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How to run sqlite3 inline command using c#?

When I run the below command in cmd prompt of windows:
sqlite3 -header -csv local-DataBase.sqlite "select * from customers;" > data.csv
It creates a file called "data.csv" with the result of "select * from customers;" in it with headers.
I need to run the same command as above in c# so that it the console app creates a file for the result of the sql command.
Till now I have done this:
string sqlLite3ExePath = "sqlite3";
string sqLitePath2 = "-header -csv local-DataBase.sqlite \"select* from customers;\" > data.csv";
using (Process pProcess = new Process())
{
pProcess.StartInfo.FileName = sqlLite3ExePath;
pProcess.StartInfo.Arguments = sqLitePath2 ;
pProcess.StartInfo.UseShellExecute = false;
pProcess.StartInfo.RedirectStandardOutput = true;
pProcess.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
pProcess.StartInfo.CreateNoWindow = false;
pProcess.EnableRaisingEvents = true;
pProcess.Exited += PProcess_Exited;
pProcess.Start();
string output = pProcess.StandardOutput.ReadToEnd();
pProcess.WaitForExit();
Debug.WriteLine(output);
}
But this throws an error:
Error: near ">": syntax error
What am I doing wrong?

As mentioned in the comments, there are two things going on when you run this command from the command prompt, you're running SQLite, but because of the redirect operator, you're also having the shell capture the output and create a file for you.
If you want to recreate this exact behavior, you need to run the shell and pass it this command:
string sqlLite3ExePath = "cmd";
string sqLitePath2 = "/c \"sqlite3 -header -csv local-DataBase.sqlite ^\"select* from customers;^\" > data.csv\"";
using (var pProcess = new Process())
{
pProcess.StartInfo.FileName = sqlLite3ExePath;
pProcess.StartInfo.Arguments = sqLitePath2;
pProcess.StartInfo.UseShellExecute = false;
pProcess.StartInfo.RedirectStandardOutput = true;
pProcess.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
pProcess.StartInfo.CreateNoWindow = false;
pProcess.EnableRaisingEvents = true;
pProcess.Exited += PProcess_Exited;
pProcess.Start();
string output = pProcess.StandardOutput.ReadToEnd();
pProcess.WaitForExit();
Console.WriteLine(output);
}

c# automation stop process

I have C# automation code that start a process
var proc1 = new ProcessStartInfo();
string anyCommand = " adb logcat - v threadtime emulator-5554 > logcat.log";
proc1.UseShellExecute = true;
proc1.WorkingDirectory = outputDirectory;
proc1.FileName = #"C:\Windows\System32\cmd.exe";
proc1.Verb = "runas";
proc1.Arguments = "/c " + anyCommand;
proc1.WindowStyle = ProcessWindowStyle.Hidden;
Process p = new Process();
p.StartInfo = proc1;
p.Start();
Console.WriteLine(p.Id);
TestLogger.WriteInformationStep("p.Id: " + p.Id);
after some steps I'm trying to read the file
string text2 = System.IO.File.ReadAllText(element);
but I receive error message
System.IO.IOException : The process cannot access the file
'C:\Users\test\Documents\overview9\bin\Debug\Results\logcat.log'
because it is being used by another process. TearDown :
HarVE.Log.FailedStepException : There were 1 failed step(s): Test did
not run to completion
what should i do?
I tried p.Close();p.Kill();
non of them work for me.

If p.Kill(); where placed after System.IO.File.ReadAllText(element); write p.Kill() before System.IO.File.ReadAllText(element),
if it placed correctly, then seems like other process is reading/writting that file,
try to use StreamReader from System.IO, StreamReader can read multiple times, something like this:
StreamReader sr = new StreamReader(path_to_file);//replace path_to_file by your txt file path
string text2 = sr.ReadToEnd();

Read from an external program/console

I have a problem, I need to execute a console program and I have to show the output information of that console on my program. I have a string variable called "result" that have to storage that information, but is always null and I don't know why. Can anyone help me? I put the code below:
Process p = new Process();
p.StartInfo.FileName = "python";
p.StartInfo.Arguments = #"C:\Users\xxx\xxx\xxx\xxx_\xxx yyy\zzz.py " + path;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
p.Start();
StreamReader sr = p.StandardOutput;
p.WaitForExit();
string result = sr.ReadToEnd();
sr.Close();
textBox1.Text = result;
On the console, I recieve 8382 JGK, for example, but my result variable is always "".

You could try something like this
StreamReader sr = p.StandardOutput;
p.WaitForExit();
char[] result = new char[p.Length]; //or sr.BaseStream.Length
sr.Read(result,0,(int)p.Length); // again or sr.BaseStream.Length
And see if result array contains anything.

