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C# - Unable to get node value from xml file

I'm trying to get the inner text from a node after loading the XML file.
I have tried this code with another file and it worked. But here I can't get the node values.
Can anyone point out what am I doing wrong?
XML file - restaurant_reviews.xml
<?xml version="1.0"?>
<restaurants xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.algonquincollege.com/onlineservice/reviews">
<restaurant>
<name>Laughing Man</name>
<logo>
<name>Visit the Laughing Man</name>
<imagefile>laughing-man.gif</imagefile>
<width unit="px">50</width>
<height unit="px">200</height>
</logo>
</restaurant>
<restaurant>
<name>Gong’s Asian Cuisine</name>
<logo>
<name/>
<imagefile>gong-asian-cuisine.gif</imagefile>
<width unit="px">150</width>
<height unit="px">250</height>
</logo>
</restaurant>
</restaurants>
C# Code
List<string> names = new List<string>();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(HttpContext.Current.Server.MapPath(#"~/App_Data/restaurant_reviews.xml"));
XmlNodeList nodes = xmlDoc.SelectNodes("/restaurants/restaurant");
foreach (XmlNode itemNode in nodes)
{
XmlNode titleNode = itemNode.SelectSingleNode("name");
if (titleNode != null)
{
names.Add(titleNode.InnerText);
}
}

Whilst this question already has an accepted answer, I wanted to add this anyway, as removing namespaces and manipulating XML in this way doesn't feel right to me, it was added for a reason I suspect.
What I believe is the correct approach is too add an XML Namespace Manager to your XPath query.
var nsMgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsMgr.AddNamespace("r", "http://www.algonquincollege.com/onlineservice/reviews");
Then in your SelectNodes and SelectSingleNodes, you add the namespace to the query and pass in the manager, like so.
XmlNodeList nodes = xmlDoc.SelectNodes("/r:restaurants/r:restaurant", nsMgr);
and
XmlNode titleNode = itemNode.SelectSingleNode("r:name", nsMgr);
But if you're happy with the other solution and can manipulate it in this way then go for it I guess.

If you remove this xmlns="http://www.algonquincollege.com/onlineservice/reviews" in your xml it works. I don't know why but the xmlDoc.SelectNodes("/restaurants/restaurant"); do not find any nodes with this xmlns namespace.
This is the code I worked with and it works:
string xml = #"<?xml version=""1.0""?>
<restaurants xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
<restaurant>
<name>Laughing Man</name>
<logo>
<name>Visit the Laughing Man</name>
<imagefile>laughing-man.gif</imagefile>
<width unit=""px"">50</width>
<height unit=""px"">200</height>
</logo>
</restaurant>
<restaurant>
<name>Gong’s Asian Cuisine</name>
<logo>
<name/>
<imagefile>gong-asian-cuisine.gif</imagefile>
<width unit=""px"">150</width>
<height unit=""px"">250</height>
</logo>
</restaurant>
</restaurants>";
List<string> names = new List<string>();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);
XmlNodeList nodes = xmlDoc.SelectNodes("/restaurants/restaurant");
foreach (XmlNode itemNode in nodes)
{
XmlNode titleNode = itemNode.SelectSingleNode("name");
if (titleNode != null)
{
names.Add(titleNode.InnerText);
}
}

The problem was with namespace. Thanks to #Sean in the comment section I have resolved the issue. Thanks to #Presi also for pointing out the namespace attribute was the problem.
List<string> names = new List<string>();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(HttpContext.Current.Server.MapPath(#"~/App_Data/restaurant_reviews.xml"));
var namespaceName = "ns";
var namespacePrefix = string.Empty;
XmlNamespaceManager nameSpaceManager = null;
if (xmlDoc.LastChild.Attributes != null)
{
var xmlns = xmlDoc.LastChild.Attributes["xmlns"];
if (xmlns != null)
{
nameSpaceManager = new XmlNamespaceManager(xmlDoc.NameTable);
nameSpaceManager.AddNamespace(namespaceName, xmlns.Value);
namespacePrefix = namespaceName + ":";
}
}
XmlNodeList nodes = xmlDoc.SelectNodes(string.Format("/{0}restaurants/{0}restaurant", namespacePrefix), nameSpaceManager);
foreach (XmlNode itemNode in nodes)
{
XmlNode titleNode = itemNode.SelectSingleNode(namespacePrefix + "name", nameSpaceManager);
if (titleNode != null)
{
names.Add(titleNode.InnerText);
}
}

