I am using following code to select a file to import in a Windows Forms project.
OpenFileDialog fdlg = new OpenFileDialog();
fdlg.Title = "C# Corner Open File Dialog";
fdlg.InitialDirectory = #"c:\";
fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
fdlg.FilterIndex = 2;
fdlg.RestoreDirectory = true;
if (fdlg.ShowDialog() == DialogResult.OK)
{
txtpath.Text = fdlg.FileName;
}
The problem is that the selected file is opened in the background which I don't want. What can I do to just get the path of selected file without opening it?
Showing an OpenFileDialog and the user selecting a file does not open the file. The file can be opened by calling OpenFile. In the code you posted the file is not opened. That code appears to be copied from an example on MSDN. The rest of the code from that example is here:
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = openFileDialog1.OpenFile()) != null) // File is opened here.
{
using (myStream)
{
// Insert code to read the stream here.
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " +
ex.Message);
}
}
If the file is being opened when you don't want it opened then the problem must be somewhere else and not in the code you posted. It is possible for example that you have not closed the file (for example by using Dispose) after you finished using it last time.
Related
When I use OpenFileDialog to select a file on my WPF project I got an error window saying:
You do not have permissions to open this file.
Request permissions from the file owner or an administrator.
This only happen when I use image format files, with other type of file the File Dialog work as intended.
I already tried to open the app as admin and the error persists.
Test code:
OpenFileDialog fileDialog = new OpenFileDialog();
fileDialog.Filter = "jpg |*.jpg|png |*.png";
fileDialog.ShowDialog();
Perhaps you could try a new way which is safe at finding what file types you are looking for:
var dlg = new Microsoft.Win32.OpenFileDialog
{
Title = "Select an Image",
Filter = "Images |*.jpg; *.png",
CheckFileExists = true
};
if (dlg.ShowDialog() == true)
{
}
On file permissions try this https://windowsreport.com/no-permission-open-file/
Using Visual Studio 2017 and Windows 10 I want to be able to open a file explorer and navigate to a file outside of the program. Once my file is collected I want to get the file path and the complete file name for the file explorer.
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.Filter = "All files (*.*)|*.*";
if (openFileDialog1.ShowDialog() == DialogResult.OK)
textBoxFolderpath.Text= openFileDialog1.FileName;
if (textBoxFolderpath.Text.Contains('\\'))
textBoxFolderpath.Text = textBoxFolderpath.Text.Substring(0, textBoxFolderpath.Text.LastIndexOf('\\'));
This is what I have tried so far. The textBoxFolderpath is being used to hold the values.
What am I missing or doing incorrectly?
When working with filenames and paths I'd highly recommend using built-in classes to handle this, like the Path class:
Path.GetDirectoryName(openFileDialog1.FileName)
This returns the path, without the filename. It's also cross-platform compatible.
Thanks Zer0 - below is what I ended up using.
private void btnCurrentFolder_Click(object sender, EventArgs e)
{
OpenFileDialog openDialog1 = new OpenFileDialog();
// Determine starting directory
if (chkSetToRoot.Checked)
{
openDialog1.InitialDirectory = #"K:\RESULTS";
}
openDialog1.Title = "Select A Test File";
openDialog1.Filter = "All Files (*.*)|*.*";
if (openDialog1.ShowDialog() == DialogResult.OK)
{
textBoxFolderpath.Text = Path.GetDirectoryName(openDialog1.FileName);
textBoxFileName.Text = Path.GetFileName(openDialog1.FileName);
}
}
I am new to c# and I am almost done with a simple project. This project needs to include an excel file available for download using a LinkLabel
How can I include this file when compiling my project and when the LinkLabel is click it will as the user where to save the file.
My google search always point me to creating an excel, I dont need to create it, its already available, i just need to include in my resource file.
I am stuck here;
private void linkLabel1_LinkClicked(object sender, LinkLabelLinkClickedEventArgs e)
{
}
Now its working fine with the below code, I cant answer my question yet due to low score.
private void linkLabel1_LinkClicked(object sender, LinkLabelLinkClickedEventArgs e)
{
string filePath = null;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
filePath = saveFileDialog1.FileName;
File.WriteAllBytes(#filePath, Properties.Resources.importPurchases);
MessageBox.Show("File Successfully saved.\r\n\r\n" + filePath, "Success Message", MessageBoxButtons.OK, MessageBoxIcon.Information);
}
else
{
return;
}
}
Add the excel file to your Project (Add -> Existing Item).
Right Click the added Excel File, go to Properties
Set Build Action to Content
Set Copy to Output Directory as Copy Always or Copy If Newer
By doing this; the Excel File would be copied to the output folder always after build.
var saveFileDialog = new SaveFileDialog();
saveFileDialog.DefaultExt = "xls";
saveFileDialog.Filter = "Excel files (*.xls)|*.xls |All files (*.*)|*.*";
if (saveFileDialog.ShowDialog() == DialogResult.OK)
{
const string MyFileName = "myExcelFile.xls";
string execPath = Path.GetDirectoryName(Assembly.GetExecutingAssembly().CodeBase);
var filePath = Path.Combine(execPath, MyFileName);
Microsoft.Office.Interop.Excel.Application app = new Application();
Microsoft.Office.Interop.Excel.Workbook book = app.Workbooks.Open(filePath);
book.SaveAs(saveFileDialog.FileName); //Save
book.Close();
}
Update: The above sample is for Windows Application...
I am using my own Custom View to show the files and folders and also using a search box to jump to a specific folder. In that case How to send a message to File Open/Save dialog to enforce it to change the current displayed folder.
e.g. If the dialog shows files and folders of current displaying folder "C:\", I want an API (or any piece of code) to enforce to change the current folder to "D:\"
You can have the dialog open at a specific directory using InitialDirectory.
If you want to control what the dialog does at runtime, that's a bit more complex.
Set SaveFileDialog.InitialDirectory after you create it, but before you open it.
For example:
Stream myStream = null;
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1 .InitialDirectory = "d:\\" ;
saveFileDialog1 .Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ;
saveFileDialog1 .FilterIndex = 2 ;
saveFileDialog1 .RestoreDirectory = true ;
if(saveFileDialog1 .ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = saveFileDialog1 .OpenFile()) != null)
{
// Code to write the stream goes here.
myStream.Close();
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not save file to disk. Original error: " + ex.Message);
}
}
set InitialDirectory property to any path
Good day
Creating an Inventory system
created a db in sql, In visual c#, I created a form where products will be entered and allowing the user to upload an image of the item, How do I go about doing it?
I'm a c++ programmer, newly into visual c#
Thanks
Here is an older post on uploading on uploading a file.
Assuming you'd want to save the images in the database as well... You need to allow the user to select an image from his/her own harddisk (Open File Dialog), and then read the bytes and send them to the database (ADO.NET's DbCommand). ADO.NET supports streams for BLOBS.
Here is a example of the Open File Dialog:
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "images (*.png)|*.png|All files (*.*)|*.*";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
using (Stream myStream = openFileDialog1.OpenFile())
{
if (myStream != null)
{
// do something with the stream bytes here....
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}