how to get xml nth element name in wpf

how to get xml nth element name in wpf - c#

public partial class XML_3 : Window
{
public XML_3()
{
this.InitializeComponent();
XmlDocument doc = new XmlDocument();
doc.Load("D:/sample.xml");
XmlNodeList student_list = doc.GetElementsByTagName("Student");
foreach (XmlNode node in student_list)
{
XmlElement student = (XmlElement)node;
int element_count = student.ChildNodes.Count;
}
}
}
In above code.I can get the count of element except root element(Student). now the count is 3.
But i have to get 2ed element name(Kavi),it's attribute element name(ID) and it's child element name(FName,MName).
what should i do to get those stuff.
Please help me...

Use XDocument (why?):
var doc = XDocument.Parse(xml); // OR Load(...)
var nodeCount = doc.Elements().Count();
var secondNode = doc.Elements().Skip(1).First();
var studentName = secondNode.Name;
var studentId = secondNode.Attribute("ID").Value;
or (for your code):
var secondNode = student.ChildNodes[1] as XmlElement;
var studentName = secondNode.LocalName;
var studentId = secondNode.Attributes["ID"];
Added:
var secondNode = student.ChildNodes[1];
var fName =
secondNode.ChildNodes.Cast<XmlElement>().FirstOrDefault(x => x.LocalName == "FName").InnerText;
var mName =
secondNode.ChildNodes.Cast<XmlElement>().FirstOrDefault(x => x.LocalName == "MName").InnerText;
var studentId = secondNode.Attributes["ID"].Value;

Related

How to hold more than one values in XML element?

xWaarde.Value is overriding with new values and flushing old values.
how to stored multiple values in Xelement.
private XElement[] AddCoordinatenList(XElement childElements)
{
XmlNode xmlCoordinatenNode = Utility.GetMappingValues(Constants.BMCoordinaten, ConnectionType.BM);
XmlNode xWaardeNode = Utility.GetMappingValues(Constants.BMXwaarde, ConnectionType.BM);
XmlNode yWaardeNode = Utility.GetMappingValues(Constants.BMYwaarde, ConnectionType.BM);
XmlNode CoordinateX = Utility.GetMappingValues(Constants.XCoordinate, ConnectionType.BM);
XmlNode CoordinateY = Utility.GetMappingValues(Constants.YCoordinate, ConnectionType.BM);
var coordinatenList = from document in childElements.DescendantsAndSelf() where document.Name.LocalName == xmlCoordinatenNode.Name select document;
List<XElement> xcoordinatenList = new List<XElement>();
XElement xWaarde = new XElement(CoordinateX.Name);
XElement yWaarde = new XElement(CoordinateY.Name);
if (coordinatenList.Count() > 0)
{
foreach (XElement element in coordinatenList.Descendants())
{
if (element.Name.LocalName == xWaardeNode.Name)
{
xWaarde.Value = element.Value;
}
if (element.Name.LocalName == yWaardeNode.Name)
{
yWaarde.Value = element.Value;
}
}
}
return xcoordinatenList.ToArray();
}

It's not possible. Use Attributes:
XAttribute attribute = new XAttribute("name1", <value>);
element.Add(attribute);
attribute = new XAttribute("name2", <value>);
element.Add(attribute);
You can also add a list of child elements or add all strings as one string, separated by a comma for instance.

