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How to contact whole text from file into the string avoiding empty lines beetwen strings

How to get whole text from document contacted into the string. I'm trying to split text by dot: string[] words = s.Split('.'); I want take this text from text document. But if my text document contains empty lines between strings, for example:
pat said, “i’ll keep this ring.”
she displayed the silver and jade wedding ring which, in another time track,
she and joe had picked out; this
much of the alternate world she had elected to retain. he wondered what - if any - legal basis she had kept in addition. none, he hoped; wisely, however, he said nothing. better not even to ask.
result looks like this:
1. pat said ill keep this ring
2. she displayed the silver and jade wedding ring which in another time track
3. she and joe had picked out this
4. much of the alternate world she had elected to retain
5. he wondered what if any legal basis she had kept in addition
6. none he hoped wisely however he said nothing
7. better not even to ask
but desired correct output should be like this:
1. pat said ill keep this ring
2. she displayed the silver and jade wedding ring which in another time track she and joe had picked out this much of the alternate world she had elected to retain
3. he wondered what if any legal basis she had kept in addition
4. none he hoped wisely however he said nothing
5. better not even to ask
So to do this first I need to process text file content to get whole text as single string, like this:
pat said, “i’ll keep this ring.” she displayed the silver and jade wedding ring which, in another time track, she and joe had picked out; this much of the alternate world she had elected to retain. he wondered what - if any - legal basis she had kept in addition. none, he hoped; wisely, however, he said nothing. better not even to ask.
I can't to do this same way as it would be with list content for example: string concat = String.Join(" ", text.ToArray());,
I'm not sure how to contact text into string from text document

I think this is what you want:
var fileLocation = #"c:\\myfile.txt";
var stringFromFile = File.ReadAllText(fileLocation);
//replace Environment.NewLine with any new line character your file uses
var withoutNewLines = stringFromFile.Replace(Environment.NewLine, "");
//modify to remove any unwanted character
var withoutUglyCharacters = Regex.Replace(withoutNewLines, "[“’”,;-]", "");
var withoutTwoSpaces = withoutUglyCharacters.Replace(" ", " ");
var result = withoutTwoSpaces.Split('.').Where(i => i != "").Select(i => i.TrimStart()).ToList();
So first you read all text from your file, then you remove all unwanted characters and then split by . and return non empty items

Have you tried replacing double new-lines before splitting using a period?
static string[] GetSentences(string filePath) {
if (!File.Exists(filePath))
throw new FileNotFoundException($"Could not find file { filePath }!");
var lines = string.Join("", File.ReadLines(filePath).Where(line => !string.IsNullOrEmpty(line) && !string.IsNullOrWhiteSpace(line)));
var sentences = Regex.Split(lines, #"\.[\s]{1,}?");
return sentences;
}
I haven't tested this, but it should work.
Explanation:
if (!File.Exists(filePath))
throw new FileNotFoundException($"Could not find file { filePath }!");
Throws an exception if the file could not be found. It is advisory you surround the method call with a try/catch.
var lines = string.Join("", File.ReadLines(filePath).Where(line => !string.IsNullOrEmpty(line) && !string.IsNullOrWhiteSpace(line)));
Creates a string, and ignores any lines which are purely whitespace or empty.
var sentences = Regex.Split(lines, #".[\s]{1,}?");
Creates a string array, where the string is split at every period and whitespace following the period.
E.g:
The string "I came. I saw. I conquered" would become
I came
I saw
I conquered
Update:
Here's the method as a one-liner, if that's your style?
static string[] SplitSentences(string filePath) => File.Exists(filePath) ? Regex.Split(string.Join("", File.ReadLines(filePath).Where(line => !string.IsNullOrEmpty(line) && !string.IsNullOrWhiteSpace(line))), #"") : null;

I would suggest you to iterate through all characters and just check if they are in range of 'a' >= char <= 'z' or if char == ' '. If it matches the condition then add it to the newly created string else check if it is '.' character and if it is then end your line and add another one :
List<string> lines = new List<string>();
string line = string.Empty;
foreach(char c in str)
{
if((char.ToLower(c) >= 'a' && char.ToLower(c) <= 'z') || c == 0x20)
line += c;
else if(c == '.')
{
lines.Add(line.Trim());
line = string.Empty;
}
}
Working online example
Or if you prefer "one-liner"s :
IEnumerable<string> lines = new string(str.Select(c => (char)(((char.ToLower(c) >= 'a' && char.ToLower(c) <= 'z') || c == 0x20) ? c : c == '.' ? '\n' : '\0')).ToArray()).Split('\n').Select(s => s.Trim());

