by default it will produce something like this:
<Persons>
<Human>...</Human>
<Human>...</Human>
</Persons>
My question is what needs to be done in order to change element Human to Person in the output? so the output would be :
<Persons>
<Person>...</Person>
<Person>...</Person>
</Persons>
and, how to deserialize the above XML to the PersonList class object?
Per Nick's advice, Here is my testing code:
[XmlRoot("Persons")]
public class Persons : List<Human>
{
}
[XmlRoot("Person")]
public class Human
{
public Human()
{
}
public Human(string name)
{
Name = name;
}
[XmlElement("Name")]
public string Name { get; set; }
}
void TestXmlSerialize()
{
Persons personList = new Persons();
personList.Add(new Human("John"));
personList.Add(new Human("Peter"));
try
{
using (StringWriter writer = new StringWriter())
{
XmlSerializer serializer = new XmlSerializer(typeof(Persons));
XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
XmlWriter xmlWriter = XmlWriter.Create(writer, settings);
serializer.Serialize(xmlWriter, personList, namespaces);
Console.Out.WriteLine(writer.ToString());
}
}
catch (Exception e)
{
Console.Out.WriteLine( e.ToString());
}
}
The output of the testing code is:
<Persons>
<Human>
<Name>John</Name>
</Human>
<Human>
<Name>Peter</Name>
</Human>
</Persons>
As the output shows, the [XmlRoot("Person")] on Human does not change the tag to Person from Human.

Mark your class with the following attributes:
[XmlType("Account")]
[XmlRoot("Account")]
The XmlType attribute will result in the output requested in the OP. Per the documentation:
Controls the XML schema that is generated when the attribute target is serialized by the XmlSerializer

I don't think there is a way for you to control the name of the generated array elements.
If you can however wrap the Persons collection inside another class you will then have complete control over the generated output using XmlArrayAttribute and XmlArrayItemAttribute.
If you cannot create this new class you can resort to implementing IXmlSerializable, but this is much more complex.
An example for the first alternative follows:
[XmlRoot("Context")]
public class Context
{
public Context() { this.Persons = new Persons(); }
[XmlArray("Persons")]
[XmlArrayItem("Person")]
public Persons Persons { get; set; }
}
public class Persons : List<Human> { }
public class Human
{
public Human() { }
public Human(string name) { Name = name; }
public string Name { get; set; }
}
class Program
{
public static void Main(string[] args)
{
Context ctx = new Context();
ctx.Persons.Add(new Human("john"));
ctx.Persons.Add(new Human("jane"));
var writer = new StringWriter();
new XmlSerializer(typeof(Context)).Serialize(writer, ctx);
Console.WriteLine(writer.ToString());
}
}

I had the identical problem with my serializer. None of the answers above worked exactly. I found that the XmlRoot attribute on the Human class is plainly ignored because it isn't the root element of the document. Wrapping the list in a context object wasn't an option for me because I can't change the XML schema. The solution is to change up the Persons class. Instead of subclassing a generic list, you wrap it in an object and change how it is serialized. See the sample code below:
[XmlRoot("Persons")]
public class Persons
{
public Persons ()
{
People = new List<Human>();
}
[XmlElement("Person")]
public List<Human> People
{ get; set; }
}
public class Human
{
public Human()
{
}
public Human(string name)
{
Name = name;
}
[XmlElement("Name")]
public string Name { get; set; }
}
Serializing your generic list using XmlElement means that it won't put the wrapper element around your list like XmlArray does or like the subclassing does. It also gives you the bonus option of adding attributes to the Persons class, which is where I got the idea from:
How do I add a attribute to a XmlArray element (XML Serialization)?

This is mine test code
using System.Collections.Generic;
using System.Xml.Serialization;
namespace TestLoadingMultiXml
{
[XmlRoot(ElementName=#"main")]
public class XmlMain
{
private XmlDataTest data;
[XmlElement(ElementName=#"datalist")]
public XmlDataTest Data
{
get { return data; }
set { data = value; }
} // public XmlDataTest Data
public XmlMain()
{
data = new XmlDataTest();
}
}
[XmlRoot(ElementName=#"xmldata")]
public class XmlDataTest
{
private List<DataDetails> listData;
[XmlElement(ElementName=#"listdata")]
public List<DataDetails> Data
{
get { return listData; }
set { listData = value; }
}
public XmlDataTest()
{
listData = new List<DataDetails>();
for (int i = 0; i < 10; i++)
{
DataDetails d = new DataDetails(string.Format("{0}", i));
listData.Add(d);
} // for (int i=0; i < 10; i++)
} // public XmlDataTest()
} // class XmlDataTest
[XmlRoot(ElementName=#"datadetail")]
public class DataDetails
{
private string name;
[XmlAttribute(AttributeName=#"name")]
public string Name
{
get
{
return name;
}
set { name = value; }
}
public DataDetails(string _value)
{
this.name = _value;
} // public DataDetails(string _value)
public DataDetails()
{
this.name = "";
} // public DataDetails()
} // public class DataDetails
}
and running program
using System;
using System.IO;
using System.Windows.Forms;
using System.Xml.Serialization;
namespace TestLoadingMultiXml
{
public partial class Form1 : Form
{
private XmlMain xt;
private string xname = #"x.xml";
public Form1()
{
InitializeComponent();
this.FormClosing += new FormClosingEventHandler(Form1_FormClosing);
}
void Form1_FormClosing(object sender, FormClosingEventArgs e)
{
XmlSerializer x = new XmlSerializer(typeof(XmlMain));
FileStream fs = new FileStream(xname, FileMode.Create);
x.Serialize(fs, xt);
fs.Close();
}
private void Form1_Load(object sender, EventArgs e)
{
xt = new XmlMain();
xname = Directory.GetCurrentDirectory() + #"\" + xname;
if (File.Exists(xname))
{
XmlSerializer x = new XmlSerializer(typeof(XmlMain));
FileStream fs = new FileStream(xname, FileMode.Open);
xt = (XmlMain)x.Deserialize(fs);
fs.Close();
} // if (File.Exists(xname))
}
}
}
Also this is the result
<?xml version="1.0"?>
<main xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<datalist>
<listdata name="0" />
<listdata name="1" />
<listdata name="2" />
<listdata name="3" />
<listdata name="4" />
<listdata name="5" />
<listdata name="6" />
<listdata name="7" />
<listdata name="8" />
<listdata name="9" />
</datalist>
</main>

Set the XmlRoot on Human to:
[XmlRoot("Person")]
Sidebar:
Persons should probably be People