Nested XML from list with needed data on multiple lines

I need to format an XML to a given hierarchy from a list (List<>). The list contains, for the banking information, data spread across multiple rows as shown in the image.
The XML output needs to be formatted like this:
<ROOT>
<DocumentElement>
<Supplier>
<Company>STV</Company>
<Code>000199</Code>
<Name>TrafTrans</Name>
<BankAccounts>
<SupplierBankAccount>
<Bban>220-012510-63</Bban>
<Name>B1</Name>
</SupplierBankAccount>
<SupplierBankAccount>
<Bban>RUIL</Bban>
<Name>RUIL</Name>
</SupplierBankAccount>
</BankAccounts>
<SupplierAddresses>
<SupplierAddress>
<Type>PostalAddress</Type>
<Name>Loc TrafTrans</Name>
<IsDefault>true</IsDefault>
<AddressParts>
<SupplierAddressPart>
<AddressPartKey>STREET_NAME</AddressPartKey>
<AddressPartText>Somewhere</AddressPartText>
</SupplierAddressPart>
<SupplierAddressPart>
<AddressPartKey>COUNTRY</AddressPartKey>
<AddressPartText>SPAIN</AddressPartText>
</SupplierAddressPart>
</AddressParts>
</SupplierAddress>
</SupplierAddresses>
</Supplier>
</DocumentElement>
</ROOT>
I already have a method that converts a list to an XML and returns a string. But the problem is that this only formats one item from the list and there could be additional info in the following items.
public static string SuppliersToXML(List<SupplierItem> supplier)
{
CultureInfo ci = new CultureInfo("en-US");
XmlDocument doc = new XmlDocument();
var root = doc.CreateElement("ROOT");
var rootNode = doc.AppendChild(root);
var docElem = doc.CreateElement("DocumentElement");
var docElemNode = rootNode.AppendChild(docElem);
foreach (var item in supplier)
{
var supplierElem = doc.CreateElement("Supplier");
var companyElem = (XmlNode)doc.CreateElement("Company");
companyElem.InnerText = item.Company.ToString();
//more code...
supplierElem.AppendChild(companyElem);
//more code...
}
return doc.OuterXml;
}

I have found the answer myself, it may not be the prettiest code ever written. But it does the job.
public static string SuppliersToXML(List<SupplierItem> supplier)
{
//A distinct select is needed because bank info can be on multiple lines. So first a list is generated with correct info except for bank information
List<SupplierItem> distinctsupplier = supplier
.GroupBy(p => p.Code)
.Select(g => g.First())
.ToList();
CultureInfo ci = new CultureInfo("en-US");
XmlDocument doc = new XmlDocument();
var root = doc.CreateElement("ROOT");
var rootNode = doc.AppendChild(root);
var docElem = doc.CreateElement("DocumentElement");
var docElemNode = rootNode.AppendChild(docElem);
foreach (var item in distinctsupplier)
{
var supplierElem = doc.CreateElement("Supplier");
var companyElem = (XmlNode)doc.CreateElement("Company");
companyElem.InnerText = item.Company.ToString();
var codeElem = (XmlNode)doc.CreateElement("Code");
codeElem.InnerText = item.Code.ToString();
var codeName = (XmlNode)doc.CreateElement("Name");
codeName.InnerText = item.Name.ToString();
//supplieridentifier part
var supplierIdsElem = doc.CreateElement("SupplierIdentifiers");
var supplierIdElem = doc.CreateElement("SupplierIdentifier");
var supplierIdValueElem = (XmlNode)doc.CreateElement("SupplierIDValue");
supplierIdValueElem.InnerText = item.SupplierIDValue;
//supplieraddress part
var supplierAddressesElem = doc.CreateElement("SupplierAddresses");
var supplierAddressElem = doc.CreateElement("SupplierAddress");
var supplierTypeValueElem = (XmlNode)doc.CreateElement("Type");
supplierTypeValueElem.InnerText = item.Type;
var supplierNameValueElem = (XmlNode)doc.CreateElement("Name");
supplierNameValueElem.InnerText = item.AddressName;
var supplierDefaultValueElem = (XmlNode)doc.CreateElement("IsDefault");
supplierDefaultValueElem.InnerText = item.AddressIsDefault;
//address part
var AddressPartElem = doc.CreateElement("AddressParts");
var supplierAddressPartsElem = doc.CreateElement("SupplierAddressPart");
//Street
var AddressPartElemStreetKeyElem = (XmlNode)doc.CreateElement("AddressPartKey");
AddressPartElemStreetKeyElem.InnerText = item.AddressStreetKey;
var AddressPartElemStreetValueElem = (XmlNode)doc.CreateElement("AddressPartText");
AddressPartElemStreetValueElem.InnerText = item.AddressStreetText;
//Country
var AddressPartElemCountryKeyElem = (XmlNode)doc.CreateElement("AddressPartKey");
AddressPartElemCountryKeyElem.InnerText = item.AddressCountryKey;
var AddressPartElemCountryValueElem = (XmlNode)doc.CreateElement("AddressPartText");
AddressPartElemCountryValueElem.InnerText = item.AddressCountryText;
//add elements to supplierelem
supplierElem.AppendChild(companyElem);
supplierElem.AppendChild(codeElem);
supplierElem.AppendChild(codeName);
//bankaccounts part
var bankAccountElem = doc.CreateElement("BankAccounts");
//select all rows that contain multiple lines, so the bank info can be extracted, for a certain supplier
var bankInformation = supplier.Where(s => s.Code == item.Code).ToList();
foreach (var bankitem in bankInformation)
{
if (item.Code == bankitem.Code)
{
var bankAccountSupplElem = doc.CreateElement("SupplierBankAccount");
var bankAccountBbanElem = doc.CreateElement("Bban");
var bankAccountBbanValueElem = (XmlNode)doc.CreateElement("Bban");
bankAccountBbanValueElem.InnerText = bankitem.Bban;
var bankAccountNameElem = doc.CreateElement("Name");
var bankAccountNameValueElem = (XmlNode)doc.CreateElement("Name");
bankAccountNameValueElem.InnerText = bankitem.BankName;
var bankAccountElemNode = supplierElem.AppendChild(bankAccountElem);
var bankAccountSupplElemNode = bankAccountElemNode.AppendChild(bankAccountSupplElem);
bankAccountSupplElemNode.AppendChild(bankAccountBbanValueElem);
bankAccountSupplElemNode.AppendChild(bankAccountNameValueElem);
}
}
//add address elements to supplierelem
var supplierAddressesElemNode = supplierElem.AppendChild(supplierAddressesElem);
var supplierAddressElemNode = supplierAddressesElemNode.AppendChild(supplierAddressElem);
supplierAddressElemNode.AppendChild(supplierTypeValueElem);
supplierAddressElemNode.AppendChild(supplierNameValueElem);
supplierAddressElemNode.AppendChild(supplierDefaultValueElem);
//add addressparts to supplieraddressesnode
//Street
var AddressPartElemNode = supplierAddressElemNode.AppendChild(AddressPartElem);
var supplierAddressPartsElemNode = AddressPartElemNode.AppendChild(supplierAddressPartsElem);
supplierAddressPartsElemNode.AppendChild(AddressPartElemStreetKeyElem);
supplierAddressPartsElemNode.AppendChild(AddressPartElemStreetValueElem);
//Country (first reinitialize supplieraddresspart)
supplierAddressPartsElem = doc.CreateElement("SupplierAddressPart");
var supplierAddressPartsCountryElemNode = AddressPartElemNode.AppendChild(supplierAddressPartsElem);
supplierAddressPartsCountryElemNode.AppendChild(AddressPartElemCountryKeyElem);
supplierAddressPartsCountryElemNode.AppendChild(AddressPartElemCountryValueElem);
//add all supplierelements to docelemnode
docElemNode.AppendChild(supplierElem);
}
return doc.OuterXml;
}

