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Two strings are given. I want to apply a math function on each number in the strings and save it in new string. Rules:
"19834675"; // keypc
"28374651";// keyserial
(1)sb[0]=max(keypc[0],keyserial[0]) the first element of final string
max(1,2)=2 1 is first of"19834675" , 2 is first of "28374651"
(2)sb[1]=Math.Floor((keypc[1]+keyserial[1])/3) the second element of final string //
(3)sb[2]= (keypc[1]+keyserial[1]) The remainder is divided by 10
8+3=11---->1 , 8 is the third char of "19834675" and 3 the third char of "28374651"
My try for (1):
I used the following code for (1)
string keypc ="19834675";
string keyserial="28374651";
StringBuilder sb = new StringBuilder(keypc,keypc.Length);
if (sbkeypc[0] < sbkeyserial[0])
{
sb[0] = sbkeyserial[0];
}else
{
sb[0] = sbkeypc[0];
}
My try for (2):The question is why the following code does not work?!
and How to do (3)?
double inttemp=Math.Floor((Char.GetNumericValue(keypc[1])+Char.GetNumericValue(keyserial[1]))/3);
sb[1]= Convert.ToChar(Convert.ToInt32(inttemp));
Console.WriteLine(Convert.ToChar(Convert.ToInt32(inttemp))); // error here --->return ""
Console.WriteLine(sb.ToString()); // error here: the length of sb reduced
I think this is what you want:
You can see it in action here
using System;
using System.Text;
public class Program
{
public static void Main()
{
string keypc = "19834675";
string keyserial = "28374651";
StringBuilder sb = new StringBuilder(keypc, keypc.Length);
sb[0] = MinChar(keypc[0], keyserial[0]);
sb[1] = FloorChar(keypc[1], keyserial[1]);
for (int i=2; i<keypc.Length; i++)
{
sb[i] = RemainderChar(keypc[i], keyserial[i]);
}
Console.WriteLine(sb.ToString());
}
public static char MinChar(char c1, char c2)
{
double val1 = Char.GetNumericValue(c1);
double val2 = Char.GetNumericValue(c2);
double val3 = Math.Min(val1, val2);
string str = val3.ToString();
return str[0];
}
public static char FloorChar(char c1, char c2)
{
double val1 = Char.GetNumericValue(c1);
double val2 = Char.GetNumericValue(c2);
double val3 = Math.Floor((val1+val2)/3);
string str = val3.ToString();
return str[0];
}
public static char RemainderChar(char c1, char c2)
{
double val1 = Char.GetNumericValue(c1);
double val2 = Char.GetNumericValue(c2);
Console.WriteLine("{0} {1}", val1, val2);
double val3 = (val1+val2) % 10;
Console.WriteLine("" + val3);
string str = val3.ToString();
return str[0];
}
}
I have a requirement to find and extract a number contained within a string.
For example, from these strings:
string test = "1 test"
string test1 = " 1 test"
string test2 = "test 99"
How can I do this?
\d+ is the regex for an integer number. So
//System.Text.RegularExpressions.Regex
resultString = Regex.Match(subjectString, #"\d+").Value;
returns a string containing the first occurrence of a number in subjectString.
Int32.Parse(resultString) will then give you the number.
Here's how I cleanse phone numbers to get the digits only:
string numericPhone = new String(phone.Where(Char.IsDigit).ToArray());
go through the string and use Char.IsDigit
string a = "str123";
string b = string.Empty;
int val;
for (int i=0; i< a.Length; i++)
{
if (Char.IsDigit(a[i]))
b += a[i];
}
if (b.Length>0)
val = int.Parse(b);
use regular expression ...
