I have some code that is returning a XNode to me which looks like this:
<File>
<Component>Main</Component>
<Path>C:\Main\</Path>
<FileName>main.txt</FileName>
</File>
I need to have some C# code that will be able to pull out the value of Path for example (C:\Main). I know that if I was using an XML node I could do it like this:
String filePath = xmlNode["Path"].InnerText;
Does anybody know what the equivalent would be for an XNode? Any help is much appreciated!
Do you have to have it returning an XNode rather than an XElement? With an XElement it's simpler than with an XNode:
string filePath = fileElement.Element("Path").Value;
That will find the first Path element, and will throw a NullReferenceException if there aren't any. An alternative if you're happy to get null if there aren't any would be:
string filePath = (string) fileElement.Element("Path");
If you're really stuck with XNode, you'll either have to cast to XElement or possibly XContainer.
You can convert your XNode into XElement to access to its properties, my example:
XNode lastNode = myXElement.LastNode;
//if I want to get the 'ID' attribute
string id = (lastNode as XElement).Attribute("ID").Value;
Casting XNode to XElement works for the individual element to retrieve its value or attributes. But you won't be able to use myXelement.Elements("XXX") to get nested elements. For that you can use xmlNode.Nodes().
This should work:
var nodes = xmlNode.Nodes();//Get all nodes under 'File'
var fileNameNode = nodes.Where(el => ((XElement)el).Name.LocalName == "FileName")
.FirstOrDefault();
string filePath = ((XElement)fileNameNode).Value;
You may use this:
XElement xtr = XElement.Load("path/to/your/xml/file");
String filePath = xtr.Descendants("Path").Single().Value;
If you import System.Xml.XPath you can use XPathSelectElement like this on the XNode object:
String component = xmlNode.XPathSelectElement("Component");
String path = xmlNode.XPathSelectElement("Path");
String fileName = xmlNode.XPathSelectElement("FileName");
It depends on what convcrete objets is the abstract XNode. From XNode Class:
XNode is an abstract common base class for the following types:
XComment
XContainer: can be XDocument or XElement
XDocumentType
XProcessingInstruction
XText
So you need to check if you can cast it to an XDocument or an XElement, and use their methods, or use LINQ to XML:
For example:
Best way to query XDocument with LINQ?
Querying an XDocument vs. Querying an XElement (C#)
XNode xnode
string value = (xnode as XElement).Value;
we can get the value form XElement object so we need to cast XNode to XElement first
should work
Related
I am trying the below sample to select a node by ignoring the case and the select single node retuns null.
XmlDocument doc = new XmlDocument();
doc.LoadXml("<root><CHILD1>c1</CHILD1><CHILD2>c2</CHILD2></root>");
var node = doc.SelectSingleNode("root");
string nodeXpath = string.Format("//*[translate(#key, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz') = '{0}']","child1");
node = node.SelectSingleNode(nodeXpath);
string innertext = node.InnerText;
Can someone help.
#key in XPath means a reference to an attribute named key. There is no such attribute in your XML. If you meant to match by element name then you're supposed to use name() or local-name() instead :
...
string xpath = "//*[translate(name(), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz') = '{0}']";
string nodeXpath = string.Format(xpath,"child1");
...
You can use LINQ to Xml in little bid more readable way
XDocument doc = XDocument.Parse("<root><CHILD1>c1</CHILD1><CHILD2>c2</CHILD2></root>");
var singleNode =
doc.Root
.Elements()
.FirstOrDefault(element => element.Name.ToString().ToLower().Equals("child1"));
But notice that XML support different nodes where name can be case sensitive(for example "Node" and "node") and "searching" elements in "ignore case" way can lead to problems in the future.
I was working through this today and I used your solution. I just wrapped it in a function and call it whenever I need to match on an element name that's under the root. Works like a charm. Thanks!
private string GetNodeXpathCaseInsensitive(string value)
{
string xpath = String.Format("//*[translate(name(), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz') = '{0}']", value.ToLower());
return xpath;
}
I need to convert to string a subset of OuterXml content of a XmlElement as in the following example.
Imagine I have an XmlElement object representing the some-element tag
<some-element attribute="value">
<inner-element>
text content
</inner-element>
</some-element>
What's the best approach to get a string that is just <some-element attribute="value">?
If possible, I'd prefer a solution without regular expressions involved, but using DOM classes
You can get the full XML of the element(which includes the close tag) by shallow cloning the node and then grabbing the outer XML of the node:
var xml = #"<some-element attribute=""value"">
<inner-element>
text content
</inner-element>
</some-element>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
MessageBox.Show(doc.DocumentElement.CloneNode(false).OuterXml);
I think after that point you will have to do some string manipulation to get exactly what you want, but that is relatively easy:
var outer = doc.DocumentElement.CloneNode(false).OuterXml;
var final = outer.Substring(0, outer.LastIndexOf(">", outer.Length - 2)+1);
MessageBox.Show(final);
I finally solved it by creating a temporary XElement instead using LINQ
IEnumerable<XAttribute> attributes = (from XmlAttribute xmlAttribute in node.Attributes select new XAttribute(xmlAttribute.Name, xmlAttribute.Value));
var xElement = new XElement(node.Name, attributes);
return xElement.ToString();
I'd like to retrieve information from an XML file, however the way it's formatted is pretty strange. Here it is...