C# how to read single item in node xml

I have xml file:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?><SENT_110 xmlns:ns2="http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd" xmlns="http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber>
I want to read in separate SenderKey, RecipientKey & CarrierKey.
When i use this code:
XmlTextReader reader = new XmlTextReader(file);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(reader);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ns", xmlDoc.DocumentElement.NamespaceURI);
XmlNodeList nodeList = xmlDoc.SelectNodes("/ns:SENT_110/ns:KeyNumber", nsmgr);
foreach (XmlNode node in nodeList)
{
key = node.InnerText;
MessageBox.Show(key);
}
i've got something like this: KS-28YMKR-52DHKD-48WW, without any separate between key.
How i could read only one key?

Use the following XPath:
"/ns:SENT_110/ns:KeyNumber/*"
It will return all nested nodes to you.

If the structure of the XML is fixed it is rather easy by using XDocument:
var xmlText = "<SENT_110 xmlns:ns2=\"http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd\" xmlns=\"http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd\"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber></SENT_110>";
var xml = XDocument.Parse(xmlText);
var nodes = xml.Descendants();
var senderKey = nodes.First(d => d.Name.ToString().EndsWith("SenderKey")).Value;
var recipientKey = nodes.First(d => d.Name.ToString().EndsWith("RecipientKey")).Value;
var carrierKey = nodes.First(d => d.Name.ToString().EndsWith("CarrierKey")).Value;
See HERE for a working snippet. If this is just a part of a bigger XML or the structure can be different maybe some more complex searching is needed.

Read particular xml node using condition c#

I want to read particular node in XML like if any "Log"(root node) node contain "Message" node the it should read all the node under the "Log" node.
Note : Log node is root node and there are many node under "log" node.
for Example :
<TestLogDataSet>
<Log>
<Assembly>TestCase</Assembly>
<TestMethod>Application</TestMethod>
<Status>Passed</Status>
<Trace />
</Log>
<Log>
<Assembly>TestCase</Assembly>
<TestMethod>Application</TestMethod>
<Status>Failed</Status>
<Message>
<pre><![CDATA[ Error while deleting the Project]]>
</pre>
</Message>
<Trace />
</Log>
</TestLogDataSet>
Code :
string xmlFile = File.ReadAllText(#"D:\demo.xml");
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlFile);
foreach (XmlNode lognode in xmlDoc.SelectNodes("/TestLogDataSet/Log[Message]"))
{
foreach (XmlNode node in lognode.ChildNodes)
{
string n1 = node.InnerText;
textBox1.Text = n1 + "\r\n";
}
}

You can use XPath for this.
StringBuilder nodeText = new StringBuilder();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(<your xml here>);
foreach (XmlNode lognode in xmlDoc.SelectNodes("/TestLogDataSet/Log[Message]")) //select all log nodes with Message as child tag
{
string status = lognode.SelectSingleNode("./Status").InnerText;
if (!string.Equals(status,"failed",StringComparison.OrdinalIgnoreCase))
{
continue;
}
foreach (XmlNode node in lognode.ChildNodes)
{
nodeText.Append(node.LocalName);
nodeText.Append(":");
nodeText.Append(node.InnerText);//read inner text of node here
nodeText.Append("\n");
}
}
Console.WriteLine(nodeText.ToString());

If you want the Log nodes then this should suffice:
var nodes =
xd
.Root
.Elements("Log")
.Where(x => x.Element("Message") != null);
That gives:
If you want a list of all of the child nodes (which is what I understand you want from your question, but it seems a bit odd) then this works:
var nodes =
xd
.Root
.Elements("Log")
.Where(x => x.Element("Message") != null)
.SelectMany(x => x.Elements());
This gives:

