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Count XML Nodes Script Task SSIS

I have the below xml:
<Users>
<User ID="User1"
<Element1>Name1<Element1>
</User>
<User ID="User2"
<Element1>Name2<Element1>
</User>
<User ID="User3"
<Element1>Name3<Element1>
</User>
</Users>
This XML is created and stored in a string variable in SSIS.
I need to count the User nodes before doing the next step and I would like to do it using a script task. This what I think I need to do
// assign string to a variable
String XMLString = Dts.Variables["User::XMLString"].Value
// Convert variable to xml data type:
XmlSerializer serializer = new XmlSerializer(XMLString );
//Count the user nodes and assign integer to a variable.
Dts.Variables["User::UserCount"].Value = serializer.SelectNodes("Users/User").Count;
I’ve been trying to figure out how to do it but I’m quite new on C# and I would really need an example about this please.
Thanks!

You can do this:
string XMLString = Dts.Variables["User::XMLString"].Value;
Dts.Variables["User::UserCount"].Value = (Regex.Matches(XMLString, #"</User>")).Count;
See the code here in this link.

Try this:
XmlDocument doc = new XmlDocument();
doc.Load(XMLString);
Dts.Variables["User::UserCount"].Value = doc.SelectNodes("User").Count;

accessing special element in xml using linq [duplicate]

This question already has answers here:
LINQ to read XML
(6 answers)
Closed 8 years ago.
how can I get Password value for specified Username using linq?
For example if Username equals AAAA then passsword is ss.
<?xml version="1.0" encoding="utf-8"?>
<User>
<Username>AAAA</Username>
<Password>ss</Password>
</User>
<User>
<Username>CCC</Username>
<Password>zzz</Password>
</User>

I will start by saying you should change your xml structure to the following:
<?xml version="1.0" encoding="utf-8"?>
<users>
<User>
<Username>AAAA</Username>
<Password>ss</Password>
</User>
<User>
<Username>CCC</Username>
<Password>zzz</Password>
</User>
</users>
Then you can try:
var username = "AAAA";
var password = XElement.Parse(xml)
.Elements("User")
.Where(x=>(string)x.Element("Username") == username)
.Select(x=>(string)x.Element("Password"));
I tend to use XElement, but some would say XDocument is better:
var xdoc = XDocument.Parse(xml);
var username = "AAAA";
var password = xdoc.Root.Elements("User")
.Where(x=>(string)x.Element("Username") == username)
.Select(x=>(string)x.Element("Password"))
.FirstOrDefault();

c#: Add element to second nesting in xml

I have a XML which looks like:
<users>
<user id="0">
<name>John</name>
<lastName>Smith</lastName>
<bills>
<bill id="0">
<name>Water</name>
<forMonth>2013-12-01</forMonth>
<money>235</money>
<lastDayToPay>2014-01-02</lastDayToPay>
<payed>False</payed>
</bill>
<bill id="1">
<name>Telephone</name>
<forMonth>2013-11-01</forMonth>
<money>690</money>
<lastDayToPay>2014-01-01</lastDayToPay>
<payed>True</payed>
</bill>
</bills>
</user>
How can i add new bill for the user, i have problem accessing "bills" node and adding element to it. I'm using c#.

use following code
XmlDocument myDocument = new XmlDocument();
myDocument.Load(XMLFile);
XmlNode newNode = myDocument.CreateElement("bill");
//add values;
var requiredNode = myDocument.ChildNodes.OfType<XmlElement>().Where(o => o.Name == "bills").First();
requiredNode.AppendChild(newNode);
myDocument.Save(XMLFile);

insert node in xml file

i have a xml file that looks like the following, and i need to edit it in c# to insert a new node:
<?xml version="1.0" encoding="utf-8"?>
<Users>
<User>
<Name>John Smith</Name>
<test>
<Date>23.05.2011</Date>
<points>33</points>
</test>
<test>
<Date>22.06.2011</Date>
<points>29</points>
</test>
</User>
<User>
<Name>David Chris</Name>
<test>
<Date>01.02.2009</Date>
<points>25</points>
</test>
<test>
<Date>14.01.2010</Date>
<points>231</points>
</test>
</User>
i need to insert another "in this example a third" Element to the user called "John Smith" with all the sub elements..
so the xml will become :
<?xml version="1.0" encoding="utf-8"?>
<Users>
<User>
<Name>John Smith</Name>
<test>
<Date>23.05.2011</Date>
<points>33</points>
</test>
<test>
<Date>22.06.2011</Date>
<points>29</points>
</test>
<test>
<Date>30.10.2011</Date>
<points>21</points>
</test></b>
</User>
<User>
<Name>David Chris</Name>
<test>
<Date>01.02.2009</Date>
<points>25</points>
</test>
<test>
<Date>14.01.2010</Date>
<points>231</points>
</test>
</User>
any help is really appreciated ..
thanks a lot ..

