How to get a value of XElement without getting child elements?
An example:
<?xml version="1.0" ?>
<someNode>
someValue
<child>1</child>
<child>2</child>
</someNode>
If i use XElement.Value for <someNode> I get "somevalue<child>1</child><child>2<child>" string but I want to get only "somevalue" without "<child>1</child><child>2<child>" substring.
You can do it slightly more simply than using Descendants - the Nodes method only returns the direct child nodes:
XElement element = XElement.Parse(
#"<someNode>somevalue<child>1</child><child>2</child></someNode>");
var firstTextValue = element.Nodes().OfType<XText>().First().Value;
Note that this will work even in the case where the child elements came before the text node, like this:
XElement element = XElement.Parse(
#"<someNode><child>1</child><child>2</child>some value</someNode>");
var firstTextValue = element.Nodes().OfType<XText>().First().Value;
There is no direct way. You'll have to iterate and select. For instance:
var doc = XDocument.Parse(
#"<someNode>somevalue<child>1</child><child>2</child></someNode>");
var textNodes = from node in doc.DescendantNodes()
where node is XText
select (XText)node;
foreach (var textNode in textNodes)
{
Console.WriteLine(textNode.Value);
}
I think what you want would be the first descendant node, so something like:
var value = XElement.Descendents.First().Value;
Where XElement is the element representing your <someNode> element.
You can specifically ask for the first text element (which is "somevalue"), so you could also do:
var value = XElement.Descendents.OfType<XText>().First().Value;
Related
How to remove the sibling node of XML. I need to remove CreationDateTime value.
I am limited to XMLdocument in C#.
How to use say that i need to select the value element which is next to CreationDateTime Name element.
xmlDoc.Descendants().Where(e => e.Name == "Value").Remove();
<Mic><Attribute>
<Name>CreatedBy</Name>
<Value>MS</Value>
</Attribute>
<Attribute>
<Name>CreationDateTime</Name>
<Value>04/13/2018 19:45:38</Value>
</Attribute></Mic>
Since you are limited to using XmlDocument, you need to get all the Attribute tags and then remove their last child (this is the Value tag).
var doc = new XmlDocument();
doc.Load("YourFile.xml");
// Get all the Attribute tags
var atts = doc.GetElementsByTagName("Attribute");
// Traverse and remove the last child (this is the Value tag)
foreach (XmlNode thisElement in atts)
{
thisElement.RemoveChild(thisElement.LastChild);
}
I have the following XML:
<Root><Node1>node1 value</Node1><Node2>node2 value</Node2></Root>
I'd like to check if Root is the first node. If so, I then want to get the values for the to child nodes.
This XML is inside of an XElement. I've tried this:
xml.Element("Root")
but that returns null. If Root exist, shouldn't it return a non null value?
string xml = #"<Root><Node1>node1 value</Node1><Node2>node2 value</Node2></Root>";
XDocument doc = XDocument.Parse(xml);
var root = doc.Root;
if(root.Name == "Root")
{
foreach(var el in root.Descendants())
{
string nodeValue = el.Value;
}
}
You can check the name of the Root element from Root.Name. After that loop all elements in the root using doc.Root.Descendants().
Since xml is an instance of XElement, it already references the root element, which in this case named Root. Doing xml.Element("Root") will return result only if the <Root> element has another child <Root>.
I'd like to check if Root is the first node.
You can simply check the Name of the root element :
var raw = "<Root><Node1>node1 value</Node1><Node2>node2 value</Node2></Root>";
var xml = XElement.Parse(raw);
if (xml.Name.ToString() == "Root")
Console.WriteLine("Success");
else
Console.WriteLine("Fail");
Try this solution
XDocument doc = XDocument.Parse(#"<Root><Node1>node1value</Node1><Node2>node2value</Node2></Root>");
if(doc!=null)
{
if (doc.Root.Name.LocalName == "Root")
{
foreach (var i in doc.Descendants())
Console.WriteLine(i.Value);
}
}
I am learning C# and trying to flatten XML following this code from this post
var doc = XDocument.Load("test.xml");
XNamespace ns = "mynamespace";
var member = doc.Root.Element(ns + "member");
// This will *sort* of flatten, but create copies...
var descendants = member.Descendants().ToList();
// So we need to strip child elements from everywhere...
