Asp.Net: Save File at Path Location - c#

I uploaded pdf files on client side.
I passed path location to .ashx file, from this i have path location in string variable. I need to save this file in that path location.
please help.

Assuming rootPath is a variable containing the root path, and fileName is the name of the file you wish to save:
var filePath = System.IO.Path.Combine(rootPath, fileName);
I don't know what form the file exists in. If you include that, I can give better instructions on what to do with filePath from there.
using (var outputStream = File.Open(filePath, FileMode.CreateNew))
{
// write to outputStream; depends on what form your PDF file is in at this point.
}

Related

PdfSharp: Get PdfDocument from specified file path and name

I am using pdfsharp in a .net application and am trying to open a pdf from a specified path and file name. However, when I try this:
PdfDocument doc = PdfReader.Open(path, PdfDocumentOpenMode.Import);
Where path is the filepath and name, it is appended to the path for my project's web folder. For example, if my path is https:\site.net\files\thisfile.pdf, it will search for C:\Users\thisuser\Proj\ProjWeb\https:\site.net\files\thisfile.pdf instead.
How can I get a PdfDocument using only the path and file name I have specified, without having this additional path being appended to it?
The solution must account for multiple filepaths as the value of path is based on other conditions.
You are trying to load file from URL, while Pdfreader.Open only supports loading files locally or from a stream.
HttpWebRequest req = (HttpWebRequest)HttpWebRequest.Create(path);
Stream pdfstream = req.GetResponse().GetResponseStream();
PdfDocument doc = PdfReader.Open(pdfstream, PdfDocumentOpenMode.Import);
The above code will try to load the PDF from a remote url into Stream, then open the PDF from said stream. I haven't tested this, but according to this ( where the code was obtained ) https://forum.pdfsharp.net/viewtopic.php?f=2&t=2030, you might have to use MemoryStream in place of Stream.

Upload to Google Drive using API C# from web user

Ultimately I'm trying to upload a document from the user's file system via MVC .NET web site to Google Drive, which utilizes a service account.
I'm not sure if I'm implementing the appropriate design to accomplish the upload but I am getting hung up on the path of the file to be uploaded.
Web
#Html.TextBox("file", "file", new { type = "file", id = "fileUpload" })
Controller
public ActionResult GoogleDriveList(GoogleDrivePageVM vm, HttpPostedFileBase file)
File _file = new File();
var _uploadFile = System.IO.Path.GetFileName(file.FileName);
byte[] byteArray = System.IO.File.ReadAllBytes(_uploadFile);
Error occurs on the ReadAllBytes statement. It could not find file 'C:\Program Files (x86)\IIS Express\Map of Universe.txt'. The file name is correct but the path is not.
byte[] byteArray = System.IO.File.ReadAllBytes(_uploadFile);
System.IO.MemoryStream stream = new System.IO.MemoryStream(byteArray);
... Google Drive file stuff goes here
Then upload the file from the stream.
FilesResource.InsertMediaUpload request = _service.Files.Insert(body, stream, body.MimeType);
request.Upload();
So, am I going down the right path using the HTML file helper? And if so, what's the trick to get the path to work correctly? Also, I want to be able to support file sizes up to 500 MB (if that makes a difference).
If your getting the filename from a user selected windows file explorer dialog, then you shouldn't be using the below as will just strip out the filename without the path into your upload file variable and I am assuming that bogus path is where your're running the code from, so ReadAllBytes is trying to read from that path with the filename
var _uploadFile = System.IO.Path.GetFileName(file.FileName)
just change so it has that full path and filename you need to use in ReadAllBytes
var _uploadFile = file.FileName

