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How to check for variable character in string and match it with another string of same length?

I have a rather complex issue that I'am unable to figure out.
I'm getting a set of string every 10 seconds from another process in which the first set has first 5 characters constant, next 3 are variable and can change. And then another set of string in which first 3 are variable and next 3 are constant.
I want to compare these values to a fixed string to check if the first 5 char matches in 1st set of string (ABCDE*** == ABCDEFGH) and ignore the last 3 variable characters while making sure the length is the same. Eg : if (ABCDE*** == ABCDEDEF) then condition is true, but if (ABCDE*** == ABCDDEFG) then the condition is false because the first 5 char is not same, also if (ABCDE*** == ABCDEFV) the condition should be false as one char is missing.
I'm using the * in fixed string to try to make the length same while comparing.

Does this solve your requirements?
private static bool MatchesPattern(string input)
{
const string fixedString = "ABCDExyz";
return fixedString.Length == input.Length && fixedString.Substring(0, 5).Equals(input.Substring(0, 5));
}
In last versions of C# you can also use ranges:
private static bool MatchesPattern(string input)
{
const string fixedString = "ABCDExyz";
return fixedString.Length == input.Length && fixedString[..5].Equals(input[..5]);
}
See this fiddle.
BTW: You could probably achieve the same using regex.

It's always a good idea to make an abstraction. Here I've made a simple function that takes the pattern and the value and makes a check:
bool PatternMatches(string pattern, string value)
{
// The null string doesn't match any pattern
if (value == null)
{
return false;
}
// If the value has a different length than the pattern, it doesn't match.
if (pattern.Length != value.Length)
{
return false;
}
// If both strings are zero-length, it's considered a match
bool result = true;
// Check every character against the pattern
for (int i = 0; i< pattern.Length; i++)
{
// Logical and the result, * matches everything
result&= (pattern[i]== '*') ? true: value[i] == pattern[i];
}
return result;
}
You can then call it like this:
bool b1 = PatternMatches("ABCDE***", "ABCDEFGH");
bool b2 = PatternMatches("ABC***", "ABCDEF");
You could use regular expressions, but this is fairly readable, RegExes aren't always.
Here is a link to a dotnetfiddle: https://dotnetfiddle.net/4x1U1E

If the string you match against is known at compile time, your best bet is probably using regular expressions. In the first case, match against ^ABCDE...$. In the second case, match against ^...DEF$.
Another way, probably better if the match string is unknown, uses Length, StartsWith and EndsWith:
String prefix = "ABCDE";
if (str.Length == 8 && str.StartsWith(prefix)) {
// do something
}
Then similarly for the second case, but using EndsWith instead of StartsWith.

check this
public bool Comparing(string str1, string str2)
=> str2.StartWith(str1.replace("*","")) && str1.length == str2.Length;

String.Compare doesn't work on greater case

I'm trying to compare string values:
using System;
public class Test
{
public static void Main()
{
int cmpValue = String.Compare("N-1.2.0.10", "N-1.2.0.8", StringComparison.InvariantCultureIgnoreCase);
if(cmpValue > 0)
Console.WriteLine("greater");
cmpValue = String.Compare("N-1.2.0.10", "N-1.2.1.10", StringComparison.InvariantCultureIgnoreCase);
if(cmpValue < 0)
Console.WriteLine("lesser");
cmpValue = String.Compare("N-1.2.0.10", "N-1.2.0.10", StringComparison.InvariantCultureIgnoreCase);
if(cmpValue == 0)
Console.WriteLine("equal");
}
}
This prints:
lesser
equal
For some reason, the greater case doesn't print. Why isn't "N-1.2.0.10" considered greater than "N-1.2.0.8"?

Why would it? String comparisons are performed character by character (with a few possiblt exceptions that do not apply here), and '1' compares as less than '8'.
The type of sorting you're looking for, where "10" compares as greater than "8", is often called a "natural sort", for which .NET Framework doesn't provide any options directly, but which is easy to create yourself (or let the native WinAPI do the work).

That happens because the strings are ordered alphabetically, not numerically:
10
11
12
20
8
etc.