XML traversing using XmlDocument

I have the following code, which I use to traverse the XML:
private void btn_readXML_Click(object sender, EventArgs e)
{
var doc = new XmlDocument();
doc.Load("e:\\contacts.xml");
// Load xml document.
TraverseNodes(doc.ChildNodes);
}
static List<string> xmlnodes = new List<string>();
private static void TraverseNodes(XmlNodeList nodes)
{
foreach (XmlNode node in nodes)
{
List<string> temp = new List<string>();
temp.Add("Node name: " + node.Name.ToString());
XmlAttributeCollection xmlAttributes = node.Attributes;
foreach (XmlAttribute at in xmlAttributes)
{
temp.Add(" Atrib: " + at.Name + ": " + at.Value);
}
xmlnodes.AddRange(temp);
TraverseNodes(node.ChildNodes);
}
But my problem is, I don't want to traverse the whole document, I only want to traverse the node and subsequently its children which has an attribute 'X'. Please note that I don't know where the node is present. So basically what I have to do is, find out if the node exists ( it'll have the attribute 'X'. That's how I identify its the right node) if yes then fetch its children.
Can anyone help me out here? I'm pretty new to XMLs. Thanks is advance!

Assuming your XML having following structure:
<Contacts>
<Contact X="abc">
<Child1></Child1>
</Contact>
<Contact X="def">
<Child2></Child2>
</Contact>
</Contacts>
Example code using XmlNode.SelectNodes:
var doc = new XmlDocument();
doc.Load("e:\\contacts.xml");
//get root element of document
XmlElement root = doc.DocumentElement;
//select all contact element having attribute X
XmlNodeList nodeList = root.SelectNodes("//Contact[#X]");
//loop through the nodelist
foreach (XmlNode xNode in nodeList)
{
//traverse all childs of the node
}
For different XPath Queries see this link.
UPDATE:
If you want to select all elements having attribute X in the document. No matters where they exists. You could use following:
//select all elements in the doucment having attribute X
XmlNodeList nodeList = root.SelectNodes("//*[#X]");

Try this:
private void btn_readXML_Click(object sender, EventArgs e)
{
var doc = new XmlDocument();
doc.Load("e:\\contacts.xml");
var nodes = xdoc.SelectNodes("//yournodename");
// ex.
// var nodes = xdoc.SelectNodes("//Company");
TraverseNodes(nodes);
}

C# how to create a custom xml document

I'm really just trying to create a custom xml document for simple configuration processing.
XmlDocument xDoc = new XmlDocument();
string[] NodeArray = { "Fruits|Fruit", "Vegetables|Veggie"};
foreach (string node in NodeArray)
{
XmlNode xmlNode = xDoc.CreateNode(XmlNodeType.Element,node.Split('|')[0],null);
//xmlNode.Value = node.Split('|')[0];
xmlNode.InnerText = node.Split('|')[1];
xDoc.DocumentElement.AppendChild(xmlNode);
}
What i'm trying to get is this.
<?xml version="1.0" encoding="ISO-8859-1"?>
<Fruits>Fruit</Fruits>
<Vegetables>Veggie</Vegetables>
i get not set to value of an object at xDoc.DocumentElement.AppendChild(xmlNode);

Unfortunately, You can't make that XML structure.
All XML documents must have a single root node. You can't have more.
Try something like this
XmlDocument xDoc = new XmlDocument();
xDoc.AppendChild( xDoc.CreateElement("root"));
string[] NodeArray = { "Fruits|Fruit", "Vegetables|Veggie" };
foreach (string node in NodeArray)
{
XmlNode xmlNode = xDoc.CreateNode(XmlNodeType.Element, node.Split('|')[0], null);
//xmlNode.Value = node.Split('|')[0];
xmlNode.InnerText = node.Split('|')[1];
xDoc.DocumentElement.AppendChild(xmlNode);
}

It is not possible to have that XML structure as XML MUST have a single root element. You may want to try:
<?xml version="1.0" encoding="ISO-8859-1"?>
<items>
<Fruits>Fruit</Fruits>
<Vegetables>Veggie</Vegetables>
</items>