I have date/time format, for example:
"2012-06-28T08:26:57Z"
What kind of date/time format is that and how can it be converted into the following format, using DateTime format in C#.:
"8/24/2012 4:09:17 AM"
You can do this:
string input = "2012-06-28T08:26:57Z";
var dt = DateTime.Parse(input);
string output = dt.ToString(#"MM/dd/yyyy h:mm:ss tt", CultureInfo.InvariantCulture);
For the meaning of each part of your input string, take a look at this link: http://www.w3.org/TR/NOTE-datetime
This is an ISO8601 date/time string. The numbers are the year, month, day, hour, minute, and second (in that order).
The "T" is a placeholder. It means nothing.
The "Z" is an indicator that the time is relative to GMT, rather than in a local time zone.
Try converting the date into string like this
date.ToString("yyyy-MM-dd HH':'mm':'ss")
Here date is a variable in which a date is present
or try this
string timeString = "11/12/2009 13:30:00.000";
IFormatProvider culture = new CultureInfo("en-US", true);
DateTime dateVal = DateTime.ParseExact(timeString, "dd/MM/yyyy HH:mm:ss.fff", culture);
These links might also be helpful to you.
DateTime.ToString() Patterns
String Format for DateTime [C#]
Try this to convert Universal datetime to local time
var date = DateTime.ParseExact("2012-08-25T06:57:57Z","yyyy-MM-ddTHH:mm:ssZ",System.Globalization.CultureInfo.CurrentCulture);
var newformat = date.ToString("MM/dd/yyyy HH:mm:ss tt");
try to use something liKe this.
var d = DateTime.Parse("2012-08-24T04:09:17Z");
Console.WriteLine (d.ToString("G"), CultureInfo.InvariantCulture);
Note that 'General date/time pattern (long time).' in .net is culture specific. From msdn:
6/15/2009 1:45:30 PM -> 6/15/2009 1:45 PM (en-US)
6/15/2009 1:45:30 PM -> 15/06/2009 13:45 (es-ES)
6/15/2009 1:45:30 PM -> 2009/6/15 13:45 (zh-CN)
That is Universal Sortable date format
You can use following code to convert it
var dt = DateTime.Parse("2012-06-28T08:26:57Z");
var newdt = String.Format("{0:G}", dt); // "6/28/2012 1:56:57 PM"
Update
You can try this also
var dt = DateTime.Parse("2012-06-28T08:26:57Z", System.Globalization.CultureInfo.InvariantCulture);
var newdt = String.Format("{0:G}", dt);
http://msdn.microsoft.com/en-us/library/8kb3ddd4.aspx this is answer to your question. Here you can see how to create different date formats. According to this resource, you may use something like this:
String olddate="2012-06-28T08:26:57Z";
DateTime date=Convert.ToDateTime(olddate);
String date1=date.ToString("M/d/yyyy h:m:s tt");
you can simply use :)
DateTime dt = Convert.ToDateTime("2012-06-28T08:26:57Z");
Related
I have a project that contain 3 string variables.
DateFormatStr is the format string I need to use to output dates.
DateFormatFrom is the start date a request will apply from
FilloutDateTo is the end date the request will apply to.
The problem is that I don't want to manually specify the dates. As you can see in my example below (a working example), I need to specify the dates, but is there a way to make it that the from date has time 00:00:00 and the end date has time 23:59:59?
string DateFormatStr = "MM/dd/yy hh:mm:ss tt";
string DateFormatFrom = "12/04/14 00:00:00";
string FilloutDateTo = "12/04/14 23:59:59";
So I would like to the system time to recognize the from date and the start date respecting the formatStr variable.
Thanks
If I understand correctly, you can use DateTime.Today property like;
var dt1 = DateTime.Today;
var dt2 = DateTime.Today.AddDays(1).AddSeconds(-1);
and use DateTime.ToString() to format them like;
var DateFormatFrom = dt1.ToString("MM/dd/yyyy HH:mm:ss", CultureInfo.InvariantCulture);
var FilloutDateTo = dt2.ToString("MM/dd/yyyy HH:mm:ss", CultureInfo.InvariantCulture);
Results will be;
12/04/2014 00:00:00
12/04/2014 23:59:59
You used hh format specifier but it is for 12-hour clock. Use HH format specifier instead which is for 24-hour clock. And since your result strings doesn't have any AM/PM designator, you don't need to use tt format specifier.
In C# 6.0 you can use string interpolation in order to display formatted dates.
DateTime startOfDay = DateTime.Today;
DateTime endOfDay = DateTime.Today.AddDays(1).AddTicks(-1);
string dateFormatFrom = $"{startOfDay: MM/dd/yy hh:mm:ss tt}";
string filloutDateTo = $"{endOfDay: MM/dd/yy hh:mm:ss tt}";
string idate = "01/11/2019 19:00:00";
DateTime odate = Convert.ToDateTime(idate);
DateTime sdate1 = DateTime.Parse(idate);
string outDate1 = String.Format("{0}/{1}/{2}", sdate1.Day, sdate1.Month,sdate1.Year);
Console.WriteLine(outDate1);
I have a time that is 16:23:01. I tried using DateTime.ParseExact, but it's not working.