I may be wrong about this. I would think that you may not want to alter the string if you are splitting it. Example, there are double/single quote(s) (“) in part of the string. Removing them may not be desired which brings up the possibly of a question, reading a text file that contains single/double quotes (as your example data text shows) like below:
var stringFromFile = File.ReadAllText(fileLocation);
will not display those characters properly in a text box or the console because the default encoding using the ReadAllText method is UTF8. Example the single/double quotes will display (replacement characters) as diamonds in a text box on a form and will be displayed as a question mark (?) when displayed to the console. To keep the single/double quotes and have them display properly you can get the encoding for the OS’s current ANSI encoding by adding a parameter to the ReadAllText method like below:
string stringFromFile = File.ReadAllText(fileLocation, ASCIIEncoding.Default);
Below is code using a simple split method to .split the string on periods (.) Hope this helps.
private void button1_Click(object sender, EventArgs e) {
string fileLocation = #"C:\YourPath\YourFile.txt";
string stringFromFile = File.ReadAllText(fileLocation, ASCIIEncoding.Default);
string bigString = stringFromFile.Replace(Environment.NewLine, "");
string[] result = bigString.Split('.');
int count = 1;
foreach (string s in result) {
if (s != "") {
textBox1.Text += count + ". " + s.Trim() + Environment.NewLine;
Console.WriteLine(count + ". " + s.Trim());
count++;
}
else {
// period at the end of the string
}
}
}

c# Read/ Write CSV - excluding Comma in field Value [duplicate]

I am looking for suggestions on how to handle a csv file that is being created, then uploaded by our customers, and that may have a comma in a value, like a company name.
Some of the ideas we are looking at are: quoted Identifiers (value "," values ","etc) or using a | instead of a comma. The biggest problem is that we have to make it easy, or the customer won't do it.

There's actually a spec for CSV format, RFC 4180 and how to handle commas:
Fields containing line breaks (CRLF), double quotes, and commas should be enclosed in double-quotes.
http://tools.ietf.org/html/rfc4180
So, to have values foo and bar,baz, you do this:
foo,"bar,baz"
Another important requirement to consider (also from the spec):
If double-quotes are used to enclose fields, then a double-quote
appearing inside a field must be escaped by preceding it with
another double quote. For example:
"aaa","b""bb","ccc"

As others have said, you need to escape values that include quotes. Here’s a little CSV reader in C♯ that supports quoted values, including embedded quotes and carriage returns.
By the way, this is unit-tested code. I’m posting it now because this question seems to come up a lot and others may not want an entire library when simple CSV support will do.
You can use it as follows:
using System;
public class test
{
public static void Main()
{
using ( CsvReader reader = new CsvReader( "data.csv" ) )
{
foreach( string[] values in reader.RowEnumerator )
{
Console.WriteLine( "Row {0} has {1} values.", reader.RowIndex, values.Length );
}
}
Console.ReadLine();
}
}
Here are the classes. Note that you can use the Csv.Escape function to write valid CSV as well.
using System.IO;
using System.Text.RegularExpressions;
public sealed class CsvReader : System.IDisposable
{
public CsvReader( string fileName ) : this( new FileStream( fileName, FileMode.Open, FileAccess.Read ) )
{
}
public CsvReader( Stream stream )
{
__reader = new StreamReader( stream );
}
public System.Collections.IEnumerable RowEnumerator
{
get {
if ( null == __reader )
throw new System.ApplicationException( "I can't start reading without CSV input." );
__rowno = 0;
string sLine;
string sNextLine;
while ( null != ( sLine = __reader.ReadLine() ) )
{
while ( rexRunOnLine.IsMatch( sLine ) && null != ( sNextLine = __reader.ReadLine() ) )
sLine += "\n" + sNextLine;
__rowno++;
string[] values = rexCsvSplitter.Split( sLine );
for ( int i = 0; i < values.Length; i++ )
values[i] = Csv.Unescape( values[i] );
yield return values;
}
__reader.Close();
}
}
public long RowIndex { get { return __rowno; } }
public void Dispose()
{
if ( null != __reader ) __reader.Dispose();
}
//============================================
private long __rowno = 0;
private TextReader __reader;
private static Regex rexCsvSplitter = new Regex( #",(?=(?:[^""]*""[^""]*"")*(?![^""]*""))" );
private static Regex rexRunOnLine = new Regex( #"^[^""]*(?:""[^""]*""[^""]*)*""[^""]*$" );
}
public static class Csv
{
public static string Escape( string s )
{
if ( s.Contains( QUOTE ) )
s = s.Replace( QUOTE, ESCAPED_QUOTE );
if ( s.IndexOfAny( CHARACTERS_THAT_MUST_BE_QUOTED ) > -1 )
s = QUOTE + s + QUOTE;
return s;
}
public static string Unescape( string s )
{
if ( s.StartsWith( QUOTE ) && s.EndsWith( QUOTE ) )
{
s = s.Substring( 1, s.Length - 2 );
if ( s.Contains( ESCAPED_QUOTE ) )
s = s.Replace( ESCAPED_QUOTE, QUOTE );
}
return s;
}
private const string QUOTE = "\"";
private const string ESCAPED_QUOTE = "\"\"";
private static char[] CHARACTERS_THAT_MUST_BE_QUOTED = { ',', '"', '\n' };
}

