I want to generate a 4 character hex number.
To generate a hex number you can use
string.format("{0:X}", number)
and to generate a 4 char string you can use
string.format("{0:0000}", number)
Is there any way to combine them?
I'm assuming you mean: 4-digit hexadecimal number.
If so, then yes:
string.Format("{0:X4}", number)
should do the trick.
Have you tried:
string hex = string.Format("{0:X4}", number);
? Alternatively, if you don't need it to be part of a composite pattern, it's simpler to write:
string hex = number.ToString("X4");
Related
I have a string in the format:
خصم بقيمة 108 بتاريخ 31-01-2021
And I want to replace the digits between the words: بقيمة & بتاريخ with a "?" character.
And keep the digits in the date part of the string
I tried using this Regular Expression: (?<=بقيمة)(.*?)(?=بتاريخ)
Which works on https://regex101.com/
But when I implement it in C# in Regex.Replace function, it doesn't have any effect when I use the Arabic words:
e.Row.Cells[3].Text = Regex.Replace(e.Row.Cells[3].Text, "(?<=بقيمة)(.*?)(?=بتاريخ)", "?");
But it works if I use Latin letters:
e.Row.Cells[3].Text = Regex.Replace(e.Row.Cells[3].Text, "(?<=X)(.*?)(?=Y)", "?");
Is there anyway to make the function work with Arabic characters?
Or is there a better approach I can take to achieve the desired result? For example excluding the date part?
Since the needed digits (without "-"s) are bookended by spaces just use \s(\d+)\s.
var txt = "خصم بقيمة 108 بتاريخ 12-31-2021";
var pattern = #"\s(\d+)\s";
Console.WriteLine( Regex.Match(txt, pattern).Value ); // 108
I have a number in string format. This number will be between 1-6 digits and i need to convert it to be filled with zeroes on left side in order to always be 6 digit number. Is there any more efficient way than this?
Int32.Parse("5").ToString("D6")
Conversion to int just feels a bit unnecessary.
You could use String.PadLeft:
string result = number.PadLeft(6, '0');
If the number can be negative this doesn't work and you need your int.Parse approach.
It is unnecessary
string result = "5".PadLeft(6,'0');
string someText = "test 5 rate";
someText = Regex.Replace(someText, #"\d+", n => n.Value.PadLeft(5, '0'));
I want to get third and fourth letters from PlayerPrefs.GetString("String")
and Parse to int.
for example;
string playerLevelstr = PlayerPrefs.GetString("Player")[2] + PlayerPrefs.GetString("Player")[3];
//My Player string is "0012000000" but when I plus third and fourth letter, playerLevelstr should be "12" but it is "96".
int playerLevelint = int.Parse(playerLevelstr);
The indexer on a string returns a char.
If you use the + operator on chars together, it essentially does integer math on the two chars.
See this question for more information on that.
Though that means you should get 99 ('1' is 49, '2' is 50') not 96. But maybe that was a typo on one end or the other?
Regardless, you should either convert the chars to strings (.ToString() on them) or use the Substring function on the string instead. And don't forget your length/null checks!
This code PlayerPrefs.GetString("Player")[2] returns a char, which is being being converted to int (being the ASCII value of the character) when you add it to another char.
Do this instead:
string playerLevelstr = PlayerPrefs.GetString("Player").Substring(2,2);
I want to convert an integer to 3 character ascii string. For example if integer is 123, the my ascii string will also be "123". If integer is 1, then my ascii will be "001". If integer is 45, then my ascii string will be "045". So far I've tried Convert.ToString but could not get the result. How?
int myInt = 52;
string myString = myInt.ToString("000");
myString is "052" now. Hope it will help
Answer for the new question:
You're looking for String.PadLeft. Use it like myInteger.ToString().PadLeft(3, '0'). Or, simply use the "0" custom format specifier. Like myInteger.ToString("000").
Answer for the original question, returning strings like "0x31 0x32 0x33":
String.Join(" ",myInteger.ToString().PadLeft(3,'0').Select(x=>String.Format("0x{0:X}",(int)x))
Explanation:
The first ToString() converts your integer 123 into its string representation "123".
PadLeft(3,'0') pads the returned string out to three characters using a 0 as the padding character
Strings are enumerable as an array of char, so .Select selects into this array
For each character in the array, format it as 0x then the value of the character
Casting the char to int will allow you to get the ASCII value (you may be able to skip this cast, I am not sure)
The "X" format string converts a numeric value to hexadecimal
String.Join(" ", ...) puts it all back together again with spaces in between
It depends on if you actually want ASCII characters or if you want text. The below code will do both.
int value = 123;
// Convert value to text, adding leading zeroes.
string text = value.ToString().PadLeft(3, '0');
// Convert text to ASCII.
byte[] ascii = Encoding.ASCII.GetBytes(text);
Realise that .Net doesn't use ASCII for text manipulation. You can save ASCII to a file, but if you're using string objects, they're encoded in UTF-16.
How do I convert a 10 digit number to a hex string in c#?
Note: if the number is less than 10 digits, I want to add padding? example
the number is 1, I want my string to be 0000000001.
Use a standard format string:
string paddedHex = myNumber.ToString("x10");
See the x format specifier.