I have a c# .net app. So I created a notifyIcon that sits in the tray. What I want to do is when the user hits the "x" button on the form, I want it to close to the tray. They should only be able to exit program by using the context menu in the tray icon.
So what I did was, on the form close event, I check whether the form is visible. If its visible, i set it to invisible and set showInTaskbar to false (simulating minimize to tray) If the form is invisible already, then they are probably closing it from the tray, so I will exit the program in that case.
However, the problem I have is that if the window is visible, but they right click on the context menu of the tray icon and hit exit, I need to exit the program and not minimize.
How do I solve this problem?
try this:
bool _closingFromMenu;
void NOTIFYICON_EXIT_MENU_HANDLER(object sender, EventArgs e)
{
_closingFromMenu = true;
Close();
}
//form closing handler
FormClosing +=(a,b) =>{
if(_closingFromMenu){
Close();
}
else{
e.Cancel = true;
//do minimize stuff;
}
}
or if you have only one form you can call Application.Exit(); in context menu item handler
You probably want to track the state of the application based on the actions of the user as that's not necessarily reflected in the state of the window. So when the user selects Exit from the menu you need to set a flag to indicate that you're really exiting, not just hiding the window.
Just make your Context Menu close event call Application.Exit()
Related
I have a Splash Screen to my program.
And when the splash end , exec the code
this.Hide();
frmLogin o = new frmLogin();
o.show();
And it works but the splash screen go invisible and when i close the program by my custom exit button it's only closing the current form.
But my splash screen is still hidden and appears the app name to task manager.
How i can close that currently opened form and the invisible ones with my custom button ?
You are launching your whole application from the splash screen form.
It would be better avoid this behaviour separating splash screen form from main form, and opening up from this last form the splash screen, as well as you have done with frmLogin.
However you can workaround this problem using this.Hide() and at the exit of the program using Application.Exit() within your "custom exit button" event.
While in design view, select the frmLogin button. On the right, the Properties window should update. Select the Events tab. Look for FormClosing in the list of events. Select the right column and type a method name of your choice. If you typed xBtnPress, the designer will generate a stub that will look like this:
private void xBtnPress(object sender, FormClosingEventArgs e) {
}
If you wish to close your application upon this event, call Application.Exit() from within the event handler.
I have a modal form (login) which I want that on closing it using "X" button, force application to exit.
I tried this:
private void Login_Deactivate(object sender, EventArgs e)
{
Application.Exit();
}
this cause my application to exit on pressing login button (closing). but I want exiting only on "X" button of window.
How can I do it?
Get rid of the Deactivate event, you don't need it.
The issue here is that you cannot tell that just the "X" button was pressed. What you really do is track all the other conditions that cause form close, and react when it's not one of those.
You should leverage the DialogResult enum, and allow the calling application to react, instead of trying to do it all in the Login form.
In your Login form constructor, set the property to None:
public Login()
{
DialogResult = DialogResult.None;
}
Then, in your button handler for "OK", set the property: DialogResult = DialogResult.OK.
If you have a specific Cancel event, you can set DialogResult = DialogResult.Cancel.
Ultimately, you could have a FormClosing event in the Login form, in which you can check this value and react. But more importantly, your calling application can check the result from the login form and react there as well.
I think you should use this.Parent.Application.Exit(), it kills whole application.
Instead of Deactivate event, subscribe to the "FormClosing" event of the "Login" form. Write the same code which you have written.
Keep the Deactivate event only if it is required to close the Application when you click outside login form.
I have a form "Main" and in Main I am creating another form which I use .ShowDialog() to display it. I do this because I don't want the rest of the code to in Main to execute until after the new form is completed. I am allowing a user to minimize the new form to system tray.
The problem: When the form gets minimized it is returning DialogResult.Cancel to the Main form that called it, causing the next line to run early.
Code to create form from Main form:
for(int i = 0; i < lvAll.SelectedItems.Count; i++)
{
this.Hide();
this.run = new RunProfile(this.profiles[lvAll.SelectedItems[i].Text]);
DialogResult result = run.ShowDialog();
MessageBox.Show(result.ToString());
}
In the new form a user will get a list of files that copy... now the user can continue and copy those files and I would expect to return a result of OK and if not I assume they are going to cancel and return Cancel...
Is my only recourse to return Abort from the new form if a user specifies a cancel and assume that a cancel is someone trying to minimize? This just seems odd
You could handle this in a number of ways, one way is like what follows:
MainTestForm mainTestForm = new MainTestForm();
if (mainTestForm.ShowDialog() != System.Windows.Forms.DialogResult.OK)
{
return;
}
You must set the DialogResult state when you close the form like
this.DialogResult = System.Windows.Forms.DialogResult.OK;
I hope this helps.