The CSV format uses commas to separate values, values which contain carriage returns, linefeeds, commas, or double quotes are surrounded by double-quotes. Values that contain double quotes are quoted and each literal quote is escaped by an immediately preceding quote: For example, the 3 values:
test
list, of, items
"go" he said
would be encoded as:
test
"list, of, items"
"""go"" he said"
Any field can be quoted but only fields that contain commas, CR/NL, or quotes must be quoted.
There is no real standard for the CSV format, but almost all applications follow the conventions documented here. The RFC that was mentioned elsewhere is not a standard for CSV, it is an RFC for using CSV within MIME and contains some unconventional and unnecessary limitations that make it useless outside of MIME.
A gotcha that many CSV modules I have seen don't accommodate is the fact that multiple lines can be encoded in a single field which means you can't assume that each line is a separate record, you either need to not allow newlines in your data or be prepared to handle this.

Put double quotes around strings. That is generally what Excel does.
Ala Eli,
you escape a double quote as two
double quotes. E.g.
"test1","foo""bar","test2"

You can put double quotes around the fields. I don't like this approach, as it adds another special character (the double quote). Just define an escape character (usually backslash) and use it wherever you need to escape something:
data,more data,more data\, even,yet more
You don't have to try to match quotes, and you have fewer exceptions to parse. This simplifies your code, too.

There is a library available through nuget for dealing with pretty much any well formed CSV (.net) - CsvHelper
Example to map to a class:
var csv = new CsvReader( textReader );
var records = csv.GetRecords<MyClass>();
Example to read individual fields:
var csv = new CsvReader( textReader );
while( csv.Read() )
{
var intField = csv.GetField<int>( 0 );
var stringField = csv.GetField<string>( 1 );
var boolField = csv.GetField<bool>( "HeaderName" );
}
Letting the client drive the file format:
, is the standard field delimiter, " is the standard value used to escape fields that contain a delimiter, quote, or line ending.
To use (for example) # for fields and ' for escaping:
var csv = new CsvReader( textReader );
csv.Configuration.Delimiter = "#";
csv.Configuration.Quote = ''';
// read the file however meets your needs
More Documentation

In case you're on a *nix-system, have access to sed and there can be one or more unwanted commas only in a specific field of your CSV, you can use the following one-liner in order to enclose them in " as RFC4180 Section 2 proposes:
sed -r 's/([^,]*,[^,]*,[^,]*,)(.*)(,.*,.*)/\1"\2"\3/' inputfile
Depending on which field the unwanted comma(s) may be in you have to alter/extend the capturing groups of the regex (and the substitution).
The example above will enclose the fourth field (out of six) in quotation marks.
In combination with the --in-place-option you can apply these changes directly to the file.
In order to "build" the right regex, there's a simple principle to follow:
For every field in your CSV that comes before the field with the unwanted comma(s) you write one [^,]*, and put them all together in a capturing group.
For the field that contains the unwanted comma(s) you write (.*).
For every field after the field with the unwanted comma(s) you write one ,.* and put them all together in a capturing group.
Here is a short overview of different possible regexes/substitutions depending on the specific field. If not given, the substitution is \1"\2"\3.
([^,]*)(,.*) #first field, regex
"\1"\2 #first field, substitution
(.*,)([^,]*) #last field, regex
\1"\2" #last field, substitution
([^,]*,)(.*)(,.*,.*,.*) #second field (out of five fields)
([^,]*,[^,]*,)(.*)(,.*) #third field (out of four fields)
([^,]*,[^,]*,[^,]*,)(.*)(,.*,.*) #fourth field (out of six fields)
If you want to remove the unwanted comma(s) with sed instead of enclosing them with quotation marks refer to this answer.

As mentioned in my comment to harpo's answer, his solution is good and works in most cases, however in some scenarios when commas as directly adjacent to each other it fails to split on the commas.
This is because of the Regex string behaving unexpectedly as a vertabim string.
In order to get this behave correct, all " characters in the regex string need to be escaped manually without using the vertabim escape.
Ie. The regex should be this using manual escapes:
",(?=(?:[^\"\"]*\"\"[^\"\"]*\"\")*(?![^\"\"]*\"\"))"
which translates into ",(?=(?:[^""]*""[^""]*"")*(?![^""]*""))"
When using a vertabim string #",(?=(?:[^""]*""[^""]*"")*(?![^""]*""))" it behaves as the following as you can see if you debug the regex:
",(?=(?:[^"]*"[^"]*")*(?![^"]*"))"
So in summary, I recommend harpo's solution, but watch out for this little gotcha!
I've included into the CsvReader a little optional failsafe to notify you if this error occurs (if you have a pre-known number of columns):
if (_expectedDataLength > 0 && values.Length != _expectedDataLength)
throw new DataLengthException(string.Format("Expected {0} columns when splitting csv, got {1}", _expectedDataLength, values.Length));
This can be injected via the constructor:
public CsvReader(string fileName, int expectedDataLength = 0) : this(new FileStream(fileName, FileMode.Open, FileAccess.Read))
{
_expectedDataLength = expectedDataLength;
}

