I have Custom Control Library and do icon "control". Also i have PathGeometry figures accessible by x:Key. So as example input is IconName="Icon_Close" in MainWindow.xaml, i want to equate IconName="Icon_Close" with PathGeometry figure which x:Key equals to "Icon_Close" and show icon
But i have no ideas how to process/convert it...
Icon.xaml (Generic)
<PathGeometry x:Key="Icon_Close" Figures="M19,6.41L17.59,5L12,10.59L6.41,5L5,6.41L10.59,12L5,17.59L6.41,19L12,13.41L17.59,19L19,17.59L13.41,12L19,6.41Z"/>
<PathGeometry x:Key="Icon_WndMinimize" Figures="M19,13H5V11H19V13Z"/>
<PathGeometry x:Key="Icon_WndMaximize" Figures="M19,3H5C3.89,3 3,3.89 3,5V19A2,2 0 0,0 5,21H19A2,2 0 0,0 21,19V5C21,3.89 20.1,3 19,3M19,5V19H5V5H19Z"/>
<Style TargetType="{x:Type local:Icon}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type local:Icon}">
<Viewbox Height="{TemplateBinding IconHeight}"
Width="Auto">
<Canvas Height="24"
Width="24">
<Path Fill="{TemplateBinding IconColor}"
Data="{TemplateBinding IconName}"/>
</Canvas>
</Viewbox>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
Icon.cs
public class Icon : Control
{
public static readonly DependencyProperty IconNameProperty =
DependencyProperty.Register("IconName", typeof(Geometry), typeof(Icon),
new PropertyMetadata(Geometry.Empty));
public Geometry IconName
{
get { return (Geometry)GetValue(IconNameProperty); }
set { SetValue(IconNameProperty, value); }
}
static Icon()
{
DefaultStyleKeyProperty.OverrideMetadata(typeof(Icon),
new FrameworkPropertyMetadata(typeof(Icon)));
}
}
MainWindow.xaml
<uiLib:Icon IconHeight="100"
IconColor="White"
IconName="Icon_Close"/>
If you instead use a Path you can do everything your control appears to be doing with the exception of setting the data with your path.
A Path can stretch so there's no point in the viewbox.
You don't need to put a path in a canvas either, it inherits from frameworkelement.
Here's an example path.
<Path Data="{StaticResource Musketeer}"
Height="18"
Stretch="Uniform"
Fill="Black"
Margin="4,0,0,0" />
Make the height 30 and the musketeer shaped geometry would be 30 px high and retain the proportions of the geometry.
All you need is a dependency property with an onChange handler that finds that geometry out resources.
Path is sealed so you can't extend it, but you could add an attached dependency property like this:
public class Attacher : DependencyObject
{
public static readonly DependencyProperty
GeometryProperty = DependencyProperty.RegisterAttached(
"Geometry", typeof(string), typeof(Attacher), new PropertyMetadata("", GeometryChanged));
private static void GeometryChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
{
var path = d as Path;
if (path == null)
{
return;
}
var geom = path.TryFindResource(e.NewValue.ToString()) as Geometry;
if (geom is Geometry)
{
path.Data = geom;
}
}
public static string GetGeometry(DependencyObject d)
{
return (string)d.GetValue(GeometryProperty);
}
public static void SetGeometry(DependencyObject d, string value)
{
d.SetValue(GeometryProperty, value);
}
}
You can probably think of a better name than attacher.
The way that works is it attaches the dependency property to the path.
Usage:
<Path Fill="Red"
Stretch="Fill"
local:Attacher.Geometry="BeeIcon"
/>
local is an xmlns reference to the clr namespace the attacher is in.