How to get xml file from isolated in wp8

I Try to get Xml file and Bind to list
Here is my Xml File
- <data>
- <Bookmarkdata>
<Bookname>TheNfame</Bookname>
<Bookid>5a1df538-6e91-4a39-819d-e043c9881fb7</Bookid>
<Pageno>0</Pageno>
</Bookmarkdata>
- <Bookmarkdata>
<Bookname>TheNfame</Bookname>
<Bookid>5a1df538-6e91-4a39-819d-e043c9881fb7</Bookid>
<Pageno>1</Pageno>
</Bookmarkdata>
</data>
This is my code
private void GetBookMarkData()
{
var doc = new XDocument();
XDocument xdoc= new XDocument();
using (IsolatedStorageFile store = IsolatedStorageFile.GetUserStoreForApplication())
{
try
{
if (store.FileExists("BookmarkFile.xml"))
{
using (var sr = new StreamReader(new IsolatedStorageFileStream("BookmarkFile.xml", FileMode.OpenOrCreate, store)))
{
doc = XDocument.Load(sr);
// xdoc = XDocument.Load(sr);
var data = from query in doc.Descendants("data")
select new Bookmarkdata
{
Bookname = (string)query.Element("Bookname"),
Bookid = (string)query.Element("Bookid"),
BookPath = (string)query.Element("BookPath"),
Pageno = (int)query.Element("Pageno")
};
Bookmark_List.ItemsSource = data;
}
}
}
catch
(Exception ex) { }
}
But in Catch return a error
Value cannot be null.
Parameter name: element
In my code doc = XDocument.Load(sr);
i have get a xml data dubag time but in next line is error Please Help

