I'm using ffmpeg to compile videos, and I'd like to prevent it from displaying a console when performing actions.
Here's how I start ffmpeg:
ProcessStartInfo si = new ProcessStartInfo();
si.Arguments = string.Format("-y -loop 1 -t " + DucationToString(frameDuration) + " -r 25 -f image2 -i \"{0}\" \"{1}\"",
item.Value, otpt);
si.FileName = "ffmpeg";
si.UseShellExecute = false;
Process.Start(si).WaitForExit();
No matter the settings I try in ProcessStartInfo, the console always shows up.
How do I prevent the console from being shown when creating child process?
You should try to use
ProcessStartInfo si = new ProcessStartInfo();
si.WindowStyle = ProcessWindowStyle.Hidden;
si.CreateNoWindow = true;
si.UseShellExecute = false;
MSDN refs
Set ProcessStartInfo.CreateNoWindow to true.
Note that:
To use ProcessWindowStyle.Hidden or ProcessStartInfo.CreateNoWindow the ProcessStartInfo.UseShellExecute property must be false.
Have you added this in your code
si.CreateNoWindow = true;
si.RedirectStandardOutput = true;
Related
My C# application is running 7zip from the command line and I have the window set to hidden, but every time I have 7zip do something a command line window still pops up and disappears, I think it's the 7zip exe itself reporting the output.
Is there a way to suppress this?
string strCmdText = "\"C:/Program Files/7-zip/7z.exe\" e \"" + listBox1.Items[i].ToString() + "\" -o\"" + label1.Text + "\" EMM*.zip RFE*.zip -r -y";
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.RedirectStandardInput = true;
cmd.StartInfo.RedirectStandardOutput = true;
cmd.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmd.StartInfo.UseShellExecute = false;
cmd.StartInfo.CreateNoWindow = true;
cmd.Start();
cmd.StandardInput.WriteLine(strCmdText);
cmd.StandardInput.Flush();
cmd.StandardInput.Close();
cmd.WaitForExit();
Your code open a cmd.exe with a hidden window what call 7-zip.exe with default window (visible by default).
If you can, just call directly 7-zip.exe
Process cmd = new Process();
cmd.StartInfo.FileName = #"C:/Program Files/7-zip/7z.exe";
cmd.StartInfo.Arguments = "e \"" + listBox1.Items[i].ToString() + "\" -o\"" + label1.Text + "\" EMM*.zip RFE*.zip -r -y";
cmd.StartInfo.RedirectStandardInput = true;
cmd.StartInfo.RedirectStandardOutput = true;
cmd.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmd.StartInfo.UseShellExecute = false;
cmd.StartInfo.CreateNoWindow = true;
cmd.Start();
cmd.WaitForExit();
I am having trouble with the Process class to pipe a command on a Linux system.
I want to execute the following command: rpm2cpio repo.rpm | cpio -divm
I've tried
process.StartInfo.FileName = "rpm2cpio;
rocess.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.Arguments = "repo.rpm | cpio - idmv";
But the program hangs.
Similarly, I tried saving the output from rpm2cpio to a string or an output file and then pass that as the argument for the cpio command, but it also hangs.
process.StartInfo.FileName = "cpio";
rocess.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.Arguments = "-idvm < output.txt";
// or
process.StartInfo.Arguments = "-idvm < " + rp2cpio_output;
What are some ways I can get this working? I saw this post with a solution, but it is on a Window's system. How do the same thing on Linux?
Setting process.StartInfo.RedirectStandardOutput=true will cause the program to redirect standard output to the stream process.StartInfo.StandardOutput. When this happens the program will hang until you read from standard output.
To get the behavior I think you are looking for, you just need to set RedirectStandardOutput=false. That way the pipes and redirects in your command will work as expected.
Rather than directly writing to a file, you can simply use a StreamWriter to fetch the output in a stream buffer and then use that to write to the file. If the process still hangs, simply use the timeout command of linux to terminate the process.