Check if all the letters in a string are capital recursively

I have to check if all the letters are capital letters in recursion, and i dont know why this isnt working:
public static bool IsCapital(string str)
{
if (str.Length == 1)
return int.Parse(str[0].ToString()) > 65 && int.Parse(str[0].ToString()) < 90;
return IsCapital(str.Substring(1)) && int.Parse(str[0].ToString()) > 65 && int.Parse(str[0].ToString()) < 90;
}
It crashes and says: "Unhandled exception: System.FormatException: Input string was not in a correct format."
Console.WriteLine(IsCapital("abc"));
thanks.

To solely address the exception, just don't parse strings. You can directly compare a char to any ushort value.
In other words, this is a valid check (without string parsing)
str[0] > 65
AsciiTable.com should show you why the checks you have will fail on the edges.
Also consider...
Characters that aren't letters.
IsCapital(null)
Finally, something that might make this easier (assuming non-letters get bypassed) is to create a method along the lines of bool IsNotLowerCase(char c).
Note -- these are all assuming ASCII, as evident by my link.
If you must support full Unicode, hopefully you can use the methods of char.

You're attempting to parse a char as an int, instead of casting it to an int.
What you're doing is taking a letter, such as A, and parsing that as an int. A isn't a number in any way, and therefore the parse fails.
What you'll want to do is explicitly cast the char as an int to get the ASCII value you're looking for:
if (str.Length == 1)
{
return ((int)str[0]) > 65
&& ((int)str[0]) < 90;
}
return IsCapital(str.Substring(1))
&& ((int)str[0]) > 65
&& ((int)str[0]) < 90;

I assume what you're trying to do with int.Parse(str[0].ToString()) is to get the ASCII value.
What you need to use instead is this (int)str[0]
A parse will try to translate the string into a number, so a string that has a value of '412' will get parsed into an int of value 412.

I have to check if all the letters are capital letters in recursion
public static bool IsCapital(string str)
{
if (String.IsNullOrEmpty(str)) return false;
if (str.Length == 1 && char.IsUpper(str[0])) return true;
return char.IsUpper(str[0]) ? IsCapital(str.Substring(1)) :false;
}

I thinks, that number comparison will not work.
First it will return false for string like this "ABC123" even if all letters are capitals. And second there are many national characters that does not fall into range 65..90 even if they are capitals. You should (if you can) use some Char method
http://msdn.microsoft.com/en-us/library/d1x97616.aspx

While there are many ways to skin this cat, I prefer to wrap such code into reusable extension methods that make it trivial to do going forward. When using extension methods, you can also avoid RegEx as it is slower than a direct character check. I like using the extensions in the Extensions.cs NuGet package. It makes this check as simple as:
Add the [https://www.nuget.org/packages/Extensions.cs][1] package to your project.
Add "using Extensions;" to the top of your code.
"smith".IsUpper() will return False whereas "SMITH".IsUpper() will return True. 4. Every other check in the rest of the code is simply MyString.IsUpper().
Your example code would become as simple as:
using Extensions;
//Console.WriteLine(IsCapital("abc"));
Console.WriteLine("abc".IsUpper());

public static bool IsCapital(string str)
{
return !Regex.IsMatch(str, "[a..z]");
}

substring help in c#

I have string qty__c which may or may not have a decimal point
The code below gives me a System.ArgumentOutOfRangeException: Length cannot be less than zero.
qty__c = qty__c.Substring(0, qty__c.IndexOf("."));
How do i cater to if there is no "."?
Thanks

The simplest way is just to test it separately:
int dotIndex = quantity.IndexOf('.');
if (dotIndex != -1)
{
quantity = quantity.Substring(0, dotIndex);
}
There are alternatives though... for example if you really wanted to do it in a single statement, you could either use a conditional operator above, or:
quantity = quantity.Split('.')[0];
or slightly more efficiently:
// C# 4 version
quantity = quantity.Split(new[] {'.'}, 2)[0];
// Pre-C# 4 version
quantity = quantity.Split(new char[] {'.'}, 2)[0];
(The second form effectively stops splitting after finding the first dot.)
Another option would be to use regular expressions.
On the whole, I think the first approach is the most sensible though. If you find you need to do this often, consider writing a method to encapsulate it:
// TODO: Think of a better name :)
public static string SubstringBeforeFirst(string text, string delimiter)
{
int index = text.IndexOf(delimiter);
return index == -1 ? text : text.Substring(0, index);
}