Regex re = new Regex(#"\d+");
Match m = re.Match("test 66");
if (m.Success)
{
Console.WriteLine(string.Format("RegEx found " + m.Value + " at position " + m.Index.ToString()));
}
else
{
Console.WriteLine("You didn't enter a string containing a number!");
}
What I use to get Phone Numbers without any punctuation...
var phone = "(787) 763-6511";
string.Join("", phone.ToCharArray().Where(Char.IsDigit));
// result: 7877636511
Regex.Split can extract numbers from strings. You get all the numbers that are found in a string.
string input = "There are 4 numbers in this string: 40, 30, and 10.";
// Split on one or more non-digit characters.
string[] numbers = Regex.Split(input, #"\D+");
foreach (string value in numbers)
{
if (!string.IsNullOrEmpty(value))
{
int i = int.Parse(value);
Console.WriteLine("Number: {0}", i);
}
}
Output:
Number: 4
Number: 40
Number: 30
Number: 10
if the number has a decimal points, you can use below
using System;
using System.Text.RegularExpressions;
namespace Rextester
{
public class Program
{
public static void Main(string[] args)
{
//Your code goes here
Console.WriteLine(Regex.Match("anything 876.8 anything", #"\d+\.*\d*").Value);
Console.WriteLine(Regex.Match("anything 876 anything", #"\d+\.*\d*").Value);
Console.WriteLine(Regex.Match("$876435", #"\d+\.*\d*").Value);
Console.WriteLine(Regex.Match("$876.435", #"\d+\.*\d*").Value);
}
}
}
results :
"anything 876.8 anything" ==> 876.8
"anything 876 anything" ==> 876
"$876435" ==> 876435
"$876.435" ==> 876.435
Sample : https://dotnetfiddle.net/IrtqVt
Here's a Linq version:
string s = "123iuow45ss";
var getNumbers = (from t in s
where char.IsDigit(t)
select t).ToArray();
Console.WriteLine(new string(getNumbers));
Another simple solution using Regex
You should need to use this
using System.Text.RegularExpressions;
and the code is
string var = "Hello3453232wor705Ld";
string mystr = Regex.Replace(var, #"\d", "");
string mynumber = Regex.Replace(var, #"\D", "");
Console.WriteLine(mystr);
Console.WriteLine(mynumber);
You can also try this
string.Join(null,System.Text.RegularExpressions.Regex.Split(expr, "[^\\d]"));
Here is another Linq approach which extracts the first number out of a string.
string input = "123 foo 456";
int result = 0;
bool success = int.TryParse(new string(input
.SkipWhile(x => !char.IsDigit(x))
.TakeWhile(x => char.IsDigit(x))
.ToArray()), out result);
Examples:
string input = "123 foo 456"; // 123
string input = "foo 456"; // 456
string input = "123 foo"; // 123
Just use a RegEx to match the string, then convert:
Match match = Regex.Match(test , #"(\d+)");
if (match.Success) {
return int.Parse(match.Groups[1].Value);
}
string input = "Hello 20, I am 30 and he is 40";
var numbers = Regex.Matches(input, #"\d+").OfType<Match>().Select(m => int.Parse(m.Value)).ToArray();
You can do this using String property like below:
return new String(input.Where(Char.IsDigit).ToArray());
which gives only number from string.
For those who want decimal number from a string with Regex in TWO line:
decimal result = 0;
decimal.TryParse(Regex.Match(s, #"\d+").Value, out result);
Same thing applys to float, long, etc...
var match=Regex.Match(#"a99b",#"\d+");
if(match.Success)
{
int val;
if(int.TryParse(match.Value,out val))
{
//val is set
}
}
The question doesn't explicitly state that you just want the characters 0 to 9 but it wouldn't be a stretch to believe that is true from your example set and comments. So here is the code that does that.
string digitsOnly = String.Empty;
foreach (char c in s)
{
// Do not use IsDigit as it will include more than the characters 0 through to 9
if (c >= '0' && c <= '9') digitsOnly += c;
}
Why you don't want to use Char.IsDigit() - Numbers include characters such as fractions, subscripts, superscripts, Roman numerals, currency numerators, encircled numbers, and script-specific digits.
Here is another simple solution using Linq which extracts only the numeric values from a string.
var numbers = string.Concat(stringInput.Where(char.IsNumber));
Example:
var numbers = string.Concat("(787) 763-6511".Where(char.IsNumber));
Gives: "7877636511"
var outputString = String.Join("", inputString.Where(Char.IsDigit));
Get all numbers in the string.
So if you use for examaple '1 plus 2' it will get '12'.