There is another alternative. You can always implement IXmlSerializable in collections (and any other class or struct) to fully control how items are written or read. Many of you will know that already, it's not generally preferred of course as you may end-up writing out "boiler-plate" code by hand which should really be automatic logic specified with attributes.
For collections which must match a sensible schema it's justifiable. Because the framework has a hard limitation here and the existing item type's serialization code does not have to be duplicated when done properly; i.e. Do not re-write the item serialization in the collection code, just create/call a child XmlSerializer inside your ReadXml/WriteXml implementation.
Once consequence of using IXmlSerializable is it does not allow you to apply the XmlTypeAttribute (throws a runtime error telling you only XmlRootAttribute may be used). So instead apply the XmlSchemaProviderAttribute and return the same qualified name you would have put in the XmlTypeAttribute. The old GetSchema method should return null anyway as it was only a reserved method (according to MSDN), probably because they forgot to include the ability to specify a different namespace. Personally I use the same "GetSchema" method name in my XmlSchemaProviderAttribute so it appears as a complete override next to the legacy placeholder GetSchema method.
Of course, the best solution would be if Microsoft would allow us to apply the XmlArrayItemAttribute to collection/list classes and use that in the XmlSerializer. By default it uses the XML type element name in collections, which I feel is a bug because it should be the XML root name when specified or class name when not.
When I get time I'll come back and add an example. For now take a look at the MSDN documentation examples of IXmlSerializable and XmlSchemaProviderAttribute.
http://msdn.microsoft.com/en-us/library/system.xml.serialization.ixmlserializable(v=vs.110).aspx
http://msdn.microsoft.com/en-us/library/system.xml.serialization.xmlschemaproviderattribute(v=vs.110).aspx

If you don't have access to the source for the Human class (in which case, setting XmlRoot is not possible), you can create an XmlElementAttribute, then add it to an XmlAttributeOverride and use that when creating an instance of your XmlSerializer. See this MSDN article for more details.