You just have to test if qty__c have a point in it before calling Substring :
var pointPos = qty__c.IndexOf('.');
if (pointPos != -1)
{
qty__c = qty__c.Substring(0, pointPos);
}

Use IndexOf method on that string. If returned value is -1, there is no character that was searched.
int index = mystring.IndexOf('.');
In your code, you are not checking the returned value of IndexOf. In the case where '.' is not present in the string, an exception will be thrown because SubString has been passed -1 as second parameter.

var indexofstring=quantity.Indexof('.');
if(indexofstring!=-1)
{
quantity=quantity.SubString(0,indexofstring);
}

Assuming you are looking for the decimal point in a number, which is at offset 3 both in
'123.456' and '123', then one solution is
var index = (mystring & ".").IndexOf(".")
(Sorry about the VB, I'm not sure of C# syntax)

Identify if a string is a number

If I have these strings:
"abc" = false
"123" = true
"ab2" = false
Is there a command, like IsNumeric() or something else, that can identify if a string is a valid number?

int n;
bool isNumeric = int.TryParse("123", out n);
Update As of C# 7:
var isNumeric = int.TryParse("123", out int n);
or if you don't need the number you can discard the out parameter
var isNumeric = int.TryParse("123", out _);
The var s can be replaced by their respective types!

This will return true if input is all numbers. Don't know if it's any better than TryParse, but it will work.
Regex.IsMatch(input, #"^\d+$")
If you just want to know if it has one or more numbers mixed in with characters, leave off the ^ + and $.
Regex.IsMatch(input, #"\d")
Edit:
Actually I think it is better than TryParse because a very long string could potentially overflow TryParse.

You can also use:
using System.Linq;
stringTest.All(char.IsDigit);
It will return true for all Numeric Digits (not float) and false if input string is any sort of alphanumeric.
Test case
Return value
Test result
"1234"
true
✅Pass
"1"
true
✅Pass
"0"
true
✅Pass
""
true
⚠️Fail (known edge case)
"12.34"
false
✅Pass
"+1234"
false
✅Pass
"-13"
false
✅Pass
"3E14"
false
✅Pass
"0x10"
false
✅Pass
Please note: stringTest should not be an empty string as this would pass the test of being numeric.

I've used this function several times:
public static bool IsNumeric(object Expression)
{
double retNum;
bool isNum = Double.TryParse(Convert.ToString(Expression), System.Globalization.NumberStyles.Any, System.Globalization.NumberFormatInfo.InvariantInfo, out retNum);
return isNum;
}
But you can also use;
bool b1 = Microsoft.VisualBasic.Information.IsNumeric("1"); //true
bool b2 = Microsoft.VisualBasic.Information.IsNumeric("1aa"); // false
From Benchmarking IsNumeric Options
(source: aspalliance.com)
(source: aspalliance.com)

This is probably the best option in C#.
If you want to know if the string contains a whole number (integer):
string someString;
// ...
int myInt;
bool isNumerical = int.TryParse(someString, out myInt);
The TryParse method will try to convert the string to a number (integer) and if it succeeds it will return true and place the corresponding number in myInt. If it can't, it returns false.
Solutions using the int.Parse(someString) alternative shown in other responses works, but it is much slower because throwing exceptions is very expensive. TryParse(...) was added to the C# language in version 2, and until then you didn't have a choice. Now you do: you should therefore avoid the Parse() alternative.
If you want to accept decimal numbers, the decimal class also has a .TryParse(...) method. Replace int with decimal in the above discussion, and the same principles apply.

