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How to get the name of elements/attributes in xml files and write these into another new xml file using LINQ

I am new to c#. Right now I am trying to get the name of some specific elements in an xml file and create a new xml file for these.
I have tried with LINQ, so that I can parse the xml and get the name of some elments that I want.
I do not want to use console.writeline to output this name. Instead I would like to create a new xml file and save these names in it.
Can anyone give me some tips?
The following is example data I would like to parse:
<root>
<Package>
<Class name="EnterpriseArchitect">
<Operation/>
</Class>
<Class name="ZachmanFramework">
<Operation/>
</Class>
</Package>
</root>
I want to get the attribute name of the element Class and save it in a new xml file like this:
<root>
<EnterpriseArchitect/>
<ZachmanFramework/>
</root>
The following is my c# code, but I can not reach the goal:
XDocument xdoc = XDocument.Load(#"C:\Users\jsc\Desktop\123456.xml");
XDocument xNew = new XDocument();
var datatype = xdoc.Root.Elements("Package").Elements("Class")
foreach (var dut in datatype)
{
var dataTypeName = dut.Attribute("name").Value;
xNew.Add(new XElement(dataTypeName));
}
xNew.Save(#"C:\Users\jsc\Desktop\1234567.xml");

Please, read my comments to the question.
This should work:
XDocument srcdoc = XDocument.Load("sourceFileName.xml");
List<XElement> names = srcdoc.Descendants("Class")
.Select(x=> new XElement(x.Attribute("name").Value))
//.Distinct() //uncomment this if duplicate values aren't allowed
.ToList();
XDocument newdoc = new XDocument();
XElement root = new XElement("root");
root.Add(names);
newdoc.Add(root);
newdoc.Save("newFileName.xml");
Good luck!

Modify xml, child nodes with same name

I am trying to modify a xmlString so i can create a dataset on the fly.
The xml looks like this:
<?xml version="1.0"?>
<ds xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<ttActivity>
<a-actno>1030371</a-actno>
<a-status>Start</a-status>
<a-solution/>
<a-descript>hei</a-descript>
<a-descript>hopp</a-descript>
<a-acttypegr>0</a-acttypegr>
<a-calltype/>
</ttActivity>
</ds>
The problem when creating a dataset using dataset.ReadXML(xmlReader) is the 2 nodes with same name "a-descript". Is there a quick way to fix this xml so that the nodes get unique names. ie: a-descript1 and a-descript2 ??

using LINQ to XML
XDocument doc = XDocument.Parse(xmlString);
doc.Descendants("a-descript").Last().Name = "a-descript2";
xmlString = doc.ToString();

xml Nodes by Element

Below is an example of the xml file that I need to pull data via C#. This is my first experience with reading xml files and a beginner with xml. Anyone have an example of how I would find/load the fieldorder values for Export_B?
<?xml version="1.0" encoding="utf-8"?>
<Config>
<OutFolderCSV>c:\Output\2012\upload_Files</OutFolderCSV>
<OutFolderImage>c:\Output\2012\NM_Scorecard_Images</OutFolderImage>
<PathOutLogFile>c:\Output\2012\Log\Matches.log</PathOutLogFile>
<FieldSeparator>,</FieldSeparator>
<ExportFile>
<Name>Export_A</Name>
<FieldOrder>matchID</FieldOrder>
<FieldOrder>contactID</FieldOrder>
<FieldOrder>stageID13</FieldOrder>
<FieldOrder>stringScore1a</FieldOrder>
<FieldOrder>xScore1a</FieldOrder>
<FieldOrder>stageID14</FieldOrder>
<FieldOrder>stringScore1b</FieldOrder>
<FieldOrder>xScore1b</FieldOrder>
<FieldOrder>stageID15</FieldOrder>
<FieldOrder>stringScore1c</FieldOrder>
<FieldOrder>xScore1c</FieldOrder>
</ExportFile>
<ExportFile>
<Name>Export_B</Name>
<FieldOrder>matchID</FieldOrder>
<FieldOrder>contactID</FieldOrder>
<FieldOrder>stageID16</FieldOrder>
<FieldOrder>stringScore1a</FieldOrder>
<FieldOrder>xScore1a</FieldOrder>
<FieldOrder>stageID17</FieldOrder>
<FieldOrder>stringScore1b</FieldOrder>
<FieldOrder>xScore1b</FieldOrder>
<FieldOrder>stageID18</FieldOrder>
<FieldOrder>stringScore1c</FieldOrder>
<FieldOrder>xScore</FieldOrder>
</ExportFile>
</Config>

Using LINQ to XML:
var doc = XDocument.Load(#"c:\path\to\file.xml");
var fieldOrders =
from exportFile in doc.Descendants("ExportFile")
where (string)exportFile.Element("Name") == "Export_B"
from fieldOrder in exportFile.Elements("FieldOrder")
select (string)fieldOrder;

I have written an article
http://www.codeproject.com/Articles/33769/Basics-of-LINQ-Lamda-Expressions
on XML using XDocument object.
You can parse the XML easily using
XDocument.Load(filepath)
Please read the section XLinq to parse the objects.
edit :
You can change value of Export_B using the code :
var document = XDocument.Load(filepath)
var exportFiles = document.Descandants("ExportFile");
List<XElement> list = new List<XElement>();
foreach(var element in exportFiles)
{
list.Add(element);
// Now you can do element.Element("Name") to get the name. Put a breakpoint on this, you can get the reference of all underlying objects.
}

How to get the value from XML?

