Hello I want to know how can I parse this simple XML file content in C#. I can have multiple "in" elements, and from those I want to use date, min, max and state child values.
<out>
<in>
<id>16769</id>
<date>29-10-2010</date>
<now>12</now>
<min>12</min>
<max>23</max>
<state>2</state>
<description>enter text</description>
</in>
<in>
<id>7655</id>
<date>12-10-2010</date>
<now>1</now>
<min>1</min>
<max>2</max>
<state>0</state>
<description>enter text</description>
</in>
</out>
The System.XML namespace has all sorts of tools for parsing, reading, and writing XML data. By the way, your XML isn't well-formed; you've got two <out> elements, but only one </out> element.
Linq to xml is also helpful for parsing xml -
http://msdn.microsoft.com/en-us/library/bb387098.aspx
Also -
http://msdn.microsoft.com/library/bb308960.aspx
You need System.XML, starting with XmlDocument.Load(filename).
Once you have the XmlDocument loaded, you can drill down into it as needed using the built-in .Net XML object model, starting from XmlDocument level. You can walk the tree recursively in a pretty intuitive way, capturing what you want from each XmlNode as you go.
Alternatively (and preferably) you can quickly locate all XmlNodes in your XmlDocument that match certain conditions using XPath - examples here. An example of usage in C# is XmlNode.SelectNodes.
using System;
using System.IO;
using System.Xml;
public class Sample {
public static void Main() {
XmlDocument doc = new XmlDocument();
doc.Load("booksort.xml");
XmlNodeList nodeList;
XmlNode root = doc.DocumentElement;
nodeList=root.SelectNodes("descendant::book[author/last-name='Austen']");
//Change the price on the books.
foreach (XmlNode book in nodeList)
{
book.LastChild.InnerText="15.95";
}
Console.WriteLine("Display the modified XML document....");
doc.Save(Console.Out);
}
}
Examples can be found here http://www.c-sharpcorner.com/uploadfile/mahesh/readwritexmltutmellli2111282005041517am/readwritexmltutmellli21.aspx
This might be beyond what you want to do, but worth mentioning...
I hate parsing XML. Seriously, I almost refuse to do it, especially since .NET can do it for me. What I would do is create an "In" object that has the properties above. You probably have one already, or it would take 60 seconds to create. You'll also need a List of In objects called "Out".
Then just deserialze the XML into the objects. This takes just a few lines of code. Here is an example. BTW, this makes changing and re-saving the data just as easy.
How to serialize/deserialize
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Is there a simple method of parsing XML files in C#? If so, what?
It's very simple. I know these are standard methods, but you can create your own library to deal with that much better.
Here are some examples:
XmlDocument xmlDoc= new XmlDocument(); // Create an XML document object
xmlDoc.Load("yourXMLFile.xml"); // Load the XML document from the specified file
// Get elements
XmlNodeList girlAddress = xmlDoc.GetElementsByTagName("gAddress");
XmlNodeList girlAge = xmlDoc.GetElementsByTagName("gAge");
XmlNodeList girlCellPhoneNumber = xmlDoc.GetElementsByTagName("gPhone");
// Display the results
Console.WriteLine("Address: " + girlAddress[0].InnerText);
Console.WriteLine("Age: " + girlAge[0].InnerText);
Console.WriteLine("Phone Number: " + girlCellPhoneNumber[0].InnerText);
Also, there are some other methods to work with. For example, here. And I think there is no one best method to do this; you always need to choose it by yourself, what is most suitable for you.
I'd use LINQ to XML if you're in .NET 3.5 or higher.
Use a good XSD Schema to create a set of classes with xsd.exe and use an XmlSerializer to create a object tree out of your XML and vice versa. If you have few restrictions on your model, you could even try to create a direct mapping between you model classes and the XML with the Xml*Attributes.
There is an introductory article about XML Serialisation on MSDN.
Performance tip: Constructing an XmlSerializer is expensive. Keep a reference to your XmlSerializer instance if you intend to parse/write multiple XML files.
If you're processing a large amount of data (many megabytes) then you want to be using XmlReader to stream parse the XML.
Anything else (XPathNavigator, XElement, XmlDocument and even XmlSerializer if you keep the full generated object graph) will result in high memory usage and also a very slow load time.
Of course, if you need all the data in memory anyway, then you may not have much choice.
Use XmlTextReader, XmlReader, XmlNodeReader and the System.Xml.XPath namespace. And (XPathNavigator, XPathDocument, XPathExpression, XPathnodeIterator).
Usually XPath makes reading XML easier, which is what you might be looking for.