You can always use the built in TryParse methods for many datatypes to see if the string in question will pass.
Example.
decimal myDec;
var Result = decimal.TryParse("123", out myDec);
Result would then = True
decimal myDec;
var Result = decimal.TryParse("abc", out myDec);
Result would then = False

In case you don't want to use int.Parse or double.Parse, you can roll your own with something like this:
public static class Extensions
{
public static bool IsNumeric(this string s)
{
foreach (char c in s)
{
if (!char.IsDigit(c) && c != '.')
{
return false;
}
}
return true;
}
}

If you want to catch a broader spectrum of numbers, à la PHP's is_numeric, you can use the following:
// From PHP documentation for is_numeric
// (http://php.net/manual/en/function.is-numeric.php)
// Finds whether the given variable is numeric.
// Numeric strings consist of optional sign, any number of digits, optional decimal part and optional
// exponential part. Thus +0123.45e6 is a valid numeric value.
// Hexadecimal (e.g. 0xf4c3b00c), Binary (e.g. 0b10100111001), Octal (e.g. 0777) notation is allowed too but
// only without sign, decimal and exponential part.
static readonly Regex _isNumericRegex =
new Regex( "^(" +
/*Hex*/ #"0x[0-9a-f]+" + "|" +
/*Bin*/ #"0b[01]+" + "|" +
/*Oct*/ #"0[0-7]*" + "|" +
/*Dec*/ #"((?!0)|[-+]|(?=0+\.))(\d*\.)?\d+(e\d+)?" +
")$" );
static bool IsNumeric( string value )
{
return _isNumericRegex.IsMatch( value );
}
Unit Test:
static void IsNumericTest()
{
string[] l_unitTests = new string[] {
"123", /* TRUE */
"abc", /* FALSE */
"12.3", /* TRUE */
"+12.3", /* TRUE */
"-12.3", /* TRUE */
"1.23e2", /* TRUE */
"-1e23", /* TRUE */
"1.2ef", /* FALSE */
"0x0", /* TRUE */
"0xfff", /* TRUE */
"0xf1f", /* TRUE */
"0xf1g", /* FALSE */
"0123", /* TRUE */
"0999", /* FALSE (not octal) */
"+0999", /* TRUE (forced decimal) */
"0b0101", /* TRUE */
"0b0102" /* FALSE */
};
foreach ( string l_unitTest in l_unitTests )
Console.WriteLine( l_unitTest + " => " + IsNumeric( l_unitTest ).ToString() );
Console.ReadKey( true );
}
Keep in mind that just because a value is numeric doesn't mean it can be converted to a numeric type. For example, "999999999999999999999999999999.9999999999" is a perfeclty valid numeric value, but it won't fit into a .NET numeric type (not one defined in the standard library, that is).

I know this is an old thread, but none of the answers really did it for me - either inefficient, or not encapsulated for easy reuse. I also wanted to ensure it returned false if the string was empty or null. TryParse returns true in this case (an empty string does not cause an error when parsing as a number). So, here's my string extension method:
public static class Extensions
{
/// <summary>
/// Returns true if string is numeric and not empty or null or whitespace.
/// Determines if string is numeric by parsing as Double
/// </summary>
/// <param name="str"></param>
/// <param name="style">Optional style - defaults to NumberStyles.Number (leading and trailing whitespace, leading and trailing sign, decimal point and thousands separator) </param>
/// <param name="culture">Optional CultureInfo - defaults to InvariantCulture</param>
/// <returns></returns>
public static bool IsNumeric(this string str, NumberStyles style = NumberStyles.Number,
CultureInfo culture = null)
{
double num;
if (culture == null) culture = CultureInfo.InvariantCulture;
return Double.TryParse(str, style, culture, out num) && !String.IsNullOrWhiteSpace(str);
}
}
Simple to use:
var mystring = "1234.56789";
var test = mystring.IsNumeric();
Or, if you want to test other types of number, you can specify the 'style'.
So, to convert a number with an Exponent, you could use:
var mystring = "5.2453232E6";
var test = mystring.IsNumeric(style: NumberStyles.AllowExponent);
Or to test a potential Hex string, you could use:
var mystring = "0xF67AB2";
var test = mystring.IsNumeric(style: NumberStyles.HexNumber)
The optional 'culture' parameter can be used in much the same way.
It is limited by not being able to convert strings that are too big to be contained in a double, but that is a limited requirement and I think if you are working with numbers larger than this, then you'll probably need additional specialised number handling functions anyway.

UPDATE of Kunal Noel Answer
stringTest.All(char.IsDigit);
// This returns true if all characters of the string are digits.
But, for this case we have that empty strings will pass that test, so, you can:
if (!string.IsNullOrEmpty(stringTest) && stringTest.All(char.IsDigit)){
// Do your logic here
}

You can use TryParse to determine if the string can be parsed into an integer.
int i;
bool bNum = int.TryParse(str, out i);
The boolean will tell you if it worked or not.

