class TcpIpCommands
{
public string Check()
{
Process p = new Process();
p.StartInfo.FileName = #"C:\Windows\syswow64\netsh.exe";
p.StartInfo.Arguments = "int tcp show global";
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.StandardOutputEncoding = Encoding.GetEncoding(737);
p.Start();
p.WaitForExit();
return p.StandardOutput.ReadToEnd();
}
public string Command(string FileName, string Arguments)
{
ProcessStartInfo p = new ProcessStartInfo();
p.FileName = FileName;
p.Arguments = Arguments;
p.UseShellExecute = false;
p.CreateNoWindow = true;
p.RedirectStandardOutput = true;
p.StandardOutputEncoding = Encoding.GetEncoding(737);
using (Process process = Process.Start(p))
{
using (StreamReader reader = process.StandardOutput)
{
string result = reader.ReadToEnd();
return result;
}
}
}
public string Reseting()
{
Process p = new Process();
p.StartInfo.FileName = #"C:\Windows\syswow64\netsh.exe";
p.StartInfo.Arguments = #"interface tcp reset";
p.StartInfo.Verb = "runas";
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.StandardOutputEncoding = Encoding.GetEncoding(737);
p.Start();
p.WaitForExit();
return p.StandardOutput.ReadToEnd();
}
}
I have an problem with Command Method and Reseting Method. If i try to execute them I receive in RichTextBox the message
set global command failed on ipv4 the parameter is incorrect
But If i run netsh interface tcp show global or hit the Check Method they info me that the status are change.
here are the buttons
private void BtnCheck_Click(object sender, EventArgs e)
{
TcpIpCommands tic = new TcpIpCommands();
richTextBox1.Text = tic.Check();
}
private void btnChimney_Click(object sender, EventArgs e)
{
TcpIpCommands tic = new TcpIpCommands();
richTextBox1.Text = tic.Command(#"C:\Windows\system32\netsh.exe", "interface tcp set global chimney=enabled");
}
private void BtnReset_Click(object sender, EventArgs e)
{
TcpIpCommands tic = new TcpIpCommands();
richTextBox1.Text = tic.Reseting();
}
I cant understand why RichTextBox shows that message but the process execute succefully.
A note. I have try to run the commands with
StartInfo.Verb = "runas";
and both from
C:\Windows\System32\netsh.exe
and
C:\Windows\syswow64\netsh.exe
and i get the same error "set global command failed on ipv4 the parameter is incorrect" but the code execute and the parameter change.
I'm running an app that uses a console app in the background
When I do this in cmd read-info.exe Myfile.file >fileinfo.txt it will create the file fileinfo.txt in the route folder.
But when I do it in code nothing happens, why?
private void button1_Click(object sender, EventArgs e)
{
FolderBrowserDialog theDialog = new FolderBrowserDialog();
theDialog.RootFolder = System.Environment.SpecialFolder.MyComputer;
if (theDialog.ShowDialog() == DialogResult.OK)
{
textBox1.Text = theDialog.SelectedPath.ToString();
string command = "read-info.exe " + textBox1.Text +"> File.txt";
string retur = CMD(command);
}
}
static string CMD(string args)
{
string cmdbat = "cd " + Application.StartupPath.Replace("\\", "/") + "\r\n";
cmdbat += args + " >> out.txt\r\n";
cmdbat += "exit\r\n";
File.WriteAllText("cmd.bat", cmdbat);
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.Arguments = "";
startInfo.UseShellExecute = true;
startInfo.WorkingDirectory = Application.StartupPath;
startInfo.CreateNoWindow = true;
startInfo.FileName = Application.StartupPath + "\\cmd.bat";
process.StartInfo = startInfo;
process.Start();
process.WaitForExit();
System.Threading.Thread.Sleep(5000);
string cmdOut = File.ReadAllText("out.txt");
File.Delete("cmd.bat");
File.Delete("out.txt");
return cmdOut;
}
See this - I tnink it is what necessary: http://www.dotnetperls.com/redirectstandardoutput
Copied from the link above:
using System;
using System.Diagnostics;
using System.IO;
class Program
{
static void Main()
{
//
// Setup the process with the ProcessStartInfo class.
