I want to get a number from the user, and then multiply that number with Pi. my attempt at this is below. But a contains gibberish. For example, if I insert 22, then a contains 50. What am I doing wrong? I don't get any compiler errors.
double a,b;
a = Console.Read();
b = a * Math.PI;
Console.WriteLine(b);
I'm not sure what your problem is (since you haven't told us), but I'm guessing at
a = Console.Read();
This will only read one character from your Console.
You can change your program to this. To make it more robust, accept more than 1 char input, and validate that the input is actually a number:
double a, b;
Console.WriteLine("istenen sayıyı sonuna .00 koyarak yaz");
if (double.TryParse(Console.ReadLine(), out a)) {
b = a * Math.PI;
Console.WriteLine("Sonuç " + b);
} else {
//user gave an illegal input. Handle it here.
}
a = double.Parse(Console.ReadLine());
Beware that if the user enters something that cannot be parsed to a double, an exception will be thrown.
Edit:
To expand on my answer, the reason it's not working for you is that you are getting an input from the user in string format, and trying to put it directly into a double. You can't do that. You have to extract the double value from the string first.
If you'd like to perform some sort of error checking, simply do this:
if ( double.TryParse(Console.ReadLine(), out a) ) {
Console.Writeline("Sonuç "+ a * Math.PI;);
}
else {
Console.WriteLine("Invalid number entered. Please enter number in format: #.#");
}
Thanks to Öyvind and abatischev for helping me refine my answer.
string input = Console.ReadLine();
double d;
if (!Double.TryParse(input, out d))
Console.WriteLine("Wrong input");
double r = d * Math.Pi;
Console.WriteLine(r);
The main reason of different input/output you're facing is that Console.Read() returns char code, not a number you typed! Learn how to use MSDN.
I think there are some compiler errors.
Writeline should be WriteLine (capital 'L')
missing semicolon at the end of a line
double a, b;
Console.WriteLine("istenen sayıyı sonuna .00 koyarak yaz");
a = double.Parse(Console.ReadLine());
b = a * Math.PI; // Missing colon!
Console.WriteLine("Sonuç " + b);
string str = Console.ReadLine(); //Reads a character from console
double a = double.Parse(str); //Converts str into the type double
double b = a * Math.PI; // Multiplies by PI
Console.WriteLine("{0}", b); // Writes the number to console
Console.Read() reads a string from console A SINGLE CHARACTER AT A TIME (but waits for an enter before going on. You normally use it in a while cycle). So if you write 25 + Enter, it will return the unicode value of 2 that is 50. If you redo a second Console.Read() it will return immediately with 53 (the unicode value of 5). A third and a fourth Console.Read() will return the end of line/carriage characters. A fifth will wait for new input.
Console.ReadLine() reads a string (so then you need to change the string to a double)
Sometime in the future .NET4.6
//for Double
double inputValues = double.Parse(Console.ReadLine());
//for Int
int inputValues = int.Parse(Console.ReadLine());
double a,b;
Console.WriteLine("istenen sayıyı sonuna .00 koyarak yaz");
try
{
a = Convert.ToDouble(Console.ReadLine());
b = a * Math.PI;
Console.WriteLine("Sonuç " + b);
}
catch (Exception)
{
Console.WriteLine("dönüştürme hatası");
throw;
}
Console.Read() takes a character and returns the ascii value of that character.So if you want to take the symbol that was entered by the user instead of its ascii value (ex:if input is 5 then symbol = 5, ascii value is 53), you have to parse it using int.parse() but it raises a compilation error because the return value of Console.Read() is already int type. So you can get the work done by using Console.ReadLine() instead of Console.Read() as follows.
int userInput = int.parse(Console.ReadLine());
here, the output of the Console.ReadLine() would be a string containing a number such as "53".By passing it to the int.Parse() we can convert it to int type.
You're missing a semicolon: double b = a * Math.PI;
Related
So, I'm creating a simple calculator getting started into programming in C# and I've had two issues so far that I have not been able to solve.
The first being that for some reason, of all operators/symbols, it won't let me add the "-" operator/symbol alongside a string. It only allows me to have the "-" operator with my variables alone. (I tried using double instead of decimal but got the same error).
The second (and more important) being that I'm trying to have an if statement that gives a message (and run another method) when the user inputs the wrong data type. Any way to solve this (or at least find a work-a-round)?
Thanks!