I know it's an old question but I ran into the same problem and none of the solutions seems to adresse the OP's question. So here is my solution (comments are in french if you wonder) :
#region Références
using System.Collections.Generic;
using System.Linq;
using System.Xml;
using System.Xml.Schema;
using System.Xml.Serialization;
#endregion
namespace XmlSerializationTests
{
/// <summary>
/// Représente une liste qui peut être sérialisée en XML en tant que noeud racine.
/// </summary>
/// <typeparam name="T">Type des éléments de la liste.</typeparam>
public class XmlSerializableList<T>
: List<T>, IXmlSerializable
{
#region Variables
private static readonly XmlSerializer _ItemSerializer = new XmlSerializer(typeof(T));
private static readonly string _ItemName;
private string _RootName;
#endregion
#region Méthodes
/// <summary>
/// Initialisation statique
/// </summary>
static XmlSerializableList()
{
_ItemName = (typeof(T).GetCustomAttributes(typeof(XmlRootAttribute), true).FirstOrDefault() as XmlRootAttribute)?.ElementName ?? typeof(T).Name;
}
/// <summary>
/// Obtient le nom racine.
/// </summary>
protected virtual string RootName
{
get
{
if (string.IsNullOrWhiteSpace(_RootName)) _RootName = (GetType().GetCustomAttributes(typeof(XmlRootAttribute), true).FirstOrDefault() as XmlRootAttribute)?.ElementName ?? GetType().Name;
return _RootName;
}
}
/// <summary>
/// Obtient le nom des éléments.
/// </summary>
protected virtual string ItemName
{
get { return _ItemName; }
}
/// <summary>
/// Cette méthode est réservée et ne doit pas être utilisée.Lorsque vous implémentez l'interface IXmlSerializable, vous devez retourner la valeur null (Nothing dans Visual Basic) à partir cette méthode et, si la spécification d'un schéma personnalisé est requise, appliquez à la place <see cref="T:System.Xml.Serialization.XmlSchemaProviderAttribute"/> à la classe.
/// </summary>
/// <returns> <see cref="T:System.Xml.Schema.XmlSchema"/> qui décrit la représentation XML de l'objet qui est généré par la méthode <see cref="M:System.Xml.Serialization.IXmlSerializable.WriteXml(System.Xml.XmlWriter)"/> et utilisé par la méthode <see cref="M:System.Xml.Serialization.IXmlSerializable.ReadXml(System.Xml.XmlReader)"/>.</returns>
public XmlSchema GetSchema()
{
return null;
}
/// <summary>
/// Génère un objet à partir de sa représentation XML.
/// </summary>
/// <param name="reader"><see cref="T:System.Xml.XmlReader"/> source à partir de laquelle l'objet est désérialisé.</param>
public void ReadXml(XmlReader reader)
{
if (!reader.IsEmptyElement)
{
reader.ReadStartElement();
while (reader.NodeType != XmlNodeType.EndElement)
{
T item = (T) _ItemSerializer.Deserialize(reader);
Add(item);
}
reader.ReadEndElement();
}
else reader.ReadStartElement();
}
/// <summary>
/// Convertit un objet en sa représentation XML.
/// </summary>
/// <param name="writer"><see cref="T:System.Xml.XmlWriter"/> flux dans lequel l'objet est sérialisé.</param>
public void WriteXml(XmlWriter writer)
{
foreach (var i in this)
{
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("", "");
_ItemSerializer.Serialize(writer, i, ns);
}
}
#endregion
}
}
And here a unit test class to demonstrate use and results :
#region Références
using System.IO;
using System.Text;
using System.Xml.Serialization;
using Microsoft.VisualStudio.TestTools.UnitTesting;
#endregion
namespace XmlSerializationTests
{
[TestClass]
public class XmlSerializableListTests
{
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
public int Birth { get; set; }
}
[XmlRoot("color")]
public class ColorDefinition
{
[XmlElement("name")] public string Name { get; set; }
[XmlElement("r")] public int Red { get; set; }
[XmlElement("g")] public int Green { get; set; }
[XmlElement("b")] public int Blue { get; set; }
}
public class Persons : XmlSerializableList<Person>
{
}
[XmlRoot("colors")]
public class ColorList : XmlSerializableList<ColorDefinition>
{
}
private T ReadXml<T>(string text) where T : class
{
XmlSerializer serializer = new XmlSerializer(typeof (T));
using (StringReader sr = new StringReader(text))
{
return serializer.Deserialize(sr) as T;
}
}
private string WriteXml<T>(T data) where T : class
{
XmlSerializer serializer = new XmlSerializer(typeof(T));
StringBuilder sb = new StringBuilder();
using (StringWriter sw = new StringWriter(sb))
{
serializer.Serialize(sw, data);
return sb.ToString();
}
}
[TestMethod]
public void ReadEmpty()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfInt32>
</XmlSerializableListOfInt32>";
XmlSerializableList<int> lst = ReadXml<XmlSerializableList<int>>(xml);
Assert.AreEqual(0, lst.Count);
}
[TestMethod]
public void ReadEmpty2()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfInt32 />";
XmlSerializableList<int> lst = ReadXml<XmlSerializableList<int>>(xml);
Assert.AreEqual(0, lst.Count);
}
[TestMethod]
public void ReadSimpleItems()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfInt32>
<int>0</int>
<int>52</int>
<int>79</int>
</XmlSerializableListOfInt32>";
XmlSerializableList<int> lst = ReadXml<XmlSerializableList<int>>(xml);
Assert.AreEqual(3, lst.Count);
Assert.AreEqual(0, lst[0]);
Assert.AreEqual(52, lst[1]);
Assert.AreEqual(79, lst[2]);
}
[TestMethod]
public void ReadComplexItems()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfPerson>
<Person>
<FirstName>Linus</FirstName>
<LastName>Torvalds</LastName>
<Birth>1969</Birth>
</Person>
<Person>
<FirstName>Bill</FirstName>
<LastName>Gates</LastName>
<Birth>1955</Birth>
</Person>
<Person>
<FirstName>Steve</FirstName>
<LastName>Jobs</LastName>
<Birth>1955</Birth>
</Person>
</XmlSerializableListOfPerson>";
XmlSerializableList<Person> lst = ReadXml<XmlSerializableList<Person>>(xml);
Assert.AreEqual(3, lst.Count);
Assert.AreEqual("Linus", lst[0].FirstName);
Assert.AreEqual("Torvalds", lst[0].LastName);
Assert.AreEqual(1969, lst[0].Birth);
Assert.AreEqual("Bill", lst[1].FirstName);
Assert.AreEqual("Gates", lst[1].LastName);
Assert.AreEqual(1955, lst[1].Birth);
Assert.AreEqual("Steve", lst[2].FirstName);
Assert.AreEqual("Jobs", lst[2].LastName);
Assert.AreEqual(1955, lst[2].Birth);
}
[TestMethod]
public void ReadInheritedPersons()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<Persons>
<Person>
<FirstName>Linus</FirstName>
<LastName>Torvalds</LastName>
<Birth>1969</Birth>
</Person>
<Person>
<FirstName>Bill</FirstName>
<LastName>Gates</LastName>
<Birth>1955</Birth>
</Person>
<Person>
<FirstName>Steve</FirstName>
<LastName>Jobs</LastName>
<Birth>1955</Birth>
</Person>
</Persons>";
Persons lst = ReadXml<Persons>(xml);
Assert.AreEqual(3, lst.Count);
Assert.AreEqual("Linus", lst[0].FirstName);
Assert.AreEqual("Torvalds", lst[0].LastName);
Assert.AreEqual(1969, lst[0].Birth);
Assert.AreEqual("Bill", lst[1].FirstName);
Assert.AreEqual("Gates", lst[1].LastName);
Assert.AreEqual(1955, lst[1].Birth);
Assert.AreEqual("Steve", lst[2].FirstName);
Assert.AreEqual("Jobs", lst[2].LastName);
Assert.AreEqual(1955, lst[2].Birth);
}
[TestMethod]
public void ReadInheritedColors()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<colors>
<color>
<name>red</name>
<r>255</r>
<g>0</g>
<b>0</b>
</color>
<color>
<name>green</name>
<r>0</r>
<g>255</g>
<b>0</b>
</color>
<color>
<name>yellow</name>
<r>255</r>
<g>255</g>
<b>0</b>
</color>
</colors>";
ColorList lst = ReadXml<ColorList>(xml);
Assert.AreEqual(3, lst.Count);
Assert.AreEqual("red", lst[0].Name);
Assert.AreEqual(255, lst[0].Red);
Assert.AreEqual(0, lst[0].Green);
Assert.AreEqual(0, lst[0].Blue);
Assert.AreEqual("green", lst[1].Name);
Assert.AreEqual(0, lst[1].Red);
Assert.AreEqual(255, lst[1].Green);
Assert.AreEqual(0, lst[1].Blue);
Assert.AreEqual("yellow", lst[2].Name);
Assert.AreEqual(255, lst[2].Red);
Assert.AreEqual(255, lst[2].Green);
Assert.AreEqual(0, lst[2].Blue);
}
[TestMethod]
public void WriteEmpty()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfInt32 />";
XmlSerializableList<int> lst = new XmlSerializableList<int>();
string result = WriteXml(lst);
Assert.AreEqual(xml, result);
}
[TestMethod]
public void WriteSimpleItems()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfInt32>
<int>0</int>
<int>52</int>
<int>79</int>
</XmlSerializableListOfInt32>";
XmlSerializableList<int> lst = new XmlSerializableList<int>() {0, 52, 79};
string result = WriteXml(lst);
Assert.AreEqual(xml, result);
}
[TestMethod]
public void WriteComplexItems()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<XmlSerializableListOfPerson>
<Person>
<FirstName>Linus</FirstName>
<LastName>Torvalds</LastName>
<Birth>1969</Birth>
</Person>
<Person>
<FirstName>Bill</FirstName>
<LastName>Gates</LastName>
<Birth>1955</Birth>
</Person>
<Person>
<FirstName>Steve</FirstName>
<LastName>Jobs</LastName>
<Birth>1955</Birth>
</Person>
</XmlSerializableListOfPerson>";
XmlSerializableList<Person> persons = new XmlSerializableList<Person>
{
new Person {FirstName = "Linus", LastName = "Torvalds", Birth = 1969},
new Person {FirstName = "Bill", LastName = "Gates", Birth = 1955},
new Person {FirstName = "Steve", LastName = "Jobs", Birth = 1955}
};
string result = WriteXml(persons);
Assert.AreEqual(xml, result);
}
[TestMethod]
public void WriteInheritedPersons()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<Persons>
<Person>
<FirstName>Linus</FirstName>
<LastName>Torvalds</LastName>
<Birth>1969</Birth>
</Person>
<Person>
<FirstName>Bill</FirstName>
<LastName>Gates</LastName>
<Birth>1955</Birth>
</Person>
<Person>
<FirstName>Steve</FirstName>
<LastName>Jobs</LastName>
<Birth>1955</Birth>
</Person>
</Persons>";
Persons lst = new Persons
{
new Person {FirstName = "Linus", LastName = "Torvalds", Birth = 1969},
new Person {FirstName = "Bill", LastName = "Gates", Birth = 1955},
new Person {FirstName = "Steve", LastName = "Jobs", Birth = 1955}
};
string result = WriteXml(lst);
Assert.AreEqual(xml, result);
}
[TestMethod]
public void WriteInheritedColors()
{
string xml = #"<?xml version=""1.0"" encoding=""utf-16""?>
<colors>
<color>
<name>red</name>
<r>255</r>
<g>0</g>
<b>0</b>
</color>
<color>
<name>green</name>
<r>0</r>
<g>255</g>
<b>0</b>
</color>
<color>
<name>yellow</name>
<r>255</r>
<g>255</g>
<b>0</b>
</color>
</colors>";
ColorList lst = new ColorList
{
new ColorDefinition { Name = "red", Red = 255, Green = 0, Blue = 0 },
new ColorDefinition { Name = "green", Red = 0, Green = 255, Blue = 0 },
new ColorDefinition { Name = "yellow", Red = 255, Green = 255, Blue = 0 }
};
string result = WriteXml(lst);
Assert.AreEqual(xml, result);
}
}
}

I know it's old but for others that will come -
Before class Human, add [XmlType("Person")] instead of [XmlRoot("Person")]

