How to add a line to the Text property of a textbox? - c#

I have TextBox in a Windows form application. And I write a text in it.
eg.
texbox.Text = " first line ";
....
textbox.Text = "second line";
When I write second text, the first line is deleted. How to leave the first line and write next texts in next line in the TextBox?
I want the following result:
first line
second line

textbox.text = "first line";
textbox.text += "\nsecond line";
or
textbox.text = "first line";
textbox.text = textbox.text + "\nsecond line";

You want to change the TextMode property to MultiLine
then you can write like
texbox.text = " first line ";
....
textbox.text += "\nsecond line";
Please note the append operator += and \n which is new line character

I usually write a wrapper.
One important difference is to use
Environment.Newline
instead of
"\n\r".
Also, as others have noted, set the textBox multiline property.
public void WriteLine(string msg)
{
if (!string.IsNullOrEmpty(textBox.Text))
{
msg = string.Format("{0}{1}", Environment.NewLine, msg);
}
textBox.AppendText(msg);
}

You can set the Textbox multiline property to true and can use \r\n for multiline text like below:
TextBox1.Text = "First line\r\nSecond line";

You can do following ways also.
textbox.text = "first line";
textbox.text = textbox.text + vbCrlf + "second line";

Related

Small Bug When When Appending Text To Multiline Text Box (C#)

i have multiline text box in my form with existing text and I am trying to append text lines on new line and everything works fine but the first line always get added with the existing last line.
Example
text box holds this value
test1
and I am using below code to enter new line
txtMasterResults.AppendText(String.Join(Environment.NewLine, "line 2"));
txtMasterResults.AppendText(String.Join(Environment.NewLine, "line 3"));
and results looks like this
test1line2
line3
how can I fix the first line of textbox so I get the new text from secondline ?
I would retrieve the old string, remove any newlines at the end, and then append the new content. So like this:
txtMasterResults.Text = txtMasterResults.Text.Trim() + "\n" + newText
String.Join joins strings from an array using a delimiter. This is not what you want here.
Use:
txtMasterResults.Text += Environment.NewLine + "line 2" + Environment.NewLine + "line 3";
Note that
txtMasterResults.Text += "something"; is the same as
txtMasterResults.Text = txtMasterResults.Text + "something";

c# replace "\n" text with newline in a textbox

I have some text (for example "o\nour first place, and this\n\n13") and I want that for each "\n" string founded into the text this must be replaced with newline...
output for the example will be:
o
our first place, and this
13
How can I make? textbox is multiline
the code is
string text_str = txtbox.Text;
text_str .Replace("(?<!\r)\n", "\r\n");
txtbox.Clear();
txtbox.Text = text_str;
I think you're looking for something like this:
string text_str = txtbox.Text;
text_str = text_str.Replace("\\n", "\r\n");
txtbox.Clear();
txtbox.Text = text_str;
Although that's a really round about way of doing things. This will accomplish the same thing:
txtbox.Text = txtbox.Text.Replace("\\n", "\r\n");
Here you are:
string text_str = "o\nour first place, and this\n\n13";
text_str = text_str.Replace("\n", "\r\n");
Hope this help.
This should work:
txtbox.Text = txtbox.Text.Replace("\\n", Environment.NewLine);
Note very sure what the OP needed, but in case someone else comes here looking for what I was:
blah.Text = Regex.Replace(origString, "(?<!\\r)\\n", "\\r\\n")