// (but only elements, not text nodes). The ToList() call
// materializes the query, so we're not removing while we're iterating.
foreach (var nested in descendants.Elements().ToList())
{
nested.Remove();
}
member.ReplaceNodes(descendants);
This is my XML (sorry I don't know how to post fancy code style)
<ApplicationExtraction>
<IsCurrent>Yes</IsCurrent>
<ApplicationDate>10/06/2015</ApplicationDate>
<Status>Application Received</Status>
<EquipmentType>Equipment</EquipmentType>
<IsLoan>No</IsLoan>
</ApplicationExtraction>
There is namespace so I changed var member = doc.Root.Element(ns + "member"); to var member = doc.Root.Element("ApplicationExtraction"); but this returns NULL.
I also try XElement sRoot = doc.Root.Element("ApplicationExtraction"); from this post I still get the same result.
I read up Microsoft XElement document but don't see how I can fix this.
What could I have done wrong?
XElement sRoot = doc.Root.Element("ApplicationExtraction");
will look for an element 'ApplicationExtraction' inside the Root.
If you want the Root, just reference
doc.Root
In your XML, doc.Root is the root node i.e. ApplicationExtraction and there is no node ApplicationExtraction inside the root node thus you are getting null.
To fetch any specific node you need(for example):-
XElement member = doc.Root.Element("IsCurrent");
and to fetch the value inside the node:-
string member = (string)doc.Root.Element("IsCurrent");
This is my XML:
<?xml version="1.0"?>
<formatlist>
<format>
<formatName>WHC format</formatName>
<delCol>ID</delCol>
<delCol>CDRID</delCol>
<delCol>TGIN</delCol>
<delCol>IPIn</delCol>
<delCol>TGOUT</delCol>
<delCol>IPOut</delCol>
<srcNum>SRCNum</srcNum>
<distNum>DSTNum</distNum>
<connectTime>ConnectTime</connectTime>
<duration>Duration</duration>
</format>
<format>
<formatName existCombineCol="1">Umobile format</formatName> //this format
<delCol>billing_operator</delCol>
<hideCol>event_start_date</hideCol>
<hideCol>event_start_time</hideCol>
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>ConnectdateTimeAFcombine</name>
<combineDate>event_start_date</combineDate>
<combineTime>event_start_time</combineTime>
</afCombineName>
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>aaa</name>
<combineDate>bbb</combineDate>
<combineTime>ccc</combineTime>
</afCombineName>
<modifyPerfixCol action="add" perfix="60">bnum</modifyPerfixCol>
<srcNum>anum</srcNum>
<distNum>bnum</distNum>
<connectTime>ConnectdateTimeAFcombine</connectTime>
<duration>event_duration</duration>
</format>
</formatlist>
I want to find format with Umobile format then iterate over those two nodes.
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>ConnectdateTimeAFcombine</name>
<combineDate>event_start_date</combineDate>
<combineTime>event_start_time</combineTime>
</afCombineName>
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>aaa</name>
<combineDate>bbb</combineDate>
<combineTime>ccc</combineTime>
</afCombineName>
and list all the two node's child nodes. The result should like this:
ConnectdateTimeAFcombine,event_start_date,event_start_time.
aaa,bbb,ccc
How can I do this?
foreach(var children in format.Descendants())
{
//Do something with the child nodes of format.
}
For all XML related traversing, you should get used to using XPath expressions. It is very useful. Even if you could perhaps do something easier in your specific case, it is good practice to use XPath. This way, if your scheme changes at some point, you just update your XPath expression and your code will be up and running.
For a complete example, you can have a look at this article.