I solve it! The problem was on the file's path. I have to put it on the same folder as the ".py" file and it works fine. I add the correct piece of code:
string python = #"C:\xxx\python.exe";
string myPythonApp = "program.py";
string x = #"file.jpg";
ProcessStartInfo myProcessStartInfo = new ProcessStartInfo(python);
myProcessStartInfo.UseShellExecute = false;
myProcessStartInfo.RedirectStandardOutput = true;
myProcessStartInfo.Arguments = myPythonApp + " " + x;
Process myProcess = new Process();
myProcess.StartInfo = myProcessStartInfo;
myProcess.StartInfo.CreateNoWindow = true;
myProcess.Start();
StreamReader myStreamReader = myProcess.StandardOutput;
string myString = myStreamReader.ReadLine();
myProcess.WaitForExit();
myProcess.Close();
textBox1.Text = myString;

Running exe with parameters doesn't work

var p = Process.Start(#"c:\PsTools\PsExec.exe", #"C:\Windows\System32\notepad.exe");
var err = p.StandardError.ReadToEnd();
var msg = p.StandardOutput.ReadToEnd();
lblStatusResponse.Text = "Err: " + err + "Msg: " + msg;
Why is my code not working?
I getting error:
System.InvalidOperationException: StandardError has not been redirected.
But when I add following:
p.StartInfo.RedirectStandardError = true;
var p = Process.Start(#"c:\PsTools\PsExec.exe", #"C:\Windows\System32\notepad.exe");)
it still gets the same error.
The main problem is that I wanna execute a exe with arguments, but I can't get it to work.

The following code generates a new p, this ignoring the settings you change in the previous instance:
var p = Process.Start(#"c:\PsTools\PsExec.exe", #"C:\Windows\System32\notepad.exe");)
So it doesn't really matter whether you initialize p like this
p.StartInfo.RedirectStandardError = true;
or not.
What you need to do
You need to create a ProcessStartInfo object, configure it and then pass it to Process.Start.
ProcessStartInfo p = new ProcessStartInfo(#"c:\PsTools\PsExec.exe", #"C:\Windows\System32\notepad.exe");
p.UseShellExecute = false;
p.RedirectStandardError = true;
p.RedirectStandardOutput = true;
Process proc = Process.Start(p);
var err = proc.StandardError.ReadToEnd();
var msg = proc.StandardOutput.ReadToEnd();

Taken from MSDN: https://msdn.microsoft.com/en-us/library/system.diagnostics.process.standardoutput(v=vs.110).aspx
The StandardOutput stream has not been defined for redirection; ensure ProcessStartInfo.RedirectStandardOutput is set to true and ProcessStartInfo.UseShellExecute is set to false.
So remember to set those flags as instructed by MS.

Process proc = new Process();
proc.StartInfo.FileName = "cmd.exe";
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.RedirectStandardError = true;
proc.StartInfo.RedirectStandardOutput = true;
proc.StartInfo.Arguments = "/C " + command; //Enter your own command
proc.Start();
string output =proc.StandardOutput.ReadToEnd();

I know this is not the same code you have but this is was the only working code I have , that will run external command/process in C# , and return all of it output/errors to the application main window
public void Processing()
{
//Create and start the ffmpeg process
System.Diagnostics.ProcessStartInfo psi = new ProcessStartInfo("ffmpeg")
{ // this is fully command argument you can make it according to user input
Arguments = "-y -i '/mnt/Disk2/Video/Antina03.jpg' pp.mp4 ",
RedirectStandardOutput = true,
WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden,
UseShellExecute = false,
RedirectStandardError=true,
RedirectStandardInput=true
};
System.Diagnostics.Process ischk;
ischk = System.Diagnostics.Process.Start(psi);
ischk.WaitForExit();
////Create a streamreader to capture the output of ischk
System.IO.StreamReader ischkout = ischk.StandardOutput;
ischk.WaitForExit();
if (ischk.HasExited) // this condition very important to make asynchronous output
{
string output = ischkout.ReadToEnd();
out0 = output;
}
/// in case you got error message
System.IO.StreamReader iserror = ischk.StandardError;
ischk.WaitForExit();
if (ischk.HasExited)
{
string output = iserror.ReadToEnd();
out0 = output;
}
}
if you want to run this process just call the function Processing() BTW out0 are global variable so it can use out the function .
credit
I'm using MonoDevlop "C# devloping tool on Linux " and I get the output this way :-
public MainWindow() : base(Gtk.WindowType.Toplevel)
{
Build();
Processing();
textview2.Buffer.Text = out0;
}

Spaces in command line argument not working

I have requirement to execute the command line arguments. If file path contains the Spaces it doesn’t work properly. It returns the error file not found. The program is given below.
public void Method()
{
string docFile = #"C:\Test Document1.doc";
string docxFile = #"C:\Test Document1.docx";
string file = #"C:\doc2x_r649 (1)\doc2x_r649\doc2x.exe";
ExecuteCommand(file, string.Format(docFile + " -o " + docxFile));
}
public static string ExecuteCommand(string file, string command)
{
String result;
try
{
//Create a new ProcessStartInfo
System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo();
//Settings
procStartInfo.UseShellExecute = false;
procStartInfo.CreateNoWindow = false;
procStartInfo.RedirectStandardOutput = true;
procStartInfo.FileName = file;
procStartInfo.Arguments = command;
//Create new Process
System.Diagnostics.Process proc = new System.Diagnostics.Process();
//Set ProcessStartInfo
proc.StartInfo = procStartInfo;
//Start Process
proc.Start();
//Wait to exit
proc.WaitForExit();
//Get Result
result = proc.StandardOutput.ReadToEnd();
//Return
return result;
}
catch
{
}
return null;
}
If file path doesn't contains spaces it works properly.

Have you tried adding quotes to your paths?
ExecuteCommand(file, string.Format("\"" + docFile + "\" -o \"" + docxFile + "\""));

Try this
ExecuteCommand(file, string.Format("\"{0}\" -o \"{1}\"",docFile , docxFile));