IEquatable, how to implement this properly [duplicate] - c#

This question already has answers here:
Is there a complete IEquatable implementation reference?
(5 answers)
Closed 2 years ago.
I am using .net 2.0 and c# and I have implemented the IEquatible interface in my class like this:-
public MyClass() : IEquatable<MyClass>
{
Guid m_id = Guid.NewGuid();
public Guid Id
{
get
{
return m_id;
}
}
#region IEquatable<MyClass> Members
public bool Equals(MyClass other)
{
if (this.Id == other.Id)
{
return true;
}
else
{
return false;
}
}
#endregion
}
Is this bad programming practice? I've read that I also need to implement Object.Equals and Object.GetHashCode as well, but I am not sure why.
I want to be able to check that an instance of MyClass is not already contained in a generic list of type MyClass. Why does the framework only suggests that you implement Equals only?
Any help would be greatly appreciated.

You can check if your list contains an item using a custom predicate for the criteria, using LINQ. In that case you don't need to override Equals nor implement IEquatable:
// check if the list contains an item with a specific ID
bool found = someList.Any(item => item.ID == someId);
Overriding Equals (with GetHashCode) and implementing IEquatable is useful if you need to store your item in a Dictionary or a Hashtable.

Is this bad programming practice?
Implementing IEquatable<T> is great, even more so for structs, but merely doing that much is not enough.
I've read that I also need to implement Object.Equals
Read it here why..
and Object.GetHashCode as well, but I am not sure why.
Read it here and here. Seriously, these have been discussed so many times, and it is pretty simple.. In short, you need it for collection types that deals with hashes like Dictionary<,> or HashSet<>
I want to be able to check that an instance of MyClass is not already contained in a generic list of type MyClass. Why does the framework only suggests that you implement Equals only?
Depends on the collection type. For a List<T>, it will check equality merely based on how you have defined Equals method, say for Contains method. For most scenario you will need Equals only. But if you have a HashSet<T> then absence and presence checks will utilize hash of your objects. Framework indeed asks us to implement good hashing approaches (without re-inventing the wheel) at appropriate places.
Any help would be greatly appreciated.
Do as below, but you have to overload operators == and != only if it make sense to you. Seeing your class I assumed its ok to have value semantics for your class. Otherwise just ignore that part (if == should mean reference equality)... Getting hashcode from your guid would suffice, provided that is all you need to test equality.
public sealed class MyClass : IEquatable<MyClass>
{
Guid m_id = Guid.NewGuid();
public Guid Id { get { return m_id; } }
public bool Equals(MyClass other)
{
if (ReferenceEquals(this, other))
return true;
if (ReferenceEquals(null, other))
return false;
return Id == other.Id;
}
public override bool Equals(object obj)
{
return Equals(obj as MyClass);
}
public static bool operator ==(MyClass lhs, MyClass rhs)
{
if (ReferenceEquals(lhs, null))
return ReferenceEquals(rhs, null);
return lhs.Equals(rhs);
}
public static bool operator !=(MyClass lhs, MyClass rhs)
{
return !(lhs == rhs);
}
public override int GetHashCode()
{
return Id.GetHashCode();
}
}
To not get it wrong, make use of the snippet available here: For a good overview see this SO thread.

Related

How to compare 2 instance of a class such that they are equal if at-most there Id differ? [duplicate]

