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how to add text from textbox to split page in windows apps

Ive used a blank page where i have textboxes for a title, subtitle and for a description. Ive added a split page in my app and what i want to do is to be able to get the textbox text from the blank page and add it to the split page where it will be displayed with the details after clicking a button.
Ive checked out how to dynamically add items to a grid view but i want the items to be in the split page format where you click an item on the left side and the description comes to the right side.
Also saw in the splitpage.xaml.cs some TO DO parts where am supposed to bind data and handle selected items i.e
// TODO: Assign a bindable group to this.DefaultViewModel["Group"]
// TODO: Assign a collection of bindable items to this.DefaultViewModel["Items"]
// TODO: Invoke this.itemsViewSource.View.MoveCurrentTo() with the selected
// item as specified by the value of pageState["SelectedItem"]
// TODO: Derive a serializable navigation parameter and assign it to pageState["SelectedItem"]
My question is how do i do that or at least how to add the textbox data to the split page? Any help would be appreciated. Thanks

How to add textbox inside listview winform?

I'm working in Winform application.
I want to make a listview with multiple columns. In which the first column should contain string, the next column should contain textbox for input and output,the next column should contain button.
The main idea is the user should select the row with description,textbox,button. Once he selects the listview, he click on the button and a packet will be sended to device connected to ma com port and display the response in the textbox provided to that row in the listview.
It is possible to add multiple textboxes and buttons to all column.

Looks like your requirement is asking for DataGridView. Take a look at how to use the control on MSDN or any other place of your choice.

Allowing user to change column order of the datagrid view

I am using Win forms and have a databound DataGridView which has around 31 columns.
AllowUserToOrderColumn is set to true. But since the number of column is 31 its quite difficult for the user to move columns from one end to another.
so I want to create a form which will display all the columns of the datagridview and with the click of up down button allow them to change the order.
I have named my textBox(readonly) from textbox0 to textbox30.
Is there any way to display the column order in text boxes.
Like when we click EditColumns in the designer view.

Certainly:
Look at the DisplayIndex of the columns -> http://msdn.microsoft.com/en-us/library/wkfe535h.aspx
With this, you should be able to read them and change them by code.

Change label to textbox for edit

Have a look at this example first,
click here. I want you to see only the example of how he changed a label into text box after he hits edit.I want to make edit profile page but I don't want to use bind grid view. Is there any possible ways to retrieve some data from table in database to be shown in labels then when uset hits the edit button, the label will change to textbox?

why do you need to show a label ?
you can show it in a text box and set IsReadOnly or ReadOnly to true, set style to flat and remove border(it'll appear like a label), and then on the Edit Action, you can change this ReadOnly/Editable property.

Inserting new row in gridview using an external Add button and a list as data source

I have a grid with three columns, two of which contain drop-downs, all of them getting filled from a web service result set. Now I want to allow the functionality of adding a new record in the grid by clicking an Add button present outside the gridview.
Whenever the user clicks the Add button, a new record should be created in the grid with value list filled in the drop-downs with the available options.
What is the best possible way to achieve this considering extensibility in mind.
Thanks a lot!
P.S. The data source set for the grid is a list.

Add a blank item to the list, and rebind with this new list and dummy item. That's typically one way to do it, or store the insert form in the footer of the columns. I've used that approach.