My beeicon is:
<Geometry x:Key="BeeIcon">
M15.551045,25.144995L16.748029,25.144995 16.249038,28.637C16.249038,28.637,15.651051,25.543997,15.551045,25.144995z M21.237988,21.152998L21.437999,21.152998C20.340014,23.049002 18.345033,24.247 16.150041,24.247 13.95404,24.247 11.959059,23.049002 10.861073,21.252997L10.96108,21.252997C15.351034,22.550002,18.943021,21.952002,21.237988,21.152998z M21.337995,14.967002L21.437999,15.067001C21.936988,15.965002,22.235997,16.962996,22.235997,18.160002L22.235997,18.658995 22.036994,18.759001C17.746037,20.653998,12.458048,19.556998,10.16308,18.858L10.063075,18.858 10.063075,18.759001 10.063075,18.160002C10.063075,17.162001,10.263086,16.164,10.761068,15.365997L10.861073,15.365997C16.150041,17.560996,20.141011,15.665,21.337995,14.967002z M16.150041,12.072998C17.746037,12.072998,19.243007,12.671997,20.340014,13.769996L20.44002,13.869003 20.340014,13.869003C17.247018,15.365997 13.356052,14.568 11.560075,14.069 12.657052,12.772003 14.353055,12.072998 16.150041,12.072998z M27.523957,8.3820033C28.821952,8.3820033 29.918929,8.6809992 30.517924,9.3789973 32.91293,12.072998 32.712918,16.663001 27.623963,15.566001 22.534976,14.468002 18.345033,11.674003 17.646031,10.875999L19.043027,10.376998C19.143001,10.376998,23.93197,8.3820033,27.523957,8.3820033z M4.5751051,8.3820033C8.0670862,8.3820033,12.957068,10.376998,12.957068,10.376998L14.353055,10.875999C13.655062,11.674003 9.4640798,14.468002 4.3751249,15.566001 -0.71285403,16.663001 -0.91286493,12.072998 1.4821384,9.3789973 2.1801321,8.5810008 3.2781166,8.3820033 4.5751051,8.3820033z M16.150041,3.2929987C18.145022,3.292999 19.64202,4.8889994 19.64202,6.7850031 19.64202,8.7809977 18.045016,10.277 16.150041,10.277 14.154051,10.277 12.657052,8.6809992 12.657052,6.7850031 12.557047,4.8889994 14.154051,3.292999 16.150041,3.2929987z M12.757057,1.0979993L13.056066,1.5960004 12.957068,1.5960004C12.857062,1.5960005 12.657052,1.4970015 12.557047,1.3970029 12.557047,1.2969969 12.657052,1.0979994 12.757057,1.0979993z M19.542016,9.6861186E-11C19.741996,-6.1625087E-08 19.840995,-6.1625087E-08 20.041005,0.099998488 20.839003,0.399002 21.237988,1.2969969 20.839003,2.0950009 20.44002,3.093002 19.342006,3.5920026 18.345033,3.1930003L18.943021,1.996002 19.043027,1.996002C19.44201,2.0950009 19.840995,1.8960036 19.940999,1.4970014 20.041005,1.1969984 19.940999,0.79800405 19.64202,0.69799812 19.342006,0.59899892 19.143001,0.69799794 18.943021,0.99800076 18.856397,1.1721237 18.921365,1.3470176 19.072932,1.4550116L19.129043,1.4886372 19.44201,1.0979993C19.542016,1.1969984 19.64202,1.2969969 19.542016,1.3970029 19.44201,1.4970015 19.342006,1.5960005 19.143001,1.5960004L19.103326,1.5960004 18.943021,1.996002C18.444032,1.7959975 18.245027,1.1969984 18.444032,0.69799812 18.644011,0.29900353 19.043027,-6.1625087E-08 19.542016,9.6861186E-11z M12.757057,9.6861186E-11C13.256047,-6.1625087E-08 13.655062,0.29900353 13.855041,0.79800428 14.054046,1.2969969 13.855041,1.8960036 13.356052,2.0950009L13.056066,1.5960004C13.256047,1.4970015 13.356052,1.2969969 13.256047,1.0979993 13.156041,0.79800405 12.857062,0.69799794 12.557047,0.79800428 12.258068,0.89800252 12.059064,1.2969969 12.258068,1.5960004 12.458048,1.996002 12.857062,2.1949994 13.156041,2.0950009L13.256047,2.0950009 13.855041,3.1930003C12.857062,3.5920026 11.759047,3.093002 11.360063,2.0950009 11.061054,1.2969969 11.460069,0.399002 12.158062,0.099998488 12.358073,-6.1625087E-08 12.557047,-6.1625087E-08 12.757057,9.6861186E-11z
</Geometry>
But it also works fine with your style of defining streamgeometries.