Your LINQ-to-XML query is a bit off. query variable represent <data> element here :
var data = from query in doc.Descendants("data")
select new Bookmarkdata
{
Bookname = (string)query.Element("Bookname"),
Bookid = (string)query.Element("Bookid"),
BookPath = (string)query.Element("BookPath"),
Pageno = (int)query.Element("Pageno")
};
so it doesn't have direct child named Bookname, Bookid, BookPath, or Pageno. I guess you want to select from <Bookmarkdata> elements instead :
var data = from query in doc.Descendants("Bookmarkdata")
select new
{
Bookname = (string)query.Element("Bookname"),
Bookid = (string)query.Element("Bookid"),
BookPath = (string)query.Element("BookPath"),
Pageno = (int)query.Element("Pageno")
};

using xmldocument to read xml

<?xml version="1.0" encoding="utf-8" ?>
<testcase>
<date>4/12/13</date>
<name>Mrinal</name>
<subject>xmlTest</subject>
</testcase>
I am trying to read the above xml using c#, But i get null exception in the try catch block can any body suggest the required change.
static void Main(string[] args)
{
XmlDocument xd = new XmlDocument();
xd.Load("C:/Users/mkumar/Documents/testcase.xml");
XmlNodeList nodelist = xd.SelectNodes("/testcase"); // get all <testcase> nodes
foreach (XmlNode node in nodelist) // for each <testcase> node
{
CommonLib.TestCase tc = new CommonLib.TestCase();
try
{
tc.name = node.Attributes.GetNamedItem("date").Value;
tc.date = node.Attributes.GetNamedItem("name").Value;
tc.sub = node.Attributes.GetNamedItem("subject").Value;
}
catch (Exception e)
{
MessageBox.Show("Error in reading XML", "xmlError", MessageBoxButtons.OK);
}
........
.....

The testcase element has no attributes. You should be looking to it's child nodes:
tc.name = node.SelectSingleNode("name").InnerText;
tc.date = node.SelectSingleNode("date").InnerText;
tc.sub = node.SelectSingleNode("subject").InnerText;
You might process all nodes like this:
var testCases = nodelist
.Cast<XmlNode>()
.Select(x => new CommonLib.TestCase()
{
name = x.SelectSingleNode("name").InnerText,
date = x.SelectSingleNode("date").InnerText,
sub = x.SelectSingleNode("subject").InnerText
})
.ToList();

You can use LINQ to XML to select all testcase elements from your xml and parse them to TestCase instances:
var xdoc = XDocument.Load("C:/Users/mkumar/Documents/testcase.xml");
var testCases = from tc in xdoc.Descendants("testcase")
select new CommonLib.TestCase {
date = (string)tc.Element("date"),
name = (string)tc.Element("name"),
sub= (string)tc.Element("subject")
};
BTW you have only one testcase element currently, which is root of XML file. So, you can do instead:
var tc = XElement.Load("C:/Users/mkumar/Documents/testcase.xml");
var testCase = new CommonLib.TestCase {
date = (string)tc.Element("date"),
name = (string)tc.Element("name"),
sub= (string)tc.Element("subject")
};

private static void Main(string[] args)
{
XmlDocument xd = new XmlDocument();
xd.Load("C:\\test1.xml");
XmlNodeList nodelist = xd.SelectNodes("/testcase"); // get all <testcase> nodes
foreach (XmlNode node in nodelist) // for each <testcase> node
{
try
{
var name = node.SelectSingleNode("date").InnerText;
var date = node.Attributes.GetNamedItem("name").Value;
var sub = node.Attributes.GetNamedItem("subject").Value;
}
catch (Exception e)
{
MessageBox.Show("Error in reading XML", "xmlError", MessageBoxButtons.OK);
}
}
This will work I have test it #Alex correct answer