Here's a sample of the code containing both issues:
static void Calc()
{
Console.Write("\n\nPlease enter a number here: ");
decimal num1 = Convert.ToDecimal(Console.ReadLine());
Console.Write("Please Specify an operator: ");
string op = Console.ReadLine();
Console.Write("Please enter another number: ");
decimal num2 = Convert.ToDecimal(Console.ReadLine());
if (op == "+")
{
Console.WriteLine("The answer is: " + num1 + num2);
}
else if (op == "-")
{
Console.WriteLine("The answer is: " + num1 - num2);
}
else if (op == "*")
{
Console.WriteLine("The answer is: " + num1 * num2);
}
else if (op == "/")
{
Console.WriteLine("The answer is: " + num1 / num2);
}
else
{
OpElse();
}
if (num1 || num2 != Decimal)
{
Console.WriteLine("You must input a number");
Else();
}
I'm trying to have an if statement that gives a message (and run another method) when the user inputs the wrong data type. Any way to solve this (or at least find a work-a-round)?
You can try the Decimal.TryParse method, which will attempt to parse a string to a decimal, but wont throw an exception if it fails. It would look something like this:
if (!Decimal.TryParse(Console.ReadLine(), out decimal num1))
{
Console.WriteLine("No no my friend. You have to enter a valid number.");
}
..of all operators/symbols, it won't let me add the "-" operator/symbol alongside a string. It only allows me to have the "-" operator with my variables alone. (I tried using double instead of decimal but got the same error).
That has to do with operator precedence. In fact, even though minus is the only one that complains at compile time, the addition gives you are wrong result at runtime. The problem is just that the (first) + is being evaluated before the -. That results in the first number being added to the string, before doing the calculation. To fix this, simply wrap the calculation part in parenthesis:
Console.WriteLine("The answer is: " + (num1 - num2));
or move the calculation out of the string concatenation:
var result = num1 + num2;
Console.WriteLine("The answer is: " + result);
In the line:
Console.WriteLine("The answer is: " + num1 - num2);
It will add firstly num1 to the string, and then will try to subtract number from string, which is invalid. Use parenthesis "some string" + (num1 - num2)
Same error will happen with addition as well, for example: "a" + 5 + 2 will result in: a52
To check if entered data is incorrect, TryParse can be used, or same Convert.ToDecimal but with try catch
Console.Write("\n\nPlease enter a number here: ");
decimal num2 = 0; // Assigning default value so compiler doesn't comlain
try
{
num2 = Convert.ToDecimal(Console.ReadLine());
}
catch (FormatException e)
{
//do something else
}
num1 and num2 are always going to be decimal type so checking if their type is a decimal is unnecessary. If you want to display a message when parsing fails, look into using decimal#TryParse() which will return true if it parsed correctly, false if not.
As for your - sign issue. I'm not too sure what you mean but I'm assuming you're trying to do something like -"some string" which is invalid C# code. Decimal could convert negative numbers just fine when typed out, assuming you don't put a space between the minus and the number itself.
Or if you're trying to do something like "num1 - num2" that won't work unless you use string interpolation $"{num1+num2}" for an example
You correctly pointed out two problems:
1. Operator Failure
The + - * / operators. Remember order of operations, * / are first, + - are second, then left to right in groups of equal order. So in the write statements the * / get executed before the +. Resulting string + decimal, and since there is implicit converter from decimal to string the + operator acts as a concatenation.
In the case of - the order is string + decimal - decimal, which from left to right means the first + concatenates two strings. However, - is not an operator on string and therefore fails.
Try using the $"Answer is: {num1 + num2}" syntax for each case (changing the operator as required).
2. Logic Failure
You are converting and throwing a runtime exception in the Parse method prior to the tests and out put. As suggested, use TryParse and place the error case at the top.
This question already has answers here:
Difference between Console.Read() and Console.ReadLine()?
(12 answers)
Closed 1 year ago.
I don't get why my integer isn't coming out correctly, Console.Read() method says it's returning an integer, why isn't WriteLine displaying it correctly?
int dimension;
dimension = Console.Read();
Console.WriteLine(""+ dimension);
Console.Read() only returns the first character of what was typed. You should be using Console.ReadLine():
Example:
int suppliedInt;
Console.WriteLine("Please enter a number greater than zero");
Int32.TryParse(Console.ReadLine(), out suppliedInt);
if (suppliedInt > 0) {
Console.WriteLine("You entered: " + suppliedInt);
}
else {
Console.WriteLine("You entered an invalid number. Press any key to exit");
}
Console.ReadLine();
Additional Resources:
MSDN - Console.Read()
MSDN - Console.ReadLine()
From the MSDN:
Return Value
Type: System.Int32 The next character from the input stream, or
negative one (-1) if there are currently no more characters to be
read.