I have just recently been required to work on an application which involved the parsing of an XML document and I agree with Jon Galloway that the LINQ to XML based approach is, in my opinion, the best. I did however have to dig a little to find usable examples, so without further ado, here are a few!
Any comments welcome as this code works but may not be perfect and I would like to learn more about parsing XML for this project!
public void ParseXML(string filePath)
{
// create document instance using XML file path
XDocument doc = XDocument.Load(filePath);
// get the namespace to that within of the XML (xmlns="...")
XElement root = doc.Root;
XNamespace ns = root.GetDefaultNamespace();
// obtain a list of elements with specific tag
IEnumerable<XElement> elements = from c in doc.Descendants(ns + "exampleTagName") select c;
// obtain a single element with specific tag (first instance), useful if only expecting one instance of the tag in the target doc
XElement element = (from c in doc.Descendants(ns + "exampleTagName" select c).First();
// obtain an element from within an element, same as from doc
XElement embeddedElement = (from c in element.Descendants(ns + "exampleEmbeddedTagName" select c).First();
// obtain an attribute from an element
XAttribute attribute = element.Attribute("exampleAttributeName");
}
With these functions I was able to parse any element and any attribute from an XML file no problem at all!
In Addition you can use XPath selector in the following way (easy way to select specific nodes):
XmlDocument doc = new XmlDocument();
doc.Load("test.xml");
var found = doc.DocumentElement.SelectNodes("//book[#title='Barry Poter']"); // select all Book elements in whole dom, with attribute title with value 'Barry Poter'
// Retrieve your data here or change XML here:
foreach (XmlNode book in nodeList)
{
book.InnerText="The story began as it was...";
}
Console.WriteLine("Display XML:");
doc.Save(Console.Out);
the documentation
If you're using .NET 2.0, try XmlReader and its subclasses XmlTextReader, and XmlValidatingReader. They provide a fast, lightweight (memory usage, etc.), forward-only way to parse an XML file.
If you need XPath capabilities, try the XPathNavigator. If you need the entire document in memory try XmlDocument.
I'm not sure whether "best practice for parsing XML" exists. There are numerous technologies suited for different situations. Which way to use depends on the concrete scenario.
You can go with LINQ to XML, XmlReader, XPathNavigator or even regular expressions. If you elaborate your needs, I can try to give some suggestions.
You can parse the XML using this library System.Xml.Linq. Below is the sample code I used to parse a XML file
public CatSubCatList GenerateCategoryListFromProductFeedXML()
{
string path = System.Web.HttpContext.Current.Server.MapPath(_xmlFilePath);
XDocument xDoc = XDocument.Load(path);
XElement xElement = XElement.Parse(xDoc.ToString());
List<Category> lstCategory = xElement.Elements("Product").Select(d => new Category
{
Code = Convert.ToString(d.Element("CategoryCode").Value),
CategoryPath = d.Element("CategoryPath").Value,
Name = GetCateOrSubCategory(d.Element("CategoryPath").Value, 0), // Category
SubCategoryName = GetCateOrSubCategory(d.Element("CategoryPath").Value, 1) // Sub Category
}).GroupBy(x => new { x.Code, x.SubCategoryName }).Select(x => x.First()).ToList();
CatSubCatList catSubCatList = GetFinalCategoryListFromXML(lstCategory);
return catSubCatList;
}
You can use ExtendedXmlSerializer to serialize and deserialize.
Instalation
You can install ExtendedXmlSerializer from nuget or run the following command:
Install-Package ExtendedXmlSerializer
Serialization:
ExtendedXmlSerializer serializer = new ExtendedXmlSerializer();
var obj = new Message();
var xml = serializer.Serialize(obj);
Deserialization
var obj2 = serializer.Deserialize<Message>(xml);
Standard XML Serializer in .NET is very limited.
Does not support serialization of class with circular reference or class with interface property,
Does not support Dictionaries,
There is no mechanism for reading the old version of XML,
If you want create custom serializer, your class must inherit from IXmlSerializable. This means that your class will not be a POCO class,
Does not support IoC.
ExtendedXmlSerializer can do this and much more.
ExtendedXmlSerializer support .NET 4.5 or higher and .NET Core. You can integrate it with WebApi and AspCore.
You can use XmlDocument and for manipulating or retrieve data from attributes you can Linq to XML classes.
I have several XML documents, all of which have the same structure (element names, attribute names and hierarchy).
However, some of the elements and attribute have custom namespaces in each XML document which are not known at design time. They change, don't ask...
How can I deal with this when traversing the documents using a single set of XPath?