You are trying to read attributes whereas date, name and subject are not attributes. They are subnodes.
your code should be like this
XmlDocument xd = new XmlDocument();
xd.Load("test.xml");
XmlNodeList nodelist = xd.SelectNodes("/testcase"); // get all <testcase> nodes
foreach (XmlNode node in nodelist) // for each <testcase> node
{
try
{
string name = node.SelectSingleNode("name").InnerText;
string date = node.SelectSingleNode("date").InnerText;
string sub = node.SelectSingleNode("subject").InnerText;
}
catch (Exception ex)
{
MessageBox.Show("Error in reading XML", "xmlError", MessageBoxButtons.OK);
}
}

Your Xml do not contain Attributes. date, name and subject - it's Child Nodes of the testcase Node.
Try this:
...
tc.name = node["name"].InnerText;
...
or this:
...
tc.name = node.SelectSingleNode("name").InnerText;
...

Adding Subroot elements in XML

I'm making an XML Document which contains subroot nodes. I'm using XmlDocument and adding the child nodes.
This is my code:
XmlDocument doc = new XmlDocument();
XmlDeclaration dec = doc.CreateXmlDeclaration("1.0", null, null);
doc.AppendChild(dec);
XmlElement root = doc.CreateElement("LICENSE");
if (strGInfo == "")
{
strGInfo = "N/A";
}
XmlElement ginfo = doc.CreateElement("GENERAL_INFO");
ginfo.InnerText = strGInfo;
root.AppendChild(ginfo);
if (strLNo == "")
{
strLNo = "N/A";
}
XmlElement subroot = doc.CreateElement("LICENSE_INFO");
//XmlElement root1 = doc.CreateElement("LICENSE_INFO");
XmlElement lno = doc.CreateElement("LICENCE_NO");
lno.InnerText = txtLNo.Text;
subroot.AppendChild(lno);
if (strUID == "")
{
strUID = "N/A";
}
XmlElement uid = doc.CreateElement("USER_ID");
uid.InnerText = txtUID.Text;
subroot.AppendChild(uid);
if (strOrg == "")
{
strOrg = "N/A";
}
XmlElement org = doc.CreateElement("ORGANIZATION");
org.InnerText = txtOrg.Text;
subroot.AppendChild(org);
if (strUName == "")
{
strUName = "N/A";
}
XmlElement uname = doc.CreateElement("USER_NAME");
uname.InnerText = txtUName.Text;
subroot.AppendChild(uname);
if (strSType == "")
{
strSType = "N/A";
}
XmlElement stype = doc.CreateElement("SOLUTION_TYPE");
stype.InnerText = txtSType.Text;
subroot.AppendChild(stype);
if (strVer == "")
{
strVer = "N/A";
}
XmlElement ver = doc.CreateElement("VERSION");
ver.InnerText = txtVer.Text;
subroot.AppendChild(ver);
XmlElement ltype = doc.CreateElement("LICENCE_TYPE");
ltype.InnerText = drpLType.SelectedItem.Text;
subroot.AppendChild(ltype);
if (strMeapSupp == "")
{
strMeapSupp = "N/A";
}
XmlElement meapsupp = doc.CreateElement("MEAP_SUPPORT");
meapsupp.InnerText = rdoMeapSupport.Text;
subroot.AppendChild(meapsupp);
XmlElement LicFrom = doc.CreateElement("LICENCE_FROM");
LicFrom.InnerText = lblLFrom.Text;
subroot.AppendChild(LicFrom);
XmlElement LicTo = doc.CreateElement("LICENCE_TO");
LicTo.InnerText = lblLTo.Text;
subroot.AppendChild(LicTo);
XmlElement suppfrom = doc.CreateElement("SUPPORT_FROM");
suppfrom.InnerText = lblSuppFrom.Text;
subroot.AppendChild(suppfrom);
XmlElement suppto = doc.CreateElement("SUPPORT_TO");
suppto.InnerText = lblSuppTo.Text;
subroot.AppendChild(suppto);
doc.AppendChild(subroot);
XmlElement subroot2 = doc.CreateElement("LICENCE_CONSTRAINT");
if (strMaxUsr == "")
{
strMaxUsr = "N/A";
}
XmlElement maxusr = doc.CreateElement("MAX_USER");
maxusr.InnerText = txtMaxUsr.Text;
subroot2.AppendChild(maxusr);
if (strMaxMach == "")
{
strMaxMach = "N/A";
}
XmlElement maxmach = doc.CreateElement("MAX_MACHINE");
maxmach.InnerText = txtMaxMach.Text;
subroot2.AppendChild(maxmach);
if (strMachIP == "")
{
strMachIP = "N/A";
}
doc.AppendChild(subroot2);
XmlElement subroot3 = doc.CreateElement("MACHINE_INFO");
XmlElement machip = doc.CreateElement("MACHINE_IP");
machip.InnerText = txtMachIP.Text;
subroot3.AppendChild(machip);
if (strMachMac == "")
{
strMachMac = "N/A";
}
XmlElement machmac = doc.CreateElement("MACHINE_MAC");
machmac.InnerText = txtMachMac.Text;
subroot3.AppendChild(machmac);
doc.AppendChild(subroot3);
XmlElement subroot4 = doc.CreateElement("LICENCE_SIGNATURE");
XmlElement UqID = doc.CreateElement("UNIQUE_ID");
UqID.InnerText = txtUqID.Text;
subroot4.AppendChild(UqID);
doc.AppendChild(subroot4);
doc.Save(#"D:\New.xml");
My XML Document should look something like this:
-<LICENSE>
<GENERAL_INFO> </GENERAL INFO>
-<LICENSE_INFO>
<LICENSE_NO> </LICENSE_NO>
<USER_ID> </USER_ID> //etc
-<LICENCE_CONSTRAINT>
<MAX_USER> </MAX_USER>
<MAX_MACHINE> </MAX_MACHINE>
</LICENCE_CONSTRAINT>
-<MACHINE_INFO>
<MACHINE_IP> </MACHINE_IP>
<MACHINE_MAC> </MACHINE_MAC>
</MACHINE_INFO>
</LICENSE_INFO>
Where am I going wrong?