The following snippet may help after making a few changes:
ProcessStartInfo processStartInfo = new ProcessStartInfo();
processStartInfo.WindowStyle = ProcessWindowStyle.Hidden;
processStartInfo.FileName = "/bin/bash";
processStartInfo.WorkingDirectory = "/";
string cmd = "timeout 1 cat > temp.txt";
var escapedArgs = cmd.Replace("\"", "\\\"");
processStartInfo.Arguments = $"-c \"{escapedArgs}\"";
processStartInfo.UseShellExecute = false;
processStartInfo.RedirectStandardInput = true;
processStartInfo.RedirectStandardOutput = true;
processStartInfo.RedirectStandardError = true;
processStartInfo.StandardErrorEncoding = System.Text.Encoding.UTF8;
processStartInfo.StandardInputEncoding = System.Text.Encoding.UTF8;
processStartInfo.StandardOutputEncoding = System.Text.Encoding.UTF8;
processStartInfo.UseShellExecute = false;
process.StartInfo = processStartInfo;
process.Start();
stdIOWriter = process.StandardInput;
stdIOWriter.WriteLine("Hey Fellas");
String error = process.StandardError.ReadToEnd();
String output = process.StandardOutput.ReadToEnd(); ```
I have this code:
string d = "-f image2 -framerate 9 -i E:\\REC\\Temp\\%06d.jpeg -r 30 E:\\REC\\Video\\" + label1.Text + ".avi";
//string d = "-f dshow -i video=\"screen-capture-recorder\" E:\\REC\\" + label1.Text + ".flv";
Process proc = new Process();
proc.StartInfo.FileName = "E:\\ffmpeg\\bin\\ffmpeg.exe";
proc.StartInfo.Arguments = d;
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = false;
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.StartInfo.WindowStyle = ProcessWindowStyle.Maximized;
if (!proc.Start())
{
Console.WriteLine("Error starting");
return;
}
proc.WaitForExit();
When it runs the ffmpeg.exe is there like this:
My question is how to hide this window?
You need the following combination of settings:
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
And that's it.
The reason being that the key setting is CreateNoWindow which has to be true. But CreateNoWindow only has any effect when UseShellExecute is false. That's because CreateNoWindow maps to the CREATE_NO_WINDOW process creation flag passed to CreateProcess. And CreateProcess is only called when UseShellExecute is false.
More information can be found from the documentation:
Property Value
true if the process should be started without creating a new window to contain it; otherwise, false. The default is false.
Remarks
If the UseShellExecute property is true or the UserName and Password
properties are not null, the CreateNoWindow property value is ignored
and a new window is created.
This on keeps the all processes in same console window. no allow to open an new one`
Process process = new Process();
// Stop the process from opening a new window
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.UseShellExecute = false;
process.StartInfo.CreateNoWindow = true;
// Setup executable and parameters
process.StartInfo.FileName = #"E:\\ffmpeg\\bin\\ffmpeg.exe"
//Optional
string d = "-f image2 -framerate 9 -i E:\\REC\\Temp\\%06d.jpeg -r 30 E:\\REC\\Video\\" + label1.Text + ".avi";
process.StartInfo.Arguments = d;
// Go
process.Start();
I am using lame for transcoding for one of my project. The issue is that when I call lame from C#, a DOS window pops out. Is there any way I can suppress this?
Here is my code so far:
Process converter =
Process.Start(lameExePath, "-V2 \"" + waveFile + "\" \"" + mp3File + "\"");
converter.WaitForExit();
Did you try something like:
using( var process = new Process() )
{
process.StartInfo.FileName = "...";
process.StartInfo.WorkingDirectory = "...";
process.StartInfo.CreateNoWindow = true;
process.StartInfo.UseShellExecute = false;
process.Start();
}
Assuming you are calling it via Process.Start, you can use the overload that takes ProcessStartInfo that has its CreateNoWindow property set to true and its UseShellExecute set to false.