//
ProcessStartInfo start = new ProcessStartInfo();
start.FileName = #"C:\7za.exe"; // Specify exe name.
start.UseShellExecute = false;
start.RedirectStandardOutput = true;
//
// Start the process.
//
using (Process process = Process.Start(start))
{
//
// Read in all the text from the process with the StreamReader.
//
using (StreamReader reader = process.StandardOutput)
{
string result = reader.ReadToEnd();
Console.Write(result);
}
}
}
}
use cmd /C for running console commands.
string command = "cmd /C read-info.exe " + textBox1.Text +"> File.txt";
Got It Working Thanks to #crashmstr
it outputs file as out.txt so just had to comment out File.Delete("out.txt");
How Can i save the CMD Commands into txt file in C#
or how can i display command prompt in C#
here is my code
private void button1_Click(object sender, EventArgs e)
{
var p = new Process();
string path = #"C:\Users\Microsoft";
string argu = "-na>somefile.bat";
ProcessStartInfo process = new ProcessStartInfo("netstat", argu);
process.RedirectStandardOutput = false;
process.UseShellExecute = false;
process.CreateNoWindow = false;
Process.Start(process);
p.StartInfo.WorkingDirectory = path;
p.StartInfo.FileName = "sr.txt";
p.Start();
p.WaitForExit();
}
You can redirect the standard output:
using System;
using System.Diagnostics;
using System.IO;
class Program
{
static void Main()
{
//
// Setup the process with the ProcessStartInfo class.
//
ProcessStartInfo start = new ProcessStartInfo();
start.FileName = #"C:\7za.exe"; // Specify exe name.
start.UseShellExecute = false;
start.RedirectStandardOutput = true;
//
// Start the process.
//
using (Process process = Process.Start(start))
{
//
// Read in all the text from the process with the StreamReader.
//
using (StreamReader reader = process.StandardOutput)
{
string result = reader.ReadToEnd();
Console.Write(result);
}
}
}
}
Code is from here
Also look to this answer: redirecting output to the text file c#
I am trying to create a Windows Forms C# project that interacts with the command prompt shell (cmd.exe).
I want to open a command prompt, send a command (like ipconfig) and then read the results back into the windows form into a string, textbox, or whatever.
Here is what I have so far, but I am stuck. I cannot write or read to the command prompt.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Forms;
using System.Diagnostics;
using System.IO;
namespace WindowsFormsApplication1
{
static class Program
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
System.Diagnostics.Process p = new System.Diagnostics.Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/k dir *.*";
p.StartInfo.RedirectStandardError = true;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.Start();
StreamWriter inputWriter = p.StandardInput;
StreamReader outputWriter = p.StandardOutput;
StreamReader errorReader = p.StandardError;
p.WaitForExit();
}
}
}
Any help would be greatly appreciated.
Thanks.
Here is a SO question that will give you the information you need:
How To: Execute command line in C#, get STD OUT results
Basically, you ReadToEnd on your System.IO.StreamReader.
So, for example, in your code you would modify the line StreamReader errorReader = p.StandardError; to read
using(StreamReader errorReader = p.StandardError)
{
error = myError.ReadToEnd();
}
var yourcommand = "<put your command here>";
var procStart = new System.Diagnostics.ProcessStartInfo("cmd", "/c " + yourcommand);
procStart.CreateNoWindow = true;
procStart.RedirectStandardOutput = true;
procStart.UseShellExecute = false;
var proc = new System.Diagnostics.Process();
proc.StartInfo = procStart;
proc.Start();
var result = proc.StandardOutput.ReadToEnd();
Console.WriteLine(result);
How do I execute a command-line program from C# and get back the STD OUT results? Specifically, I want to execute DIFF on two files that are programmatically selected and write the results to a text box.
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "YOURBATCHFILE.bat";
p.Start();
// Do not wait for the child process to exit before
// reading to the end of its redirected stream.
// p.WaitForExit();
// Read the output stream first and then wait.
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Code is from MSDN.
