ItemsControl: How To Use FindName within ItemsPanelTemplate to access Panel - c#

<Style TargetType="{x:Type local:CustomItemsControl}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate>
<ScrollViewer>
<ItemsPresenter x:Name="PART_Presenter"/>
</ScrollViewer>
</ControlTemplate>
</Setter.Value>
</Setter>
<Setter Property="ItemsPanel">
<Setter.Value>
<ItemsPanelTemplate>
<StackPanel x:Name="PART_StackPanel" IsItemsHost="True"/>
</ItemsPanelTemplate>
</Setter.Value>
</Setter>
</Style>
Trying to access the StackPanel to set Events when children are changed.
[TemplatePartAttribute(Name = "PART_StackPanel", Type = typeof(StackPanel))]
[TemplatePartAttribute(Name = "PART_Presenter", Type = typeof(ItemsPresenter))]
public class CustomItemsControl: ItemsControl
{
public override void OnApplyTemplate()
{
base.OnApplyTemplate();
var presenter = (ItemsPresenter)this.Template.FindName("PART_Presenter", this);
var stackPanel = (StackPanel)this.ItemsPanel.FindName("PART_StackPanel",this);
}
}
Get Exception when I try to locate the StackPanel.
InvalidOperationException:
This operation is valid only on elements that have this template applied.
Please advise if there is a way to find a TemplatePart within an ItemsPanelTemplate. And when should I expect to know when the ItemsPanelTemplate is applied?

Another option is to call .ApplyTemplate() on the ItemsPresenter while still in the ItemControl's OnApplyTemplate method. Then the call to .FindName will succeed.
[TemplatePartAttribute(Name = "PART_StackPanel", Type = typeof(StackPanel))]
[TemplatePartAttribute(Name = "PART_Presenter", Type = typeof(ItemsPresenter))]
public class CustomItemsControl : ItemsControl
{
public override void OnApplyTemplate()
{
base.OnApplyTemplate();
var presenter = (ItemsPresenter)this.Template.FindName("PART_Presenter", this);
presenter.ApplyTemplate();
var stackPanel = (StackPanel)this.ItemsPanel.FindName("PART_StackPanel", presenter);
}
}

Figured out that the Loaded event was the one to wait for on an ItemsPanelTemplate. I am able to find the StackPanel using the TemplatePart Name. Thanks to Rick for suggesting the StackPanel should be found within the Presenter.
protected override void OnInitialized(EventArgs e)
{
base.OnInitialized(e);
this.Loaded += new Accordion_Loaded;
}
void Accordion_Loaded(object sender, RoutedEventArgs e)
{
var presenter = (ItemsPresenter)this.Template.FindName("PART_Presenter", this);
var stackPanel = (StackPanel)this.ItemsPanel.FindName("PART_StackPanel", presenter);
}

The FindName method only finds names in a template that has been expanded and the ItemsPanel is expanded by the ItemsPresenter, not the ItemsControl. In your situation the "PART_StackPanel" will always be the child of the "PART_Presenter" so you can get a reference to it like this:
var stackPanel = (StackPanel)VisualTreeHelper.GetChild(presenter, 0);

Related

When drag text and On Mouse hover to drop it into TextBox, increase TextBox size and overlap on the other controls