Extension method to get all positive numbers contained in a string:
public static List<long> Numbers(this string str)
{
var nums = new List<long>();
var start = -1;
for (int i = 0; i < str.Length; i++)
{
if (start < 0 && Char.IsDigit(str[i]))
{
start = i;
}
else if (start >= 0 && !Char.IsDigit(str[i]))
{
nums.Add(long.Parse(str.Substring(start, i - start)));
start = -1;
}
}
if (start >= 0)
nums.Add(long.Parse(str.Substring(start, str.Length - start)));
return nums;
}
If you want negative numbers as well simply modify this code to handle the minus sign (-)
Given this input:
"I was born in 1989, 27 years ago from now (2016)"
The resulting numbers list will be:
[1989, 27, 2016]
An interesting approach is provided here by Ahmad Mageed, uses Regex and StringBuilder to extract the integers in the order in which they appear in the string.
An example using Regex.Split based on the post by Ahmad Mageed is as follows:
var dateText = "MARCH-14-Tue";
string splitPattern = #"[^\d]";
string[] result = Regex.Split(dateText, splitPattern);
var finalresult = string.Join("", result.Where(e => !String.IsNullOrEmpty(e)));
int DayDateInt = 0;
int.TryParse(finalresult, out DayDateInt);
I have used this one-liner to pull all numbers from any string.
var phoneNumber = "(555)123-4567";
var numsOnly = string.Join("", new Regex("[0-9]").Matches(phoneNumber)); // 5551234567
string verificationCode ="dmdsnjds5344gfgk65585";
string code = "";
Regex r1 = new Regex("\\d+");
Match m1 = r1.Match(verificationCode);
while (m1.Success)
{
code += m1.Value;
m1 = m1.NextMatch();
}
Did the reverse of one of the answers to this question:
How to remove numbers from string using Regex.Replace?
// Pull out only the numbers from the string using LINQ
var numbersFromString = new String(input.Where(x => x >= '0' && x <= '9').ToArray());
var numericVal = Int32.Parse(numbersFromString);
Here is my Algorithm
//Fast, C Language friendly
public static int GetNumber(string Text)
{
int val = 0;
for(int i = 0; i < Text.Length; i++)
{
char c = Text[i];
if (c >= '0' && c <= '9')
{
val *= 10;
//(ASCII code reference)
val += c - 48;
}
}
return val;
}
static string GetdigitFromString(string str)
{
char[] refArray = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' };
char[] inputArray = str.ToCharArray();
string ext = string.Empty;
foreach (char item in inputArray)
{
if (refArray.Contains(item))
{
ext += item.ToString();
}
}
return ext;
}
here is my solution
string var = "Hello345wor705Ld";
string alpha = string.Empty;
string numer = string.Empty;
foreach (char str in var)
{
if (char.IsDigit(str))
numer += str.ToString();
else
alpha += str.ToString();
}
Console.WriteLine("String is: " + alpha);
Console.WriteLine("Numeric character is: " + numer);
Console.Read();
You will have to use Regex as \d+
\d matches digits in the given string.
string s = "kg g L000145.50\r\n";
char theCharacter = '.';
var getNumbers = (from t in s
where char.IsDigit(t) || t.Equals(theCharacter)
select t).ToArray();
var _str = string.Empty;
foreach (var item in getNumbers)
{
_str += item.ToString();
}
double _dou = Convert.ToDouble(_str);
MessageBox.Show(_dou.ToString("#,##0.00"));
Using #tim-pietzcker answer from above, the following will work for PowerShell.
PS C:\> $str = '1 test'
PS C:\> [regex]::match($str,'\d+').value
1
I am looking to generate a Sequence Number in this format
00000A
00000B
00000B
and so on till
00000Z
and then
00001A
00001B
00001C
...
00001Z
...
00010A
till
99999Z
I know that I can generate Max 2.6 million rows using this method but I guess that is enough
so, if I have the a String, lets say 26522C, Now i want the next number as 26522D
or If I have 34287Z, i want 34288A
I can write the Algorithm about it but there will be lots of parsing of the input string characters by characters
I was wondering is there any easier way of doing it
String GetNextNumberInSequence(String inputString)
{
if (inputString.Length == 6)
{
var charArray = inputString.ToCharArray();
char[] inputChars = { charArray[0], charArray[1], charArray[2],charArray[3],charArray[4],charArray[5] };
if(Char.IsDigit(charArray[5]))
{
//Parse first 5 characters
}
}
}
private static String GetNextNumberInSequence(String inputString)
{
var integerpart = int.Parse(inputString.Substring(0, 5));
var characterPart = inputString[5];
if (characterPart == 'Z')
return string.Format("{0}{1}", (++integerpart).ToString("D5"), "A");
var nextChar = (char)(characterPart + 1);
return string.Format("{0}{1}", (integerpart).ToString("D5"), nextChar.ToString());
}
You can achieve this by converting a number to Base36.