programmatic textblock entry with linebreaks

How do I programmatically add text with line breaks to a textblock?
If I insert text like this:
helpBlock.Text = "Here is some text. <LineBreak/> Here is <LineBreak/> some <LineBreak/> more.";
Then the linebreaks get interpreted as part of the string literal. I want it to be more like what would happen if I had it in the XAML.
I can't seem to do it the WPF way either:
helpBlock.Inlines.Add("Here is some content.");
Since the Add() method wants to accept objects of type "inline".
I can't create an Inline object and pass it as a parameter because it is "inaccessible due to its protection level:
helpBlock.Inlines.Add(new Windows.UI.Xaml.Documents.Inline("More text"));
I don't see a way to programmatically add runs.
I can find a ton of WPF examples of this, but nothing for WinRT.
I've also turned up a lot of XAML examples, but nothing from C#.
You could just pass in newline \n instead of <LineBreak/>
helpBlock.Text = "Here is some text. \n Here is \n some \n more.";
Or in Xaml you would use the Hex value of newline
<TextBlock Text="Here is some text.
Here is
some
more."/>
Both results:
Use Enviroment.NewLine
testText.Text = "Testing 123" + Environment.NewLine + "Testing ABC";
StringBuilder builder = new StringBuilder();
builder.Append(Environment.NewLine);
builder.Append("Test Text");
builder.Append(Environment.NewLine);
builder.Append("Test 2 Text");
testText.Text += builder.ToString();
You could convert \n to <LineBreak/> programmatically.
string text = "This is a line.\nThis is another line.";
IList<string> lines = text.Split(new string[] { #"\n" }, StringSplitOptions.None);
TextBlock tb = new TextBlock();
foreach (string line in lines)
{
tb.Inlines.Add(line);
tb.Inlines.Add(new LineBreak());
}
Solution:
I would use "\n" instead of linebreaks. Best way would be use it on this way:
Resources.resx file:
myTextline: "Here is some text. \n Here is \n some \n more."
In yours Class:
helpBlock.Text = Resources.myTextline;
This will looks like:
Other solution would be to build your string here with Environment.NewLine.
StringBuilder builder = new StringBuilder();
builder.Append(Environment.NewLine);
builder.Append(Resources.line1);
builder.Append(Environment.NewLine);
builder.Append(Resources.line2);
helpBlock.Text += builder.ToString();
Or use here "\n"
StringBuilder builder = new StringBuilder();
builder.Append("\n");
builder.Append(Resources.line1);
builder.Append("\n");
builder.Append(Resources.line2);
helpBlock.Text += builder.ToString();
I have one component XAML
<TextBlock x:Name="textLog" TextWrapping="Wrap" Background="#FFDEDEDE"/>
Then I pass the string + Environment.NewLine;
Example:
textLog.Inlines.Add("Inicio do processamento " + DateTime.Now.ToString("dd/MM/yyyy HH:mm:ss") + Environment.NewLine);
textLog.Inlines.Add("-----------------------------------" + Environment.NewLine);
The result is
Inicio do processamento 19/08/2019 20:31:13
-----------------------------------

Replacing newline in multiline textbox with <br/>

I am trying to use a multiline textbox to insert text into a table which is displayed as html. I want to with javascript take the text inside of the textbox and find where the user pressed enter and place "<br/>" in that position so when the text is displayed it will show line break. Any ideas on how I could do this?
I tried something like this but it did not work.
var text = document.getElementById("announcementid").value;
var newtext = text.replace("\n", "<br/>");
text = newtext;
The newtext variable ends up being a copy of the original string from your announcementid element. Thus, you'll need to re-set the value property on the original document element:
var text = document.getElementById("announcementid").value;
var newtext = text.replace(/\n/g, "<br />");
document.getElementById("announcementid").value = newtext;
Also, as Konstantin pointed out, the replace() function in Javascript will just replace the first instance unless you pass in a global regular expression.
Fiddle example
Text is a primitive so it would not replace the value. Use a regular expression to globally replace instead of replacing just the first instance:
var text = document.getElementById("announcementid").value;
var newtext = text.replace(/\n/g, "<br />");
document.getElementById("announcementid").value = newtext;

How to insert newline in string literal?