I want to increase the size of a TextBox Control whenever the user drag a node from Treeview control and hovers the mouse over the TextBox.
The size increase should not readjust the other controls, rather the current control should overlap the neighboring controls.
I tried to implement the code WPF: On Mouse hover on a particular control, increase its size and overlap on the other controls
but it doesn't work when hover on TextBox and left mouse button is pressed for dragged text.
<ItemsControl Margin="50">
<ItemsControl.Resources>
<Style x:Key="ScaleStyle" TargetType="TextBox">
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Grid.ZIndex" Value="1"/>
<Setter Property="RenderTransform">
<Setter.Value>
<ScaleTransform ScaleX="1.1" ScaleY="1.1"/>
</Setter.Value>
</Setter>
</Trigger>
</Style.Triggers>
</Style>
</ItemsControl.Resources>
</ItemsControl>
Here is a small sample application. Contrary to my comment, we need the PreviewDragEnter event since the text box already has Drag/Drop support. In Window_Loaded, the application registers the event handlers. Then, in TextBox_PreviewDragEnter, the new style is set manually. We also store the old z-index to allow restoring it in TextBox_PreviewDragLeave.
<Window x:Class="WpfApp1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Height="350" Width="525" Loaded="Window_Loaded">
<StackPanel Margin="8">
<TextBox/>
<TextBox/>
<TextBox/>
<TextBox/>
</StackPanel>
</Window>
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
//From https://stackoverflow.com/a/978352/1210053
public static IEnumerable<T> FindVisualChildren<T>(DependencyObject depObj) where T : DependencyObject
{
if (depObj != null)
{
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
{
DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
if (child != null && child is T)
{
yield return (T)child;
}
foreach (T childOfChild in FindVisualChildren<T>(child))
{
yield return childOfChild;
}
}
}
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
foreach (var txt in FindVisualChildren<TextBox>(this))
{
txt.PreviewDragEnter += TextBox_PreviewDragEnter;
txt.PreviewDragLeave += TextBox_PreviewDragLeave;
txt.PreviewDrop += TextBox_PreviewDragLeave;
}
}
private Dictionary<TextBox, int> oldZIndex = new Dictionary<TextBox, int>();
private void TextBox_PreviewDragEnter(object sender, DragEventArgs e)
{
var txt = (TextBox)sender;
oldZIndex.Add(txt, Panel.GetZIndex(txt));
Panel.SetZIndex(txt, 1);
var scaleTransform = new ScaleTransform(1.1, 1.1, txt.ActualWidth / 2, txt.ActualHeight / 2);
txt.RenderTransform = scaleTransform;
}
private void TextBox_PreviewDragLeave(object sender, DragEventArgs e)
{
var txt = (TextBox)sender;
txt.RenderTransform = null;
Panel.SetZIndex(txt, oldZIndex[txt]);
oldZIndex.Remove(txt);
}
}
Approach from a different angle. Use the code behind to handle left click and drag.
Pseudo code...
If hover over textbox.text ==true
Textbox size = 300;
Then check the Grid location of the textbox. It should be allowed to columnspan over the other columns, while the rest of the controls stay fixed in their grid.row and grid.column locations.

How can I find a style trigger-embedded element by name in WPF?

