I am creating an usercontrol contains a "Tao.Platform.Windows.SimpleOpenGlControl".
In my control's constructor, I have
{
InitializeComponent();
simpleOpenGlControl1.InitializeContexts();
}
My problem:
When I use the control on a "Windows Forms Application" it's ok, but if I put the computer at hibernate or sleep mode, when visual studio is open and form that contains the control, is in design mode, the next time I turn it on this error comes up:
Fatal Error
can not activate the gl rendering context
and visual studio is not responding!
What's wrong here? I am doing something wrong?
I am using Tao framework.
After implementing OpenGL chart solution, I encounter those error.
Every time I tried to close form, error occurred.
After few times of debugging, I found the reason.
The reason is like this.
On my form closing, Draw function tried to use OpenGlControl object ONE MORE TIME.
So I make condition to check the additional flag.
I solved my problem in this way:
In control's InitializeComponent(); I removed simpleOpenGlControl1 Initialization and then in control's Load() function, I have
isDesignMode = LicenseManager.UsageMode == LicenseUsageMode.Designtime;
if (!isDesignMode)
{
// init simpleOpenGlControl1
}
Now when my control is used in a project, there is no simpleOpenGlControl1 in design mode to make problem!
Related
So essentially, I have a custom user control called ExcelDisplay. I try to drag it over in visual studio from the toolbox into my webform in the same project and I get a missing method exception. At one time the constructor was parameterized, but I changed it after deciding it was a bad design idea.
It looks like it is saying the constructor is missing, but its obviously there.
My winform to house the control is empty with the exception of the autogenerated code visual studio puts there.
The code for my ExcelDisplay's constructor looks like this.
namespace STS_Console.UserControls
{
public partial class ExcelDisplay : UserControl
{
public ExcelDisplay()
{
InitializeComponent();
DataDisplay.Columns[0].HeaderText = "Data";
//debug
string x = DataDisplay.Columns[0].GetType().ToString();
x.ToString();
}
The error message is this.
So that error occurs when do I drag and drop in the designer like this
Anyway so that is my problem. I am not sure what is causing it or how to fix it. I would be glad to post additional code upon request.
You should put your user controls in a class library of their own. For the designer to work, it needs a compiled version of your user control. If you cannot compile your user control before you compile your form, you will get into all kinds of trouble.
Rebuild Solution fixed it for me, although if your making regular changes to your user control, you should put them into a separate project.
My particular problem, was a user control, within a user control.
I have a userControl which starts a timer. It looks like the XAML designer is trying to call that code, which links to some back-end database stuff. I keep getting an unhanded exception error in the design screen.
Any ideas how I can stop the designer trying to run the code?
XAML designer will call the UserControl's constructor when loading in designer. In order to avoid this you can place a if condition as follows in your UserControl constructor
if(System.ComponentModel.DesignMode) return;
You can also check in this way
if (!System.ComponenyModel.DesignProperties.GetIsInDesignMode(this))
{ // write constructor code here }
I plan to add functionalities to TextBox with the following:
public class TextBoxExt : TextBox
{
protected override void OnKeyPress(KeyPressEventArgs e)
{
base.OnKeyPress(e);
}
}
The question is how can we use this TextBoxExt? Is there anyway to get this class onto the ToolBox so that we can just drag and drop it onto the form? If not, what is the best way to use the TextBoxExt?
Build you project with TextBoxExt, make sure it compiles ok.
With the form that you want TextBoxExt on, open the toolbox, right click and select "choose items"
Browse to you .exe or dll that you compiled in 1)
make sure that TextBoxExt has a tick next to it, press ok
TextBoxExt should appear in the toolbox, drag it onto your form
(There is another way of doing this, opening the designer file and renaming the instances of TextBox to TextBoxExt but manual editing of designer files can be considered hazardous by some)
I know this is super old question, but maybe still useful for someone else that has same problem like me - as it's still on the top Google :)
You might interest to use ToolboxItemAttribute (http://msdn.microsoft.com/en-us/library/system.componentmodel.toolboxitemattribute(v=vs.110).aspx).
I did this at my end to resolve the problem.
[ToolboxItem(true)]
public class PanelTitle : LabelControl {
// Whatever code to override LabelControl here...
}
Rebuild the solution and the extended control should be shown in the toolbox.
Any custom control in your project should show up in the Toolbox automatically. I have found that sometimes the controls won't show until you close a re-open Visual Studio. I assume the issue has something to do with caching of the contents of the Toolbox.