This is entirely by design. When you hide a modal dialog, the user doesn't have any way to get back to the program. Dialogs don't have a taskbar button and the rest of the windows in the app are disabled so cannot be activated. The only recourse the user would have is to kill your program with Task Manager.
So Winforms does the logical thing, it automatically closes the dialog to avoid this UI trap. And of course you'll get DialogResult.Cancel.
Use proper UI design, a dialog should always have its MinimizeBox property set to False.
I'm not sure what you are trying to achieve with that. However, to get the Dialog to return anything else, you have to set it in the form's (Dialog's) DialogResult property before the form is closed.
You may also use the Form_Closing event of the dialog to set the DialogResult property to what you want. This is done before the form closes.
Here is a quote from MSDN regarding ShowDialog:
When this method is called, the code following it is not executed
until after the dialog box is closed.
After further reading it does state the X does not close the form but hides it and so you must dispose of it:
When a form is displayed as a modal dialog box, clicking the Close
button (the button with an X in the top-right corner of the form)
causes the form to be hidden and the DialogResult property to be set
to DialogResult.Cancel. The Close method is not automatically called
when the user clicks the Close button of a dialog box or sets the
value of the DialogResult property. Instead, the form is hidden and
can be shown again without creating a new instance of the dialog box.
Because of this behavior, you must call the Dispose method of the form
when the form is no longer needed by your application.
It seems this same issues applies to minimizing a userform as well.
I have program that opens subwindows inside of it (mdi.parent). I have made component that is in one window under it, however, i want that that window never actually disposed after its created because i want to keep only one instance of it.
This can be made with code:
// This prevents this window disposing from window close button, we want always show one and only
// one instance of this window.
FormClosing += (o, e) =>
{
Hide();
e.Cancel = true;
};
However, after this there is problem, closing program requires pressing close button press twice. First press closes subwindow and second terminates program. How this can be get around?
I am working with Winforms.
As Habib said, you can call Application.Exit, but:
The Form.Closed and Form.Closing events are not raised when the
Application.Exit method is called to exit your application
If this is important to you, you can do something like this (MDI parent code):
private Boolean terminating;
protected override void OnClosing(CancelEventArgs e)
{
if (!terminating)
{
terminating = true;
Close();
}
base.OnClosing(e);
}
Call Application.Exit() in the form close event.
Application.Exit - MSDN
Informs all message pumps that they must terminate, and then closes
all application windows after the messages have been processed.
The code inside of your FormClosing event handler method is a bit too terse. It does its job of preventing the user from closing the form, but as you've also noticed, it prevents you from closing the form programmatically as well.
This is easily solved by testing the value of the CloseReason property of the FormClosingEventArgs that are passed in each time the event is raised.
These will tell you the reason why the form is attempting to close. If the value is CloseReason.UserClosing, then you want to set e.Cancel to true and hide the form. If the value is something else, then you want to allow the form to continue closing.
// This prevents this window disposing when its close button is clicked by the
// user; we want always show one and only one instance of this window.
// But we still want to be able to close the form programmatically.
FormClosing += (o, e) =>
{
if (e.CloseReason == CloseReason.UserClosing)
{
Hide();
e.Cancel = true;
}
};
Use This
Form[] ch = this.MdiChildren;
foreach (Form chfrm in ch)
chfrm.Close();
You can use Application.Exit if there is no processing happening when the application is closed. Otherwise, you can check Application.OpenForms collection in MDI parent's closing event and close all the other forms that are open.
Currently I am developing a windows form application in c# that has several forms.
I am running a background form that operates the notifyicon property that allows the icon to appear in the taskbar.
When I launch the program, it will launch a loginForm, after which logging in it will go into a mainForm. After closing the mainForm, the application does not close yet, which in this case works like Windows Live Messenger.
How do I make my program in a way that after I the mainForm, through double clicking it will bring the form back up? (Like how MSN works.)
Or is it a better solution for me to close the whole application when I press the X button in the title bar. Which brings up another problem for me as I cant seem to exit the application when I close other forms other than the main form.
Probably you have NotifyIcon on your main form. Subscribe on the DoubleClick event of this control and change state of your main form in the handler:
private void notifyIcon1_DoubleClick(object sender, EventArgs e)
{
this.Show();
this.Visible = true;
this.WindowState = FormWindowState.Normal;
}
Just set the Visible property of the form to true/false. Or you could call Show()/Hide().