Your program is returning but you're not seeing, would you please see below code block:
You are not be able to see the output if the output window doesn't stay.
int dimension;
dimension = Console.Read();
Console.WriteLine("" + dimension);
Console.ReadLine();
Console.Read() returns ASCII code of first symbol in input. You can do
int dimension;
dimension = Console.Read();
Console.WriteLine(""+ (char)dimension);
and you'll see right first symbol in input, as
(char)dimension
will give you symbol by it's ASCII code.
int a = 0;
if(Int32.TryParse(Console.ReadLine(), out a))
{
// Do your calculations with 'a'
}
else
{
// Some warnings
}
The Console.Read method returns only a single character wrapped in an int, so that is only applicable if you are reading a number that is only one digit long, otherwise you'll always get only the first digit.
Since the return value of Read is actually a character, you cannot use it directly as an integer, you would need to parse it from character to integer.
But assuming that you want a number that is longer than one digit, then you really need to use Console.ReadLine instead and convert the input to an integer using int.TryParse. If int.TryParse returns false you can warn the user that he provided an invalid input and ask for the dimension again.
Sample code:
int dimension;
bool isValidDimension;
do
{
Console.Write("Dimension: ");
string input = Console.ReadLine();
isValidDimension = int.TryParse(input, out dimension);
if (!isValidDimension)
{
Console.WriteLine("Invalid dimension... please try again.");
Console.WriteLine();
}
} while (!isValidDimension);
you should it as follow
static void Main()
{
int Number;
string strNumber;
strNumber = Console.ReadLine();
Number = int.Parse(strNumber);
Console.WriteLine("" + dimension);
}
I'm trying to check if the user's response is a double or an int, but the int is specific, whereas the double is not, as I probably made a right mess of explaining it, here's the code:
Console.WriteLine("\n 2) Q: How old is Sally? \n");
int nSallyAge = Convert.ToInt32(Console.ReadLine());
double dSallyAge = Convert.ToDouble((nSallyAge));
if (nSallyAge == 62 || dSallyAge == 62.0)
{
// Increase Score
sUser1Score++;
Console.WriteLine("\n A: Correct, Sally's age is 62, you have been awarded 1 point. \n");
Console.ReadLine();
}
What I'm trying to do, is instead of dSallyAge HAS to equal 62.0, it just has to equal any double figure.
I would approach this problem by first creating a method that gets a double from the user (that will, of course, also accept an int). This removes error handling from your main code.
NOTE in the code below, Math.Truncate can be replaced by Math.Floor, with the same result:
private static double GetDoubleFromUser(string prompt)
{
double input;
while (true)
{
if (prompt != null) Console.Write(prompt);
if (double.TryParse(Console.ReadLine(), out input)) break;
Console.WriteLine("Sorry, that is not a valid number. Please try again.");
}
return input;
}
Then, in my main code, I would get the number from the user, and use the Math.Truncate method to just read the first part of the double passed in by the user (this is what it sounds like you want to do). This means that if the user enters anything from 62 to 62.0 to 62.999, it will truncate the result to '62':
double nSallyAge = GetDoubleFromUser("2) Q: How old is Sally? ");
if (Math.Truncate(nSallyAge) == 62)
{
// Increase Score
sUser1Score++;
Console.WriteLine("A: Correct, Sally's age is 62, you have been awarded 1 point.");
Console.ReadLine();
}
Other alternative ways to use this are:
int sallyAge = Math.Truncate(GetDoubleFromUser("2) Q: How old is Sally? "));
if (sallyAge == 62)
{
// Increase Score
sUser1Score++;
Console.WriteLine("A: Correct, Sally's age is 62, you have been awarded 1 point.");
Console.ReadLine();
}
Or, you could use an input function that returns an int in the first place:
private static int GetIntFromUser(string prompt)
{
return Math.Truncate(GetDoubleFromUser(prompt));
}
In your code above, you are converting the input to an integer and then converting the int result to a double.
Assuming that you are only allowing numerical values to be entered, why not try something like this. This will identify if the input contained decimals or not:
string input = Console.ReadLine();
int iSallyAge;
double dSallyAge;
if (!Int32.TryParse(input, iSallyAge))
{
dSallyAge = Double.Parse(input);
}
You should be using Double.TryParse to parse the user input to a double and then test that value to see whether it's equal to 62.0.
double age;
if (double.TryParse(Console.ReadLine(), out age) && age == 62.0)
{
// age is 62.
// ...