<Path Fill="Red"
Stretch="Uniform"
Height="32"
local:Attacher.Geometry="Icon_Close"
/>
You can then bind fill, stroke, height, stretch etc and a string for the geometry.
I am trying to convert a System.Windows.Shapes.Shape object into a System.Windows.Media.Geometry object.
With the Geometry object, I am going to render it multiple times with a custom graph control depending on a set of data points. This requires that each instance of the Geometry object has a unique TranslateTransform object.
Now, I am approaching the issue in two different ways, but neither seems to be working correctly. My custom control uses the following code in order to draw the geometry:
//Create an instance of the geometry the shape uses.
Geometry geo = DataPointShape.RenderedGeometry.Clone();
//Apply transformation.
TranslateTransform translation = new TranslateTransform(dataPoint.X, dataPoint.Y);
geo.Transform = translation;
//Create pen and draw geometry.
Pen shapePen = new Pen(DataPointShape.Stroke, DataPointShape.StrokeThickness);
dc.DrawGeometry(DataPointShape.Fill, shapePen, geo);
I have also tried the following alternate code:
//Create an instance of the geometry the shape uses.
Geometry geo = DataPointShape.RenderedGeometry;
//Apply transformation.
TranslateTransform translation = new TranslateTransform(dataPoint.X, dataPoint.Y);
dc.PushTransform(translation);
//Create pen and draw geometry.
Pen shapePen = new Pen(DataPointShape.Stroke, DataPointShape.StrokeThickness);
dc.DrawGeometry(DataPointShape.Fill, shapePen, geo);
dc.Pop(); //Undo translation.
The difference is that the second snippet doesn't clone or modify the Shape.RenderedGeometry property.
Oddly enough, I occasionally can view the geometry used for the data points in the WPF designer. However, the behavior is inconsistent and difficult to figure out how to make the geometry always appear. Also, when I execute my application, the data points never appear with the specified geometry.
EDIT: I have figured out how to generate the appearance of the geometry. But this only works in design-mode. Execute these steps:
Rebuild project.
Go to MainWindow.xaml and click in the custom shape object so that the shape's properties load into Visual Studio's property window. Wait until the property window renders what the shape looks like.
Modify the data points collection or properties to see the geometry rendered properly.
Here is what I want the control to ultimately look like for now:
How can I convert a Shape object to a Geometry object for rendering multiple times?
Your help is tremendously appreciated!
Let me give the full context of my problem, as well as all necessary code to understanding how my control is set up. Hopefully, this might indicate what problems exist in my method of converting the Shape object to a Geometry object.
MainWindow.xaml
<Window x:Class="CustomControls.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:CustomControls">
<Grid>
<local:LineGraph>
<local:LineGraph.DataPointShape>
<Ellipse Width="10" Height="10" Fill="Red" Stroke="Black" StrokeThickness="1" />
</local:LineGraph.DataPointShape>
<local:LineGraph.DataPoints>
<local:DataPoint X="10" Y="10"/>
<local:DataPoint X="20" Y="20"/>
<local:DataPoint X="30" Y="30"/>
<local:DataPoint X="40" Y="40"/>
</local:LineGraph.DataPoints>
</local:LineGraph>
</Grid>
DataPoint.cs
This class just has two DependencyProperties (X & Y) and it gives a notification when any of those properties are changed. This notification is used to trigger a re-render via UIElement.InvalidateVisual().