Here's a quick sample:
//Create process
System.Diagnostics.Process pProcess = new System.Diagnostics.Process();
//strCommand is path and file name of command to run
pProcess.StartInfo.FileName = strCommand;
//strCommandParameters are parameters to pass to program
pProcess.StartInfo.Arguments = strCommandParameters;
pProcess.StartInfo.UseShellExecute = false;
//Set output of program to be written to process output stream
pProcess.StartInfo.RedirectStandardOutput = true;
//Optional
pProcess.StartInfo.WorkingDirectory = strWorkingDirectory;
//Start the process
pProcess.Start();
//Get program output
string strOutput = pProcess.StandardOutput.ReadToEnd();
//Wait for process to finish
pProcess.WaitForExit();
There one other parameter I found useful, which I use to eliminate the process window
pProcess.StartInfo.CreateNoWindow = true;
this helps to hide the black console window from user completely, if that is what you desire.
// usage
const string ToolFileName = "example.exe";
string output = RunExternalExe(ToolFileName);
public string RunExternalExe(string filename, string arguments = null)
{
var process = new Process();
process.StartInfo.FileName = filename;
if (!string.IsNullOrEmpty(arguments))
{
process.StartInfo.Arguments = arguments;
}
process.StartInfo.CreateNoWindow = true;
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.RedirectStandardOutput = true;
var stdOutput = new StringBuilder();
process.OutputDataReceived += (sender, args) => stdOutput.AppendLine(args.Data); // Use AppendLine rather than Append since args.Data is one line of output, not including the newline character.
string stdError = null;
try
{
process.Start();
process.BeginOutputReadLine();
stdError = process.StandardError.ReadToEnd();
process.WaitForExit();
}
catch (Exception e)
{
throw new Exception("OS error while executing " + Format(filename, arguments)+ ": " + e.Message, e);
}
if (process.ExitCode == 0)
{
return stdOutput.ToString();
}
else
{
var message = new StringBuilder();
if (!string.IsNullOrEmpty(stdError))
{
message.AppendLine(stdError);
}
if (stdOutput.Length != 0)
{
message.AppendLine("Std output:");
message.AppendLine(stdOutput.ToString());
}
throw new Exception(Format(filename, arguments) + " finished with exit code = " + process.ExitCode + ": " + message);
}
}
private string Format(string filename, string arguments)
{
return "'" + filename +
((string.IsNullOrEmpty(arguments)) ? string.Empty : " " + arguments) +
"'";
}
The accepted answer on this page has a weakness that is troublesome in rare situations. There are two file handles which programs write to by convention, stdout, and stderr.
If you just read a single file handle such as the answer from Ray, and the program you are starting writes enough output to stderr, it will fill up the output stderr buffer and block. Then your two processes are deadlocked. The buffer size may be 4K.
This is extremely rare on short-lived programs, but if you have a long running program which repeatedly outputs to stderr, it will happen eventually. This is tricky to debug and track down.
There are a couple good ways to deal with this.
One way is to execute cmd.exe instead of your program and use the /c argument to cmd.exe to invoke your program along with the "2>&1" argument to cmd.exe to tell it to merge stdout and stderr.
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/c mycmd.exe 2>&1";
Another way is to use a programming model which reads both handles at the same time.
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = #"/c dir \windows";
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardInput = false;
p.OutputDataReceived += (a, b) => Console.WriteLine(b.Data);
p.ErrorDataReceived += (a, b) => Console.WriteLine(b.Data);
p.Start();
p.BeginErrorReadLine();
p.BeginOutputReadLine();
p.WaitForExit();
System.Diagnostics.ProcessStartInfo psi =
new System.Diagnostics.ProcessStartInfo(#"program_to_call.exe");
psi.RedirectStandardOutput = true;
psi.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
psi.UseShellExecute = false;
System.Diagnostics.Process proc = System.Diagnostics.Process.Start(psi); ////
System.IO.StreamReader myOutput = proc.StandardOutput;
proc.WaitForExit(2000);
if (proc.HasExited)
{
string output = myOutput.ReadToEnd();
}
You will need to use ProcessStartInfo with RedirectStandardOutput enabled - then you can read the output stream. You might find it easier to use ">" to redirect the output to a file (via the OS), and then simply read the file.
[edit: like what Ray did: +1]
One-liner run command:
new Process() { StartInfo = new ProcessStartInfo("echo", "Hello, World") }.Start();
Read output of command in shortest amount of reable code:
var cliProcess = new Process() {
StartInfo = new ProcessStartInfo("echo", "Hello, World") {
UseShellExecute = false,
RedirectStandardOutput = true
}
};
cliProcess.Start();
string cliOut = cliProcess.StandardOutput.ReadToEnd();
cliProcess.WaitForExit();
cliProcess.Close();
In case you also need to execute some command in the cmd.exe, you can do the following:
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/C vol";
p.Start();
// Read the output stream first and then wait.