If you want to know if a string is a number, you could always try parsing it:
var numberString = "123";
int number;
int.TryParse(numberString , out number);
Note that TryParse returns a bool, which you can use to check if your parsing succeeded.

I guess this answer will just be lost in between all the other ones, but anyway, here goes.
I ended up on this question via Google because I wanted to check if a string was numeric so that I could just use double.Parse("123") instead of the TryParse() method.
Why? Because it's annoying to have to declare an out variable and check the result of TryParse() before you know if the parse failed or not. I want to use the ternary operator to check if the string is numerical and then just parse it in the first ternary expression or provide a default value in the second ternary expression.
Like this:
var doubleValue = IsNumeric(numberAsString) ? double.Parse(numberAsString) : 0;
It's just a lot cleaner than:
var doubleValue = 0;
if (double.TryParse(numberAsString, out doubleValue)) {
//whatever you want to do with doubleValue
}
I made a couple extension methods for these cases:
Extension method one
public static bool IsParseableAs<TInput>(this string value) {
var type = typeof(TInput);
var tryParseMethod = type.GetMethod("TryParse", BindingFlags.Static | BindingFlags.Public, Type.DefaultBinder,
new[] { typeof(string), type.MakeByRefType() }, null);
if (tryParseMethod == null) return false;
var arguments = new[] { value, Activator.CreateInstance(type) };
return (bool) tryParseMethod.Invoke(null, arguments);
}
Example:
"123".IsParseableAs<double>() ? double.Parse(sNumber) : 0;
Because IsParseableAs() tries to parse the string as the appropriate type instead of just checking if the string is "numeric" it should be pretty safe. And you can even use it for non numeric types that have a TryParse() method, like DateTime.
The method uses reflection and you end up calling the TryParse() method twice which, of course, isn't as efficient, but not everything has to be fully optimized, sometimes convenience is just more important.
This method can also be used to easily parse a list of numeric strings into a list of double or some other type with a default value without having to catch any exceptions:
var sNumbers = new[] {"10", "20", "30"};
var dValues = sNumbers.Select(s => s.IsParseableAs<double>() ? double.Parse(s) : 0);
Extension method two
public static TOutput ParseAs<TOutput>(this string value, TOutput defaultValue) {
var type = typeof(TOutput);
var tryParseMethod = type.GetMethod("TryParse", BindingFlags.Static | BindingFlags.Public, Type.DefaultBinder,
new[] { typeof(string), type.MakeByRefType() }, null);
if (tryParseMethod == null) return defaultValue;
var arguments = new object[] { value, null };
return ((bool) tryParseMethod.Invoke(null, arguments)) ? (TOutput) arguments[1] : defaultValue;
}
This extension method lets you parse a string as any type that has a TryParse() method and it also lets you specify a default value to return if the conversion fails.
This is better than using the ternary operator with the extension method above as it only does the conversion once. It still uses reflection though...
Examples:
"123".ParseAs<int>(10);
"abc".ParseAs<int>(25);
"123,78".ParseAs<double>(10);
"abc".ParseAs<double>(107.4);
"2014-10-28".ParseAs<DateTime>(DateTime.MinValue);
"monday".ParseAs<DateTime>(DateTime.MinValue);
Outputs:
123
25
123,78
107,4
28.10.2014 00:00:00
01.01.0001 00:00:00

If you want to check if a string is a number (I'm assuming it's a string since if it's a number, duh, you know it's one).
Without regex and
using Microsoft's code as much as possible
you could also do:
public static bool IsNumber(this string aNumber)
{
BigInteger temp_big_int;
var is_number = BigInteger.TryParse(aNumber, out temp_big_int);
return is_number;
}
This will take care of the usual nasties:
Minus (-) or Plus (+) in the beginning
contains decimal character BigIntegers won't parse numbers with decimal points. (So: BigInteger.Parse("3.3") will throw an exception, and TryParse for the same will return false)
no funny non-digits
covers cases where the number is bigger than the usual use of Double.TryParse
You'll have to add a reference to System.Numerics and have
using System.Numerics; on top of your class (well, the second is a bonus I guess :)