public class DataPoint : DependencyObject, INotifyPropertyChanged
{
public static readonly DependencyProperty XProperty = DependencyProperty.Register("XProperty", typeof(double), typeof(DataPoint), new FrameworkPropertyMetadata(0.0d, DataPoint_PropertyChanged));
public static readonly DependencyProperty YProperty = DependencyProperty.Register("YProperty", typeof(double), typeof(DataPoint), new FrameworkPropertyMetadata(0.0d, DataPoint_PropertyChanged));
private static void DataPoint_PropertyChanged(DependencyObject sender, DependencyPropertyChangedEventArgs e)
{
DataPoint dp = (DataPoint)sender;
dp.RaisePropertyChanged(e.Property.Name);
}
public event PropertyChangedEventHandler PropertyChanged;
protected void RaisePropertyChanged(string name)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(name));
}
}
public double X
{
get { return (double)GetValue(XProperty); }
set { SetValue(XProperty, (double)value); }
}
public double Y
{
get { return (double)GetValue(YProperty); }
set { SetValue(YProperty, (double)value); }
}
}
LineGraph.cs
This is the control. It contains the collection of data points and provides mechanisms for re-rendering the data points (useful for WPF designer). Of particular importance is the logic posted above which is inside of the UIElement.OnRender() method.
public class LineGraph : FrameworkElement
{
public static readonly DependencyProperty DataPointShapeProperty = DependencyProperty.Register("DataPointShapeProperty", typeof(Shape), typeof(LineGraph), new FrameworkPropertyMetadata(default(Shape), FrameworkPropertyMetadataOptions.AffectsRender, DataPointShapeChanged));
public static readonly DependencyProperty DataPointsProperty = DependencyProperty.Register("DataPointsProperty", typeof(ObservableCollection<DataPoint>), typeof(LineGraph), new FrameworkPropertyMetadata(default(ObservableCollection<DataPoint>), FrameworkPropertyMetadataOptions.AffectsRender, DataPointsChanged));
private static void DataPointShapeChanged(DependencyObject sender, DependencyPropertyChangedEventArgs e)
{
LineGraph g = (LineGraph)sender;
g.InvalidateVisual();
}
private static void DataPointsChanged(DependencyObject sender, DependencyPropertyChangedEventArgs e)
{ //Collection referenced set or unset.
LineGraph g = (LineGraph)sender;
INotifyCollectionChanged oldValue = e.OldValue as INotifyCollectionChanged;
INotifyCollectionChanged newValue = e.NewValue as INotifyCollectionChanged;
if (oldValue != null)
oldValue.CollectionChanged -= g.DataPoints_CollectionChanged;
if (newValue != null)
newValue.CollectionChanged += g.DataPoints_CollectionChanged;
//Update the point visuals.
g.InvalidateVisual();
}
private void DataPoints_CollectionChanged(object sender, NotifyCollectionChangedEventArgs e)
{ //Collection changed (added/removed from).
if (e.OldItems != null)
foreach (INotifyPropertyChanged n in e.OldItems)
{
n.PropertyChanged -= DataPoint_PropertyChanged;
}
if (e.NewItems != null)
foreach (INotifyPropertyChanged n in e.NewItems)
{
n.PropertyChanged += DataPoint_PropertyChanged;
}
InvalidateVisual();
}
private void DataPoint_PropertyChanged(object sender, PropertyChangedEventArgs e)
{
//Re-render the LineGraph when a DataPoint has a property that changes.
InvalidateVisual();
}
public Shape DataPointShape
{
get { return (Shape)GetValue(DataPointShapeProperty); }
set { SetValue(DataPointShapeProperty, (Shape)value); }
}
public ObservableCollection<DataPoint> DataPoints
{
get { return (ObservableCollection<DataPoint>)GetValue(DataPointsProperty); }
set { SetValue(DataPointsProperty, (ObservableCollection<DataPoint>)value); }
}
public LineGraph()
{ //Provide instance-specific value for data point collection instead of a shared static instance.