<?xml version="1.0"?>
<Careers>
<CareerList>
<CareerName></CareerName>
<CareerDescription></CareerDescription>
</CareerList>
<CareerList>
<CareerName>Cook</CareerName>
<CareerDescription>Cooks food for people</CareerDescription>
</CareerList>
</Careers>
I'd like to get the 2nd value, which would be Cook and the description which is Cooks food for people, but instead I'm getting only the empty node. For example...
public string CareerDescription(string CareerFile)
{
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(CareerFile);
string Description = xmlDoc.SelectSingleNode("Careers/CareerList/CareerDescription").InnerText;
return Description;
}
How would I select the second node instead of the first?
You can use an index in your XPath expression:
xmlDoc.SelectSingleNode("Careers/CareerList[2]/CareerDescription").InnerText
Personally I'd use LINQ to XML instead, mind you:
var doc = XDocument.Load(CareerFile);
return doc.Root
.Elements("CareerList")
.ElementAt(1) // 0-based
.Element("CareerDescription")
.Value;
Instead of SelectSingleNode you should use SelectNodes: it will return XmlNodeList nodeList. Then you should take the InnerText of the element from that node list with index [1];
public string CareerDescription(string CareerFile)
{
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(CareerFile);
string Description = xmlDoc.SelectNodes("Careers/CareerList/CareerDescription")[1].InnerText;
return Description;
}
Refer to the documentation on this method on MSDN for more details: http://msdn.microsoft.com/en-us/library/system.xml.xmlnode.selectnodes%28v=vs.71%29.aspx
Just a straight way of LINQ to XML routine (and because it is LINQ, I prefer this way much more than the "standard" usage of XmlDocument with the support of XPath):
return XDocument.Load(CareerFile)
.Descendants("CareerDescription").Skip(1).First().Value;
I've been trying to pull the value of the XML node into a string. Here is what the XML looks like:
<currentvin value="1FTWW31R08EB18119" />
I can't seem to figure out how to grab that value. I didn't write this XML, by the way. So far I have tried several approaches, including the following:
public void xmlParse(string filePath)
{
XmlDocument xml = new XmlDocument();
xml.Load(filePath);
XmlNode currentVin = xml.SelectSingleNode("/currentvin");
string xmlVin = currentVin.Value;
Console.WriteLine(xmlVin);
}
Which doesn't work. I then tried:
public void xmlParse(string filePath)
{
XmlDocument xml = new XmlDocument();
xml.Load(filePath);
string xmlVin = xml.SelectSingleNode("/currentvin").Value;
Console.WriteLine(xmlVin);
}
But that doesn't work either. I am getting a null reference exception stating that Object reference not set to an instance of an object. Any ideas?
I think you're confusing the Value property of the XmlNode class, with an XML attribute named "value".
value is an attribute in your xml so either modify your xpath query to be
xml.SelectSingleNode("/currentvin/#value").Value
Or user the Attributes collection of the selected XmlNode.
You are looking for the value of the attribute "value" (that's a handful) not the value of the node itself - so you have to use the Attribute property:
string xmlVin = xml.SelectSingleNode("/currentvin").Attributes["value"].Value;
Or in the first version:
XmlNode currentVin = xml.SelectSingleNode("/currentvin");
string xmlVin = currentVin.Attributes["value"].Value;
If your entire XML contains only this node then it could be xml.DocumentElement.Attributes["value"].Value;
I have an Xml document in which some of the elements look like this:
<rootNode attib1="qwerty" >
<subNode1>W</subNode1>
<subNode2>X</subNode2>
<subNode3>Y</subNode3>
<subNode4>Z</subNode4>
ABC
</rootNode>
My objective is to get "ABC" out of the above example. I tried looking at the InnerText (which returns "WXYZABC") and InnerXml and Value (which returns null) properties in the XmlElement class and bunch of properties in the XmlReader class too. Somehow I don't see an elegant way to extract the data I need.
Can someone please help me out?
Thanks in advance.
Have a go with this one:
string xml = #"<rootNode attib1=""qwerty"" >
<subNode1>W</subNode1>
<subNode2>X</subNode2>
<subNode3>Y</subNode3>
<subNode4>Z</subNode4>
ABC
</rootNode>";
var xElement = XElement.Parse(xml);
xElement.Elements().Remove();
xElement.Value.Dump();
What it does is remove all the known Elements and that leaves you with the text you are looking for.
Based on the excellent suggestion from #djechelon, I seem to have found a solution to this:
XmlDocument xdoc = new XmlDocument();
xdoc.Load(#"D:\Test.xml");
XmlElement xmlElement = xdoc.DocumentElement;
foreach (XmlNode node in xmlElement.ChildNodes)
if (node.NodeType == XmlNodeType.Text
&& !string.IsNullOrWhiteSpace(node.Value))
Console.WriteLine(node.Value.Trim());
The above uses the simple fact that the inner text is also an XmlNode as part of the ChildNodes collection of the XmlElement.
Thanks everyone for the great responses!
Try XmlElement.Value
Edit: This is the wrong approach as this will always return NULL on an element node.