I am opening a file using the OpenFileDialog in c# and I am noticing it is taking between 20-40 seconds to load my file and clear the dialog.
Here is my sample code:
private void btnOpen_Click(object sender, EventArgs e)
{
if (ofdSettings.ShowDialog() == DialogResult.OK)
{
// do nothing
}
}
even with this limited example it takes the 20-40 second duration for the dialog to clear.
the file i'm selecting is a xml file that is only 1.36kb large
I had the same problem, openFileDialog1.ShowDialog() was slow, taking 10 seconds after closing it to execute the next line of my program.
I noticed in the dialog that I had a couple old shortcuts under "Computer" pointing to webdav url's which were no longer valid. I deleted these shortcuts from windows explorer, and the program is fast now.
Check if you have any network connection shortcuts tied to your computer, which also display in the dialog (on the left-hand panel in Windows 7). Try removing them and see if the dialog is faster.
Another option which helped in my case:
OpenFileDialog ofd = new OpenFileDialog
{
...
AutoUpgradeEnabled = false
};
With this option, OpenFileDialog renders simpler UI, "pre-Vista" style according to MSDN article.
I also had this problem when I want to open a example.url file with file open dialog. It takes 0-10 seconds. Then I find out that this has something todo with the file type association (*.url) When I changed the association from default web browser to notepad++ the problem was gone. But I this was no solution for me, because when somebody clicked on a example.url, the default browser should open this file. To solve this I added DereferenceLinks = false.
OpenFileDialog ofd = new OpenFileDialog
{
...
DereferenceLinks = false
};
For me this solution works perfect
You can use a free tool like ProcExp (SysInternals.com) to monitor what your application is doing during the lag. Is it scanning the file system? The registry? The network (maybe it is trying to connect to a network share that is slow to respond).
BTW, you can run ProcExp.exe without installing it from http://live.sysinternals.com/!
Related
I saw the other topic and I'm having another problem. The process is starting (saw at task manager) but the folder is not opening on my screen. What's wrong?
System.Diagnostics.Process.Start("explorer.exe", #"c:\teste");
Have you made sure that the folder "c:\teste" exists? If it doesn't, explorer will open showing some default folder (in my case "C:\Users\[user name]\Documents").
Update
I have tried the following variations:
// opens the folder in explorer
Process.Start(#"c:\temp");
// opens the folder in explorer
Process.Start("explorer.exe", #"c:\temp");
// throws exception
Process.Start(#"c:\does_not_exist");
// opens explorer, showing some other folder)
Process.Start("explorer.exe", #"c:\does_not_exist");
If none of these (well, except the one that throws an exception) work on your computer, I don't think that the problem lies in the code, but in the environment. If that is the case, I would try one (or both) of the following:
Open the Run dialog, enter "explorer.exe" and hit enter
Open a command prompt, type "explorer.exe" and hit enter
Just for completeness, if all you want to do is to open a folder, use this:
System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo() {
FileName = "C:\\teste\\",
UseShellExecute = true,
Verb = "open"
});
Ensure FileName ends with Path.DirectorySeparatorChar to make it unambiguously point to a folder. (Thanks to #binki.)
This solution won't work for opening a folder and selecting an item, since there doesn't seem a verb for that.
If you want to select the file or folder you can use the following:
Process.Start("explorer.exe", "/select, c:\\teste");
You're using the # symbol, which removes the need for escaping your backslashes.
Remove the # or replace \\ with \
You don't need the double backslash when using unescaped strings:
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
You should use one of the System.Diagnostics.Process.Start() overloads. It's quite simple!
If you don't place the filename of the process you want to run (explorer.exe), the system will recognize it as a valid folder path and try to attach it to the already running Explorer process. In this case, if the folder is already open, Explorer will do nothing.
If you place the filename of the process (as you did), the system will try to run a new instance of the process, passing the second string as a parameter. If the string is a valid folder, it is opened on the newly created process, if not, the new process will do nothing.
I don't know how invalid folder paths are treated by the process in any case. Using System.IO.Directory.Exists() should be enough to ensure that.
Use an overloaded version of the method that takes a ProcessStartInfo instance and set the ProcessWindowStyle property to a value that works for you.
You're escaping the backslash when the at sign does that for you.
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
This code works fine from the VS2010 environment and opens the local folder properly, but if you host the same application in IIS and try to open then it will fail for sure.
Ive just had this issue, and i found out why. my reason isnt listed here so anyone else who gets this issue and none of these fix it.