I have a class like this
public class TestData
{
public string Name {get;set;}
public string type {get;set;}
public List<string> Members = new List<string>();
public void AddMembers(string[] members)
{
Members.AddRange(members);
}
}
I want to know if it is possible to directly compare to instances of this class to eachother and find out they are exactly the same? what is the mechanism? I am looking gor something like if(testData1 == testData2) //Do Something And if not, how to do so?
You should implement the IEquatable<T> interface on your class, which will allow you to define your equality-logic.
Actually, you should override the Equals method as well.
public class TestData : IEquatable<TestData>
{
public string Name {get;set;}
public string type {get;set;}
public List<string> Members = new List<string>();
public void AddMembers(string[] members)
{
Members.AddRange(members);
}
// Overriding Equals member method, which will call the IEquatable implementation
// if appropriate.
public override bool Equals( Object obj )
{
var other = obj as TestData;
if( other == null ) return false;
return Equals (other);
}
public override int GetHashCode()
{
// Provide own implementation
}
// This is the method that must be implemented to conform to the
// IEquatable contract
public bool Equals( TestData other )
{
if( other == null )
{
return false;
}
if( ReferenceEquals (this, other) )
{
return true;
}
// You can also use a specific StringComparer instead of EqualityComparer<string>
// Check out the specific implementations (StringComparer.CurrentCulture, e.a.).
if( EqualityComparer<string>.Default.Compare (Name, other.Name) == false )
{
return false;
}
...
// To compare the members array, you could perhaps use the
// [SequenceEquals][2] method. But, be aware that [] {"a", "b"} will not
// be considerd equal as [] {"b", "a"}
return true;
}
}
One way of doing it is to implement IEquatable<T>
public class TestData : IEquatable<TestData>
{
public string Name {get;set;}
public string type {get;set;}
public List<string> Members = new List<string>();
public void AddMembers(string[] members)
{
Members.AddRange(members);
}
public bool Equals(TestData other)
{
if (this.Name != other.Name) return false;
if (this.type != other.type) return false;
// TODO: Compare Members and return false if not the same
return true;
}
}
if (testData1.Equals(testData2))
// classes are the same
You can also just override the Equals(object) method (from System.Object), if you do this you should also override GetHashCode see here
There are three ways objects of some reference type T can be compared to each other:
With the object.Equals method
With an implementation of IEquatable<T>.Equals (only for types that implement IEquatable<T>)
With the comparison operator ==
Furthermore, there are two possibilities for each of these cases:
The static type of the objects being compared is T (or some other base of T)
The static type of the objects being compared is object
The rules you absolutely need to know are:
The default for both Equals and operator== is to test for reference equality
Implementations of Equals will work correctly no matter what the static type of the objects being compared is
IEquatable<T>.Equals should always behave the same as object.Equals, but if the static type of the objects is T it will offer slightly better performance
So what does all of this mean in practice?
As a rule of thumb you should use Equals to check for equality (overriding object.Equals as necessary) and implement IEquatable<T> as well to provide slightly better performance. In this case object.Equals should be implemented in terms of IEquatable<T>.Equals.
For some specific types (such as System.String) it's also acceptable to use operator==, although you have to be careful not to make "polymorphic comparisons". The Equals methods, on the other hand, will work correctly even if you do make such comparisons.
You can see an example of polymorphic comparison and why it can be a problem here.
Finally, never forget that if you override object.Equals you must also override object.GetHashCode accordingly.
I see many good answers here but just in case you want the comparison to work like
if(testData1 == testData2) // DoSomething
instead of using Equals function you can override == and != operators:
public static bool operator == (TestData left, TestData right)
{
bool comparison = true; //Make the desired comparison
return comparison;
}
public static bool operator != (TestData left, TestData right)
{
return !(left == right);
}
You can override the equals method and inside it manually compare the objects
Also take a look at Guidelines for Overloading Equals() and Operator ==
You will need to define the rules that make object A equal to object B and then override the Equals operator for this type.
http://msdn.microsoft.com/en-us/library/ms173147(v=vs.80).aspx
First of all equality is difficult to define and only you can define as to what equality means for you
Does it means members have same value
Or they are pointing to same location.
Here is a discussion and an answer here
What is "Best Practice" For Comparing Two Instances of a Reference Type?
Implement the IEquatable<T> interface. This defines a generalized method that a value type or class implements to create a type-specific method for determining equality of instances. More information here:
http://msdn.microsoft.com/en-us/library/ms131187.aspx

Equals override vs. IEquatable<> [duplicate]

This question already has answers here:
What's the difference between IEquatable and just overriding Object.Equals()?
(4 answers)
Closed 6 years ago.
For the life of me, I can't get my WPF binding to work correctly for a RibbonComboBox's SelectedItem property.
Then I started reading about how .NET compares items. My understanding is that, in some cases, it compares the actual pointer. In which case, loading a new and equal value from a database, for example, it may not be considered equal.
So then I started looking into explicitly implementing Equals for my type. However, this seems a bit confusing as there are at least two different versions I can implement.
The code below shows I can either override object.Equals, or I can implement IEquatable<>. In fact, the code below implements both, and testing indicates that both are called.
public class TextValuePair : IEquatable<TextValuePair>
{
public string Text { get; set; }
public int Value { get; set; }
public override bool Equals(object obj)
{
if (obj == null || !(obj is TextValuePair))
return false;
return Value == (obj as TextValuePair).Value;
}
public override int GetHashCode()
{
return Value;
}
public bool Equals(TextValuePair obj)
{
Debug.Assert(obj != null);
if (obj == null)
return false;
return Value == obj.Value;
}
}
Can someone help me understand what is required to avoid my objects from being compared for equivalence by .NET library routines according to pointers having the same value? Is it really necessary to implement both versions of Equals?
As pointed by msdn, if you are implementing IEquatable<T> you will still need to override Equals because it will still be called with the signature Equals(System.Object, System.Object) and yhe override should be consistent with the methods implemented from IEquatable<T>.
Also as in the question about the difference between iequatable and just overriding object equals which Arno showed in the comment, IEquatable<T> is used when operations on collections are required to optimize them, not to need the boxing anymore, and instead call the direct Equals with the specific type.
You have two options:
If you are interested in performance when you are working with collections in your program, you could keep implementing the both Equals methods;
or
You could just remove the IEquatable<T> and only override Equals to simplify your code.
Additionally, whenever you override Equals, you should also always override GetHashCode as well.