Should I remove all the namespaces before processing?
Can I automatically register all namespaces with an XmlNamespaceManager?
Any thoughts?
Update: some examples (with namespace declarations omitted for clarity):
<root>
<child attr="val" />
</root>
<root>
<x:child attr="val" />
</root>
<root>
<y:child z:attr="val" />
</root>
Thanks
Suppose you have following xml:
<root xmlns="first">
<el1 xmlns="second">
<el2 xmlns="third">...
You can write you queries to ignore namespaces in the following way:
/*[local-name()='root']/*[local-name()='el1']/*[local-name()='el2']
etc.
Of course you can iterate over the whole document to get namespaces and load them into nsmanager. But in general case this will cause you to evaluate every node in the document. In this case it will be faster to just treat document as a tree of objects and don't use XPath.
I believe you'll find some good insight in this Stackoverflow thread
XPath + Namespace Driving me crazy
In my opinion you have either of two solutions:
1- If the set of all possible namespaces are know before hand, then you can register them all in a XmlNamespaceManager before you begin parsing
2- Use Xpath namespace-agnostic selectors
Of course you can always scrub the xml document from any inline namespaces and start your parsing on a clean unfiorm xml without namespace.. but honestly I don't see the gain in adding this overhead step.
Scott Hanselman has a nice article about extracting all of the XML Namespaces in an XML document. Presumably, when you get all of the XML Namespaces, you can just iterate over all of them and register them in your namespace manager.
You could try something like this to strip the namespaces:
//Implemented based on interface, not part of algorithm
public string RemoveAllNamespaces(string xmlDocument)
{
return RemoveAllNamespaces(XElement.Parse(xmlDocument)).ToString();
}
//Core recursion function
private XElement RemoveAllNamespaces(XElement xmlDocument)
{
if (!xmlDocument.HasElements)
{
XElement xElement = new XElement(xmlDocument.Name.LocalName);
xElement.Value = xmlDocument.Value;
return xElement;
}
return new XElement(xmlDocument.Name.LocalName, xmlDocument.Elements().Select(el => RemoveAllNamespaces(el)));
}
See Peter Stegnar's answer here for more details:
How to remove all namespaces from XML with C#?
You can also use direct node tests with wildcards, which will match any namespace (or lack thereof):
$your-document/*:root/*:child/#*:attr
Is it possible to get the open tag from a XmlNode with all attributes, namespace, etc?
eg.
<root xmlns="urn:..." rattr="a">
<child attr="1">test</child>
</root>
I would like to retrieve the entire opening tag, exactly as retrieved from the original XML document if possible, from the XmlNode and later the closing tag. Both as strings.
Basically XmlNode.OuterXml without the child nodes.
EDIT
To elaborate, XmlNode.OuterXml on a node that was created with the XML above would return the entire XML fragment, including child nodes as a single string.
XmlNode.InnerXml on that same fragment would return the child nodes but not the parent node, again as a single string.
But I need the opening tag for the XML fragment without the children nodes. And without building it using the XmlAttribute array, LocalName, Namespace, etc.
This is C# 3.5
Thanks
Is there some reason you can't simply say:
string s = n.OuterXml.Substring(0, n.OuterXml.IndexOf(">") + 1);
I think the simplest way would be to call XmlNode.CloneNode(false) which (according to the docs) will clone all the attributes but not child nodes. You can then use OuterXml - although that will give you the closing tag as well.
For example:
using System;
using System.Xml;
public class Test
{
static void Main()
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(#"<root xmlns='urn:xyz' rattr='a'>
<child attr='1'>test</child></root>");
XmlElement root = doc.DocumentElement;
XmlNode clone = root.CloneNode(false);
Console.WriteLine(clone.OuterXml);
}
}
Output:
<root xmlns="urn:xyz" rattr="a"></root>
Note that this may not be exactly as per the original XML document, in terms of the ordering of attributes etc. However, it will at least be equivalent.
How about:
xmlNode.OuterXML.Replace(xmlNode.InnerXML, String.Empty);
Poor man's solution :)
Say I need to find a particular node in an XML file, using C#.
<node attribute="my-target-attribute">
"my-target-attribute" is a variable input at runtime.
The node is in no particular place in the XML file, I basically just need to scan the entire XML hierarchy until I find a node with the matching attribute.
Is there any way I can pre-process the XML so finding the node will be faster? I need to keep the original XML structure in place. The XML file could potentially have 10,000 nodes.