Add a reference to the Microsoft.VisualBasic (yes, it says VisualBasic but it works in C# just as well - remember that at the end it is all just IL).
Use the Microsoft.VisualBasic.FileIO.TextFieldParser class to parse CSV file Here is the sample code:
Dim parser As TextFieldParser = New TextFieldParser("C:\mar0112.csv")
parser.TextFieldType = FieldType.Delimited
parser.SetDelimiters(",")
While Not parser.EndOfData
'Processing row
Dim fields() As String = parser.ReadFields
For Each field As String In fields
'TODO: Process field
Next
parser.Close()
End While

You can use alternative "delimiters" like ";" or "|" but simplest might just be quoting which is supported by most (decent) CSV libraries and most decent spreadsheets.
For more on CSV delimiters and a spec for a standard format for describing delimiters and quoting see this webpage

If you're interested in a more educational exercise on how to parse files in general (using CSV as an example), you may check out this article by Julian Bucknall. I like the article because it breaks things down into much smaller problems that are much less insurmountable. You first create a grammar, and once you have a good grammar, it's a relatively easy and methodical process to convert the grammar into code.
The article uses C# and has a link at the bottom to download the code.

If you feel like reinventing the wheel, the following may work for you:
public static IEnumerable<string> SplitCSV(string line)
{
var s = new StringBuilder();
bool escaped = false, inQuotes = false;
foreach (char c in line)
{
if (c == ',' && !inQuotes)
{
yield return s.ToString();
s.Clear();
}
else if (c == '\\' && !escaped)
{
escaped = true;
}
else if (c == '"' && !escaped)
{
inQuotes = !inQuotes;
}
else
{
escaped = false;
s.Append(c);
}
}
yield return s.ToString();
}

In Europe we have this problem must earlier than this question. In Europe we use all a comma for a decimal point. See this numbers below:
| American | Europe |
| ------------- | ------------- |
| 0.5 | 0,5 |
| 3.14159265359 | 3,14159265359 |
| 17.54 | 17,54 |
| 175,186.15 | 175.186,15 |
So it isn't possible to use the comma separator for CSV files. Because of that reason, the CSV files in Europe are separated by a semicolon (;).
Programs like Microsoft Excel can read files with a semicolon and it's possible to switch from separator. You could even use a tab (\t) as separator. See this answer from Supper User.

Here's a neat little workaround:
You can use a Greek Lower Numeral Sign instead (U+0375)
It looks like this ͵
Using this method saves you a lot of resources too...

I know it's almost 13 years later, but we came across a similar situation where the client inputs us a CSV and has values with commas, there are 2 use cases:
If the client uses a windows Excel client to write the CSV (usually that's the case in windows environment) then commas are automatically added to the value.
The actual text value of the CSV:
3786962,1st Meridian Care Services,John,"Person A,Person B, Person C, Person D",Voyager
If the client is sending you the excel programmatically, then he should adhere to RFC4180 and enclose the value with "quotes". example:
Col1, Col2, "a, b, c", Col4

Just use SoftCircuits.CsvParser on NuGet. It will handle all those details for you and efficiently handles very large files. And, if needed, it can even import/export objects by mapping columns to object properties. In addition, my testing showed it averages nearly 4 times faster than the popular CsvHelper.

You can read the csv file like this.
this makes use of splits and takes care of spaces.
ArrayList List = new ArrayList();
static ServerSocket Server;
static Socket socket;
static ArrayList<Object> list = new ArrayList<Object>();
public static void ReadFromXcel() throws FileNotFoundException
{
File f = new File("Book.csv");
Scanner in = new Scanner(f);
int count =0;
String[] date;
String[] name;
String[] Temp = new String[10];
String[] Temp2 = new String[10];
String[] numbers;
ArrayList<String[]> List = new ArrayList<String[]>();
HashMap m = new HashMap();
in.nextLine();
date = in.nextLine().split(",");
name = in.nextLine().split(",");
numbers = in.nextLine().split(",");
while(in.hasNext())
{
String[] one = in.nextLine().split(",");
List.add(one);
}
int xount = 0;
//Making sure the lines don't start with a blank
for(int y = 0; y<= date.length-1; y++)
{
if(!date[y].equals(""))
{
Temp[xount] = date[y];
Temp2[xount] = name[y];
xount++;
}
}
date = Temp;
name =Temp2;
int counter = 0;
while(counter < List.size())
{
String[] list = List.get(counter);
String sNo = list[0];
String Surname = list[1];
String Name = list[2];
for(int x = 3; x < list.length; x++)
{
m.put(numbers[x], list[x]);
}
Object newOne = new newOne(sNo, Name, Surname, m, false);
StudentList.add(s);
System.out.println(s.sNo);
counter++;
}

I generally URL-encode the fields which can have any commas or any special chars. And then decode it when it is being used/displayed in any visual medium.
(commas becomes %2C)
Every language should have methods to URL-encode and decode strings.
e.g., in java
URLEncoder.encode(myString,"UTF-8"); //to encode
URLDecoder.decode(myEncodedstring, "UTF-8"); //to decode
I know this is a very general solution and it might not be ideal for situation where user wants to view content of csv file, manually.