Comparing objects

I have a class it contains some string members, some double members and some array objects.
I create two objects of this class, is there any simplest, efficient way of comparing these objects and say their equal? Any suggestions?
I know how to write a compare function, but will it be time consuming.
The only way you can really do this is to override bool Object.Equals(object other) to return true when your conditions for equality are met, and return false otherwise. You must also override int Object.GetHashCode() to return an int computed from all of the data that you consider when overriding Equals().
As an aside, note that the contract for GetHashCode() specifies that the return value must be equal for two objects when Equals() would return true when comparing them. This means that return 0; is a valid implementation of GetHashCode() but it will cause inefficiencies when objects of your class are used as dictionary keys, or stored in a HashSet<T>.
The way I implement equality is like this:
public class Foo : IEquatable<Foo>
{
public bool Equals(Foo other)
{
if (other == null)
return false;
if (other == this)
return true; // Same object reference.
// Compare this to other and return true/false as appropriate.
}
public override bool Equals(Object other)
{
return Equals(other as Foo);
}
public override int GetHashCode()
{
// Compute and return hash code.
}
}
A simple way of implementing GetHashCode() is to XOR together the hash codes of all of the data you consider for equality in Equals(). So if, for example, the properties you compare for equality are string FirstName; string LastName; int Id;, your implementation might look like:
public override int GetHashCode()
{
return (FirstName != null ? FirstName.GetHashCode() : 0) ^
(LastName != null ? LastName.GetHashCode() : 0) ^
Id; // Primitives of <= 4 bytes are their own hash codes
}
I typically do not override the equality operators, as most of the time I'm concerned with equality only for the purposes of dictionary keys or collections. I would only consider overriding the equality operators if you are likely to do more comparisons by value than by reference, as it is syntactically less verbose. However, you have to remember to change all places where you use == or != on your object (including in your implementation of Equals()!) to use Object.ReferenceEquals(), or to cast both operands to object. This nasty gotcha (which can cause infinite recursion in your equality test if you are not careful) is one of the primary reasons I rarely override these operators.
The 'proper' way to do it in .NET is to implement the IEquatable interface for your class:
public class SomeClass : IEquatable<SomeClass>
{
public string Name { get; set; }
public double Value { get; set; }
public int[] NumberList { get; set; }
public bool Equals(SomeClass other)
{
// whatever your custom equality logic is
return other.Name == Name &&
other.Value == Value &&
other.NumberList == NumberList;
}
}
However, if you really want to do it right, this isn't all you should do. You should also override the Equals(object, object) and GetHashCode(object) methods so that, no matter how your calling code is comparing equality (perhaps in a Dictionary or perhaps in some loosely-typed collection), your code and not reference-type equality will be the determining factor:
public class SomeClass : IEquatable<SomeClass>
{
public string Name { get; set; }
public double Value { get; set; }
public int[] NumberList { get; set; }
/// <summary>
/// Explicitly implemented IEquatable method.
/// </summary>
public bool IEquatable<SomeClass>.Equals(SomeClass other)
{
return other.Name == Name &&
other.Value == Value &&
other.NumberList == NumberList;
}
public override bool Equals(object obj)
{
var other = obj as SomeClass;
if (other == null)
return false;
return ((IEquatable<SomeClass>)(this)).Equals(other);
}
public override int GetHashCode()
{
// Determine some consistent way of generating a hash code, such as...
return Name.GetHashCode() ^ Value.GetHashCode() ^ NumberList.GetHashCode();
}
}
Just spent the whole day writing an extension method looping through reflecting over properties of an object with various complex bits of logic to deal with different property type and actually got it close to good, then at 16:55 it dawned on me that if you serialize the two object, you simply need compare the two strings ... duh
So here is a simple serializer extension method that even works on Dictionaries
public static class TExtensions
{
public static string Serialize<T>(this T thisT)
{
var serializer = new DataContractSerializer(thisT.GetType());
using (var writer = new StringWriter())
using (var stm = new XmlTextWriter(writer))
{
serializer.WriteObject(stm, thisT);
return writer.ToString();
}
}
}
Now your test can be as simple as
Asset.AreEqual(objA.Serialise(), objB.Serialise())
Haven't done extensive testing yet, but looks promising and more importantly, simple. Either way still a useful method to have in your utility set right ?
The best answer is to implement IEquatable for your class - it may not be the answer you want to hear, but that's the best way to implement value equivalence in .NET.
Another option would be computing a unique hash of all of the members of your class and then doing value comparisons against those, but that's even more work than writing a comparison function ;)
Since these are objects my guess is that you will have to override the Equals method for objects. Otherwise the Equals method will give you ok only if both objects refering to the same object.
I know this is not the answer you want. But since there is little number of properties in your class you can easily override the method.