In .NET I can provide both \r or \n string literals, but there is a way to insert
something like "new line" special character like Environment.NewLine static property?
Well, simple options are:
string.Format:
string x = string.Format("first line{0}second line", Environment.NewLine);
String concatenation:
string x = "first line" + Environment.NewLine + "second line";
String interpolation (in C#6 and above):
string x = $"first line{Environment.NewLine}second line";
You could also use \n everywhere, and replace:
string x = "first line\nsecond line\nthird line".Replace("\n",
Environment.NewLine);
Note that you can't make this a string constant, because the value of Environment.NewLine will only be available at execution time.
If you want a const string that contains Environment.NewLine in it you can do something like this:
const string stringWithNewLine =
#"first line
second line
third line";
EDIT
Since this is in a const string it is done in compile time therefore it is the compiler's interpretation of a newline. I can't seem to find a reference explaining this behavior but, I can prove it works as intended. I compiled this code on both Windows and Ubuntu (with Mono) then disassembled and these are the results:
As you can see, in Windows newlines are interpreted as \r\n and on Ubuntu as \n
var sb = new StringBuilder();
sb.Append(first);
sb.AppendLine(); // which is equal to Append(Environment.NewLine);
sb.Append(second);
return sb.ToString();
One more way of convenient placement of Environment.NewLine in format string.
The idea is to create string extension method that formats string as usual but also replaces {nl} in text with Environment.NewLine
Usage
" X={0} {nl} Y={1}{nl} X+Y={2}".FormatIt(1, 2, 1+2);
gives:
X=1
Y=2
X+Y=3
Code
///<summary>
/// Use "string".FormatIt(...) instead of string.Format("string, ...)
/// Use {nl} in text to insert Environment.NewLine
///</summary>
///<exception cref="ArgumentNullException">If format is null</exception>
[StringFormatMethod("format")]
public static string FormatIt(this string format, params object[] args)
{
if (format == null) throw new ArgumentNullException("format");
return string.Format(format.Replace("{nl}", Environment.NewLine), args);
}
Note
If you want ReSharper to highlight your parameters, add attribute to the method above
[StringFormatMethod("format")]
This implementation is obviously less efficient than just String.Format
Maybe one, who interested in this question would be interested in the next question too:
Named string formatting in C#
string myText =
#"<div class=""firstLine""></div>
<div class=""secondLine""></div>
<div class=""thirdLine""></div>";
that's not it:
string myText =
#"<div class=\"firstLine\"></div>
<div class=\"secondLine\"></div>
<div class=\"thirdLine\"></div>";
If you really want the New Line string as a constant, then you can do this:
public readonly string myVar = Environment.NewLine;
The user of the readonly keyword in C# means that this variable can only be assigned to once. You can find the documentation on it here. It allows the declaration of a constant variable whose value isn't known until execution time.
static class MyClass
{
public const string NewLine="\n";
}
string x = "first line" + MyClass.NewLine + "second line"
newer .net versions allow you to use $ in front of the literal which allows you to use variables inside like follows:
var x = $"Line 1{Environment.NewLine}Line 2{Environment.NewLine}Line 3";
If you are working with Web application you can try this.
StringBuilder sb = new StringBuilder();
sb.AppendLine("Some text with line one");
sb.AppendLine("Some mpre text with line two");
MyLabel.Text = sb.ToString().Replace(Environment.NewLine, "<br />")
If I understand the question: Couple "\r\n" to get that new line below in a textbox. My example worked -
string s1 = comboBox1.Text; // s1 is the variable assigned to box 1, etc.
string s2 = comboBox2.Text;
string both = s1 + "\r\n" + s2;
textBox1.Text = both;
A typical answer could be s1
s2 in the text box using defined type style.
I like more the "pythonic way"
List<string> lines = new List<string> {
"line1",
"line2",
String.Format("{0} - {1} | {2}",
someVar,
othervar,
thirdVar
)
};
if(foo)
lines.Add("line3");
return String.Join(Environment.NewLine, lines);
Here, Environment.NewLine doesn't worked.
I put a "<br/>" in a string and worked.
Ex:
ltrYourLiteral.Text = "First line.<br/>Second Line.";

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