I usually do this in my CSV files parsing routines. Assume that 'line' variable is one line within a CSV file and all of the columns' values are enclosed in double quotes. After the below two lines execute, you will get CSV columns in the 'values' collection.
// The below two lines will split the columns as well as trim the DBOULE QUOTES around values but NOT within them
string trimmedLine = line.Trim(new char[] { '\"' });
List<string> values = trimmedLine.Split(new string[] { "\",\"" }, StringSplitOptions.None).ToList();

The simplest solution I've found is the one LibreOffice uses:
Replace all literal " by ”
Put double quotes around your string
You can also use the one that Excel uses:
Replace all literal " by ""
Put double quotes around your string
Notice other people recommended to do only step 2 above, but that doesn't work with lines where a " is followed by a ,, like in a CSV where you want to have a single column with the string hello",world, as the CSV would read:
"hello",world"
Which is interpreted as a row with two columns: hello and world"

public static IEnumerable<string> LineSplitter(this string line, char
separator, char skip = '"')
{
var fieldStart = 0;
for (var i = 0; i < line.Length; i++)
{
if (line[i] == separator)
{
yield return line.Substring(fieldStart, i - fieldStart);
fieldStart = i + 1;
}
else if (i == line.Length - 1)
{
yield return line.Substring(fieldStart, i - fieldStart + 1);
fieldStart = i + 1;
}
if (line[i] == '"')
for (i++; i < line.Length && line[i] != skip; i++) { }
}
if (line[line.Length - 1] == separator)
{
yield return string.Empty;
}
}

I used Csvreader library but by using that I got data by exploding from comma(,) in column value.
So If you want to insert CSV file data which contains comma(,) in most of the columns values, you can use below function.
Author link => https://gist.github.com/jaywilliams/385876
function csv_to_array($filename='', $delimiter=',')
{
if(!file_exists($filename) || !is_readable($filename))
return FALSE;
$header = NULL;
$data = array();
if (($handle = fopen($filename, 'r')) !== FALSE)
{
while (($row = fgetcsv($handle, 1000, $delimiter)) !== FALSE)
{
if(!$header)
$header = $row;
else
$data[] = array_combine($header, $row);
}
fclose($handle);
}
return $data;
}

I used papaParse library to have the CSV file parsed and have the key-value pairs(key/header/first row of CSV file-value).
here is example that I use:
https://codesandbox.io/embed/llqmrp96pm
it has dummy.csv file in there to have the CSV parsing demo.
I've used it within reactJS though it is easy and simple to replicate in app written with any language.

An example might help to show how commas can be displayed in a .csv file. Create a simple text file as follows:
Save this text file as a text file with suffix ".csv" and open it with Excel 2000 from Windows 10.
aa,bb,cc,d;d
"In the spreadsheet presentation, the below line should look like the above line except the below shows a displayed comma instead of a semicolon between the d's."
aa,bb,cc,"d,d", This works even in Excel
aa,bb,cc,"d,d", This works even in Excel 2000
aa,bb,cc,"d ,d", This works even in Excel 2000
aa,bb,cc,"d , d", This works even in Excel 2000
aa,bb,cc, " d,d", This fails in Excel 2000 due to the space belore the 1st quote
aa,bb,cc, " d ,d", This fails in Excel 2000 due to the space belore the 1st quote
aa,bb,cc, " d , d", This fails in Excel 2000 due to the space belore the 1st quote
aa,bb,cc,"d,d " , This works even in Excel 2000 even with spaces before and after the 2nd quote.
aa,bb,cc,"d ,d " , This works even in Excel 2000 even with spaces before and after the 2nd quote.
aa,bb,cc,"d , d " , This works even in Excel 2000 even with spaces before and after the 2nd quote.
Rule: If you want to display a comma in a a cell (field) of a .csv file:
"Start and end the field with a double quotes, but avoid white space before the 1st quote"

As this is about general practices let's start from rules of the thumb:
Don't use CSV, use XML with a library to read & write the xml file instead.
If you must use CSV. Do it properly and use a free library to parse and store the CSV files.
To justify 1), most CSV parsers aren't encoding aware so if you aren't dealing with US-ASCII you are asking for troubles.
For example excel 2002 is storing the CSV in local encoding without any note about the encoding. The CSV standard isn't widely adopted :(.
On the other hand xml standard is well adopted and it handles encodings pretty well.
To justify 2), There is tons of csv parsers around for almost all language so there is no need to reinvent the wheel even if the solutions looks pretty simple.
To name few:
for python use build in csv module
for perl check CPAN and Text::CSV
for php use build in fgetcsv/fputcsv functions
for java check SuperCVS library
Really there is no need to implement this by hand if you aren't going to parse it on embedded device.