First, the heart of the question: If an element is assigned as the Content of a ContentControl via a style trigger, I can't seem to find it by name.
Now, for more detail: I have a panel that varies greatly in its layout and functionality based on its data context, which is a bug from a bug depot. When that bug is null, it is a search form, when it is non-null, it is a simple viewer for properties of that bug. The XAML then look something like:
<ContentControl DataContext="...">
<ContentControl.Style>
<Style TargetType="ContentControl">
<Setter Property="Content">
<Setter.Value>
...
</Setter.Value>
</Setter>
<Style.Triggers>
<DataTrigger Binding="{Binding}" Value="{x:Null}">
<Setter Property="Content">
<StackPanel>
<TextBox Name="Waldo"/>
<Button .../>
</StackPanel>
</Setter>
</DataTrigger>
</Style.Triggers>
</Style>
</ContentControl.Style>
</ContentControl>
When the user clicks the button that sits alongside the text box, I get a callback in the code behind. From that point I'd like to be able to access various properties of the text box. The question is, where's Waldo? :)
In the code behind I have tried a few variants of the following, all with little success:
this.FindName("Waldo"); // Always returns null
I've seen a lot of discussion on this topic as it relates to templates but not as it relates to setting content directly with triggers. Maybe it's because I am violating all sorts of best practices by doing this :)
Thank you!
If an element is assigned as the Content of a ContentControl via a style trigger, I can't seem to find it by name.
If you needed to access to the Content before trigger occurs, it would most likely not possible. In this situation, the main thing to get access after the DataTrigger occurs.
I am violating all sorts of best practices by doing this
Maybe it's not the right way to work with the Сontrol in WPF, the more that you still need access to dynamic content, which can later be changed. But in any case, there are two ways to work with the Сontrol - it's like now and in the MVVM style. MVVM style is best suited for large and less complex applications with different business logic. If in your case for easy application, in this situation, I do not see anything wrong with that. In addition to doing a project in MVVM style need from scratch, combine conventional method and the correct method is not a good way.
I created a small example to demonstrate access controls for a given situation. There is a property that corresponds to the type of Content, the default is Init. If you assigns null for this property, the dynamic Content is loaded.
That's how I get access to TextBox:
private void GetAccessToTextBox_Click(object sender, RoutedEventArgs e)
{
TextBox MyTextBox = null;
StackPanel panel = MainContentControl.Content as StackPanel;
foreach (object child in panel.Children)
{
if (child is TextBox)
{
MyTextBox = child as TextBox;
}
}
if (MyTextBox != null)
{
MyTextBox.Background = Brushes.Gainsboro;
MyTextBox.Height = 100;
MyTextBox.Text = "Got access to me!";
}
}
Below it's a full example:
XAML
<Window x:Class="AccessToElementInContentControl.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:this="clr-namespace:AccessToElementInContentControl"
WindowStartupLocation="CenterScreen"
Title="MainWindow" Height="350" Width="525">
<Window.DataContext>
<this:TestData />
</Window.DataContext>
<Window.Resources>
<Style TargetType="{x:Type ContentControl}">
<Setter Property="Content">
<Setter.Value>
<Label Content="InitContent"
HorizontalAlignment="Center"
VerticalAlignment="Center" />
</Setter.Value>
</Setter>
<Style.Triggers>
<DataTrigger Binding="{Binding Path=TypeContent}" Value="{x:Null}">
<Setter Property="Content">
<Setter.Value>
<StackPanel Name="NullStackPanel">
<TextBox Name="Waldo" Text="DynamicText" />
<Button Width="100" Height="30" Content="DynamicButton" />
</StackPanel>
</Setter.Value>
</Setter>
</DataTrigger>
</Style.Triggers>
</Style>
</Window.Resources>
<Grid>
<ContentControl Name="MainContentControl" />
<Button Name="SetContentType"
Width="100"
Height="30"
HorizontalAlignment="Left"
Content="SetContentType"
Click="SetContentType_Click" />
<Button Name="GetAccessToButton"
Width="110"
Height="30"
HorizontalAlignment="Right"
Content="GetAccessToTextBox"
Click="GetAccessToTextBox_Click" />
</Grid>
</Window>
Code-behind
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void SetContentType_Click(object sender, RoutedEventArgs e)
{
TestData test = this.DataContext as TestData;
test.TypeContent = null;
}
private void GetAccessToTextBox_Click(object sender, RoutedEventArgs e)
{
TextBox MyTextBox = null;
StackPanel panel = MainContentControl.Content as StackPanel;
foreach (object child in panel.Children)
{
if (child is TextBox)
{
MyTextBox = child as TextBox;
}
}
if (MyTextBox != null)
{
MyTextBox.Background = Brushes.Gainsboro;
MyTextBox.Height = 100;
MyTextBox.Text = "Got access to me!";
}
}
}
public class TestData : NotificationObject
{
private string _typeContent = "Init";
public string TypeContent
{
get
{
return _typeContent;
}
set
{
_typeContent = value;
NotifyPropertyChanged("TypeContent");
}
}
}
public class NotificationObject : INotifyPropertyChanged
{
public event PropertyChangedEventHandler PropertyChanged;
protected void NotifyPropertyChanged(string propertyName)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(propertyName));
}
}
}

Validating WPF Visual Tree

I am trying to enforce that any new style added should have to meet some standards. Here is a simple example.
<Style TargetType="{x:Type CellValuePresenter}" BasedOn="{StaticResource {x:Type CellValuePresenter}}">
<Setter Property="Tag" Value="1"></Setter>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate>
<Border BorderThickness="{TemplateBinding BorderThickness}" />
....
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
Updated:
I am trying to validate the style from code behindthat if the style has ControlTemplate, its root should be Border with BorderThickness template binded.
Since Visual Tree is not created until the Control is rendered, I am creating the control at runtime based on target type and applying the style. And I even tried the following
Appropriate way to force loading of a WPF Visual
I can see the visual tree in WPF Tree Visualizer, but I cannot navigate fully using LogicalTreeHelper.GetChildren
I am just experimenting with ideas around:
private void ValidateStyle(Style fieldStyle_, Field field_)
{
if (fieldStyle_.TargetType == typeof(CellValuePresenter))
{
StringBuilder sb = new StringBuilder();
CellValuePresenter presenter = new CellValuePresenter();
presenter.Style = fieldStyle_;
if (fieldStyle_.Setters.Count > 0)
{
foreach (Setter setter in fieldStyle_.Setters)
{
if (setter.Property != null && setter.Property.PropertyType == typeof(ControlTemplate))
{
presenter.ApplyTemplate();
ValidateColumnStyle(0, presenter);
}
}
}
}
}
private void ValidateColumnStyle(int depth_, object obj_)
{
Debug.WriteLine(new string(' ', depth_) + obj_);
if (!(obj_ is DependencyObject))
{
return;
}
if (obj_ is UIElement)
{
Viewbox vb = new Viewbox() {Child = obj_ as UIElement};
vb.Measure(new Size(Double.PositiveInfinity, Double.PositiveInfinity));
vb.Arrange(new Rect(vb.DesiredSize));
}
foreach (object child in LogicalTreeHelper.GetChildren(obj_ as DependencyObject))
ValidateColumnStyle(depth_ + 1, child);
}
I am not able to navigate to Border element, any idea how to properly load the control.