If you run Visual Studio as another user and attempt to use Process.Start it will run in that users context and you will not see it on your screen.
Does it open correctly when you run "explorer.exe c:\teste" from your start menu? How long have you been trying this? I see a similar behavior when my machine has a lot of processes and when I open a new process(sets say IE)..it starts in the task manager but does not show up in the front end. Have you tried a restart?
The following code should open a new explorer instance
class sample{
static void Main()
{
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
}
}
Do you have a lot of applications running when you are trying this?
I encounter weird behavior at work sometimes because my system runs out of GDI Handles as I have so many windows open (our apps use alot).
When this happens, windows and context menus no long appear until I close something to free up some GDI handles.
The default limit in XP and Vista is 10000.
It is not uncommon for my DevStudio to have 1500 GDI handles, so if you have a couple of copies of Dev studio open, it can eat them up pretty quickly. You can add a column in TaskManager to see how many handles are being used by each process.
There is a registry tweak you can do to increase the limit.
For more information see http://msdn.microsoft.com/en-us/library/ms724291(VS.85).aspx
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
Just change the path or declare it in a string
In my WPF app the user needs to select a folder, which path is in the company network. I use the System.Windows.Forms.FolderBrowserDialog and the following code gets executed on a button click event:
FolderBrowserDialog fbd = new FolderBrowserDialog();
fbd.SelectedPath = "\\\\company.net\\data\\_Confidential";
DialogResult result = fbd.ShowDialog();
When the FolderBrowserDialog opens, the system automatically scans for other network devices and that causes the following problem:
The network tree gets filled with other devices and causes my SelectedPath to scroll away. This is pretty annoying when a user starts searching for a special subfolder, because he has to scroll down or his selection clicks can hit a newly added device (lost focus).
How can i avoid this problem?
Thoughts:
Can I extend/overwrite the System.Environment.SpecialFolder Enum and
set fbd.RootFolder = System.Environment.SpecialFolder.MySepcialNetworkPath;
Should I access the network folder with another dialog/control?
Should I remove the "Browse..." Button in my View and instead scan the whole \\\\company.net\\data\\_Confidential path and provide a combobox/other selection control(e.g. own subfolder-tree)?
The FolderBrowserDialog is 'adopting' your PC settings depending on how your Network Discovery is configured on your PC/network. By doing so your folder browsing experience will be consistent over other applications.
Although what you see is default behavior of the FolderBrowserDialog, you may also look at this: https://stackoverflow.com/a/15440926/5793786 Solved an issue somewhat similar to yours #Frank
While I was searching for the same problem I came across this thread:
How to use OpenFileDialog to select a folder?
Where the user uses a "CommonOpenFileDialog" available in the Nuget Package "WindowsAPICodePack-Shell".
This solved my issue, though it uses the OpenFileDialog interface.
Then the network drive can just be browsed.
Using the code described in this answer of the SO posting "Open folder and select the file", I've created this function:
public static void OpenExplorerAndSelectFile(string filePath)
{
Process.Start(
#"explorer.exe",
string.Format(#"/select, ""{0}""", filePath));
}
This function works well, with one small issue:
Calling the function for the first time for a specific file, Windows Explorer is correctly shown with the folder of the file, but it does not select the file.
Calling the same function again for the same file, it switches back to the already open folder in Windows Explorer and then it selects the file.
E.g. the first call to OpenExplorerAndSelectFile("C:\MyFolder\MyFile.txt") opens the folder "C:\MyFolder" in a new Windows Explorer Window. The second call to OpenExplorerAndSelectFile("C:\MyFolder\MyFile.txt") actually activates that Window again and selects MyFile.txt.
Doing something similar in e.g. Google Chrome (Going to the download page and showing a previously downloaded file) actually works well right in the first try.
So my conclusion is that Google Chrome seems to do it a bit different than I do.
My question:
Is there a way to debug/trace the Win32/Shell method that Google Chrome calls?
I would then compare them to what I do to see the differences.
Rather than the explorer command line Chrome most probably uses the more flexible SHOpenFolderAndSelectItems Shell API.
This answer contains the required p/invoke/implementation.
Try using the shell function "SHOpenFolderAndSelectItems".
I'm making a program which saves text documents and also opens them in the program in a textbox, the program works fine and I've managed to make it so I can save the files, and open them when giving the file name
However, I want to know if there's a way to open up explorer, then click the file and have it open in the program, I know Process.Start("explorer.exe"); is used to open explorer, but the files i open from there open in their default programs
If you know how to make it so text documents open in my program please let me know.