Double.TryParse
bool Double.TryParse(string s, out double result)

The best flexible solution with .net built-in function called- char.IsDigit. It works with unlimited long numbers. It will only return true if each character is a numeric number. I used it lot of times with no issues and much easily cleaner solution I ever found. I made a example method.Its ready to use. In addition I added validation for null and empty input. So the method is now totally bulletproof
public static bool IsNumeric(string strNumber)
{
if (string.IsNullOrEmpty(strNumber))
{
return false;
}
else
{
int numberOfChar = strNumber.Count();
if (numberOfChar > 0)
{
bool r = strNumber.All(char.IsDigit);
return r;
}
else
{
return false;
}
}
}

Try the regex define below
new Regex(#"^\d{4}").IsMatch("6") // false
new Regex(#"^\d{4}").IsMatch("68ab") // false
new Regex(#"^\d{4}").IsMatch("1111abcdefg")
new Regex(#"^\d+").IsMatch("6") // true (any length but at least one digit)

With c# 7 it you can inline the out variable:
if(int.TryParse(str, out int v))
{
}

Use these extension methods to clearly distinguish between a check if the string is numerical and if the string only contains 0-9 digits
public static class ExtensionMethods
{
/// <summary>
/// Returns true if string could represent a valid number, including decimals and local culture symbols
/// </summary>
public static bool IsNumeric(this string s)
{
decimal d;
return decimal.TryParse(s, System.Globalization.NumberStyles.Any, System.Globalization.CultureInfo.CurrentCulture, out d);
}
/// <summary>
/// Returns true only if string is wholy comprised of numerical digits
/// </summary>
public static bool IsNumbersOnly(this string s)
{
if (s == null || s == string.Empty)
return false;
foreach (char c in s)
{
if (c < '0' || c > '9') // Avoid using .IsDigit or .IsNumeric as they will return true for other characters
return false;
}
return true;
}
}

public static bool IsNumeric(this string input)
{
int n;
if (!string.IsNullOrEmpty(input)) //.Replace('.',null).Replace(',',null)
{
foreach (var i in input)
{
if (!int.TryParse(i.ToString(), out n))
{
return false;
}
}
return true;
}
return false;
}

Regex rx = new Regex(#"^([1-9]\d*(\.)\d*|0?(\.)\d*[1-9]\d*|[1-9]\d*)$");
string text = "12.0";
var result = rx.IsMatch(text);
Console.WriteLine(result);
To check string is uint, ulong or contains only digits one .(dot) and digits
Sample inputs
123 => True
123.1 => True
0.123 => True
.123 => True
0.2 => True
3452.434.43=> False
2342f43.34 => False
svasad.324 => False
3215.afa => False

Hope this helps
string myString = "abc";
double num;
bool isNumber = double.TryParse(myString , out num);
if isNumber
{
//string is number
}
else
{
//string is not a number
}

Pull in a reference to Visual Basic in your project and use its Information.IsNumeric method such as shown below and be able to capture floats as well as integers unlike the answer above which only catches ints.
// Using Microsoft.VisualBasic;
var txt = "ABCDEFG";
if (Information.IsNumeric(txt))
Console.WriteLine ("Numeric");
IsNumeric("12.3"); // true
IsNumeric("1"); // true
IsNumeric("abc"); // false

All the Answers are Useful. But while searching for a solution where the Numeric value is 12 digits or more (in my case), then while debugging, I found the following solution useful :
double tempInt = 0;
bool result = double.TryParse("Your_12_Digit_Or_more_StringValue", out tempInt);
Th result variable will give you true or false.

Here is the C# method.
Int.TryParse Method (String, Int32)

bool is_number(string str, char delimiter = '.')
{
if(str.Length==0) //Empty
{
return false;
}
bool is_delimetered = false;
foreach (char c in str)
{
if ((c < '0' || c > '9') && (c != delimiter)) //ASCII table check. Not a digit && not delimeter
{
return false;
}
if (c == delimiter)
{
if (is_delimetered) //more than 1 delimiter
{
return false;
}
else //first time delimiter
{
is_delimetered = true;
}
}
}
return true;
}