Related

How to change a value inside XML file using c# Visual Studio

I am trying to change values inside XML file. This is my XML "person.xml" file:
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<Table>
<Person>
<Number>1</Number>
<Name>Mariano</Name>
<Last Name>Italiano</Last Name>
<Age>36</Age>
</Person>
<Person>
<Number>2</Number>
<Name>John</Name>
<Last Name>Smith</Last Name>
<Age>32</Age>
</Person>
<Person>
<Number>3</Number>
<Name>Bob</Name>
<Last Name>Leckie</Last Name>
<Age>50</Age>
</Person>
<Person>
<Number>4</Number>
<Name>Patrick</Name>
<Last Name>Collins</Last Name>
<Age>63</Age>
</Person>
</Table>
And i want my program to do some things:
Find a name written in textBox2->Text. Then if the name exists i want to change it to name written in textBox3->Text.
Remove (if found) whole Person if CheckBoxDelete is set to true
I know how to create such a XML file (found an example somewhere) but i can't find a solution how to find and remove if neccessary.
I am using Visual Studio 2015 if it matters.
Thank You.
You can use XDocument to replace the value and delete the person according to the Name.
Code:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
public string filename = "D:\\test.xml";
private void BtnRePlace_Click(object sender, EventArgs e)
{
XDocument doc = XDocument.Load(filename);
doc.Descendants("Person").Descendants("Name").Where(i => i.Value == txtReplaceFirstName.Text).FirstOrDefault().SetValue(txtReplaceLastName.Text);
doc.Save(filename);
}
private void btndelete_Click(object sender, EventArgs e)
{
XDocument doc = XDocument.Load(filename);
doc.Descendants("Person").Where(i => i.Element("Name").Value == txtReplaceFirstName.Text&& i.Element("LastName").Value == txtReplaceLastName.Text).FirstOrDefault().Remove();
doc.Save(filename);
}
}
Besides, your xml file have an error, the Last Name should be LastName without space.
You could map (i.e. deserialize) the data to POCO objects, manipulate the data and serialize again. Might be a bit overkill though. As others stated, using XDocument might be good enough.
Here is a minimal example:
public class Person
{
[XmlElement]
public int Number { get; set; }
[XmlElement]
public string Name { get; set; }
[XmlElement]
public string LastName { get; set; }
[XmlElement]
public int Age { get; set; }
public override string ToString() => $"{Name} {LastName} is {Age}";
}
[XmlRoot("Table")]
public class RootObject
{
[XmlElement("Person")]
public List<Person> Persons;
}
class Program
{
static void Main(string[] args)
{
var xmlSer = new XmlSerializer(typeof(RootObject));
using var fs = new FileStream("input.xml", FileMode.Open);
var doc = (RootObject)xmlSer.Deserialize(fs);
foreach (var p in doc.Persons)
{
System.Console.WriteLine(p);
}
// do whatever with the RootObject instance
}
}
XML is the object, so consider re-using existing objects before creating more POCOs.
Here's code that shows how to find, delete, and update elements in XML. Take some time to learn XPath, it's very powerful, flexible, and available across nearly every platform.
using System;
using System.Threading.Tasks;
using System.Xml;
namespace testconsole
{
class Program
{
public static string strFileName = "c:\\temp\\test.xml";
static void Main(string[] args) {
XmlDocument xml = new XmlDocument();
xml.Load(strFileName);
string strMatchName = "Mariano";
string strXPath = "/Table/Person[Name='" + strMatchName + "']";
XmlElement ndPerson = (XmlElement)xml.SelectSingleNode(strXPath);
if (ndPerson != null) {
// Delete if the person is found
ndPerson.ParentNode.RemoveChild(ndPerson);
}
string strNewName = "Bob";
strXPath = "/Table/Person/Name[.='" + strNewName + "']";
XmlElement ndName = (XmlElement)xml.SelectSingleNode(strXPath);
if (ndName != null) {
ndName.InnerText = "Robert"; // new name
}
xml.Save(strFileName);
}
}
}