Take a look at this sample:
private const string CharList = "0123456789abcdefghijklmnopqrstuvwxyz";
public static String Base36Encode(long input, char paddingChar, int totalWidth)
{
char[] clistarr = CharList.ToCharArray();
var result = new Stack<char>();
while (input != 0)
{
result.Push(clistarr[input % 36]);
input /= 36;
}
return new string(result.ToArray()).PadLeft(totalWidth, paddingChar).ToUpper();
}
and then use it this way:
for(int i = 0; i < 1000; i++)
{
Debug.WriteLine(Base36Encode(i, '0', 6));
}
which will produce this:
000000, 000001, 000002, 000003, 000004, 000005, 000006, 000007, 000008, 000009, 00000A, 00000B, 00000C, 00000D, 00000E, 00000F, 00000G, 00000H, 00000I, 00000J, 00000K, 00000L, 00000M, 00000N, 00000O, 00000P, 00000Q, 00000R, 00000S, 00000T, 00000U, 00000V, 00000W, 00000X, 00000Y, 00000Z, 000010, 000011, 000012, 000013, 000014, 000015, 000016, 000017, 000018, 000019, 00001A, 00001B, 00001C, 00001D, 00001E, 00001F, 00001G, 00001H, 00001I, 00001J, 00001K, 00001L, 00001M, 00001N, 00001O, 00001P, 00001Q, 00001R, 00001S, 00001T, 00001U, 00001V, 00001W, 00001X, 00001Y, 00001Z, 000020, 000021, 000022, 000023, 000024, 000025, 000026, 000027, 000028, 000029, 00002A, 00002B, 00002C, 00002D, 00002E, 00002F, 00002G, 00002H, 00002I, 00002J, 00002K, 00002L, 00002M, 00002N, 00002O, 00002P, 00002Q, 00002R, 00002S, 00002T...
and the positive thing about this approach is that you can convert this back to number by using:
public static Int64 Base36Decode(string input)
{
var reversed = input.ToLower().Reverse();
long result = 0;
int pos = 0;
foreach (char c in reversed)
{
result += CharList.IndexOf(c) * (long)Math.Pow(36, pos);
pos++;
}
return result;
}
How can I delete the first n lines in a string?
Example:
String str = #"a
b
c
d
e";
String output = DeleteLines(str, 2)
//Output is "c
//d
//e"
You can use LINQ:
String str = #"a
b
c
d
e";
int n = 2;
string[] lines = str
.Split(Environment.NewLine.ToCharArray())
.Skip(n)
.ToArray();
string output = string.Join(Environment.NewLine, lines);
// Output is
// "c
// d
// e"
If you need to take into account "\r\n" and "\r" and "\n" it's better to use the following regex:
public static class StringExtensions
{
public static string RemoveFirstLines(string text, int linesCount)
{
var lines = Regex.Split(text, "\r\n|\r|\n").Skip(linesCount);
return string.Join(Environment.NewLine, lines.ToArray());
}
}
Here are some more details about splitting text into lines.
Combination of Get the index of the nth occurrence of a string? (search for Environment.NewLine) and substring should do the trick.
Try the following:
public static string DeleteLines(string s, int linesToRemove)
{
return s.Split(Environment.NewLine.ToCharArray(),
linesToRemove + 1
).Skip(linesToRemove)
.FirstOrDefault();
}
the next example:
string str = #"a
b
c
d
e";
string output = DeleteLines(str, 2);
returns
c
d
e
Try this:
public static string DeleteLines (string text, int lineCount) {
while (text.Split('\n').Length > lineCount)
text = text.Remove(0, text.Split('\n')[0].Length + 1);
return text;
}
It might not be very efficient but it works perfectly for the little project i've been working on recently
Try the following:
private static string DeleteLines(string input, int lines)
{
var result = input;
for(var i = 0; i < lines; i++)
{
var idx = result.IndexOf('\n');
if (idx < 0)
{
// do what you want when there are less than the required lines
return string.Empty;
}
result = result.Substring(idx+1);
}
return result;
}
Note: This method is not ideal for extremely long multi-line strings as it does not consider memory management. If dealing with these kind of strings, I suggest you alter the method to use the StringBuilder class.
