To get the Form from its Processhandle - c#

Is there any way to get the Form from its Processhandle ?
Some thing like this.
Form form = (Form)Form.FromHandle(_process.MainWindowHandle);
But this is not working.

According to this post, that only works for window handles owned by your process. You can't use Form.FromHandle to get a form from some other process.
See also: How to use Control.FromHandle?

It's possible to do this from within a process. Trying to grab a Form or Control from another process won't work.
Can you give us some more information as to what you're trying to do here with the Form? There may be a better way to accomplish it.

Related

Start and Immediately Close application without showing Form

I have a very simple GUI application in C# and there is some codes in Form Load function. I just want to start and close the application without showing Form for running those codes in form load function.
How to do it?
If you don't want to show a form, you should move your code to the Main() method and get rid of the form.
Or you could try to create a service which contains no GUIs
http://msdn.microsoft.com/en-us/library/zt39148a%28v=vs.110%29.aspx
form.Opacity = 0;
I am not sure if this is what you want.
EDIT: - This will keep form opaque and you can run and close it when an event occur.

C# using FileOpendialogbox control within my form class

I have a weird requirement. I need to use FileOpenDialogBox control within my form. I mean not as other window but as control of a form. I know many applicationss that doing it. How can I do it in C#?
Try this object I found on the web.

C# Forms: Lock Main form and process another form

I want to create something like this.
When the button clicks main form will lock/disable/inaccessible. Then the another form load and do some processing.
(actually when the button clicked, it will read some text from a file and write to db. I put progress bar to give a nice look)
As I said I want to lock/disable/inaccessible main form and load the another form.
How can I do this ?
Please Help
Yohan
new Form().ShowDialog() will do just that.
oldForm.Hide() and newForm().ShowDialog()
as J.N. mentioned, ShowDialog will work, but I think you will need to have your processing code in the new form you open up, as the program will only return and 'unlock' your main form after the new form has finished and closed.
Edit I just saw the comments below the original post, I guess this has been sorted, but I'll leave my comments above just in case

How can I get the reference to currently active modal form?

I am writing a small class for driving integration testing of a win form application. The test driver class has access to the main Form and looks up the control that needs to be used by name, and uses it to drive the test. To find the control I am traversing the Control.Controls tree. However, I get stuck when I want to get to controls in a dialog window (a custom form shown as a dialog). How can I get hold of it?
You can get a reference to the currently active form by using the static Form.ActiveForm property.
Edit: If no Form has the focus, Form.ActiveForm will return null.
One way to get around this is to use the Application.OpenForms collection and retrieve the last item, witch will be the active Form when it is displayed using ShowDialog:
// using Linq:
var lastOpenedForm = Application.OpenForms.Cast<Form>().Last()
// or (without Linq):
var lastOpenedForm = Application.OpenForms[Application.OpenForms.Count - 1]
I'm not sure if you can access controls on a pre-built dialog box; they seem all packaged together. You may have more luck building a dialog box of your own that does what you want it to do. Then you can access the .Controls inside of it.
Correct me if i'm wrong, though, it sounds as if you are possibly attempting to access the controls on the dialog form when it's not quite possible to.
What I mean is, ShowDialog will "hold up" the thread that the form was created on and will not return control to the application (or, your test class) until ShowDialog has finished processing, in which case your user code would continue on its path.
Try accessing or manipulating the controls from a separate thread (in this case, refactor the test driver class to spawn a separate thread for each new form that must be displayed and tested).

Load a form without showing it

Short version: I want to trigger the Form_Load() event without making the form visible. This doesn't work because Show() ignores the current value of the Visible property:
tasksForm.Visible = false;
tasksForm.Show();
Long version: I have a WinForms application with two forms: main and tasks. The main form is always displayed. The user can either click a button to open the tasks form, or click some buttons that just run a task directly without opening the tasks form.
When a user asks to run a task directly, I'd like to just call some public methods on the tasks form without showing it. Unfortunately, the task logic depends on stuff that happens in the Form_Load() event. The only way I can find to trigger Form_Load() is to call Show(). The best I've been able to do is to show the form in the minimized state:
tasksForm.WindowState = FormWindowState.Minimized;
tasksForm.Show();
I suppose the cleanest solution would be to pull the tasks logic out of the tasks form and into a controller class. Then I can use that class from the main form and from the tasks form, and only load the tasks form when I need it visible for the user. However, if it's an easy thing to load the form without displaying it, that would be a smaller change.
Perhaps it should be noted here that you can cause the form's window to be created without showing the form. I think there could be legitimate situations for wanting to do this.
Anyway, good design or not, you can do that like this:
MyForm f = new MyForm();
IntPtr dummy = f.Handle; // forces the form Control to be created
I don't think this will cause Form_Load() to be called, but you will be able to call f.Invoke() at this point (which is what I was trying to do when I stumbled upon this SO question).
It sounds to me like you need to sit down and re-think your approach here. I cannot imagine a single reason your public methods need to be in a form if you are not going to show it. Just make a new class.
I totally agree with Rich B, you need to look at where you are placing your application logic rather than trying to cludge the WinForms mechanisms. All of those operations and data that your Tasks form is exposing should really be in a separate class say some kind of Application Controller or something held by your main form and then used by your tasks form to read and display data when needed but doesn't need a form to be instantiated to exist.
It probably seems a pain to rework it, but you'll be improving the structure of the app and making it more maintainable etc.
From MSDN:
Form.Load
Occurs before a form is displayed for the first time.
Meaning the only thing that would cause the form to load, is when it is displayed.
Form.Show(); and Form.Visible = true; are the exact same thing. Basically, behind the scenes, Show checks for various conditions, then sets Visible to true. So obviously, setting visible to false (which it already is) before showing the form is meaningless.
But let's forget the technicalities. I completely agree with Rich B and Shaun Austin - the logic shouldn't be in that form anyway.
Sometimes this would be useful without it being bad design. Sometimes it could be the start of a migration from native to managed.
If you were migrating a c++ app to .NET for example, you may simply make yourwhole app a child window of the .NET form or panel, and gradually migrate over to the .NET by getting rid of your c++ app menu, status bar, toolbar and mapping teh .NEt ones to your app using platform invoke etc...
Your C++ app may take a while to load, but the .NET form doesn't..in which you may like to hide the .NEt form until your c++ app has initialised itself.
I'd set opacity=0 and visible=false to false after calling show, then when your c++ app loads, then reverse.
If you make the method public, then you could access it directly.... however, there could be some unexpected side effects when you call it. But making it public and calling it directly will not draw the screen or open the form.
Move mandatory initialization code for the form class out of the Load event handler into the constructor. For a Form class, instantiation of an instance (via the constructor), form loading and form visibility are three different things, and don't need to happen at the same time (although they do obviously need to happen in that order).
None of the answers solved the original question, so, add the below, call .Show() to load the form without showing it, then call .ShowForm() to allow it to be visible if you want to after:
private volatile bool _formVisible;
protected override void SetVisibleCore(bool value)
{
base.SetVisibleCore(_formVisible);
}
public void ShowForm()
{
_formVisible = true;
if (InvokeRequired)
{
Invoke((Action) Show);
}
else
{
Show();
}
}

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