Map XML tags with dot(.) to C# object

I have XML file which have some tags with dot(.), now i am using "StringWriter"
to Map XML data with C#, but i am not able to handle XML tags which have dot(.) in tag name like:- "Customer.Name", how can i map this with C# class.
I had give XmlElement with my class model, but still i am not getting values map with my class.
Can any one give me suggestion.
[XmlElement(ElementName = "PARENTNAME")]
public string PARENTNAME { get; set; } //This is perfect mapped
[XmlElement(ElementName = "DISPLAYCONTACT.CONTACTNAME")]
public string DISPLAYCONTACTCONTACTNAME { get; set; } // This is not mapped
[XmlElement(ElementName = "DISPLAYCONTACT.COMPANYNAME")]
public string DISPLAYCONTACTCOMPANYNAME { get; set; }
Convert XML to C#
XmlDocument doc = new XmlDocument();
doc.LoadXml(custome‌​rString);
StringWriter sw = new StringWriter();
XmlTextWriter xw = new XmlTextWriter(sw);
doc.WriteTo(xw);
String XmlString = sw.ToString();
string xmlToJson = JsonConvert.SerializeXmlNode(doc);
var deserialized = JsonConvert.SerializeXmlNode(doc);
var custome‌​r = new CusGetResIn();
custome‌​r= JsonConvert.DeserializeObject<CusGetResIn>(deserialized);
Also Tried:-
XmlSerializer serializer = new XmlSerializer(typeof(CusGetResIn));
MemoryStream memStream = new MemoryStream(Encoding.UTF8.GetBytes(XmlString));
CusGetResIn resultingMessage = (CusGetResIn)serializer.Deserialize(memStream);
XML:-
<?xml version="1.0" encoding="UTF-8"?>
<response>
<control>
<status>success</status>
<senderid>Intacct_ISB</senderid>
<controlid>17/12/2018</controlid>
<uniqueid>false</uniqueid>
<dtdversion>3.0</dtdversion>
</control>
<operation>
<authentication>
<status>success</status>
<userid>vinit1</userid>
<companyid>FASTMORE-trial</companyid>
<locationid></locationid>
<sessiontimestamp>2018-12-19T00:41:15-08:00</sessiontimestamp>
</authentication>
<result>
<status>success</status>
<function>readByQuery</function>
<controlid>testFunctionId</controlid>
<data listtype="customer" count="31" totalcount="31" numremaining="0" resultId="">
<customer>
<RECORDNO>5</RECORDNO>
<CUSTOMERID>CUST-00101</CUSTOMERID>
<NAME>Sun Microsystems - EBC</NAME>
<ENTITY>CCUST-00101</ENTITY>
<PARENTKEY></PARENTKEY>
<PARENTID></PARENTID>
<PARENTNAME></PARENTNAME>
<DISPLAYCONTACT.CONTACTNAME>Sun Microsystems - EBC(CCUST-00101)</DISPLAYCONTACT.CONTACTNAME>
<DISPLAYCONTACT.COMPANYNAME>Sun Microsystems - EBC</DISPLAYCONTACT.COMPANYNAME>
<DISPLAYCONTACT.PREFIX></DISPLAYCONTACT.PREFIX>
<DISPLAYCONTACT.FIRSTNAME></DISPLAYCONTACT.FIRSTNAME>
<DISPLAYCONTACT.LASTNAME></DISPLAYCONTACT.LASTNAME>
<DISPLAYCONTACT.INITIAL></DISPLAYCONTACT.INITIAL>
<DISPLAYCONTACT.PRINTAS>Sun Microsystems - Executive Briefing Center</DISPLAYCONTACT.PRINTAS>
<DISPLAYCONTACT.TAXABLE>true</DISPLAYCONTACT.TAXABLE>
<DISPLAYCONTACT.TAXGROUP></DISPLAYCONTACT.TAXGROUP>
<DISPLAYCONTACT.PHONE1></DISPLAYCONTACT.PHONE1>
<DISPLAYCONTACT.PHONE2></DISPLAYCONTACT.PHONE2>
<DISPLAYCONTACT.CELLPHONE></DISPLAYCONTACT.CELLPHONE>
<DISPLAYCONTACT.PAGER></DISPLAYCONTACT.PAGER>
<DISPLAYCONTACT.FAX></DISPLAYCONTACT.FAX>
<DISPLAYCONTACT.EMAIL1>sevans#intacct.com</DISPLAYCONTACT.EMAIL1>
<DISPLAYCONTACT.EMAIL2></DISPLAYCONTACT.EMAIL2>
<DISPLAYCONTACT.URL1></DISPLAYCONTACT.URL1>
<DISPLAYCONTACT.URL2></DISPLAYCONTACT.URL2>
<DISPLAYCONTACT.VISIBLE>true</DISPLAYCONTACT.VISIBLE>
<DISPLAYCONTACT.MAILADDRESS.ADDRESS1>1245 Williams Lane</DISPLAYCONTACT.MAILADDRESS.ADDRESS1>
<DISPLAYCONTACT.MAILADDRESS.ADDRESS2></DISPLAYCONTACT.MAILADDRESS.ADDRESS2>
<DISPLAYCONTACT.MAILADDRESS.CITY>San Jose</DISPLAYCONTACT.MAILADDRESS.CITY>
<DISPLAYCONTACT.MAILADDRESS.STATE>CA</DISPLAYCONTACT.MAILADDRESS.STATE>
<DISPLAYCONTACT.MAILADDRESS.ZIP>95112</DISPLAYCONTACT.MAILADDRESS.ZIP>
<DISPLAYCONTACT.MAILADDRESS.COUNTRY>USA</DISPLAYCONTACT.MAILADDRESS.COUNTRY>
<DISPLAYCONTACT.MAILADDRESS.COUNTRYCODE></DISPLAYCONTACT.MAILADDRESS.COUNTRYCODE>
<DISPLAYCONTACT.MAILADDRESS.LATITUDE></DISPLAYCONTACT.MAILADDRESS.LATITUDE>
<DISPLAYCONTACT.MAILADDRESS.LONGITUDE></DISPLAYCONTACT.MAILADDRESS.LONGITUDE>
<DISPLAYCONTACT.STATUS>active</DISPLAYCONTACT.STATUS>
<TERMNAME>2/10 Net30</TERMNAME>
<TERMVALUE>2:10:1#30#1%:W:</TERMVALUE>
<CUSTREPID>EMP-002</CUSTREPID>
<CUSTREPNAME>Joanna Drake</CUSTREPNAME>
<RESALENO></RESALENO>
<TAXID></TAXID>
<CREDITLIMIT></CREDITLIMIT>
<TOTALDUE>3525172.72</TOTALDUE>
<COMMENTS></COMMENTS>
<ACCOUNTLABEL></ACCOUNTLABEL>
<ARACCOUNT>4000</ARACCOUNT>
<ARACCOUNTTITLE>Sales</ARACCOUNTTITLE>
<LAST_INVOICEDATE>10/01/2012</LAST_INVOICEDATE>
<LAST_STATEMENTDATE></LAST_STATEMENTDATE>
<DELIVERY_OPTIONS>Print#~#E-Mail</DELIVERY_OPTIONS>
<TERRITORYID></TERRITORYID>
<SHIPPINGMETHOD>Delivery</SHIPPINGMETHOD>
<CUSTTYPE>Corporate</CUSTTYPE>
<GLGRPKEY></GLGRPKEY>
<GLGROUP></GLGROUP>
<PRICESCHEDULE></PRICESCHEDULE>
<DISCOUNT></DISCOUNT>
<PRICELIST></PRICELIST>
<VSOEPRICELIST></VSOEPRICELIST>
<CURRENCY></CURRENCY>
<CONTACTINFO.CONTACTNAME></CONTACTINFO.CONTACTNAME>
<CONTACTINFO.PREFIX></CONTACTINFO.PREFIX>
<CONTACTINFO.FIRSTNAME></CONTACTINFO.FIRSTNAME>
<CONTACTINFO.INITIAL></CONTACTINFO.INITIAL>
<CONTACTINFO.LASTNAME></CONTACTINFO.LASTNAME>
<CONTACTINFO.COMPANYNAME></CONTACTINFO.COMPANYNAME>
<CONTACTINFO.PRINTAS></CONTACTINFO.PRINTAS>
<CONTACTINFO.PHONE1></CONTACTINFO.PHONE1>
<CONTACTINFO.PHONE2></CONTACTINFO.PHONE2>
<CONTACTINFO.CELLPHONE></CONTACTINFO.CELLPHONE>
<CONTACTINFO.PAGER></CONTACTINFO.PAGER>
<CONTACTINFO.FAX></CONTACTINFO.FAX>
<CONTACTINFO.EMAIL1></CONTACTINFO.EMAIL1>
<CONTACTINFO.EMAIL2></CONTACTINFO.EMAIL2>
<CONTACTINFO.URL1></CONTACTINFO.URL1>
<CONTACTINFO.URL2></CONTACTINFO.URL2>
<CONTACTINFO.VISIBLE></CONTACTINFO.VISIBLE>
<CONTACTINFO.MAILADDRESS.ADDRESS1></CONTACTINFO.MAILADDRESS.ADDRESS1>
<CONTACTINFO.MAILADDRESS.ADDRESS2></CONTACTINFO.MAILADDRESS.ADDRESS2>
<CONTACTINFO.MAILADDRESS.CITY></CONTACTINFO.MAILADDRESS.CITY>
<CONTACTINFO.MAILADDRESS.STATE></CONTACTINFO.MAILADDRESS.STATE>
<CONTACTINFO.MAILADDRESS.ZIP></CONTACTINFO.MAILADDRESS.ZIP>
<CONTACTINFO.MAILADDRESS.COUNTRY></CONTACTINFO.MAILADDRESS.COUNTRY>
<CONTACTINFO.MAILADDRESS.COUNTRYCODE></CONTACTINFO.MAILADDRESS.COUNTRYCODE>
<SHIPTO.CONTACTNAME></SHIPTO.CONTACTNAME>
<SHIPTO.PREFIX></SHIPTO.PREFIX>
<SHIPTO.FIRSTNAME></SHIPTO.FIRSTNAME>
<SHIPTO.INITIAL></SHIPTO.INITIAL>
<SHIPTO.LASTNAME></SHIPTO.LASTNAME>
<SHIPTO.COMPANYNAME></SHIPTO.COMPANYNAME>
<SHIPTO.PRINTAS></SHIPTO.PRINTAS>
<SHIPTO.TAXABLE></SHIPTO.TAXABLE>
<SHIPTO.TAXGROUP></SHIPTO.TAXGROUP>
<SHIPTO.PHONE1></SHIPTO.PHONE1>
<SHIPTO.PHONE2></SHIPTO.PHONE2>
<SHIPTO.CELLPHONE></SHIPTO.CELLPHONE>
<SHIPTO.PAGER></SHIPTO.PAGER>
<SHIPTO.FAX></SHIPTO.FAX>
<SHIPTO.EMAIL1></SHIPTO.EMAIL1>