I think you need an OpenFileDialog control. which is basically a mini explorer that saves the file name you select in a property. Something like this should work:
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
DialogResult result = ofd.ShowDialog();
if(result != DialogResult.Cancel)
{
richTextBox1.Text = File.ReadAllText(ofd.FileName);
}
}
There's not really an easy way to do what you want (windows explorer integration and change the default 'open with' program). Even if it was easy, it'd be considered bad practice.
If you need your program open a file, the best option is to allow an user to open the file from the program. There's a control called OpenFileDialog in the tool box (assuming you're using WinForms that can do this). Work through this tutorial. It's a bit old, but should get you started.
I saw the other topic and I'm having another problem. The process is starting (saw at task manager) but the folder is not opening on my screen. What's wrong?
System.Diagnostics.Process.Start("explorer.exe", #"c:\teste");
Have you made sure that the folder "c:\teste" exists? If it doesn't, explorer will open showing some default folder (in my case "C:\Users\[user name]\Documents").
Update
I have tried the following variations:
// opens the folder in explorer
Process.Start(#"c:\temp");
// opens the folder in explorer
Process.Start("explorer.exe", #"c:\temp");
// throws exception
Process.Start(#"c:\does_not_exist");
// opens explorer, showing some other folder)
Process.Start("explorer.exe", #"c:\does_not_exist");
If none of these (well, except the one that throws an exception) work on your computer, I don't think that the problem lies in the code, but in the environment. If that is the case, I would try one (or both) of the following:
Open the Run dialog, enter "explorer.exe" and hit enter
Open a command prompt, type "explorer.exe" and hit enter
Just for completeness, if all you want to do is to open a folder, use this:
System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo() {
FileName = "C:\\teste\\",
UseShellExecute = true,
Verb = "open"
});
Ensure FileName ends with Path.DirectorySeparatorChar to make it unambiguously point to a folder. (Thanks to #binki.)
This solution won't work for opening a folder and selecting an item, since there doesn't seem a verb for that.
If you want to select the file or folder you can use the following:
Process.Start("explorer.exe", "/select, c:\\teste");
You're using the # symbol, which removes the need for escaping your backslashes.
Remove the # or replace \\ with \
You don't need the double backslash when using unescaped strings:
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
You should use one of the System.Diagnostics.Process.Start() overloads. It's quite simple!
If you don't place the filename of the process you want to run (explorer.exe), the system will recognize it as a valid folder path and try to attach it to the already running Explorer process. In this case, if the folder is already open, Explorer will do nothing.
If you place the filename of the process (as you did), the system will try to run a new instance of the process, passing the second string as a parameter. If the string is a valid folder, it is opened on the newly created process, if not, the new process will do nothing.
I don't know how invalid folder paths are treated by the process in any case. Using System.IO.Directory.Exists() should be enough to ensure that.
Use an overloaded version of the method that takes a ProcessStartInfo instance and set the ProcessWindowStyle property to a value that works for you.
You're escaping the backslash when the at sign does that for you.
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
This code works fine from the VS2010 environment and opens the local folder properly, but if you host the same application in IIS and try to open then it will fail for sure.
Ive just had this issue, and i found out why. my reason isnt listed here so anyone else who gets this issue and none of these fix it.
If you run Visual Studio as another user and attempt to use Process.Start it will run in that users context and you will not see it on your screen.
Does it open correctly when you run "explorer.exe c:\teste" from your start menu? How long have you been trying this? I see a similar behavior when my machine has a lot of processes and when I open a new process(sets say IE)..it starts in the task manager but does not show up in the front end. Have you tried a restart?
The following code should open a new explorer instance
class sample{
static void Main()
{
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
}
}
Do you have a lot of applications running when you are trying this?
I encounter weird behavior at work sometimes because my system runs out of GDI Handles as I have so many windows open (our apps use alot).
When this happens, windows and context menus no long appear until I close something to free up some GDI handles.
The default limit in XP and Vista is 10000.
It is not uncommon for my DevStudio to have 1500 GDI handles, so if you have a couple of copies of Dev studio open, it can eat them up pretty quickly. You can add a column in TaskManager to see how many handles are being used by each process.
There is a registry tweak you can do to increase the limit.
For more information see http://msdn.microsoft.com/en-us/library/ms724291(VS.85).aspx
System.Diagnostics.Process.Start("explorer.exe",#"c:\teste");
Just change the path or declare it in a string