Make select controls visible based on selected tab using xaml

I've got following code:
private Dictionary<int, UserControl> tabControls = new Dictionary<int, UserControl>();
public MainWindow()
{
InitializeComponent();
tabControls[0] = new Panel1();
tabControls[1] = new Panel2();
tabControls[2] = new Panel3();
tabControls[3] = new Panel4();
tabControls[4] = new Panel5();
tabControls[5] = new Panel6();
tabControls[6] = new Panel7();
tabControls[7] = new Panel8();
}
public object SelectedTab
{
//this is assigned from xaml binding
set
{
OnCurrentTabChanged(tabControl.SelectedIndex);
}
}
void OnCurrentTabChanged(int tabIndex)
{
if (dataDisplay != null)
{
dataDisplay.Children.Clear();
dataDisplay.Children.Add(tabControls[tabIndex]);
}
}
Every time the user selects different tab, an other control appears.
Is there any way to simplify this using xaml?
I cannot put the controls themselves inside the tab control
I've done this before with another TabControl which has it's headers and frame hidden. Then I just bind the SelectedIndex to your other tab's SelectedIndex, and the two are synchronized
<!-- TabControl without the TabHeaders -->
<Style x:Key="TabControl_NoHeadersStyle" TargetType="{x:Type TabControl}">
<Setter Property="SnapsToDevicePixels" Value="true"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type TabControl}">
<DockPanel>
<!-- This is needed to draw TabControls with Bound items -->
<StackPanel IsItemsHost="True" Height="0" Width="0" />
<ContentPresenter x:Name="PART_SelectedContentHost"
ContentSource="SelectedContent" />
</DockPanel>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
Then you can setup your two tab controls, each bound to different sources, and bind the SelectedIndex of one to the SelectedIndex of the other
<TabControl x:Name="MainTabControl" />
<TabControl ItemsSource="{Binding Panels}"
SelectedIndex="{Binding ElementName=MainTabControl, Path=SelectedIndex}"
Style="{StaticResource TabControl_NoHeadersStyle}" />
Another alternative is to bind the SelectedIndex to something in your code-behind, then anytime it changes, raise a PropertyChanged notification on another property that exposes the panel you want to display.
<TabControl SelectedIndex="{Binding SelectedTabIndex} />
<ContentControl Content="{Binding SelectedPanel}" />
and in the code behind
public int SelectedTabIndex
{
get { return _selectedTabIndex;}
set
{
if (_selectedTabIndex != value)
{
_selectedTabIndex = value;
RaisePropertyChanged("SelectedTabIndex");
RaisePropertyChanged("SelectedPanel");
}
}
}
public UserControl SelectedPanel
{
get { return tabControls[SelectedTabIndex]; }
}
TabItem has an IsSelected propery you could bind to that I think would simplify the syntax.
public bool TabIsSelected
{
get { return tabIsSelected; }
set
{
if (value && dataDisplay != null)
{
dataDisplay.Children.Clear();
dataDisplay.Children.Add(tabControls[tabIndex]);
}
tabIsSelected = value;
}
But I still don't get why you can't just put the control in the tabitem?
using codebehind
void OnCurrentTabChanged(int tabIndex)
{
if (dataDisplay != null)
{
UIElemnt[] pp = dataDisplay.Children.Cast<UIElement>().ToArray();
Array.ForEach(pp, x=> x.visibility = Visibility.Collapsed);
pp[tabIndex].visibility = Visibility.Visible;
}
}