SetCurrentValue(DataPointsProperty, new ObservableCollection<DataPoint>());
}
protected override void OnRender(DrawingContext dc)
{
if (DataPointShape != null)
{
Pen shapePen = new Pen(DataPointShape.Stroke, DataPointShape.StrokeThickness);
foreach (DataPoint dp in DataPoints)
{
Geometry geo = DataPointShape.RenderedGeometry.Clone();
TranslateTransform translation = new TranslateTransform(dp.X, dp.Y);
geo.Transform = translation;
dc.DrawGeometry(DataPointShape.Fill, shapePen, geo);
}
}
}
}
EDIT 2:In response to this answer by Peter Duniho, I would like to provide the alternate method to lying to Visual Studio in creating a custom control. For creating the custom control execute these steps:
Create folder in root of project named Themes
Create resource dictionary in Themes folder named Generic.xaml
Create a style in the resource dictionary for the control.
Apply the style from the control's C# code.
Generic.xamlHere is an example of for the SimpleGraph described by Peter.
<ResourceDictionary
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:CustomControls">
<Style TargetType="local:SimpleGraph" BasedOn="{StaticResource {x:Type ItemsControl}}">
<Style.Resources>
<EllipseGeometry x:Key="defaultGraphGeometry" Center="5,5" RadiusX="5" RadiusY="5"/>
</Style.Resources>
<Style.Setters>
<Setter Property="ItemsPanel">
<Setter.Value>
<ItemsPanelTemplate>
<Canvas IsItemsHost="True"/>
</ItemsPanelTemplate>
</Setter.Value>
</Setter>
<Setter Property="ItemTemplate">
<Setter.Value>
<DataTemplate DataType="{x:Type local:DataPoint}">
<Path Fill="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type local:SimpleGraph}}, Path=DataPointFill}"
Stroke="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type local:SimpleGraph}}, Path=DataPointStroke}"
StrokeThickness="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type local:SimpleGraph}}, Path=DataPointStrokeThickness}"
Data="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type local:SimpleGraph}}, Path=DataPointGeometry}">
<Path.RenderTransform>
<TranslateTransform X="{Binding X}" Y="{Binding Y}"/>
</Path.RenderTransform>
</Path>
</DataTemplate>
</Setter.Value>
</Setter>
</Style.Setters>
</Style>
</ResourceDictionary>
Lastly, apply the style like so in the SimpleGraph constructor:
public SimpleGraph()
{
DefaultStyleKey = typeof(SimpleGraph);
DataPointGeometry = (Geometry)FindResource("defaultGraphGeometry");
}
I think that you are probably not approaching this in the best way. Based on the code you posted, it seems that you are trying to do manually things that WPF is reasonably good at handling automatically.
The main tricky part (at least for me…I'm hardly a WPF expert) is that you appear to want to use an actual Shape object as the template for your graph's data point graphics, and I'm not entirely sure of the best way to allow for that template to be replaced programmatically or declaratively without exposing the underlying transformation mechanic that controls the positioning on the graph.
So here's an example that ignores that particular aspect (I will comment on alternatives below), but which I believe otherwise serves your precise needs.