You need to add a constructor to your derived class.
public class TextBoxExt : TextBox
{
public TextBoxExt()
{
}
protected override void OnKeyPress(KeyPressEventArgs e)
{
base.OnKeyPress(e);
}
}
Your control should appear in the toolbox for your solution automatically. To have it appear for other projects, you have to do Choose Toolbox items, as others have said.
If you want to provide special design-time functionality, then you will also need to provide some additional designer related attributes and probably your own class derived from ControlDesigner.
I fell into this trap just a couple of hours ago.
I've got a .NET 2.0 Windows Application project with some custom UserControls; it worked fine.
So I decided to order my files in subfolders, to make my project a little bit cleaner.
After that, Visual Studio 2010 designer stopped loading my forms, and ToolBox won't show my controls anymore.
I freaked out, moving back source files in project root, resetting ToolBox, but nothing seemed to work.
After that, I remembered I used ReSharper "Remove Unused References", so I tried to put back unused reference, in particular System.Data: problem solved! :O
I can't say you why, but this worked for me.
Hope my experience can help someone else. :)
Bye,
Nando
I created an empty constructor for my custom implementation of UltraGridBagLayoutPanel. Although david.healed is right it isn't necessary, it is quite useful to put a breakpoint in to check that when the form initialises it is using your class to implement your custom control.
It would have been a lot easier to edit the designer file, but I tried it and changed both the field type for the control and also changed the assignment of the field to a new instance of my custom control.
private Infragistics.Win.Misc.UltraGridBagLayoutPanel ultraGridBagLayoutPanel1;
this.ultraGridBagLayoutPanel1 = new Infragistics.Win.Misc.UltraGridBagLayoutPanel();
to
private Athia.Reports.ultraGridBagLayoutPanel1 ultraGridBagLayoutPanel1;
this.ultraGridBagLayoutPanel1 = new Athia.Reports.ultraGridBagLayoutPanel1();
Doing this destroys Visual Studio every time, and to fix it requires using a text editor to put it back again. Therefore unless anyone can describe what is wrong with my implementation of this approach, perhaps calling the class the same as the control name isn't a great idea, I think the only safe and reliable way to achieve this is as Calanus describes in steps 1 to 5 or as an small deviation from that as Rob Windsor rightly points out restarting VS will bring the control into the Toolbox automatically. Unfortunately for me I then have to change all of the child controls over from the original class to my customised class :-(.
Within the same Solution this should work automatically. However, I have found that if the Target Framework aren't matching the Toolbox does not populate. ( I'm assuming really Reference needs to be of version same or lower than target of Reference. ) ( I did get a warning about non-matching Frameworks )
By making these the same Target Framework, Recompile, Restart VS. the control populated correctly. ( I also added the ToolboxItem(true) Attribute)
I have subclassed a Treeview and on instantiation it loads a new ImageList (and the associated Images).
Whenever I switch to the designer view, it's also trying to run this code, however the images aren't in the designer's path, so it crashes. I ended up putting in a hack to see if the current directory is "Visual Studio", then do nothing... but that's so ugly.
I find this happening for other things. If a control is trying to use objects during load/initalization that are only available while the program is running, then the Design View cannot bring up the control.
But is there a way to get around this?
I guess what I'm hoping for is having a try/catch for the Designer (only) with the ability to ignore a few errors I know will be happening (like FileNotFoundException, etc.).
Thanks
Everything that inherits from System.Windows.Forms.Control has a DesignMode property that returns a boolean indicating if you are in design mode or not. You could use this to determine when to/when not to load external resources.
Usually it is better to move the loading of these resources to an override of OnLoad as they are rarely required directly at construction. This fixes the issue you are seeing and means that only trees which get displayed at least once will perform these additional resource loading steps.
Otherwise, you can just exclude these steps during design time by checking the DesignMode property and acting accordingly.
This is a fine pattern to use if you're making a control library with a sample of images when shown in the designer or hook ins to other designer features but as a pattern for development I'm not sure it's very effective.
I would suggest shifting your "business logic" (in this case your loading of certain images into a treeview) outside of the bounds of your treeview control. In your case I would place the logic within the Load event of the form that the control is inside:
public void Load(object sender, EventArgs e)
{
string path = "c:\somePath\toAwesome\Images";
myFunkyTreeView.AddImages(path);
}
For larger apps I personally think you want to shift the logic even out of the forms themselves, but this is debatable measure as it requires additional plumbing as a trade-off for the flexibility this provides.