First, let's ask ourselves, "Why do we feel the need to handle commas differently for CSV files?"
For me, the answer is, "Because when I export data into a CSV file, the commas in a field disappear and my field gets separated into multiple fields where the commas appear in the original data." (That it because the comma is the CSV field separator character.)
Depending on your situation, semi colons may also be used as CSV field separators.
Given my requirements, I can use a character, e.g., single low-9 quotation mark, that looks like a comma.
So, here's how you can do it in Go:
// Replace special CSV characters with single low-9 quotation mark
func Scrub(a interface{}) string {
s := fmt.Sprint(a)
s = strings.Replace(s, ",", "‚", -1)
s = strings.Replace(s, ";", "‚", -1)
return s
}
The second comma looking character in the Replace function is decimal 8218.
Be aware that if you have clients that may have ascii-only text readers that this decima 8218 character will not look like a comma. If this is your case, then I'd recommend surrounding the field with the comma (or semicolon) with double quotes per RFC 4128: https://www.rfc-editor.org/rfc/rfc4180

Thank you others in this post.
I used the information here to create a function in JavaScript that will get csv output for an array of objects which may have property values containing commas.
like
rowsArray = [{obj1prop1: "foo", obj1prop2: "bar,baz"}, {obj2prop1: "qux", obj2prop2: "quux,corge,thud"}]
into
csvRowsArray = [{obj1prop1: "foo", obj1prop2: "\"bar,baz\""}, {...} ]
To use the commas in the values in a csv, the value needs to be wrapped in double quotes. And in order to have double quotes in the value in the json object, they just need to be escaped, i.e., \", backslash double quote. The escape is made here by subbing in a template literal and including the necessary quotes `"${row[key]}"`. The quotes are escaped when put in the object.
Here is my function:
const calculateTheCSVExport = (props) => {
if (props.rows === undefined) return;
let jsonRowsArray = props.rows;
// console.log(jsonRowsArray);
let csvRowsArrayNoCommasInObjectValues = [];
let csvCurrRowObject = {}
jsonRowsArray.forEach(row => {
Object.keys(row).forEach(key => {
// console.log(key, row[key])
if (row[key].indexOf(',') > -1) {
csvCurrRowObject = {...csvCurrRowObject, [key]: `"${row[key]}"`} // enclose value in escaped double quotes in JSON in order to export commas to csv correctly. see more: https://stackoverflow.com/questions/769621/dealing-with-commas-in-a-csv-file
} else {
csvCurrRowObject = {...csvCurrRowObject, [key]: row[key]}
}
});
csvRowsArrayNoCommasInObjectValues.push(csvCurrRowObject);
csvCurrRowObject = {};
})
// console.log(csvRowsArrayNoCommasInObjectValues)
return csvRowsArrayNoCommasInObjectValues;
}

I think the easiest solution to this problem is to have the customer to open the csv in excel, and then ctrl + r to replace all comma with whatever identifier you want. This is very easy for the customer and require only one change in your code to read the delimiter of your choice.

Use a tab character (\t) to separate the fields.

why regex split add to pattern \r\n

I want to split the body of article by html div tag so I have a pattern to search div.
the problem is that the pattern also split \r\n
[enter image description here][1]
string pattern = #"<div[^<>]*>(.*?)</div>";
string[] bodyParagraphsnew = Regex.Split(body, pattern,RegexOptions.None);
Response.Write("num of paragraph =" + bodyParagraphsnew.Length);
for (int i = 0; i < bodyParagraphsnew.Length; i++)
{
Response.Write("bodyParagraphs" + i + "= " + bodyParagraphsnew[i]+ Environment.NewLine);
}
When I debug this code I see a lot of "\r\n" in the array bodyParagraphsnew.
Its seen that the pattern include split by the string "\r\n"
I try to replace \r\n to string empty and i hoped that bodyParagraphsnew length will change.but not.I got instead of item(in array) that contain \r\n it contain ""
WHY?
here is link to image http://i.stack.imgur.com/Hxqki.gif that explain the problem