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine(output);
This returns just the output of the command itself:
You can also use StandardInput instead of StartInfo.Arguments:
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.Start();
// Read the output stream first and then wait.
p.StandardInput.WriteLine("vol");
p.StandardInput.WriteLine("exit");
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine(output);
The result looks like this:
Since the most answers here dont implement the using statemant for IDisposable and some other stuff wich I think could be nessecary I will add this answer.
For C# 8.0
// Start a process with the filename or path with filename e.g. "cmd". Please note the
//using statemant
using myProcess.StartInfo.FileName = "cmd";
// add the arguments - Note add "/c" if you want to carry out tge argument in cmd and
// terminate
myProcess.StartInfo.Arguments = "/c dir";
// Allows to raise events
myProcess.EnableRaisingEvents = true;
//hosted by the application itself to not open a black cmd window
myProcess.StartInfo.UseShellExecute = false;
myProcess.StartInfo.CreateNoWindow = true;
// Eventhander for data
myProcess.Exited += OnOutputDataRecived;
// Eventhandler for error
myProcess.ErrorDataReceived += OnErrorDataReceived;
// Eventhandler wich fires when exited
myProcess.Exited += OnExited;
// Starts the process
myProcess.Start();
//read the output before you wait for exit
myProcess.BeginOutputReadLine();
// wait for the finish - this will block (leave this out if you dont want to wait for
// it, so it runs without blocking)
process.WaitForExit();
// Handle the dataevent
private void OnOutputDataRecived(object sender, DataReceivedEventArgs e)
{
//do something with your data
Trace.WriteLine(e.Data);
}
//Handle the error
private void OnErrorDataReceived(object sender, DataReceivedEventArgs e)
{
Trace.WriteLine(e.Data);
//do something with your exception
throw new Exception();
}
// Handle Exited event and display process information.
private void OnExited(object sender, System.EventArgs e)
{
Trace.WriteLine("Process exited");
}
Here is small example:
using System;
using System.Diagnostics;
class Program
{
static void Main(string[] args)
{
var p = Process.Start(
new ProcessStartInfo("git", "branch --show-current")
{
CreateNoWindow = true,
UseShellExecute = false,
RedirectStandardError = true,
RedirectStandardOutput = true,
WorkingDirectory = Environment.CurrentDirectory
}
);
p.WaitForExit();
string branchName =p.StandardOutput.ReadToEnd().TrimEnd();
string errorInfoIfAny =p.StandardError.ReadToEnd().TrimEnd();
if (errorInfoIfAny.Length != 0)
{
Console.WriteLine($"error: {errorInfoIfAny}");
}
else {
Console.WriteLine($"branch: {branchName}");
}
}
}
I believe this is shortest form.
Please notice that most of command line tools easily confuse standard output and standard error, sometimes it makes sense just to clue those together into single string.
Also p.ExitCode might be sometimes useful.
Example above serves for purpose of writing command line utility like tools if you want to do it by yourself. Please note that for cli automation it's also possible to use Cake Frosten and Cake Git extension.
You can launch any command line program using the Process class, and set the StandardOutput property of the Process instance with a stream reader you create (either based on a string or a memory location). After the process completes, you can then do whatever diff you need to on that stream.
This might be useful for someone if your attempting to query the local ARP cache on a PC/Server.
List<string[]> results = new List<string[]>();
using (Process p = new Process())
{
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
p.StartInfo.Arguments = "/c arp -a";
p.StartInfo.FileName = #"C:\Windows\System32\cmd.exe";
p.Start();
string line;
while ((line = p.StandardOutput.ReadLine()) != null)
{
if (line != "" && !line.Contains("Interface") && !line.Contains("Physical Address"))
{
var lineArr = line.Trim().Split(' ').Select(n => n).Where(n => !string.IsNullOrEmpty(n)).ToArray();
var arrResult = new string[]
{
lineArr[0],
lineArr[1],
lineArr[2]
};
results.Add(arrResult);
}
}
p.WaitForExit();
}
This may not be the best/easiest way, but may be an option:
When you execute from your code, add " > output.txt" and then read in the output.txt file.