I would use Linq2Xml for this
string xml = FormXml(licenceNo: "1",machineIP:"1.2.3.4",generalInfo:"some Info");
public string FormXml(
string generalInfo="N/A",
string licenceNo="N/A",
string userID="N/A",
string maxUser="N/A",
string maxMachine="N/A",
string machineIP="N/A",
string machineMAC="N/A")
{
return new XElement("LICENSE",
new XElement("GENERAL_INFO", generalInfo),
new XElement("LICENSE_INFO",
new XElement("LICENSE_NO", licenceNo),
new XElement("USER_ID", userID)),
new XElement("LICENCE_CONSTRAINT",
new XElement("MAX_USER", maxUser),
new XElement("MAX_MACHINE", maxMachine)),
new XElement("MACHINE_INFO",
new XElement("MACHINE_IP", machineIP),
new XElement("MACHINE_MAC", machineMAC))).ToString();
}
and OUTPUT:
<LICENSE>
<GENERAL_INFO>some Info</GENERAL_INFO>
<LICENSE_INFO>
<LICENSE_NO>1</LICENSE_NO>
<USER_ID>N/A</USER_ID>
</LICENSE_INFO>
<LICENCE_CONSTRAINT>
<MAX_USER>N/A</MAX_USER>
<MAX_MACHINE>N/A</MAX_MACHINE>
</LICENCE_CONSTRAINT>
<MACHINE_INFO>
<MACHINE_IP>1.2.3.4</MACHINE_IP>
<MACHINE_MAC>N/A</MACHINE_MAC>
</MACHINE_INFO>
</LICENSE>

you are creating your root element "LICENSE":
XmlElement root = doc.CreateElement("LICENSE");
but you're not appending it to doc.
Furthermore, you are appending to doc multiple times:
doc.AppendChild(subroot);
...
doc.AppendChild(subroot2);
...
doc.AppendChild(subroot3);
which is not possible since an XML document can have only 1 root.
Add your root element like so:
XmlElement root = doc.CreateElement("LICENSE");
doc.AppendChild(root);
And change every doc.AppendChild() lateron into root.AppendChild()
And I have to agree with L.B.: LINQ to XML is much easier for stuff like this (but that wasn't the question ;) )

We Keep Coding

C# (C-Sharp) is a programming language developed by Microsoft that runs on the .NET Framework.

how to get xml nth element name in wpf - c#

Related

How to hold more than one values in XML element?

Nested XML from list with needed data on multiple lines

How to get xml file from isolated in wp8

using xmldocument to read xml

Adding Subroot elements in XML

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