Simple (assuming you're using .NET 3.5 or higher):
Load the document (e.g. using XDocument.Load)
Add the relevant element (create a new XElement, find the insertion point, call insertionPoint.Add(newElement))
Save the document (XDocument.Save)
LINQ to XML makes almost all XML-based tasks simpler than older APIs... if the above isn't a good enough start, I'd strongly recommend reading a tutorial on LINQ to XML.
There's no simple way of inserting the new element without reading the old file totally, manipulating it and then writing it out totally. In theory you could do it in a streaming fashion with XmlReader and XmlWriter, but they're almost always more trouble than they're worth.

class Program
{
static void Main()
{
var doc = XDocument.Load("test.xml");
var johnSmith = doc
.Descendants("User")
.Descendants("Name")
.Where(x => x.Value == "John Smith")
.Select(x => x.Parent)
.First();
johnSmith.Add(
new XElement("test",
new XElement("Date", "30.10.2011"),
new XElement("points", "21")
)
);
doc.Save("new.xml");
}
}

For .NET Framework 3.5 and higher: XDocument
For .NET Framework 1.1 and higher: XmlDocument

Here you go:
class Program
{
static void Main(string[] args)
{
XElement main = XElement.Load(#"users.xml");
// write new data to new file
string newDate = "01.01.2012";
string newPoints = "42";
main.Descendants("User")
.Descendants("Name")
.Where(e => e.Value == "John Smith")
.Select(e => e.Parent)
.First()
.Add(new XElement("test",
new XElement("date", newDate),
new XElement("points", newPoints)
)
);
main.Save("users2.xml");
}
}

Deleting whole sections of my XML file

I have a userlist for a program I'm designing, and all the users are stored to an XML file, like so:
<?xml version="1.0"?>
<Users>
<User ID="1">
<nickname>Tom</nickname>
<password>Sams</password>
<host>ahost#asd.com</host>
<email>badrandom#as.com</email>
<isloggedin>true</isloggedin>
<permission>10</permission>
</User>
<User ID="2">
<nickname>ohai</nickname>
<password>asdalkdj9u</password>
<host>meh#meh.com</host>
<email>my#email</email>
<isloggedin>false</isloggedin>
<permission>1</permission>
</User>
<User ID="3">
<nickname>ohai</nickname>
<password>sercret</password>
<host>my#host</host>
<email>my#email</email>
<isloggedin>false</isloggedin>
<permission>1</permission>
</User>
<User ID="4">
<nickname>mib_hr6qhr</nickname>
<password>YXNsa2RhZGxrYXNk</password>
<host>adb7e51b#webchat.mibbit.com</host>
<email>alskd#alskd.com</email>
<isloggedin>true</isloggedin>
<permission>1</permission>
</User>
</Users>
Now, based on the users ID number, I need to be able to delete all reference to that user.
So say, I have ID number 3, how can I completely delete userid number 3's existence from the xml file?
I'm looking for code examples, but any help would be greatly appreciated!

One approach using the XML DOM (.NET 1.x and up) would be to just load the file, find user no. 3, and remove that node, and save the file back:
XmlDocument doc = new XmlDocument();
doc.Load("yourXmlFile.xml");
XmlNode userNo3 = doc.SelectSingleNode("//Users/User[#ID='3']");
if(userNo3 != null)
{
userNo3.ParentNode.RemoveChild(userNo3);
}
doc.Save("YourNewXmlFile.xml");
Marc

Assuming you have the XML loaded in an XDocument:
using System.Linq;
using System.Xml.Linq;
void Delete()
{
XDocument document = LoadXML();
document.Elements("Users")
.Single(e => e.Attribute("ID").Value == "3")
.Remove();
}
Of course, this assumes that the user you request will always be present in the XML. To be safe, you should use SingelOrDefault() and check for a null value before deleting.

The problem with linq and DOM approach is that there is a round-trip (parsing/serialization) which can be efficient, vtd-xml has something called incremental update, here is an article that explains it... http://www.codeproject.com/KB/XML/xml_processing_future.aspx
VTDGen vg = new VTDGen();
if (vg.parseFile("your.xml", false)){
VTDNav vn = vg.getNav();
AutoPilot ap = new AutoPilot(vn);
ap.selectXPath("/users/user[#ID='3']");
XMLModifier xm = new XMLModifier(vn);
if (ap.evalXPath()!=-1){
xm.remove();
xm.output("new.xml");
}
}