First, I create a custom ItemsControl class (in Visual Studio, I do this by lying and telling VS I want to add a UserControl, which gets me a XAML-based item in the project…I immediately replace "UserControl" with "ItemsControl" in both the .xaml and .xaml.cs files):
XAML:
<ItemsControl x:Class="TestSO28332278SimpleGraphControl.SimpleGraph"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:TestSO28332278SimpleGraphControl"
mc:Ignorable="d"
x:Name="root"
d:DesignHeight="300" d:DesignWidth="300">
<ItemsControl.Resources>
<EllipseGeometry x:Key="defaultGraphGeometry" Center="5,5" RadiusX="5" RadiusY="5" />
</ItemsControl.Resources>
<ItemsControl.ItemsPanel>
<ItemsPanelTemplate>
<Canvas IsItemsHost="True" />
</ItemsPanelTemplate>
</ItemsControl.ItemsPanel>
<ItemsControl.ItemTemplate>
<DataTemplate DataType="{x:Type local:DataPoint}">
<Path Data="{Binding ElementName=root, Path=DataPointGeometry}"
Fill="Red" Stroke="Black" StrokeThickness="1">
<Path.RenderTransform>
<TranslateTransform X="{Binding X}" Y="{Binding Y}"/>
</Path.RenderTransform>
</Path>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
C#:
public partial class SimpleGraph : ItemsControl
{
public Geometry DataPointGeometry
{
get { return (Geometry)GetValue(DataPointShapeProperty); }
set { SetValue(DataPointShapeProperty, value); }
}
public static DependencyProperty DataPointShapeProperty = DependencyProperty.Register(
"DataPointGeometry", typeof(Geometry), typeof(SimpleGraph));
public SimpleGraph()
{
InitializeComponent();
DataPointGeometry = (Geometry)FindResource("defaultGraphGeometry");
}
}
The key here is that I have an ItemsControl class with a default ItemTemplate that has a single Path object. That object's geometry is bound to the controls DataPointGeometry property, and its RenderTransform is bound to the data item's X and Y values as offsets for a translation transform.
A simple Canvas is used for the ItemsPanel, as I just need a place to draw things, without any other layout features. Finally, there is a resource defining a default geometry to use, in case the caller doesn't provide one.
And about that caller…
Here is a simple example of how one might use the above:
<Window x:Class="TestSO28332278SimpleGraphControl.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:TestSO28332278SimpleGraphControl"
Title="MainWindow" Height="350" Width="525">
<Window.Resources>
<PathGeometry x:Key="dataPointGeometry"
Figures="M 0.5000,0.0000
L 0.6176,0.3382
0.9755,0.3455
0.6902,0.5618
0.7939,0.9045
0.5000,0.7000
0.2061,0.9045
0.3098,0.5618
0.0245,0.3455
0.3824,0.3382 Z">
<PathGeometry.Transform>
<ScaleTransform ScaleX="20" ScaleY="20" />
</PathGeometry.Transform>
</PathGeometry>
</Window.Resources>
<Grid>
<Border Margin="3" BorderBrush="Black" BorderThickness="1">
<local:SimpleGraph Width="450" Height="300" DataPointGeometry="{StaticResource dataPointGeometry}">
<local:SimpleGraph.Items>
<local:DataPoint X="10" Y="10" />
<local:DataPoint X="25" Y="25" />
<local:DataPoint X="40" Y="40" />
<local:DataPoint X="55" Y="55" />
</local:SimpleGraph.Items>
</local:SimpleGraph>
</Border>
</Grid>
</Window>
In the above, the only truly interesting thing is that I declare a PathGeometry resource, and then bind that resource to the control's DataPointGeometry property. This allows the program to provide a custom geometry for the graph.
WPF handles the rest through implicit data binding and templating. If the values of any of the DataPoint objects change, or the data collection itself is modified, the graph will be updated automatically.
Here's what it looks like:
I will note that the above example only allows you to specify the geometry. The other shape attributes are hard-coded in the data template. This seems slightly different from what you asked to do. But note that you have a few alternatives here that should address your need without requiring the reintroduction of all the extra manual-binding/updating code in your example:
Simply add other properties, bound to the template Path object in a fashion similar to the DataPointGeometry property. E.g. DataPointFill, DataPointStroke, etc.
Go ahead and allow the user to specify a Shape object, and then use the properties of that object to populate specific properties bound to the properties of the template object. This is mainly a convenience to the caller; if anything, it's a bit of added complication in the graph control itself.