Here is my code:
string Time = "16:23:01";
DateTime date = DateTime.ParseExact(Time, "hh:mm:ss tt", System.Globalization.CultureInfo.CurrentCulture);
lblClock.Text = date.ToString();
I want it to show in the label as 04:23:01 PM.
"16:23:01" doesn't match the pattern of "hh:mm:ss tt" - it doesn't have an am/pm designator, and 16 clearly isn't in a 12-hour clock. You're specifying that format in the parsing part, so you need to match the format of the existing data. You want:
DateTime dateTime = DateTime.ParseExact(time, "HH:mm:ss",
CultureInfo.InvariantCulture);
(Note the invariant culture, not the current culture - assuming your input genuinely always uses colons.)
If you want to format it to hh:mm:ss tt, then you need to put that part in the ToString call:
lblClock.Text = date.ToString("hh:mm:ss tt", CultureInfo.CurrentCulture);
Or better yet (IMO) use "whatever the long time pattern is for the culture":
lblClock.Text = date.ToString("T", CultureInfo.CurrentCulture);
Also note that hh is unusual; typically you don't want to 0-left-pad the number for numbers less than 10.
(Also consider using my Noda Time API, which has a LocalTime type - a more appropriate match for just a "time of day".)
string Time = "16:23:01";
DateTime date = DateTime.Parse(Time, System.Globalization.CultureInfo.CurrentCulture);
string t = date.ToString("HH:mm:ss tt");
This gives you the needed results:
string time = "16:23:01";
var result = Convert.ToDateTime(time);
string test = result.ToString("hh:mm:ss tt", CultureInfo.CurrentCulture);
//This gives you "04:23:01 PM" string
You could also use CultureInfo.CreateSpecificCulture("en-US") as not all cultures will display AM/PM.
The accepted solution doesn't cover edge cases.
I found the way to do this with 4KB script. Handle your input and convert a data.
Examples:
00:00:00 -> 00:00:00
12:01 -> 12:01:00
12 -> 12:00:00
25 -> 00:00:00
12:60:60 -> 12:00:00
1dg46 -> 14:06
You got the idea...
Check it https://github.com/alekspetrov/time-input-js
I want to format the input string into MM/dd/yyyy hh:mm:ss format in C#.
The input string is in format MM/dd/yyyy hh:mm:ss
For example :"04/30/2013 23:00"
I tried Convert.ToDateTime() function, but it considers 4 as date and 3 as month which is not what I want. Actually month is 04 and date is 03.
I tried DateTime.ParseExact() function also, But getting Exception.
I am getting error:
String was not recognized as a valid DateTime.
Your date time string doesn't contains any seconds. You need to reflect that in your format (remove the :ss).
Also, you need to specify H instead of h if you are using 24 hour times:
DateTime.ParseExact("04/30/2013 23:00", "MM/dd/yyyy HH:mm", CultureInfo.InvariantCulture)
See here for more information:
Custom Date and Time Format Strings
You can use DateTime.ParseExact() method.
Converts the specified string representation of a date and time to its
DateTime equivalent using the specified format and culture-specific
format information. The format of the string representation must match
the specified format exactly.
DateTime date = DateTime.ParseExact("04/30/2013 23:00",
"MM/dd/yyyy HH:mm",
CultureInfo.InvariantCulture);
Here is a DEMO.
hh is for 12-hour clock from 01 to 12, HH is for 24-hour clock from 00 to 23.
For more information, check Custom Date and Time Format Strings
try this:
string strTime = "04/30/2013 23:00";
DateTime dtTime;
if(DateTime.TryParseExact(strTime, "MM/dd/yyyy HH:mm",
System.Globalization.CultureInfo.InvariantCulture,
System.Globalization.DateTimeStyles.None, out dtTime))
{
Console.WriteLine(dtTime);
}
This can also be the problem if your string is 6/15/2019. DateTime Parse expects it to be 06/15/2019.
So first split it by slash
var dateParts = "6/15/2019"
var month = dateParts[0].PadLeft(2, '0');
var day = dateParts[1].PadLeft(2, '0');
var year = dateParts[2]
var properFormat = month + "/" +day +"/" + year;
Now you can use DateTime.Parse(properFormat, "MM/dd/yyyy"). It is very strange but this is only thing working for me.
change the culture and try out like this might work for you
string[] formats= { "MM/dd/yyyy HH:mm" }
var dateTime = DateTime.ParseExact("04/30/2013 23:00",
formats, new CultureInfo("en-US"), DateTimeStyles.None);
Check for details : DateTime.ParseExact Method (String, String[], IFormatProvider, DateTimeStyles)
DateTime dt1 = DateTime.ParseExact([YourDate], "dd-MM-yyyy HH:mm:ss",
CultureInfo.InvariantCulture);
Note the use of HH (24-hour clock) rather than hh (12-hour clock), and the use of InvariantCulture because some cultures use separators other than slash.
