my code is-
Stream myStream;
saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "Ticket files (*.tkt)|*.tkt";
saveFileDialog1.FilterIndex = 1;
saveFileDialog1.RestoreDirectory = true;
saveFileDialog1.Title = "Save text Files";
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
myStream = saveFileDialog1.OpenFile();
if (myStream != null)
{
StreamWriter wText = new StreamWriter(myStream);
string st = gettxt();
wText.Write(st);
//wText.WriteLine("sdfsderfsdsf");
myStream.Close();
}
}
whenever i uncomment Writeline and comment write(st) notthing is written..
and the string should be of specific length then only data is saved in the tkt file..
and last problem is that if text is too large then part of the text is only written..
please help me
try with
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
TextWriter tw = new StreamWriter(saveFileDialog1.FileName);
tw.WriteLine(gettxt());
tw.Close();
}
Hope this helps.
There are very few ways to explain the problem, other than there's a problem with the app that reads the file. Beware that you are writing a .txt file, it might not necessarily be compatible with a .tkt file format. Whatever that looks like. For one, the file will contain a BOM, 3 bytes at the start of the file that says it is a utf-8 formatted text file.
One thing you could try to diagnose the problem better:
using (var wText = new StreamWriter(myStream, Encoding.Default)) {
string st = gettxt();
wText.Write(st);
//wText.WriteLine("sdfsderfsdsf");
}
The Encoding argument specifies that the characters should be written in the default code page and without a BOM.
saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "Ticket files (*.tkt)|*.tkt";
saveFileDialog1.FilterIndex = 1;
saveFileDialog1.RestoreDirectory = true;
saveFileDialog1.Title = "Save text Files";
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
using (Stream myStream = saveFileDialog1.OpenFile())
{
using (StreamWriter wText = new StreamWriter(myStream))
{
wText.WriteLine(gettext());
}
}
}
Related
I'm using DatasListView from OLV, and I want to export my data to csv.
They said to use olvexporter, but I can not find an example of it.
Can anyone explain how to use OlvExporter to me?
You can try this:
string csv = string.Empty;
var olvExporter = new OLVExporter(objectListView1,
objectListView1.FilteredObjects);
csv = olvExporter.ExportTo(OLVExporter.ExportFormat.CSV);
csv = csv.Replace(",", ";");
SaveFileDialog saveFile = new SaveFileDialog();
saveFile.FileName = "ExportFile.csv";
saveFile.Filter = "csv files (*.csv)|*.csv";
if (saveFile.ShowDialog() == DialogResult.OK)
{
using (StreamWriter sw = new StreamWriter(saveFile.FileName))
{
sw.Write(csv);
}
}
The second parameter at the OLVExporter is only necessary if you want to enable Filtering at your objectListView. It it's set you are only exporting the results after the filtering.
If you choose CSV as ExportFormat you can use the csv.Replace() to change the output at the csv file.
The SaveFileDialog is also not necessary.
I have such code that saves bin file, but user has to choose file
Stream myStream;
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "Binary File (*.bin)|*.bin";
saveFileDialog1.FilterIndex = 2;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
if ((myStream = saveFileDialog1.OpenFile()) != null)
{
Question.PersistObject(questions, myStream);
myStream.Close();
}
}
But I want to choose file in code, and if a file with such name doesn't exist, then create it. How to set in myStream that file?
Replace all your logic related to the OpenFileDialog with File.Open:
using (var myStream = File.Open(someFilePath, FileMode.OpenOrCreate))
{
Question.PersistObject(questions, myStream); // do something with the stream
}
The OpenOrCreate file mode will open the file if it exists, or create it if it does not.
The using statement will take care of closing the stream for you.
One option would be to have a base name and append a number:
string templateName = "myfile{0}.bin";
string finalName;
int count = 0;
do {
finalName = String.Format(templateName, count++);
} while (File.Exists(finalName);
Or, if you don't care about the name, use Path.GetTempFileName
Then pass that name to StreamWriter:
using (StreamWriter writer = new StreamWriter(finalName))
{
// Write stuff
}
In ReportView I want to export to the following formats: .docx, .pdf, or .xlsx
Export to .pdf:
reportViewer.ExportDialog(_reportViewer.LocalReport.ListRenderingExtensions()[3]);
Export to .docx:
reportViewer.ExportDialog(_reportViewer.LocalReport.ListRenderingExtensions()[5]);
Export to .xlsx:
reportViewer.ExportDialog(_reportViewer.LocalReport.ListRenderingExtensions()[1]);
But at first I have to choose a format for saving.
I want at first to open SaveFileDialog and in it to choose a format for saving
How can I do it ?