What you are seeing is the text that is between the end of the first </div> tag and the start of the next <div> tag. This is what Split does, it finds the text between the Regular Expression matches.
What is curious here though is that you are also going to get the text between the open and close tags because you put brackets in your string forming a capturing group. Consider the following program:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
string body = "<div>some text</div>\r\n<div>some more text</div>";
string pattern = #"<div[^>]*?>(.*?)</div>";
string[] bodyParagraphsnew = Regex.Split(body, pattern, RegexOptions.None);
Console.WriteLine("num of paragraph =" + bodyParagraphsnew.Length);
for (int i = 0; i < bodyParagraphsnew.Length; i++)
{
Console.WriteLine("bodyParagraphs {0}: '{1}'", i, bodyParagraphsnew[i]);
}
}
}
What you will get from this is:
"" - An empty string taken from before the first <div>.
"some text" - The contents of the first <div>, because of the capturing group.
"\r\n" - The text between the end of the first </div> and the start of the last <div>.
"some more text" - The contents of the second div, again because of the capturing group.
"" - An empty string taken from after the last </div>.
What you are probably after is the contents of the div tags. This can kind of be achieved using this code:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
string body = "<div>some text</div>\r\n<div>some more text</div>";
string pattern = #"<div[^>]*?>(.*?)</div>";
MatchCollection bodyParagraphsnew = Regex.Matches(body, pattern, RegexOptions.None);
Console.WriteLine("num of paragraph =" + bodyParagraphsnew.Count);
for (int i = 0; i < bodyParagraphsnew.Count; i++)
{
Console.WriteLine("bodyParagraphs {0}: '{1}'", i, bodyParagraphsnew[i].Groups[1].Value);
}
}
}
Note however that in HTML, div tags can be nested within each other. For example, the following is a valid HTML string:
string test = "<div>Outer div<div>inner div</div>outer div again</div>";
With this kind of situation Regular expressions are not going to work! This is largely due to HTML not being a Regular Language. To deal with this situation you are going to need to write a Parser (of which regular expressions are only a small part). However personally I wouldn't bother as there are plenty of open source HTML parsers already available HTML Agility Pack for example.

Two possibilies
you use llist instead of array and list.remove
you go through your array search for \r\n and remove it by index
if(bodyParagraphsnew[i] == "\r\n")
{
bodyParagraphsnew = bodyParagraphsnew.Where(w => w != bodyParagraphsnew[i]).ToArray();
}
Not very nice but maybe it is what you were looking for

How to split at every second quotation mark

I have a string that looks like this
2,"E2002084700801601390870F"
3,"E2002084700801601390870F"
1,"E2002084700801601390870F"
4,"E2002084700801601390870F"
3,"E2002084700801601390870F"
This is one whole string, you can imagine it being on one row.
And I want to split this in the way they stand right now like this
2,"E2002084700801601390870F"
I cannot change the way it is formatted. So my best bet is to split at every second quotation mark. But I haven't found any good ways to do this. I've tried this https://stackoverflow.com/a/17892392/2914876 But I only get an error about invalid arguements.
Another issue is that this project is running .NET 2.0 so most LINQ functions aren't available.
Thank you.

Try this
var regEx = new Regex(#"\d+\,"".*?""");
var lines = regex.Matches(txt).OfType<Match>().Select(m => m.Value).ToArray();
Use foreach instead of LINQ Select on .Net 2
Regex regEx = new Regex(#"\d+\,"".*?""");
foreach(Match m in regex.Matches(txt))
{
var curLine = m.Value;
}

I see three possibilities, none of them are particularly exciting.
As #dvnrrs suggests, if there's no comma where you have line-breaks, you should be in great shape. Replace ," with something novel. Replace the remaining "s with what you need. Replace the "something novel" with ," to restore them. This is probably the most solid--it solves the problem without much room for bugs.
Iterate through the string looking for the index of the next " from the previous index, and maintain a state machine to decide whether to manipulate it or not.
Split the string on "s and rejoin them in whatever way works the best for your application.

I realize regular expressions will handle this but here's a pure 2.0 way to handle as well. It's much more readable and maintainable in my humble opinion.
using System;
using System.Collections.Generic;
namespace ConsoleApplication1
{
internal class Program
{
private static void Main(string[] args)
{
const string data = #"2,""E2002084700801601390870F""3,""E2002084700801601390870F""1,""E2002084700801601390870F""4,""E2002084700801601390870F""3,""E2002084700801601390870F""";
var parsedData = ParseData(data);
foreach (var parsedDatum in parsedData)
{
Console.WriteLine(parsedDatum);
}
Console.ReadLine();
}
private static IEnumerable<string> ParseData(string data)
{
var results = new List<string>();
var split = data.Split(new [] {'"'}, StringSplitOptions.RemoveEmptyEntries);
if (split.Length % 2 != 0)
{
throw new Exception("Data Formatting Error");
}
for (var index = 0; index < split.Length / 2; index += 2)
{
results.Add(string.Format(#"""{0}""{1}""", split[index], split[index + 1]));
}
return results;
}
}
}