You can use the System.Xml namespace APIs along with System.Xml.XPath namespace API. Here is a quick algorithm that will help you do your task:
Fetch the text node containing the string Umobile format using the below XPATH:
XmlNode umobileFormatNameNode = document.SelectSingleNode("//formatName[text()='Umobile format']");
Now the parent of umobileFormatNameNode will be the node that you are interested in:
XmlNode formatNode = umobileFormatNameNode.ParentNode;
Now get the children for this node:
XmlNodeList afCombineFormatNodes = formatNode.SelectNodes("afCombineName");
You can now process the list of afCombineFormatNodes
for(XmlNode xmlNode in afCombineNameFormtNodes)
{
//process nodes
}
This way you can access those elements:
var doc = System.Xml.Linq.XDocument.Load("PATH TO YOUR XML FILE");
var result = doc.Descendants("format")
.Where(x => (string)x.Element("formatName") == "Umobile format")
.Select(x => x.Element("afCombineName"));
Then you can iterate the result this way:
foreach (var item in result)
{
string format = item.Attribute("format").Value.ToString();
string name = item.Element("name").Value.ToString();
string combineDate = item.Element("combineDate").Value.ToString();
string combineTime = item.Element("combineTime").Value.ToString();
}
I have a simple XML
<AllBands>
<Band>
<Beatles ID="1234" started="1962">greatest Band<![CDATA[lalala]]></Beatles>
<Last>1</Last>
<Salary>2</Salary>
</Band>
<Band>
<Doors ID="222" started="1968">regular Band<![CDATA[lalala]]></Doors>
<Last>1</Last>
<Salary>2</Salary>
</Band>
</AllBands>
However ,
when I want to reach the "Doors band" and to change its ID :
using (var stream = new StringReader(result))
{
XDocument xmlFile = XDocument.Load(stream);
var query = from c in xmlFile.Elements("Band")
select c;
...
query has no results
But
If I write xmlFile.Elements().Elements("Band") so it Does find it.
What is the problem ?
Is the full path from the Root needed ?
And if so , Why did it work without specify AllBands ?
Does the XDocument Navigation require me to know the full level structure down to the required element ?
Elements() will only check direct children - which in the first case is the root element, in the second case children of the root element, hence you get a match in the second case. If you just want any matching descendant use Descendants() instead:
var query = from c in xmlFile.Descendants("Band") select c;
Also I would suggest you re-structure your Xml: The band name should be an attribute or element value, not the element name itself - this makes querying (and schema validation for that matter) much harder, i.e. something like this:
<Band>
<BandProperties Name ="Doors" ID="222" started="1968" />
<Description>regular Band<![CDATA[lalala]]></Description>
<Last>1</Last>
<Salary>2</Salary>
</Band>
You can do it this way:
xml.Descendants().SingleOrDefault(p => p.Name.LocalName == "Name of the node to find")
where xml is a XDocument.
Be aware that the property Name returns an object that has a LocalName and a Namespace. That's why you have to use Name.LocalName if you want to compare by name.
You should use Root to refer to the root element:
xmlFile.Root.Elements("Band")
If you want to find elements anywhere in the document use Descendants instead:
xmlFile.Descendants("Band")
The problem is that Elements only takes the direct child elements of whatever you call it on. If you want all descendants, use the Descendants method:
var query = from c in xmlFile.Descendants("Band")
My experience when working with large & complicated XML files is that sometimes neither Elements nor Descendants seem to work in retrieving a specific Element (and I still do not know why).
In such cases, I found that a much safer option is to manually search for the Element, as described by the following MSDN post:
https://social.msdn.microsoft.com/Forums/vstudio/en-US/3d457c3b-292c-49e1-9fd4-9b6a950f9010/how-to-get-tag-name-of-xml-by-using-xdocument?forum=csharpgeneral
In short, you can create a GetElement function:
private XElement GetElement(XDocument doc,string elementName)
{
foreach (XNode node in doc.DescendantNodes())
{
if (node is XElement)
{
XElement element = (XElement)node;
if (element.Name.LocalName.Equals(elementName))
return element;
}
}
return null;
}
Which you can then call like this:
XElement element = GetElement(doc,"Band");
Note that this will return null if no matching element is found.
The Elements() method returns an IEnumerable<XElement> containing all child elements of the current node. For an XDocument, that collection only contains the Root element. Therefore the following is required:
var query = from c in xmlFile.Root.Elements("Band")
select c;
Sebastian's answer was the only answer that worked for me while examining a xaml document. If, like me, you'd like a list of all the elements then the method would look a lot like Sebastian's answer above but just returning a list...
private static List<XElement> GetElements(XDocument doc, string elementName)
{
List<XElement> elements = new List<XElement>();
foreach (XNode node in doc.DescendantNodes())
{
if (node is XElement)
{
XElement element = (XElement)node;
if (element.Name.LocalName.Equals(elementName))
elements.Add(element);
}
}
return elements;
}
Call it thus:
var elements = GetElements(xamlFile, "Band");
or in the case of my xaml doc where I wanted all the TextBlocks, call it thus:
var elements = GetElements(xamlFile, "TextBlock");