Here's the code I came up with:
string _sSuggestedName = String.Empty;
byte[] byteViewerPDF = _reportViewer.LocalReport.Render("PDF");
byte[] byteViewerExcel = _reportViewer.LocalReport.Render("Excel");
byte[] byteViewerWord = _reportViewer.LocalReport.Render("Word");
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "PDF files (*.pdf)|*.pdf| Doc files
(*.doc)|*.doc| Excel files (*.xls)|*.xls";
if (saveFileDialog1.ShowDialog() == DialogResult.Ok)
{
FileStream newFile = new FileStream(saveFileDialog1.FileName, FileMode.Create);
if (saveFileDialog1.FilterIndex == 1)
{
newFile.Write(byteViewerPDF, 0, byteViewerPDF.Length);
newFile.Close();
}
else
if (saveFileDialog1.FilterIndex == 2)
{
newFile.Write(byteViewerWord, 0, byteViewerWord.Length);
newFile.Close();
}
else
if (saveFileDialog1.FilterIndex == 3)
{
newFile.Write(byteViewerExcel, 0, byteViewerExcel.Length);
newFile.Close();
}
}
I have a listbox, I save it to a txt file with following code.
String[] array = new String[listBox2.Items.Count];
listBox2.Items.CopyTo(array, 0);
Microsoft.Win32.SaveFileDialog saveFileDialog1 = new Microsoft.Win32.SaveFileDialog();
saveFileDialog1.FileName = "per_" ;
saveFileDialog1.DefaultExt = ".txt";
saveFileDialog1.Filter = "Text files (.txt)|*.txt";
Nullable<bool> res = saveFileDialog1.ShowDialog();
if (res == true)
{
string filename = saveFileDialog1.FileName;
File.WriteAllLines(filename, array, Encoding.UTF8);
MessageBox.Show("File saved successfully");
}
I save chart to c://
chart2.SaveImage("C://", System.Drawing.Imaging.ImageFormat.Jpeg);
However I want to save my chart at same direction which user chosed with savefiledialog. What should I do to manage this?
Try this
chart2.SaveImage(Path.GetDirectoryName(saveFileDialog1.FileName), System.Drawing.Imaging.ImageFormat.Jpeg);
or this
chart2.SaveImage(Path.GetDirectoryName(saveFileDialog1.FileName) + "\\chart.jpg", System.Drawing.Imaging.ImageFormat.Jpeg);
if SaveImage method needs a filename
i have the code for saving a gridview as an html file using a savefiledialog. i want to save it to a specific path (without using the savefiledialog)... how can i do that?
here's my code:
SaveFileDialog dialog = new SaveFileDialog();
dialog.DefaultExt = "*.html";
dialog.Filter = "WORD Document (*.html)|*.html";
if (dialog.ShowDialog() == true)
{
RadDocument document = CreateDocument(rgvReportData);
document.LayoutMode = DocumentLayoutMode.Paged;
document.Measure(RadDocument.MAX_DOCUMENT_SIZE);
document.Arrange(new RectangleF(PointF.Empty, document.DesiredSize));
document.SectionDefaultPageMargin = new Telerik.Windows.Documents.Layout.Padding(2, 2, 2, 2);
document.SectionDefaultPageOrientation = PageOrientation.Landscape;
HtmlFormatProvider provider = new HtmlFormatProvider();
using (Stream output = dialog.OpenFile())
{
provider.Export(document, output);
}
}
how can i sve it without using a savefiledialog?
using(StreamWriter output = new StreamWriter("path\to\your\file")) {
provider.Export(document, output);
}
will do the same thing, but to a specific path. You can read more on file access on MSDN.
String fileName = "youfilename.html"; // give the full path if required
RadDocument document = CreateDocument(rgvReportData);
document.LayoutMode = DocumentLayoutMode.Paged;
document.Measure(RadDocument.MAX_DOCUMENT_SIZE);
document.Arrange(new RectangleF(PointF.Empty, document.DesiredSize));
document.SectionDefaultPageMargin = new Telerik.Windows.Documents.Layout.Padding(2, 2, 2, 2);
document.SectionDefaultPageOrientation = PageOrientation.Landscape;
HtmlFormatProvider provider = new HtmlFormatProvider();
Stream output = File.Open(filename, FileMode.Open, FileAccess.ReadWrite);
provider.Export(document, output);
}
using (var output = new FileStream("path", FileMode.Create, FileAccess.Write))
{
provider.Export(document, output);
}
OpenFileDialog displays the specific path that you have choosen.
You could set the path of the SaveFileDialog, is not necessary to show the dialog like dialog.ShowDialog(), you have just to set the path like dialog.Filename = "file name".
And replace it like :
SaveFileDialog dialog = new SavefileDialog();
dialog.FileName = "path"; // like "C:\\someFolder\\someFile.html"
You could try it