Complex object comparison in C# [duplicate]

This question already has answers here:
C# implementation of deep/recursive object comparison in .net 3.5
(6 answers)
Closed 8 years ago.
I have two complex objects of the same type. I want to compare both the objects to determine if they have the exact same values. What is the efficient way of doing this ?
sample class structure given below:
class Package
{
public List<GroupList> groupList;
}
class GroupList
{
public List<Feature> featurelist;
}
class Feature
{
public int qty;
}
Okay, so you want deep unordered structural comparison. The "unordered" part is tricky, and in fact it is a strong hint that your classes are not designed right: List<T> is inherently ordered, so perhaps you would rather want to use a HashSet<T> there (if you don't expect to have any duplicates). Doing so would make the comparison both easier to implement, and faster (though insertions would be slower):
class Package
{
public HashSet<GroupList> groupList;
public override bool Equals(object o)
{
Package p = o as Package;
if (p == null) return false;
return groupList.SetEquals(p.groupList);
}
public override int GetHashCode()
{
return groupList.Aggregate(0, (hash, g) => hash ^ g.GetHashCode());
}
}
class GroupList
{
public HashSet<Feature> featureList;
public override bool Equals(object o)
{
GroupList g = o as GroupList;
if (g == null) return false;
return featureList.SetEquals(g.featureList);
}
public override int GetHashCode()
{
return featureList.Aggregate(0, (hash, f) => hash ^ f.GetHashCode());
}
}
class Feature
{
public int qty;
public override bool Equals(object o)
{
Feature f = o as Feature;
if (f == null) return false;
return qty == f.qty;
}
public override int GetHashCode()
{
return qty.GetHashCode();
}
}
If you want to keep using List<T>, you'll need to use LINQ set operations - note, however, that those are significantly slower:
class Package
{
public List<GroupList> groupList;
public override bool Equals(object o)
{
Package p = o as Package;
if (p == null) return false;
return !groupList.Except(p.groupList).Any();
}
}
class GroupList
{
public List<Feature> featureList;
public override bool Equals(object o)
{
GroupList g = o as GroupList;
if (g == null) return false;
return !featureList.Except(f.featureList).Any();
}
}
For complex objects, I would consider operator overloading.
On the overloaded operator, I would define my condition for equality.
http://msdn.microsoft.com/en-us/library/aa288467%28VS.71%29.aspx
We always just end up writing a method on the class that goes through everything and compares it. You could implement this as IComparable, or override Equals.
As the comment said, depends on how "exact" you want to measure.
You could just override equality and implement a GetHashCode method, however this does not guarantee they are exact matches. Will however ensure they are "very likely" an exact match.
Next thing you could do, is to go through every property/field in the class and compare those hash values. This would be "extremely likely" an exact match.
And to truly get an exact match, you have to compare every field and member in a recursive loop...not recommended.
If I were you, I would implement the IComparable Interface on the two types:
http://msdn.microsoft.com/en-us/library/system.icomparable.aspx
From there you can use .CompareTo, and implement the exact comparisons required under your circumstances. This is a general best practice within .NET and I think applies well to your case.
Depends on what you what you want to do with comparison. Like others have pointed out IComparer is a good choice. If you are planning on using lambdas and LINQ, I would go with IEqualityComparer
http://msdn.microsoft.com/en-us/library/system.collections.iequalitycomparer.aspx
In general, you need a method to check the two, regardless of whether or not you overload equals, or use IComparer.
You asked how to do it most efficiently, here are some tips:
Your equality method should try to give up quickly, e.g. check if the size of the lists are the same, if they are not then return false right away
If you could implement an efficient hashCode, you could compare the hashes first, if they are not equal then the objects are not equal, if they are equal, then you need to compare the objects to see if the objects are equal
So in general, do the fastest comparisons first to try to return false.
Here is a somewhat simplified way to do it, using reflection. You will probably need to add other checks of datatypes for specific comparisons or loop through lists etc, but this should get you started.
void Mymethod(){
Class1 class1 = new Class1();
//define properties for class1
Class1 class2 = new Class1();
//define properties for class2
PropertyInfo[] properties = class1.GetType().GetProperties();
bool bClassesEqual = true;
foreach (PropertyInfo property in properties)
{
Console.WriteLine(property.Name.ToString());
if (property.GetValue(class1, null) != property.GetValue(class2, null))
{
bClassesEqual = false;
break;
}
}
}