Thanks for pointing me in the right directioon guys.
I had tried registering to the OnLoad event, but that event is triggered when the Design View comes up, so that didn't quite work for me (am I doing something wrong?).
Anyway, I looked a bit more into the DesignMode property. It can only work for Controls, and sometimes your object may not even be a control.
So here's the answer I prefer:
if (LicenseManager.UsageMode == LicenseUsageMode.Designtime) {
// design-time stuff
} else {
// run-time stuff
}
Found it here.
I have an object that starts a thread, opens a file, and waits for input from other classes. As it receives input, it writes it to disk. Basically, it's a thread safe data logging class...
Here's the weird part. When I open a form in the designer (Visual Studio 2008) that uses the object the file gets created. It's obviously running under the design time vhost process...
The odd thing is I've not been able to reproduce the issue in another project. I'm not sure what the rules are for code that gets executed in the designer and code that does not. For example, creating a file in a Windows Forms constructor doesn't actually create the file at design time...
What is the explanation? Is there a reference?
The constructor of a control or form does not get executed when editing that class in the designer (nor does OnLoad get called). I've occasionally used this to set one value in the designer (eg. making its child controls all Visible in the designer) but override some of them to a different default value in the constructor (eg. hiding certain child controls which will only show in certain circumstances, such as an indicator on a status bar).
However, the constructor does get executed if the control is placed as a child on another control or form in the designer. OnLoad gets executed as well. This may be how your logging code was getting accidentally triggered in the designer.
For detecting design vs runtime, an answer to another question has screenshots of some emperical tests showing the values returned by some common approaches. It appears that a child control of a child control (two levels down) of the form or control being edited in the designer sees its own DesignMode == false, so the normal property check will fail to protect code (eg. in the OnLoad method) for controls nested within a control added in the designer. If you were checking DesignMode as one would expect, it could be the nesting which caused it to get around that check. It also always sees DesignMode == false within the constructor.
Also, note that the LicenseManager.UsageMode check only sees DesignTime within the constructor; when OnLoad is called it is within a RunTime LicenseContext. The most complete solution seems to be to check LicenseManager.UsageMode in the constructor of the control or form (or component) and save the setting to a member variable or property which you can check later to avoid running code that should never run in the designer even when nested. There's also another approach in another answer to that other question which accounts for nesting but only works outside the constructor.
You can check the UsageMode of the LicenseManager, to check if the code is in design time or not.
System.ComponentModel.LicenseManager.UsageMode == System.ComponentModel.LicenseUsageMode.Designtime
Here is a quick example:
using System;
using System.ComponentModel;
using System.Windows.Forms;
namespace Test
{
public class ComponentClass : Component
{
public ComponentClass()
{
MessageBox.Show("Runtime!");
}
}
}
When this component gets add to your form in the designer, you will immediatly get a message box.
To prevent this you can add a simple if statement to check if the code is not in design time
using System;
using System.ComponentModel;
using System.Windows.Forms;
namespace Test
{
public class ComponentClass : Component
{
public ComponentClass()
{
if (LicenseManager.UsageMode != LicenseUsageMode.Designtime)
{
MessageBox.Show("Runtime!");
}
}
}
}
After adding the if statement, the messagebox no longer appears when the component is added to the form via the designer.
Well, since this has been resurrected anyway, here's the function I use to determine whether I'm in design mode:
public static bool IsAnyInDesignMode(Control control){
while(control != null){
if(control.Site != null && control.Site.DesignMode)
return true;
control = control.Parent;
}
return false;
}
This handles the case where the control is a child created by another control. The DesignMode property is only set for controls created by the designer itself.
You could also use this to check if the Visual Studio Designer is running the code:
public static bool DesignMode
{
get { return (System.Diagnostics.Process.GetCurrentProcess().ProcessName == "devenv"); }
}
Then in Form_Load:
if (!DesignMode)
{
// Run code that breaks in Visual Studio Designer (like trying to get a DB connection)
}
However, this is less elegant than using the LicensManager.UsageMode, but it works (until Microsoft changes the name of the process Visual Studio runs under).
There are some things you shouldn't do with the designer. I don't have any hard evidence, but I found that the Windows Forms designer hates it when you take away the default constructor from it. Just go ahead and create new overloads, but leave the empty constructor in place.
Also try to avoid doing Form_Load events in base classes you inherit from.