<SHIPTO.EMAIL2></SHIPTO.EMAIL2>
<SHIPTO.URL1></SHIPTO.URL1>
<SHIPTO.URL2></SHIPTO.URL2>
<SHIPTO.VISIBLE></SHIPTO.VISIBLE>
<SHIPTO.MAILADDRESS.ADDRESS1></SHIPTO.MAILADDRESS.ADDRESS1>
<SHIPTO.MAILADDRESS.ADDRESS2></SHIPTO.MAILADDRESS.ADDRESS2>
<SHIPTO.MAILADDRESS.CITY></SHIPTO.MAILADDRESS.CITY>
<SHIPTO.MAILADDRESS.STATE></SHIPTO.MAILADDRESS.STATE>
<SHIPTO.MAILADDRESS.ZIP></SHIPTO.MAILADDRESS.ZIP>
<SHIPTO.MAILADDRESS.COUNTRY></SHIPTO.MAILADDRESS.COUNTRY>
<SHIPTO.MAILADDRESS.COUNTRYCODE></SHIPTO.MAILADDRESS.COUNTRYCODE>
<BILLTO.CONTACTNAME></BILLTO.CONTACTNAME>
<BILLTO.PREFIX></BILLTO.PREFIX>
<BILLTO.FIRSTNAME></BILLTO.FIRSTNAME>
<BILLTO.INITIAL></BILLTO.INITIAL>
<BILLTO.LASTNAME></BILLTO.LASTNAME>
<BILLTO.COMPANYNAME></BILLTO.COMPANYNAME>
<BILLTO.PRINTAS></BILLTO.PRINTAS>
<BILLTO.TAXABLE></BILLTO.TAXABLE>
<BILLTO.TAXGROUP></BILLTO.TAXGROUP>
<BILLTO.PHONE1></BILLTO.PHONE1>
<BILLTO.PHONE2></BILLTO.PHONE2>
<BILLTO.CELLPHONE></BILLTO.CELLPHONE>
<BILLTO.PAGER></BILLTO.PAGER>
<BILLTO.FAX></BILLTO.FAX>
<BILLTO.EMAIL1></BILLTO.EMAIL1>
<BILLTO.EMAIL2></BILLTO.EMAIL2>
<BILLTO.URL1></BILLTO.URL1>
<BILLTO.URL2></BILLTO.URL2>
<BILLTO.VISIBLE></BILLTO.VISIBLE>
<BILLTO.MAILADDRESS.ADDRESS1></BILLTO.MAILADDRESS.ADDRESS1>
<BILLTO.MAILADDRESS.ADDRESS2></BILLTO.MAILADDRESS.ADDRESS2>
<BILLTO.MAILADDRESS.CITY></BILLTO.MAILADDRESS.CITY>
<BILLTO.MAILADDRESS.STATE></BILLTO.MAILADDRESS.STATE>
<BILLTO.MAILADDRESS.ZIP></BILLTO.MAILADDRESS.ZIP>
<BILLTO.MAILADDRESS.COUNTRY></BILLTO.MAILADDRESS.COUNTRY>
<BILLTO.MAILADDRESS.COUNTRYCODE></BILLTO.MAILADDRESS.COUNTRYCODE>
<STATUS>active</STATUS>
<ONETIME>false</ONETIME>
<CUSTMESSAGEID></CUSTMESSAGEID>
<ONHOLD>false</ONHOLD>
<PRCLST_OVERRIDE>C</PRCLST_OVERRIDE>
<OEPRCLSTKEY></OEPRCLSTKEY>
<OEPRICESCHEDKEY></OEPRICESCHEDKEY>
<ENABLEONLINECARDPAYMENT>true</ENABLEONLINECARDPAYMENT>
<ENABLEONLINEACHPAYMENT>true</ENABLEONLINEACHPAYMENT>
<VSOEPRCLSTKEY></VSOEPRCLSTKEY>
<WHENMODIFIED>12/18/2018 16:07:40</WHENMODIFIED>
<ARINVOICEPRINTTEMPLATEID></ARINVOICEPRINTTEMPLATEID>
<OEQUOTEPRINTTEMPLATEID></OEQUOTEPRINTTEMPLATEID>
<OEORDERPRINTTEMPLATEID></OEORDERPRINTTEMPLATEID>
<OELISTPRINTTEMPLATEID></OELISTPRINTTEMPLATEID>
<OEINVOICEPRINTTEMPLATEID></OEINVOICEPRINTTEMPLATEID>
<OEADJPRINTTEMPLATEID></OEADJPRINTTEMPLATEID>
<OEOTHERPRINTTEMPLATEID></OEOTHERPRINTTEMPLATEID>
<WHENCREATED>01/01/1970 00:00:00</WHENCREATED>
<CREATEDBY></CREATEDBY>
<MODIFIEDBY>1</MODIFIEDBY>
<OBJECTRESTRICTION>Unrestricted</OBJECTRESTRICTION>
<DISPLAYCONTACTKEY>38</DISPLAYCONTACTKEY>
<CONTACTKEY></CONTACTKEY>
<SHIPTOKEY></SHIPTOKEY>
<BILLTOKEY></BILLTOKEY>
<CUSTREPKEY>2</CUSTREPKEY>
<SHIPVIAKEY>1</SHIPVIAKEY>
<TERRITORYKEY></TERRITORYKEY>
<TERMSKEY>1</TERMSKEY>
<ACCOUNTLABELKEY></ACCOUNTLABELKEY>
<ACCOUNTKEY>25</ACCOUNTKEY>
<CUSTTYPEKEY>1</CUSTTYPEKEY>
<PRICESCHEDULEKEY></PRICESCHEDULEKEY>
<OFFSETGLACCOUNTNO></OFFSETGLACCOUNTNO>
<OFFSETGLACCOUNTNOTITLE></OFFSETGLACCOUNTNOTITLE>
<ADVBILLBY></ADVBILLBY>
<ADVBILLBYTYPE></ADVBILLBYTYPE>
<SUPDOCID></SUPDOCID>
<MEGAENTITYKEY></MEGAENTITYKEY>
<MEGAENTITYID></MEGAENTITYID>
<MEGAENTITYNAME></MEGAENTITYNAME>
<RESTRICTEDLOCATIONS></RESTRICTEDLOCATIONS>
<RESTRICTEDDEPARTMENTS></RESTRICTEDDEPARTMENTS>
</customer></data>
</result>
</operation>
</response>
Please help me.
Quick test shows XmlSerializer can handle this pretty easily
Test class:
[XmlRoot]
public class Test
{
[XmlElement(ElementName="Foo.Alpha")]
public string Alpha {get;set;}
[XmlElement(ElementName="Foo.Beta")]
public string Beta {get;set;}
}
Example method:
private static void Main()
{
var src = #"<Test>
<Foo.Alpha>value 1</Foo.Alpha>
<Foo.Beta>value 2</Foo.Beta>
</Test>";
using (var sreader = new StringReader(src))
using (var reader = XmlReader.Create(sreader))
{
var serializer = new XmlSerializer(typeof(Test));
var test = (Test)serializer.Deserialize(reader);
Console.WriteLine(test.Alpha);
Console.WriteLine(test.Beta);
}
}
Update: since the XML document you are processing is very large, you should consider what you actually need to do. If you need to manipulate the entire document as objects then the approach taken in JP Hellemons's answer may be the way to go. If you are only interested in certain fields, then it may be better to load the XML into an XDocument or XmlDocument and extract the fields you are interested in from that, or even write a forward-only parser using XmlReader to do the same thing.
I have pasted your XML in an XMLFile1.xml and pasted it in Visual Studio to generate classes, so this will be a lot of autogenerated code... warning
could not fit auto gen code...
Body is limited to 30000 characters; you entered 93977
Full code here:
https://pastebin.com/VxzNUjsv
Smaller version:
<?xml version="1.0" encoding="UTF-8"?>
<customer>
<RECORDNO>5</RECORDNO>
<CUSTOMERID>CUST-00101</CUSTOMERID>
<PARENTNAME>parent</PARENTNAME>
<DISPLAYCONTACT.CONTACTNAME>Sun Microsystems - EBC(CCUST-00101)</DISPLAYCONTACT.CONTACTNAME>
<DISPLAYCONTACT.COMPANYNAME>Sun Microsystems - EBC</DISPLAYCONTACT.COMPANYNAME>
</customer>
and C# code:
class Program
{
static void Main(string[] args)
{
using (var sreader = new StringReader(File.ReadAllText(#"C:\Users\JP\source\repos\soXmlParsing\soXmlParsing\XMLFile1.xml")))
using (var reader = XmlReader.Create(sreader))
{
var serializer = new XmlSerializer(typeof(customer));
var test = (customer)serializer.Deserialize(reader);
Console.WriteLine(test.PARENTNAME);
Console.WriteLine(test.DISPLAYCONTACTCONTACTNAME);
}
}
}
// NOTE: Generated code may require at least .NET Framework 4.5 or .NET Core/Standard 2.0.
/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class customer
{
private byte rECORDNOField;
private string cUSTOMERIDField;
private string pARENTNAMEField;
private string dISPLAYCONTACTCONTACTNAMEField;
private string dISPLAYCONTACTCOMPANYNAMEField;
/// <remarks/>
public byte RECORDNO
{
get
{
return this.rECORDNOField;
}
set
{
this.rECORDNOField = value;
}
}
/// <remarks/>
public string CUSTOMERID
{
get
{
return this.cUSTOMERIDField;
}
set
{
this.cUSTOMERIDField = value;
}
}
/// <remarks/>
public string PARENTNAME
{
get
{
return this.pARENTNAMEField;
}
set
{
this.pARENTNAMEField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("DISPLAYCONTACT.CONTACTNAME")]
public string DISPLAYCONTACTCONTACTNAME
{
get
{
return this.dISPLAYCONTACTCONTACTNAMEField;
}
set
{
this.dISPLAYCONTACTCONTACTNAMEField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("DISPLAYCONTACT.COMPANYNAME")]
public string DISPLAYCONTACTCOMPANYNAME
{
get
{
return this.dISPLAYCONTACTCOMPANYNAMEField;
}
set
{
this.dISPLAYCONTACTCOMPANYNAMEField = value;
}
}
}