What needs to be overridden in a struct to ensure equality operates properly?

As the title says: do I need to override the == operator? how about the .Equals() method? Anything I'm missing?
An example from msdn
public struct Complex
{
double re, im;
public override bool Equals(Object obj)
{
return obj is Complex c && this == c;
}
public override int GetHashCode()
{
return re.GetHashCode() ^ im.GetHashCode();
}
public static bool operator ==(Complex x, Complex y)
{
return x.re == y.re && x.im == y.im;
}
public static bool operator !=(Complex x, Complex y)
{
return !(x == y);
}
}
You should also implement IEquatable<T>. Here is an excerpt from Framework Design Guidelines:
DO implement IEquatable on value types.
The Object.Equals method on value types causes boxing, and its
default implementation is not very effcient because it uses refection.
IEquatable.Equals can offer much better performance and can be
implemented so that it does not cause boxing.
public struct Int32 : IEquatable<Int32> {
public bool Equals(Int32 other){ ... }
}
DO follow the same guidelines as for
overriding Object.Equals when
implementing IEquatable.Equals.
See section 8.7.1 for detailed
guidelines on overriding Object.Equals
Unfortunetely I don't have enough reputation to comment other entries. So I'm posting possible enhancement to the top solution here.
Correct me, if i'm wrong, but implementation mentioned above
public struct Complex
{
double re, im;
public override bool Equals(Object obj)
{
return obj is Complex && this == (Complex)obj;
}
public override int GetHashCode()
{
return re.GetHashCode() ^ im.GetHashCode();
}
public static bool operator ==(Complex x, Complex y)
{
return x.re == y.re && x.im == y.im;
}
public static bool operator !=(Complex x, Complex y)
{
return !(x == y);
}
}
Has major flaw. I'm refering to
public override int GetHashCode()
{
return re.GetHashCode() ^ im.GetHashCode();
}
XORing is symmetrical, so Complex(2,1) and Complex(1,2) would give same hashCode.
We should probably make something more like:
public override int GetHashCode()
{
return re.GetHashCode() * 17 ^ im.GetHashCode();
}
Most of the time you can avoid implementing Equals and GetHashcode in structs - because there is an automatic implementation by the compiler for Value types using bitwise content + reflection for reference members.
Have a look at that post :
Which is best for data store Struct/Classes?
So for ease of use you could still implement == and !=.
But most of the time you can avoid implementing Equals and GetHashcode.
A case where you'd have to implement Equals and GetHashCode is for a field that you don't wan't to take into account.
For instance a field that varies as time goes by like Age of a Person or instantSpeed of a car( the identity of the object shouldn't change if you want to find it back in the dictionary at the same place)
Regards, best code
The basic difference among the two is that the == operator is static, i.e. the appropriate method to invoke is determined at compile time, while the Equals method is invoked dinamically on an instance.
Defining both is probably the best thing to do, even if this matters less in the case of structs, since structs cannot be extended (a struct can't inherit from another).
Just for completness I would also advice to overload Equals method:
public bool Equals(Complex other)
{
return other.re == re && other.im == im;
}
this is a real spead improvement as there is no boxing occuring of the input argument of Equals(Object obj) method
Some best prac­tices for using value types:
make them immutable
over­ride Equals (the one that takes an object as argument);
over­load Equals to take another instance of the same value type (e.g. * Equals(Complex other));
over­load oper­a­tors == and !=;
over­ride GetHashCode
This comes from this post: http://theburningmonk.com/2015/07/beware-of-implicit-boxing-of-value-types/

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