There is a ProcessHelper Class in PublicDomain open source code which might interest you.
Julian's solution is tested working with some minor corrections. The following is an example that also used https://sourceforge.net/projects/bat-to-exe/ GenericConsole.cs and https://www.codeproject.com/Articles/19225/Bat-file-compiler program.txt for args part:
using System;
using System.Text; //StringBuilder
using System.Diagnostics;
using System.IO;
class Program
{
private static bool redirectStandardOutput = true;
private static string buildargument(string[] args)
{
StringBuilder arg = new StringBuilder();
for (int i = 0; i < args.Length; i++)
{
arg.Append("\"" + args[i] + "\" ");
}
return arg.ToString();
}
static void Main(string[] args)
{
Process prc = new Process();
prc.StartInfo = //new ProcessStartInfo("cmd.exe", String.Format("/c \"\"{0}\" {1}", Path.Combine(Environment.CurrentDirectory, "mapTargetIDToTargetNameA3.bat"), buildargument(args)));
//new ProcessStartInfo(Path.Combine(Environment.CurrentDirectory, "mapTargetIDToTargetNameA3.bat"), buildargument(args));
new ProcessStartInfo("mapTargetIDToTargetNameA3.bat");
prc.StartInfo.Arguments = buildargument(args);
prc.EnableRaisingEvents = true;
if (redirectStandardOutput == true)
{
prc.StartInfo.UseShellExecute = false;
}
else
{
prc.StartInfo.UseShellExecute = true;
}
prc.StartInfo.CreateNoWindow = true;
prc.OutputDataReceived += OnOutputDataRecived;
prc.ErrorDataReceived += OnErrorDataReceived;
//prc.Exited += OnExited;
prc.StartInfo.RedirectStandardOutput = redirectStandardOutput;
prc.StartInfo.RedirectStandardError = redirectStandardOutput;
try
{
prc.Start();
prc.BeginOutputReadLine();
prc.BeginErrorReadLine();
prc.WaitForExit();
}
catch (Exception e)
{
Console.WriteLine("OS error: " + e.Message);
}
prc.Close();
}
// Handle the dataevent
private static void OnOutputDataRecived(object sender, DataReceivedEventArgs e)
{
//do something with your data
Console.WriteLine(e.Data);
}
//Handle the error
private static void OnErrorDataReceived(object sender, DataReceivedEventArgs e)
{
Console.WriteLine(e.Data);
}
// Handle Exited event and display process information.
//private static void OnExited(object sender, System.EventArgs e)
//{
// var process = sender as Process;
// if (process != null)
// {
// Console.WriteLine("ExitCode: " + process.ExitCode);
// }
// else
// {
// Console.WriteLine("Process exited");
// }
//}
}
The code need to compile inside VS2007, using commandline csc.exe generated executable will not show console output correctly, or even crash with CLR20r3 error. Comment out the OnExited event process, the console output of the bat to exe will be more like the original bat console output.
Just for fun, here's my completed solution for getting PYTHON output - under a button click - with error reporting. Just add a button called "butPython" and a label called "llHello"...
private void butPython(object sender, EventArgs e)
{
llHello.Text = "Calling Python...";
this.Refresh();
Tuple<String,String> python = GoPython(#"C:\Users\BLAH\Desktop\Code\Python\BLAH.py");
llHello.Text = python.Item1; // Show result.
if (python.Item2.Length > 0) MessageBox.Show("Sorry, there was an error:" + Environment.NewLine + python.Item2);
}
public Tuple<String,String> GoPython(string pythonFile, string moreArgs = "")
{
ProcessStartInfo PSI = new ProcessStartInfo();
PSI.FileName = "py.exe";
PSI.Arguments = string.Format("\"{0}\" {1}", pythonFile, moreArgs);
PSI.CreateNoWindow = true;
PSI.UseShellExecute = false;
PSI.RedirectStandardError = true;
PSI.RedirectStandardOutput = true;
using (Process process = Process.Start(PSI))
using (StreamReader reader = process.StandardOutput)
{
string stderr = process.StandardError.ReadToEnd(); // Error(s)!!
string result = reader.ReadToEnd(); // What we want.
return new Tuple<String,String> (result,stderr);
}
}