how to serialize List of CustomClass with object attribute

I want to serialize CMainClass:
[XmlType("Param")]
public class CParam
{
[XmlElement]
public string Name;
[XmlElement]
public object Value;
public CParam() { }
public CParam(string name, object value)
{
Name = name;
Value = value;
}
}
public class CMainClass
{
public List<CParam> Parameters = new List<CParam>();
public CMainClass() { }
public string GetXML()
{
XmlDocument doc = new XmlDocument();
Type[] extraTypes = new Type[1];
extraTypes[0] = typeof(CParam);
XmlSerializer serializer = new XmlSerializer(typeof(CMainClass), extraTypes);
MemoryStream stream = new MemoryStream();
try
{
serializer.Serialize(stream, this);
stream.Position = 0;
doc.Load(stream);
return doc.InnerXml;
}
catch { throw; }
finally
{
stream.Close();
stream.Dispose();
}
}
}
The type of attribute Value can be various, that why object-type is used.
here is test code
CMainClass mc = new CMainClass();
mc.Parameters.Add(new CParam("number", 123));
mc.Parameters.Add(new CParam("text", "lorem ipsum"));
mc.Parameters.Add(new CParam("price", 23.50));
string s = mc.GetXML();
Console.WriteLine(s);
Console.ReadLine();
All I want is to get output in following form
<?xml version="1.0"?>
<CMainClass>
<Parameters>
<Param Name="number" Value="123" />
<Param Name="text" Value="lorem ipsum" />
<Param Name="price" Value="23.5" />
</Parameters>
</CMainClass>
instead of
<?xml version="1.0"?>
<CMainClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Parameters>
<Param>
<Name>number</Name>
<Value xsi:type="xsd:int">123</Value>
</Param>
<Param>
<Name>text</Name>
<Value xsi:type="xsd:string">lorem ipsum</Value>
</Param>
<Param>
<Name>price</Name>
<Value xsi:type="xsd:double">23.5</Value>
</Param>
</Parameters>
</CMainClass>
Is it possible? Changing property of Value from [XmlElement] to [XmlAttribute] leads to error.
If you want to use attributes, then you'll have to specify their types explicitly. The reason for the error you get when trying this is that the serializer doesn't know what type object actually is when deserializing as, unlike elements, it can't use type attributes to indicate this. You will have to change it to string instead and handle the conversion yourself.
public class Param
{
[XmlAttribute]
public string Name { get; set; }
[XmlAttribute]
public string Value { get; set; }
}
Also note that your GetXML method can be simplified to just this:
var serializer = new XmlSerializer(typeof(CMainClass));
using (var writer = new StringWriter())
{
serializer.Serialize(writer, this);
return writer.ToString();
}
See this fiddle for a working demo.
To serialize a class you should add [Serializable()] attribute.