Go whole-hog and allow the user to specify a Shape object, which you then convert to a template by using XamlWriter to create some XAML for the object, add the necessary Transform element to the XAML and wrap it in a DataTemplate declaration (e.g. by loading the XAML as an in-memory DOM to modify the XAML), and then using XamlReader to then load the XAML as a template which you can then assign to the ItemTemplate property.
Option #3 seems the most complicated to me. So complicated in fact that I did not bother to prototype an example using it…I did a little research and it seems to me that it should work, but I admit that I did not verify for myself that it does. But it would certainly be the gold standard in terms of absolute flexibility for the caller.
I have been stumped with trying to convert the following code into pure c#. This XAML code is from Cavanaghs blog on how to make rounded corners on anything. The code works but I need to convert it to c# as i need it to be dynamic in some cases. If you could help that would be great.
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType='{x:Type ListViewItem}'>
<Grid>
<Border CornerRadius="15" Name="mask" Background="White"/>
<StackPanel Background="Beige">
<StackPanel.OpacityMask>
<VisualBrush Visual="{Binding ElementName=mask}"/>
</StackPanel.OpacityMask>
<GridViewRowPresenter Content="{TemplateBinding Content}" Columns="{TemplateBinding GridView.ColumnCollection}"/>
<TextBlock Background="LightBlue" Text="{Binding News}" />
</StackPanel>
</Grid>
</ControlTemplate>
</Setter.Value>
So far I have the following but I am getting errors.
FrameworkElementFactory border = new FrameworkElementFactory(typeof(Border));
border.SetValue(Border.BackgroundProperty, Brushes.White);
border.SetValue(Border.CornerRadiusProperty, new CornerRadius(8, 8, 8, 8));
border.SetValue(Border.NameProperty, "roundedMask");
As far as I can tell I cant make the VisualBrush as a FrameworkElementFactory (crashes), but if i declare it as a regular element VisualBrush i cant pass border in as a Visual since its a FrameworkElementFactory.
Simply i am getting lost, any help would be appreciated.
Thanks for any help
You don't actually have to convert this into C# to apply it dynamically. If you add it to your application resources, within your App.xaml file as follows:
<Application.Resources>
<ControlTemplate TargetType='{x:Type ListViewItem}' x:Key="MyListViewItemTemplate">
<Grid>
<Border CornerRadius="15" Name="mask" Background="White"/>
<StackPanel Background="Beige">
<StackPanel.OpacityMask>
<VisualBrush Visual="{Binding ElementName=mask}"/>
</StackPanel.OpacityMask>
<GridViewRowPresenter Content="{TemplateBinding Content}" Columns="{TemplateBinding GridView.ColumnCollection}"/>
<TextBlock Background="LightBlue" Text="{Binding News}" />
</StackPanel>
</Grid>
</ControlTemplate>
</Application.Resources>
Note the x:Key attribute which keys this item.
You can then look it up anywhere in your code ...
ControlTemplate template = this.Findresource("MyListViewItemTemplate") as ControlTemplate
You can then apply it as and when you need it!
You do not want to know this. Seriously, you don't, it's a nightmare.
Edit: If i did not make any mistake this is the translation of your code...