Add Items to ListBox and Style

I have a simple class:
public class Foo
{
public string Text { get; set; }
public bool AppleStyle { get; set; }
public Foo(string text, bool applyStyle)
{
Text = text;
ApplyStyle = applyStyle;
}
public override string ToString()
{
return Text;
}
}
Which is then used to add items to a ListBox:
var one = new Foo("Some Text", false);
var two = new Foo("More Text", true);
MyListBox.Items.Add(one);
MyListBox.Items.Add(two);
I then loop through the items in the ListBox to figure out how to style them. This is where I get stuck. I tried inheriting from ListBoxItem for the class, but no items get added if I do that.
for (int i = 0; i < MyListBox.Items.Count; i++)
{
if(((Foo)MyListBox.Items[i]).ApplyStyle)
{
((ListBoxItem)MyListBox.Items[i]).Style = Resources["MyStyle"] as Style;
}
}
Update:
In MainWindow.xaml:
<Window.Resources>
<Style x:Key="MyStyle" TargetType="ListBoxItem">
<Setter Property="Background" Value="Bisque"></Setter>
<Setter Property="FontWeight" Value="Bold"></Setter>
</Style>
</Window.Resources>
Update 3:
Making some progress, just need to know how to refresh the styles (after clicking on a button). Plus if Resource is not in MainWindow.xaml, would it then look in App.xaml before returning null?
MainWindow.xaml
<Window...>
<Window.Resources>
<Style x:Key="MyClass" TargetType="ListBoxItem">
<Setter Property="Background" Value="Bisque"></Setter>
<Setter Property="FontWeight" Value="Bold"></Setter>
</Style>
<myapp:MyListItemStyleSelector x:Key="MyListItemStyleSelector" />
</Window.Resources>
<Grid>
...
<ListBox .... ItemContainerStyleSelector="{StaticResource: MyListItemStyleSelector}" />
...
</Grid>
</Window>
MyListItemStyleSelector.cs
public class MyListItemStyleSelector : StyleSelector
{
public override Style SelectStyle(object item, DependencyObject container)
{
ItemsControl ic = ItemsControl.ItemsControlFromItemContainer(container);
int index = ic.ItemContainerGenerator.IndexFromContainer(container);
Style applyStyle = null;
var data = item as Foo;
if (data != null && data.ApplyStyle)
{
applyStyle = ic.TryFindResource("MyStyle") as Style;
}
return applyStyle;
}
}
I think you have some sort of mixup here, i try to explain as good as i can.
First of all You usually never need to change the Style in code, like your last code block.
One thing that is difficult to understand in the beginning is the use of a ItemContainerStyle and DataTemplate.
I would suggest that you do the following.
Instead of changing the style off your ListBoxItem see if it is sufficient to use a DataTemplate. The DataTemplate defines how the Content of your ListBoxItem is shown.
<DataTemplate TargetType="{x:Type Foo}">
<!-- your visuals and controls here -->
</DataTemplate>
Now if you want to use different datatemplates you could use different classes and create different DataTemplates for them, or you use a DataTemplateSelector
public class FooTemplateSelector : DataTemplateSelector
{
public override DataTemplate SelectTemplate(object item, DependencyObject container)
{
FrameworkElement element = container as FrameworkElement;
var mdl = item as Foo;
if( mdl.AppleStyle )
return element.FindResource("appleTemplate") as DataTemplate;
return element.FindResource("normalTemplate") as DataTemplate;
}
}
Create that templateselector in xaml and reference it in your listbox
<myNs:FooTemplateSelector x:Key="fooTemplateSelector"/>
<Listbox DataTemplateSelector="{StaticResource fooTemplateSelector}"/>
now you need to create 2 DataTemplates appleTemplate *normalTemplate* and you can easyl distinguish which data template to use vial the selector. Which is done automatically in the ListBox for you.
If you really want to change the Style of the ItemContainer you can use ItemContainerStyleSelector which works similar to the DataTemplateSelector. But i would not suggest it. You should supply the content and leave the ListBoxItem as it is, only if you want to modify the design(in this case, the selection color etc.), otherwise it might confuse the user or break functionality.
If you add data-objects directly to the ListBox the container-items will be generated automatically, you cannot get them this way.
Use the ItemContainerGenerator:
((ListBoxItem)MyListBox.ItemContainerGenerator.ContainerFromIndex(i)).Style = Resources["MyStyle"] as Style;
Why not do this in the XAML?
<ListBox Name="MyListBox">
<ListBox.Resources>
<Style TargetType="{x:Type ListBoxItem}">
<Style.Triggers>
<DataTrigger Binding="{Binding ApplyStyle}" Value="True">
<Setter Property="Background" Value="Bisque" />
<Setter Property="FontWeight" Value="Bold" />
</DataTrigger>
</Style.Triggers>
</Style>
</ListBox.Resources>
</ListBox>
But your overall problem is that ListBox.Items returns a collection of data objects, not XAML Controls. To get the XAML control that contains the Data Object you have to do as H.B. suggested and use MyListBox.ItemContainerGenerator.ContainerFromItem(dataObject) to get the XAML Container for the data object. Just be sure you wait until after the ItemContainerGenerator has finished rendering items to get the container (I believe it has a Status property or StatusChanged event you can use... it's been a while and I can't remember the exact syntax)

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