Serialize to xml using a class with multiple classes

I am using an asp.net and C# to serialize some entered data using a class. This class was generated from an xsd file. I am using this class to generate an xml file. I am struggling to understand how I can reference all these classes and serialize it to one xml file.
Here is my class code. It is in a separate file within my project:
namespace Ce
{
using System.Xml.Serialization;
//
// This source code was auto-generated by xsd, Version=4.0.30319.33440.
//
public partial class AddRequest
{
private CDocument cDocumentField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "x")]
public CDocument CDocument
{
get
{
return this.cDocumentField;
}
set
{
this.cDocumentField = value;
}
}
}
public partial class CDocument
{
private CaseA caseAField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "x")]
public CaseA CaseA
{
get
{
return this.caseAField;
}
set
{
this.caseAField = value;
}
}
}
public partial class CaseA
{
public string dCTextField;
private string dLField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "x")]
public string DCText
{
get
{
return this.dCTextField;
}
set
{
this.dCTextField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "x")]
public string DLU
{
get
{
return this.dLField;
}
set
{
this.dLField = value;
}
}
}
}
To serialize I have this in my code-behind in a button click event:
protected void CaseSubmitButton_Click(object sender, EventArgs e)
{
CaseA CSerialize = new CaseA();
CSerialize.DCText = casetextboxt.text;
CSerialize.DLu = "\\app";
XmlSerializer Serializer = new XmlSerializer(typeof(CaseA));
StreamWriter Writer = new StreamWriter(Server.MapPath("~/XmlPackages/" + xmlPackageFilename));
Serializer.Serialize(Writer, CSerialize);
Serializer.Serialize(Writer, CSerialize);
}
With this button click event I get this xml format:
<?xml version="1.0" encoding="utf-8"?>
<CaseA xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<DCText>\apptest</DCText>
<DLU>\apptest</DLU>
</CaseA>
I would like to reference the other two classes to get:
<?xml version="1.0" encoding="utf-8"?>
<Addrequest>
<Cdocument>
<CaseA xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<DCText>\apptest</DCText>
<DLU>\apptest</DLU>
</CaseA>
</Cdocument>
</Addrequest>
You're serializing an instance of CaseA class, which is why you're only seeing members of CaseA in the output. You need to create an instance of AddRequest and serialize that as the root, something like this:
CaseA cSerialize = new CaseA();
cSerialize .DCText = casetextboxt.text;
cSerialize .DLu = "\\app";
CDocument document = new CDocument();
document.CaseA = cSerialize ;
AddRequest root = new AddRequest();
root.CDocument = document;
XmlSerializer serializer = new XmlSerializer(typeof(AddRequest), new Type[] { typeof(CDocument), typeof(CaseA) });
StreamWriter writer = new StreamWriter(Server.MapPath("~/XmlPackages/" + xmlPackageFilename));
serializer.Serialize(writer, root);
As a side note, please follow C# coding standards for naming your local variables :)

Placing a Property into a Different XML Namespace with XML Serialization

I am using VSTS2008 + C# + .Net 3.0. I am using below code to serialize XML, here is my current code and serialized XML file. My purpose is I want to make MyInnerObjectProperties belongs to a special XML namespace (http://foo/2009) and making this namespace as default namespace. Any ideas how to implement this?
Current output:
<?xml version="1.0"?>
<MyClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<MyObjectProperty>
<MyInnerObjectProperties>
<MyInnerObjectProperty>
<ObjectName>Foo Type</ObjectName>
</MyInnerObjectProperty>
<MyInnerObjectProperty>
<ObjectName>Goo Type</ObjectName>
</MyInnerObjectProperty>
</MyInnerObjectProperties>
</MyObjectProperty>
</MyClass>
Current code:
public class MyClass
{
private MyObject[] _myObjectProperty;
[XmlElement(IsNullable=false)]
public MyObject[] MyObjectProperty
{
get
{
return _myObjectProperty;
}
set
{
_myObjectProperty = value;
}
}
}
public class MyObject
{
private MyInnerObject[] _myInnerObjectProperty;
[XmlArrayItemAttribute("MyInnerObjectProperty", typeof(MyInnerObject), IsNullable=false)]
public MyInnerObject[] MyInnerObjectProperties
{
get
{
return _myInnerObjectProperty;
}
set
{
_myInnerObjectProperty = value;
}
}
}
public class MyInnerObject
{
public string ObjectName;
}
public class Program
{
static void Main(string[] args)
{
XmlSerializer s = new XmlSerializer(typeof(MyClass));
FileStream fs = new FileStream("foo.xml", FileMode.Create);
MyClass instance = new MyClass();
instance.MyObjectProperty = new MyObject[1];
instance.MyObjectProperty[0] = new MyObject();
instance.MyObjectProperty[0].MyInnerObjectProperties = new MyInnerObject[2];
instance.MyObjectProperty[0].MyInnerObjectProperties[0] = new MyInnerObject();
instance.MyObjectProperty[0].MyInnerObjectProperties[0].ObjectName = "Foo Type";
instance.MyObjectProperty[0].MyInnerObjectProperties[1] = new MyInnerObject();
instance.MyObjectProperty[0].MyInnerObjectProperties[1].ObjectName = "Goo Type";
s.Serialize(fs, instance);
return;
}
}
How about this:
[XmlArrayItemAttribute( Namespace = "http://foo.com/2009" /* other attr. params. */ )]
public MyInnerObject[] MyInnerObjectProperties
{
get { ... }
set { ... }
}
Try
public class MyObject
{
[XmlArrayItemAttribute("MyInnerObjectProperty", typeof (MyInnerObject),
IsNullable = false)]
[XmlArray(Namespace = "http://foo.com/2009")]
public MyInnerObject[] MyInnerObjectProperties { get; set; }
}
for me, this produces:
<?xml version="1.0" encoding="utf-8"?>
<MyClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<MyObjectProperty>
<MyInnerObjectProperties xmlns="http://foo.com/2009">
<MyInnerObjectProperty>
<ObjectName>Foo Type</ObjectName>
</MyInnerObjectProperty>
<MyInnerObjectProperty>
<ObjectName>Goo Type</ObjectName>
</MyInnerObjectProperty>
</MyInnerObjectProperties>
</MyObjectProperty>
</MyClass>
You need to create an XmlSerializerNamespaces object, and add your needed namespaces to it.
The XmlSerializerNamespaces object contains the XML namespaces and prefixes that the XmlSerializer uses to generate qualified names in an XML-document instance.
In your c# code:
XmlSerializerNamespaces myNameSpaces = new XmlSerializerNamespaces();
myNameSpaces.Add("MyInnerObject", "http://foo/2009");
Then, add an attribute to your class, like this:
public class MyInnerObject
{
[XmlElement(Namespace = "http://foo/2009")]
More info at:
http://msdn.microsoft.com/en-us/library/system.xml.serialization.xmlserializernamespaces.aspx

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