Setter setter = new Setter();
setter.Property = ListViewItem.TemplateProperty;
ControlTemplate template = new ControlTemplate(typeof(ListViewItem));
var grid = new FrameworkElementFactory(typeof(Grid));
var border = new FrameworkElementFactory(typeof(Border));
border.SetValue(Border.BackgroundProperty, Brushes.White);
border.SetValue(Border.NameProperty, "mask");
border.SetValue(Border.CornerRadiusProperty, new CornerRadius(15));
grid.AppendChild(border);
var stackPanel = new FrameworkElementFactory(typeof(StackPanel));
stackPanel.SetValue(StackPanel.BackgroundProperty, Brushes.Beige);
var visualBrush = new FrameworkElementFactory(typeof(VisualBrush));
visualBrush.SetBinding(VisualBrush.VisualProperty, new Binding() { ElementName = "mask" });
stackPanel.SetValue(StackPanel.OpacityMaskProperty, visualBrush);
var gridViewRowPresenter = new FrameworkElementFactory(typeof(GridViewRowPresenter));
gridViewRowPresenter.SetValue(GridViewRowPresenter.ContentProperty, new TemplateBindingExtension(GridViewRowPresenter.ContentProperty));
gridViewRowPresenter.SetValue(GridViewRowPresenter.ColumnsProperty, new TemplateBindingExtension(GridView.ColumnCollectionProperty));
stackPanel.AppendChild(gridViewRowPresenter);
var textBlock = new FrameworkElementFactory(typeof(TextBlock));
textBlock.SetValue(TextBlock.BackgroundProperty, Brushes.LightBlue);
textBlock.SetBinding(TextBlock.TextProperty, new Binding("News"));
stackPanel.AppendChild(textBlock);
grid.AppendChild(stackPanel);
template.VisualTree = grid;
setter.Value = template;
Edit: There is still a bug left, the VisualBrush cannot be created like that, the rest seems to work.
I wanna show an image in WPF that is created by a process,
e.g : we have a method that is named createWPFImage()
Image createWPFImage() { ... }
So, the output of createWPFImage() is an Image.
In the XAML code, we have a something like below :
<StackPanel.ToolTip>
<StackPanel Orientation="Horizontal">
<Image Width="64" Height="64" Margin="0 2 4 0" />
<TextBlock Text="{Binding Path=Description}" VerticalAlignment="Center" />
</StackPanel>
</StackPanel.ToolTip>
Now, How can I bind the output of createWPFImage() to the Image in XAML code ?
I would be appreciate if you guide me.
Say you have class "MyClass" with method "CreateWpfImage" (see example below).
In your XAML you can create MyClass, and then call CreateWpfImage, using ObjectDataProvider in a Resources section (See Bea Stollnitz blog article ObjectDataProvider).
XAML
<Window x:Class="MyApplicationNamespace.Window1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:MyApplicationNamespace="clr-namespace:MyApplicationNamespace"
Title="Window1" Height="300" Width="300">
<Window.Resources>
<ObjectDataProvider ObjectType="{x:Type MyApplicationNamespace:MyClass}" x:Key="MyClass" />
<ObjectDataProvider ObjectInstance="{StaticResource MyClass}" MethodName="CreateWpfImpage" x:Key="MyImage" />
</Window.Resources>
<StackPanel>
<Image Source="{Binding Source={StaticResource MyImage}, Path=Source}"/>
</StackPanel>
Example MyClass code to create an image for the XAML to use -
using System;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Media;
namespace MyApplicationNamespace
{
public class MyClass
{
public Image CreateWpfImpage()
{
GeometryDrawing aGeometryDrawing = new GeometryDrawing();
aGeometryDrawing.Geometry = new EllipseGeometry(new Point(50, 50), 50, 50);
aGeometryDrawing.Pen = new Pen(Brushes.Red, 10);
aGeometryDrawing.Brush = Brushes.Blue;
DrawingImage geometryImage = new DrawingImage(aGeometryDrawing);
Image anImage = new Image();
anImage.Source = geometryImage;
return anImage;
}
}
}
If you have a path to your image and just want to be able to change the image on the fly, then bind to a dependency property of type string and in your method, set the value of the dependency property.
<Image Source="{Binding MyImagePath}" />
public static readonly DependencyProperty MyImagePathProperty = DependencyProperty.Register("MyImagePath", typeof(string), typeof(ClassName), new PropertyMetadata("pack://application:,,,/YourAssembly;component//icons/icon1.png"));
public string MyImagePath
{
get { return (string)GetValue(MyImagePathhProperty); }
set { SetValue(MyImagePathProperty, value); }
}