With ability to delete first n lines or last n lines:
public static string DeleteLines(
string stringToRemoveLinesFrom,
int numberOfLinesToRemove,
bool startFromBottom = false) {
string toReturn = "";
string[] allLines = stringToRemoveLinesFrom.Split(
separator: Environment.NewLine.ToCharArray(),
options: StringSplitOptions.RemoveEmptyEntries);
if (startFromBottom)
toReturn = String.Join(Environment.NewLine, allLines.Take(allLines.Length - numberOfLinesToRemove));
else
toReturn = String.Join(Environment.NewLine, allLines.Skip(numberOfLinesToRemove));
return toReturn;
}
public static string DeleteLines(string input, int linesToSkip)
{
int startIndex = 0;
for (int i = 0; i < linesToSkip; ++i)
startIndex = input.IndexOf('\n', startIndex) + 1;
return input.Substring(startIndex);
}
i have a String in HTML (1-3 of 3 Trip) how do i get the number 3(before trip) and convert it to int.I want to use it as a count
Found this code
public static string GetNumberFromStr(string str)
{
str = str.Trim();
Match m = Regex.Match(str, #"^[\+\-]?\d*\.?[Ee]?[\+\-]?\d*$");
return (m.Value);
}
But it can only get 1 number
Regex is unnecessary overhead in your case. try this:
int ExtractNumber(string input)
{
int number = Convert.ToInt32(input.Split(' ')[2]);
return number;
}
Other useful methods for Googlers:
// throws exception if it fails
int i = int.Parse(someString);
// returns false if it fails, returns true and changes `i` if it succeeds
bool b = int.TryParse(someString, out i);
// this one is able to convert any numeric Unicode character to a double. Returns -1 if it fails
double two = char.GetNumericValue('٢')
Forget Regex. This code splits the string using a space as a delimiter and gets the number in the index 2 position.
string trip = "1-3 of 3 trip";
string[] array = trip.Split(' ');
int theNumberYouWant = int.Parse(array[2]);
Try this:
public static int GetNumberFromStr(string str)
{
str = str.Trim();
Match m = Regex.Match(str, #"^.*of\s(?<TripCount>\d+)");
return m.Groups["TripCount"].Length > 0 ? int.Parse(m.Groups["TripCount"].Value) : 0;
}
Another way to do it:
public static int[] GetNumbersFromString(string str)
{
List<int> result = new List<int>();
string[] numbers = Regex.Split(input, #"\D+");
int i;
foreach (string value in numbers)
{
if (int.TryParse(value, out i))
{
result.Add(i);
}
}
return result.ToArray();
}
Example of how to use:
const string input = "There are 4 numbers in this string: 40, 30, and 10.";
int[] numbers = MyHelperClass.GetNumbersFromString();
for(i = 0; i < numbers.length; i++)
{
Console.WriteLine("Number {0}: {1}", i + 1, number[i]);
}
Output:
Number: 4
Number: 40
Number: 30
Number: 10
Thanks to: http://www.dotnetperls.com/regex-split-numbers
If I'm reading your question properly, you'll get a string that is a single digit number followed by ' Trip' and you want to get the numeric value out?
public static int GetTripNumber(string tripEntry)
{
return int.Parse(tripEntry.ToCharArray()[0]);
}
Not really sure if you mean that you always have "(x-y of y Trip)" as a part of the string you parse...if you look at the pattern it only catches the "x-y" part thought with the acceptance of .Ee+- as seperators. If you want to catch the "y Trip" part you will have to look at another regex instead.
You could do a simple, if you change the return type to int instead of string:
Match m = Regex.Match(str, #"(?<maxTrips>\d+)\sTrip");
return m.Groups["maxTrips"].Lenght > 0 ? Convert.ToInt32(m.Groups["maxTrips"].Value) : 0;