For example, if the culture is de-DE, the format "dd/MM/yyyy" would expect period as a separator (31.01.2011).
Below code worked for me:
string _stDate = Convert.ToDateTime(DateTime.Today.AddMonths(-12)).ToString("MM/dd/yyyy");
String format ="MM/dd/yyyy";
IFormatProvider culture = new System.Globalization.CultureInfo("fr-FR", true);
DateTime _Startdate = DateTime.ParseExact(_stDate, format, culture);
You may use this type format (get formatted data from sql server)
FORMAT(convert(datetime,'16/04/2018 10:52:20',103),'dd/MM/yyyy HH:mm:ss', 'en-us')
CONVERT(VARCHAR,convert(datetime,'16/04/2018 10:52:20',103), 120)
I'm storing user time in UTC time and when I show it I need to convert it to am pm time.
Here is example in database I have 17:00:00 convert to 5:00 pm
Here is the code what I came up so far but it's not working
var time = DateTime.ParseExact(object.Time.ToString(), "HHmm", CultureInfo.CurrentCulture).ToString("hh:mm tt");
var time = DateTime.ParseExact("17:00", "HH:mm", null).ToString("hh:mm tt");
returns 05:00 PM
DateTime.ParseExact is returning DateTime
Edited:
Include CultureInfo
var time = DateTime.ParseExact("17:00", "HH:mm", null).ToString("hh:mm tt", CultureInfo.GetCultureInfo("en-US"));
TimeSpan is a duration "17 hours", not a time. Maybe add this to a date (only) and use the existing datetime formatting options? (although watch for daylight savings)
i.e.
string s = DateTime.Today.Add(duration).ToString(specifier);
Don't forget to specify appropriate culture, e.g.: CultureInfo.InvariantCulture.
var time = DateTime.Now.ToString("h:mm tt", CultureInfo.InvariantCulture);
See also: Custom Date and Time Format Strings
I just needed to display static html with my TimeSpan. So in my view I used,
DateTime.Today.Add(StartTime).ToString("%h:mm tt")
"StartTime" is my TimeSpan, it converts it to a DateTime and then displays it. My time now displays as "3:00 PM" instead of "15:00". The "%h" eliminates a leading zero for time that is between 1-9.
Based on your comment, first convert the TimeSpan to a DateTime:
var dtUtc = DateTime.Now.ToUniversalTime();
dtUtc.AddHours(timeSpanObject.Hours);
dtUtc.AddMinutes(timeSpanObject.Minutes);
Once it's a DateTime, you can convert it from UTC to localtime:
var dtLocal = dtUtc.ToLocalTime();
Only when you display it would you include AM/PM, like:
dtLocal.ToString("h:mm tt");
I have a date of the following format in a file (YYYY-MM-DD HH:MM:SS.millisecs):
1987-04-03 19:17:12.000
When I use DateTime to parse this string, it gets only the date part and does not get the time part. Can someone please tell me how to parse this into the DateTime object?
Use DateTime.ParseExact().
var format = "yyyy-MM-dd hh:mm:ss.fff"
var dt = DateTime.ParseExact(s, format);
See http://msdn.microsoft.com/en-us/library/w2sa9yss.aspx. You should also add a format provider, just as CultureInfo.InvariantCulture.
var dt = DateTime.ParseExact(s, format, CultureInfo.InvariantCulture);
I did up a quick console app and it's showing both date and time:
string dateTimeString = "1987-04-03 19:17:12.000";
Console.WriteLine(DateTime.Parse(dateTimeString));
Console.ReadLine();
The resulting output is:
4/3/1987 7:17:12 PM
You might be using the resulting parse value incorrectly?
DateTime.Parse("1987-04-03 19:17:12.000") returns 4/3/1987 7:17:12 PM
The format string you are looking for is:
yyyy-MM-dd HH:mm:ss.fff
So
DateTime myDateTime = DateTime.ParseExact(sourceString, "yyyy-MM-dd HH:mm:ss.fff",
CultureInfo.InvarientCulture);
See MSDN for more information
How are you parsing it? How are you converting the DateTime to a string?
DateTime date = DateTime.Parse ("1987-04-03 19:17:12.000");
Console.WriteLine (date);
// yields: 4/3/1987 7:17:12 PM
Console.WriteLine (date.Date);
// yields: 4/3/1987
IFormatProvider culture = new CultureInfo("en-US", true);
DateTime.ParseExact(timeString, "dd/MM/yyyy HH:mm:ss.fff",culture);