You can certainly preprocess the XML to make lookups faster:
Dictionary<string, XmlElement> elementMap = new Dictionary<string, XmlElement>();
AddElementToMap(doc.DocumentElement, elementMap);
...
private void AddElementToMap(XmlElement elm, Dictionary<string, XmlElement> elementMap)
{
elementMap[elm.GetAttribute("attribute")] = elm;
foreach (XmlElement child in elm.SelectNodes("node"))
{
AddElementToMap(child, elementMap);
}
}
Once you've done this, a lookup is simple:
XmlElement elm = elementMap[value];
That code assumes that every element in your document is named "node", that every one has an attribute named "attribute", and that all of the attribute values are unique. The code's more complicated if any of those conditions are untrue, but not exceptionally so.
You could use xslt to transform the xml so that the node is in a known depth. Then when you select with XPath, you can select accordingly without using the // operator.
With VTD-XML (http://vtd-xml.sf.net) you can index the XML document into VTD+XML,
which eliminate the overhead of parsing
http://www.codeproject.com/KB/XML/VTD-XML-indexing.aspx
similar to another answer, you can use xpath similar like selectNodes("//[#attribute='my-target-attribute']"). // will search nodes in all level depths.
I'm having a problem getting the "xmlns" to appear first in the root attribute list.
Im getting this:
<myroot
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.someurl.com/ns/myroot http://www.someurl.com/xml/schemas/myschema.xsd"
xmlns="http://www.someurl.com/ns/myroot">
<sometag>somecontent</sometag>
</myroot>
And i want this:
<myroot
xmlns="http://www.someurl.com/ns/myroot"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.someurl.com/ns/myroot http://www.someurl.com/xml/schemas/myschema.xsd">
<sometag>somecontent</sometag>
</myroot>
My code looks like this:
XNamespace rt = "http://www.someurl.com/ns/myroot";
XNamespace xsi = "http://www.w3.org/2001/XMLSchema-instance";
var submissionNode = new XElement(XmlNameSpaces.rt + "myroot");
submissionNode.Add(new XAttribute(XNamespace.Xmlns + "xsi", "http://www.w3.org/2001/XMLSchema-instance"));
submissionNode.Add(new XAttribute(xsi + "schemaLocation", #"http://www.someurl.com/ns/myroot http://www.someurl.com/xml/schemas/myschema.xsd"););
What do i need to do different to change the order?
EDIT: I understand the order is not normally relavent, but its a requirement in this case.
IIRC, the order of attributes (in xml) is unimportant... so why change it? Is it causing an actual problem?
Would XmlWriter be an option for you?
Afaik, it gives you full control of the order of attributes and namespace declarations.
Attribute ordering is NOT specified in the XML document, and shouldn't be relied upon. It may be worth looking at the spec
You'll find that if you read a XML document into a DOM, and write it out, regardless of the platform/library, you can't (and shouldn't) rely on the attribute ordering. It's a common misconception, btw!
I have a customer with this very problem. This was a real pain in the s, so I wrote a workaround to solve this.
Please note this is not a beautiful solution, and this should be not encouraged, but works.
public static class MyKludgeXmlClass
{
public static XmlDocument CreateXmlDocumentWithOrderedNamespaces()
{
var xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?><MyRoot xmlns=\"http://www.example.com/schemas/1.0/VRSync\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xsi:schemaLocation=\"http://www.example.com/schemas/1.0/VRSync http://xml.example.com/vrsync.xsd\"></MyRoot>";
System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
doc.LoadXml(xml);
return doc;
}
}
With XmlDocument you can retrieve the root:
var xmlDoc = MyKludgeXmlClass.CreateXmlDocumentWithOrderedNamespaces();
XmlElement root = xmlDoc.DocumentElement;
And append children nodes using your favorite method.
Software that requires attributes to be in a specified order doesn't conform to the XML recommendation.
The first question you should be asking is not, "How can I produce XML with namespace attributes in a defined order?" Instead, it should be, "What are the other respects in which this software doesn't conform to the XML recommendation?" Because I will bet you one crisp new American dollar that if the recipient's process violates the XML recommendation in one respect, it violates it in at least one other.
Because sometimes the right answer is to say, no, don't do that...
Per W3C Namespaces in XML Recommendation, section 3 Declaring Namespaces:
[Definition: A namespace (or more precisely, a namespace binding) is
declared using a family of reserved attributes. Such an attribute's name must either be xmlns or begin xmlns:. These
attributes, like any other XML attributes, may be provided directly or
by default. ]
Therefore, the order of namespace declarations, like the order of any attributes, is insignificant.
So, no conformant XML tool or library will care about the order of namespace declarations, and neither should you.