The ProcessStartInfo object can also be accessed via the Process.StartInfo property and can be set there directly before starting the process (easier if you have a small number of properties to setup).
Process bhd = new Process();
bhd.StartInfo.FileName = "NSOMod.exe";
bhd.StartInfo.Arguments = "/mod NSOmod /d";
bhd.StartInfo.CreateNoWindow = true;
bhd.StartInfo.UseShellExecute = false;
Is another way.
This is my code that does a similar thing, (and also reads the output and return code)
process.StartInfo.FileName = toolFilePath;
process.StartInfo.Arguments = parameters;
process.StartInfo.UseShellExecute = false; // needs to be false in order to redirect output
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.RedirectStandardInput = true; // redirect all 3, as it should be all 3 or none
process.StartInfo.WorkingDirectory = Path.GetDirectoryName(toolFilePath);
process.StartInfo.Domain = domain;
process.StartInfo.UserName = userName;
process.StartInfo.Password = decryptedPassword;
process.Start();
output = process.StandardOutput.ReadToEnd(); // read the output here...
process.WaitForExit(); // ...then wait for exit, as after exit, it can't read the output
returnCode = process.ExitCode;
process.Close(); // once we have read the exit code, can close the process
How to hide cmd window while running a batch file?
I use the following code to run batch file
process = new Process();
process.StartInfo.FileName = batchFilePath;
process.Start();
If proc.StartInfo.UseShellExecute is false, then you are launching the process and can use:
proc.StartInfo.CreateNoWindow = true;
If proc.StartInfo.UseShellExecute is true, then the OS is launching the process and you have to provide a "hint" to the process via:
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
However the called application may ignore this latter request.
If using UseShellExecute = false, you might want to consider redirecting standard output/error, to capture any logging produced:
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.RedirectStandardOutput = true;
proc.OutputDataReceived += new DataReceivedEventHandler(ProcessOutputHandler);
proc.StartInfo.RedirectStandardError = true;
proc.ErrorDataReceived += new DataReceivedEventHandler(ProcessOutputHandler);
And have a function like
private void ProcessOutputHandler(object sendingProcess, DataReceivedEventArgs outLine)
{
if (!String.IsNullOrEmpty(outLine.Data)) // use the output outLine.Data somehow;
}
There's a good page covering CreateNoWindow this on an MSDN blog.
There is also a bug in Windows which may throw a dialog and defeat CreateNoWindow if you are passing a username/password. For details
http://connect.microsoft.com/VisualStudio/feedback/ViewFeedback.aspx?FeedbackID=98476
http://support.microsoft.com/?kbid=818858
According to the Process properties, you do have a:
Property: CreateNoWindow
Notes: Allows you to run a command line program silently.
It does not flash a console window.
and:
Property: WindowStyle
Notes: Use this to set windows as hidden.
The author has used ProcessWindowStyle.Hidden often.
As an example!
static void LaunchCommandLineApp()
{
// For the example
const string ex1 = "C:\\";
const string ex2 = "C:\\Dir";
// Use ProcessStartInfo class
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = "dcm2jpg.exe";
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.Arguments = "-f j -o \"" + ex1 + "\" -z 1.0 -s y " + ex2;
try
{
// Start the process with the info we specified.
// Call WaitForExit and then the using statement will close.
using (Process exeProcess = Process.Start(startInfo))
{
exeProcess.WaitForExit();
}
}
catch
{
// Log error.
}
}
Use:
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
This is what worked for me,
When you redirect all of the input and output, and set the window hidden it should work
Process p = new Process();
p.StartInfo.RedirectStandardError = true;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
try with this and this where the c# code is embedded into the batch files:
#echo off
echo self minimizing
call getCmdPid.bat
call windowMode.bat -pid %errorlevel% -mode minimized
echo --other commands--
pause
Though it might be not so easy to unhide the window.