}
First of all I am a beginner in C#, I have just started to play around with it as that's what my University course requires.
My problem is an assignment question which says:
h) To test if a number entered has an integer value. Hint: The number will have to be of type Double. If, for example, the number is 2.5 that doesn’t have an integer value but 2 does. You will need to use Convert.ToInt32(TheNumber) to convert the Double to an Int then compare the two.
double a, b, result;
Console.WriteLine("Input a number");
a = Convert.ToDouble(Console.ReadLine());
b = Convert.ToInt32(a);
This is what I have at the moment and I don't know how to compare these 2 to test which one is an integer. I am pretty sure that you have to use an if statement but how to tell C# to test which of these 2 numbers is an integer and which one isn't!
Any help is highly appreciated :)
Update:
I'd do it like this:
double d;
int i;
Console.WriteLine("Input a number");
d = Convert.ToDouble(Console.ReadLine());
i = Convert.ToInt32(d);
if(i == d) Console.WriteLine("It is an integral value");
This means: if you convert a double to an integer, it will lose all its digits after the decimal point. If this integer has the same value as the double, then the double had no digits after the decimal point, so it has an integer value.
You can use TryParse method which returns boolean
double mydouble;
int myInt;
string value = Console.ReadLine();
if (double.TryParse(value, out mydouble))
{
//This is double value, you can perform your operations here
}
if (int.TryParse(value, out myInt))
{
//This is Int value, you can perform your operation here
}
Should be like this:
double d;
int i;
Console.WriteLine("Input a number");
d = Convert.ToDouble(Console.ReadLine());
i = Convert.ToInt32(d);
if(i == d) Console.WriteLine("It is an integral value");
I think you can use TryParse with do while loop
int number;
string value;
do
{
Console.Write("Enter a number : ");
value =Console.ReadLine();
if (!Int32.TryParse(value, out number))
{
Console.WriteLine("Wrong Input!!!!");
}
}while (!Int32.TryParse(value, out number));
This question already has answers here:
Difference between Console.Read() and Console.ReadLine()?
(12 answers)
Closed 1 year ago.
I don't get why my integer isn't coming out correctly, Console.Read() method says it's returning an integer, why isn't WriteLine displaying it correctly?
int dimension;
dimension = Console.Read();
Console.WriteLine(""+ dimension);
Console.Read() only returns the first character of what was typed. You should be using Console.ReadLine():
Example:
int suppliedInt;
Console.WriteLine("Please enter a number greater than zero");
Int32.TryParse(Console.ReadLine(), out suppliedInt);
if (suppliedInt > 0) {
Console.WriteLine("You entered: " + suppliedInt);
}
else {
Console.WriteLine("You entered an invalid number. Press any key to exit");
}
Console.ReadLine();
Additional Resources:
MSDN - Console.Read()
MSDN - Console.ReadLine()
From the MSDN:
Return Value
Type: System.Int32 The next character from the input stream, or
negative one (-1) if there are currently no more characters to be
read.
Your program is returning but you're not seeing, would you please see below code block:
You are not be able to see the output if the output window doesn't stay.
int dimension;
dimension = Console.Read();
Console.WriteLine("" + dimension);
Console.ReadLine();
Console.Read() returns ASCII code of first symbol in input. You can do
int dimension;
dimension = Console.Read();
Console.WriteLine(""+ (char)dimension);
and you'll see right first symbol in input, as
(char)dimension
will give you symbol by it's ASCII code.
int a = 0;
if(Int32.TryParse(Console.ReadLine(), out a))
{
// Do your calculations with 'a'
}
else
{
// Some warnings
}
The Console.Read method returns only a single character wrapped in an int, so that is only applicable if you are reading a number that is only one digit long, otherwise you'll always get only the first digit.
Since the return value of Read is actually a character, you cannot use it directly as an integer, you would need to parse it from character to integer.
But assuming that you want a number that is longer than one digit, then you really need to use Console.ReadLine instead and convert the input to an integer using int.TryParse. If int.TryParse returns false you can warn the user that he provided an invalid input and ask for the dimension again.
Sample code:
int dimension;
bool isValidDimension;
do
{
Console.Write("Dimension: ");
string input = Console.ReadLine();
isValidDimension = int.TryParse(input, out dimension);
if (!isValidDimension)
{
Console.WriteLine("Invalid dimension... please try again.");
Console.WriteLine();
}
} while (!isValidDimension);
you should it as follow
static void Main()
{
int Number;
string strNumber;
strNumber = Console.ReadLine();
Number = int.Parse(strNumber);
Console.WriteLine("" + dimension);
}