Write file to project folder on any computer

I'm working on a project for a class. What I have to do is export parsed instructions to a file. Microsoft has this example which explains how to write to a file:
// Compose a string that consists of three lines.
string lines = "First line.\r\nSecond line.\r\nThird line.";
// Write the string to a file.
System.IO.StreamWriter file = new System.IO.StreamWriter("c:\\test.txt");
file.WriteLine(lines);
file.Close();
I'm fine with that part, but is there a way to write the file to the current project's environment/location? I'd like to do that instead of hard coding a specific path (i.e. "C:\\test.txt").
Yes, just use a relative path. If you use #".\test.txt" ( btw the # just says I'm doing a string literal, it removes the need for the escape character so you could also do ".\\test.txt" and it would write to the same place) it will write the file to the current working directory which in most cases is the folder containing your program.
You can use Assembly.GetExecutingAssembly().Location to get the path of your main assembly (.exe). Do note that if that path is inside a protected folder (for example Program Files) you won't be able to write there unless the user is an administrator - don't rely on this.
Here is sample code:
string path = System.Reflection.Assembly.GetExecutingAssembly().Location;
string fileName = Path.Combine(path, "test.txt");
This question / answer shows how to get the user's profile folder where you'll have write access. Alternatively, you can use the user's My Documents folder to save files - again, you're guaranteed to have access to it. You can get that path by calling
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments)
If you want to get the current folder location of your program use this code :
string path = Directory.GetParent(System.Reflection.Assembly.GetExecutingAssembly().Location).FullName; // return the application.exe current folder
string fileName = Path.Combine(path, "test.txt"); // make the full path as folder/test.text
Full code to write the data to the file :
string path = Directory.GetParent(System.Reflection.Assembly.GetExecutingAssembly().Location).FullName;
string fileName = Path.Combine(path, "test.txt");
if (!File.Exists(fileName))
{
// Create the file.
using (FileStream fs = File.Create(fileName))
{
Byte[] info =
new UTF8Encoding(true).GetBytes("This is some text in the file.");
// Add some information to the file.
fs.Write(info, 0, info.Length);
}
}

DirectoryNotFound Exception in C#

I'm trying to save a file at path WindowsFormsApplication1\WindowsFormsApplication1\SaveFile but the following code returning me a "DirectoryNotFound" Exception with the message :
Could not find a part of the path
'D:\WindowsFormsApplication1\WindowsFormsApplication1\WindowsFormsApplication1\bin\Debug\SaveFile\Hello.tx
String Path = #".\SaveFile\Hello.txt";
FileInfo info = new FileInfo(Path);
if (!info.Exists)
{
using (StreamWriter writer = info.CreateText())
{
writer.WriteLine("HELLO");
}
}
Could anyone please tell me how should I save a file at my desirable folder with specifying complete path?
When you are running in the debugger, your default path is under bin\Debug. That's what "." means in your path.
Which folder do you want to save to? You'll need to specify the full path. Perhaps you'll want to pull the path from a config file. That way, the path will be able to change based on where your application is deployed.
As the error message tells you the file will be saved in the subdirectory SaveFile under bin/debug. Before you can save a file you have to create a directory with Directory.CreateDirectory("SaveFile"). It will not be automatically created.
You need to make sure the directory exists prior to creating the text file.
String Path = #".\SaveFile\Hello.txt";
FileInfo info = new FileInfo(Path);
if (!info.Exists)
{
if (!info.Directory.Exists)
info.Directory.Create();
using (StreamWriter writer = info.CreateText())
{
writer.WriteLine("HELLO");
}
}

problem with opening a file in C#

What am I doing wrong in the following code?
public string ReadFromFile(string text)
{
string toReturn = "";
System.IO.FileStream stream = new System.IO.FileStream(text, System.IO.FileMode.Open);
System.IO.StreamReader reader = new System.IO.StreamReader(text);
toReturn = reader.ReadToEnd();
stream.Close();
return toReturn;
}
I put a text.txt file inside my bin\Debug folder and for some reason, each time when I enter this file name ("text.txt") I am getting an exception of System.IO.FileNotFoundException.
It is not safe to assume that the current working directory is identical to the directory in which your binary is residing. You can usually use code like the following to refer to the directory of your application:
string applicationDirectory = System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase);
string filename = System.IO.Path.Combine(applicationDirectory, text);
This may or may not be a solution for your given problem. On a sidenote, text is not really a decent variable name for a filename.
If I want to open a file that is always in a folder relative to the application's startup path, I use:
Application.StartupPath
to simply get the startuppath, then I append the rest of the path (subfolders and or file name).
On a side note: in real life (i.e. in the end user's configuration) the location of a file you need to read is seldom relative to the applications startup path. Applications are usually installed in the Program Files folder, application data is stored elsewhere.
File.ReadAllText(path) does the same thing as your code. I would suggest using rooted path like "c:......\text.txt" instead of the relative path. The current directory is not necessarily set to your app's home directory.
You can use Process Monitor (successor to FileMon) to find out exactly what file your application tries to read.
My suggestions:
public string ReadFromFile(string fileName)
{
using(System.IO.FileStream stream = new System.IO.FileStream(fileName, System.IO.FileMode.Open))
using(System.IO.StreamReader reader = new System.IO.StreamReader(stream))
{
return = reader.ReadToEnd();
}
}
or even
string text = File.OpenText(fileName).ReadToEnd();
You can also check is file exists:
if(File.Exists(fileName))
{
// do something...
}
At last - maybe your text.txt file is open by other process and it can't be read at this moment.

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