what does format {0:x} mean? [closed] - c#

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Closed 10 years ago.
I came across this C# literal and was wondering what does it mean?
Especially, in the following case:
string.Format("{0:x}", byteArray[i]);
Thanks

It means format the first argument (index 0) as hexadecimal: http://msdn.microsoft.com/en-us/library/s8s7t687(v=vs.80).aspx

It means the first argument will be output as hexadecimal (in lowercase !!).
To output uppercase you could use "{0:X}".
Look msdn for more info about string formatting : MSDN Custom string format

This represents the hexadecimal format.

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C# CodeDom Cant type in " [closed]

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Closed 9 years ago.
I want to compile a code with codedom which should connect to my ftp server.
But I cant type in the credentials because of the ""...
Look here :
Temp.AppendLine(#"request.Credentials = new NetworkCredential("userid","userpassword");");
If I type " in the code, it automatic ends the content of the brackets...
Help?
You may need to escape the content by using double quotes, like this:
Temp.AppendLine(#"request.Credentials = new NetworkCredential(""userid"",""userpassword"");");
Temp.AppendLine(#"request.Credentials = new NetworkCredential(""userid"",""userpassword"");");
Escape the " with ""

How can I get from a string of a directory and file name only the file name? [closed]

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Closed 10 years ago.
The code:
'Files' is a List<string> and _indx is an int.
label22.Text = files[_indx];
For example in 'files' in index[0] I have this string:
D:\New folder (45)\converted.avi_Automatic\Lightning 0 Length 2 [91 - 93]\000091.bmp
But instead in label22.Text I want it to show me only '000091.bmp' without the rest of the directory path.
How can I do it ?
Use Path.GetFileName:
label22.Text = Path.GetFileName(files[_indx]);
I believe you are looking for Path.GetFileName():
label22.Text = Path.GetFileName(files[_indx]);
Path.GetFileName(fileName) returns the file name without the directory.
taken from http://msdn.microsoft.com/en-us/library/system.io.path.getfilename(v=vs.100).aspx
The simplest way is
Path.GetFileName(files[_indx]);

Converting C# line to VB.net [closed]

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Closed 10 years ago.
I was trying to convert the following c# code to vb.net.
I see the problem is my lack of familiarity with the syntax of the parameters of OrderByDescending() What is the proper VB.Net equivalent of the C# line?
//C# code
SelectedFolder.Search("ALL", true).OrderByDescending(_ => _.Date).ToList();
//VB.Net part which doesn't work
For Each msg In SelectedFolder.Search("ALL", True).OrderByDescending(Function(_).[Date]).ToList()
After removing the underscore before [Date] the error became,
Error 1 Identifier expected.
The _ character is a line continuation in VB. Try changing the variable name to something more common, like x
For Each msg In SelectedFolder.Search("ALL", True).OrderByDescending(Function(x) x.[Date]).ToList()

C# check line number of stringreader [closed]

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Closed 10 years ago.
How do I check if the string reader has passed a certain line number, or has passed a line number which contains some text? I put this in the line processing code of a string reader:
if (currentline.Contains("123"))
currentbank = "123";
else if (currentline.Contains("456"))
currentbank = "456";
else if (currentline.Contains("789"))
currentbank = "789";
I want to change the contents of a string based on what range of line numbers it is in, with my code it always gives 123. Like for example if it's from lines 10-20 (or from 123 to 456) then the string should have 123, 20-30 (or 456 to 789) it should have 456 and 30-40 have 789. How can I do this using a StringReader?
Fixed it myself, problem being I used upper case (e.g. TEST) instead of lower case.

How to form this Regex [closed]

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Closed 10 years ago.
Suppose the string is:
string item = "t-ewrwerwerwerwer\r-rr\wrjkwlr";
I want to Replace all - except when it is preceded by r.
So resut will be
string cleanItem = "tewrwerwerwerwer\r-rr\wrjkwlr"'
What regular expression can be used?
I think this regular expression is a little more efficient:
-(?<!r-)
Or if your language doesn’t support negative look-behind assertions, use this expression:
(^|[^r])-
and replace it by \1 (first matching group).
A replacement on (?<!r)- by an empty string should do the trick I think.
(?<!r)-
As long as your regex flavor supports zero-width look-behind, that is.

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