Highlight a list of words using a regular expression in c#

I have some site content that contains abbreviations. I have a list of recognised abbreviations for the site, along with their explanations. I want to create a regular expression which will allow me to replace all of the recognised abbreviations found in the content with some markup.
For example:
content: This is just a little test of the memb to see if it gets picked up.
Deb of course should also be caught here.
abbreviations: memb = Member; deb = Debut;
result: This is just a little test of the [a title="Member"]memb[/a] to see if it gets picked up.
[a title="Debut"]Deb[/a] of course should also be caught here.
(This is just example markup for simplicity).
Thanks.
EDIT:
CraigD's answer is nearly there, but there are issues. I only want to match whole words. I also want to keep the correct capitalisation of each word replaced, so that deb is still deb, and Deb is still Deb as per the original text. For example, this input:
This is just a little test of the memb.
And another memb, but not amemba.
Deb of course should also be caught here.deb!

First you would need to Regex.Escape() all the input strings.
Then you can look for them in the string, and iteratively replace them by the markup you have in mind:
string abbr = "memb";
string word = "Member";
string pattern = String.Format("\b{0}\b", Regex.Escape(abbr));
string substitue = String.Format("[a title=\"{0}\"]{1}[/a]", word, abbr);
string output = Regex.Replace(input, pattern, substitue);
EDIT: I asked if a simple String.Replace() wouldn't be enough - but I can see why regex is desirable: you can use it to enforce "whole word" replacements only by making a pattern that uses word boundary anchors.
You can go as far as building a single pattern from all your escaped input strings, like this:
\b(?:{abbr_1}|{abbr_2}|{abbr_3}|{abbr_n})\b
and then using a match evaluator to find the right replacement. This way you can avoid iterating the input string more than once.

Not sure how well this will scale to a big word list, but I think it should give the output you want (although in your question the 'result' seems identical to 'content')?
Anyway, let me know if this is what you're after
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
var input = #"This is just a little test of the memb to see if it gets picked up.
Deb of course should also be caught here.";
var dictionary = new Dictionary<string,string>
{
{"memb", "Member"}
,{"deb","Debut"}
};
var regex = "(" + String.Join(")|(", dictionary.Keys.ToArray()) + ")";
foreach (Match metamatch in Regex.Matches(input
, regex /*#"(memb)|(deb)"*/
, RegexOptions.IgnoreCase | RegexOptions.ExplicitCapture))
{
input = input.Replace(metamatch.Value, dictionary[metamatch.Value.ToLower()]);
}
Console.Write (input);
Console.ReadLine();
}
}
}

For anyone interested, here is my final solution. It is for a .NET user control. It uses a single pattern with a match evaluator, as suggested by Tomalak, so there is no foreach loop. It's an elegant solution, and it gives me the correct output for the sample input while preserving correct casing for matched strings.
public partial class Abbreviations : System.Web.UI.UserControl
{
private Dictionary<String, String> dictionary = DataHelper.GetAbbreviations();
protected void Page_Load(object sender, EventArgs e)
{
string input = "This is just a little test of the memb. And another memb, but not amemba to see if it gets picked up. Deb of course should also be caught here.deb!";
var regex = "\\b(?:" + String.Join("|", dictionary.Keys.ToArray()) + ")\\b";
MatchEvaluator myEvaluator = new MatchEvaluator(GetExplanationMarkup);
input = Regex.Replace(input, regex, myEvaluator, RegexOptions.IgnoreCase);
litContent.Text = input;
}
private string GetExplanationMarkup(Match m)
{
return string.Format("<b title='{0}'>{1}</b>", dictionary[m.Value.ToLower()], m.Value);
}
}
The output looks like this (below). Note that it only matches full words, and that the casing is preserved from the original string:
This is just a little test of the <b title='Member'>memb</b>. And another <b title='Member'>memb</b>, but not amemba to see if it gets picked up. <b title='Debut'>Deb</b> of course should also be caught here.<b title='Debut'>deb</b>!

I doubt it will perform better than just doing normal string.replace, so if performance is critical measure (refactoring a bit to use a compiled regex). You can do the regex version as:
var abbrsWithPipes = "(abbr1|abbr2)";
var regex = new Regex(abbrsWithPipes);
return regex.Replace(html, m => GetReplaceForAbbr(m.Value));
You need to implement GetReplaceForAbbr, which receives the specific abbr being matched.

I'm doing pretty exactly what you're looking for in my application and this works for me:
the parameter str is your content:
public static string GetGlossaryString(string str)
{
List<string> glossaryWords = GetGlossaryItems();//this collection would contain your abbreviations; you could just make it a Dictionary so you can have the abbreviation-full term pairs and use them in the loop below
str = string.Format(" {0} ", str);//quick and dirty way to also search the first and last word in the content.
foreach (string word in glossaryWords)
str = Regex.Replace(str, "([\\W])(" + word + ")([\\W])", "$1<span class='glossaryItem'>$2</span>$3", RegexOptions.IgnoreCase);
return str.Trim();
}