I'm making a small tool for checking the material number from the XML file.
I know this quite easy for you experts and I would like to ask for your help on this to get me started on this. On my machine I have .NET 2.0 framework I guess, and VS C# Express 2005 installed.
I have an XML that contains data of a material. It is located at my local drive. I am able now to browse the XML file and save the file in a string variable. Well, that's what I have done so far..
if(folderBrowserDialog1.ShowDialog() == DialogResult.OK)
{
string[] files = Directory.GetFiles(folderBrowserDialog1.SelectedPath, "Product.xml");
string prodFile = files[0];
...
...
Suppose this is the structure of the XML:
<Record>
<Product>
<Material_Number>20209485</Material_Number>
<Product_Type>Type1</Product_Type>
...
...
</Product>
</Record>
How can I get the material number value?

You can use the XmlDocument class for loading your XML File into a DOM.
MSDN - This class implements the W3C Document Object Model (DOM) Level 1 Core and the Core DOM Level 2. The DOM is an in-memory (cache) tree representation of an XML document and enables the navigation and editing of this document. Because XmlDocument implements the IXPathNavigable interface it can also be used as the source document for the XslTransform class.
Sample
There are many ways to read your value. I really encourage you to read Working with Xml DOM
XmlNodeList list = xml.GetElementsByTagName("Product");
XmlAttributeCollection attr = list[0].Attributes;
string materialNumber = list[0].ChildNodes[0].InnerText;
or
XmlNodeList list = xml.GetElementsByTagName("Material_Number");
string materialNumber = list[0].InnerText;
More Information
MSDN - XmlDocument Class
Working with Xml DOM

You could also use XPathNavigator and XPathExpression with XmlDocument.
var xmlDoc = new XmlDocument();
xmlDoc.Load("Product.xml") //or xmlDoc.LoadXml(xmlString);
var xmlNav = xmlDoc.CreateNavigator();
string materialNum;
var iterator = xmlNav.Select("/Record/Product/Material_Number");
if (iterator.MoveNext() && iterator.Current != null)
materialNum = iterator.Current.Value;
If you use .Net 3.0+ you could use System.Xml.Linq.XDocument.
var xdoc = XDocument.Load("Product.xml"); //or var xdoc = XDocument.Parse(xmlString);
var materialNum = xdoc.Root.Element("Product").Element("Material_Number").Value;

I was able to find a solution. Not so elegant though...
XmlDocument xmlDoc= new XmlDocument();
xmlDoc.Load(#"C:\Product.xml");
XmlNodeList a = xmlDoc.GetElementsByTagName("Material_Number");
string materialNumber = a[0].InnerText;

XmlSerializer Deserializing Array/List of Multiple Objects at Root

I'm trying to deserialize the following XML output:
<?xml version="1.0" encoding="ISO-8859-1"?>
<Foo>
<Val>Data1</Val>
</Foo>
<Foo>
<Val>Data2</Val>
</Foo>
(This is output from a hardware device, and cannot be changed)
I have an XML type defined as:
[XmlType(AnonymousType=true, Namespace="")]
public class Foo
{
public string Val { get; set; }
}
I've tried to deserialize this array by creating a serializer like:
var s = new XmlSerializer(typeof(Foo[]));
//or
var s = new XmlSerializer(typeof(List<Foo>);
But every call to s.Deserialize() causes an InvalidOperaitonException:
System.InvalidOperationException: <Foo xmlns=''> was not expected.
Note
var s = new XmlSerializer(typeof(Foo));
// Only deseralizes the first Foo (Data1).
Thanks for your help.

I think the issue is with your provided xml.
Test app says
List<Foo> list = new List<Foo> {new Foo {Val = "Data1"}, new Foo {Val = "Data2"}};
var s = new XmlSerializer(typeof(List<Foo>));
StringBuilder sb = new StringBuilder();
XmlWriter wr = XmlWriter.Create(sb);
s.Serialize(wr, list);
string ss = sb.ToString();
var s2 = new XmlSerializer(typeof(List<Foo>));
StringReader sr = new StringReader(ss);
List<Foo> returnList = (List<Foo>)s2.Deserialize(sr);
And the XML should be
<?xml version="1.0" encoding="utf-16"?>
<ArrayOfFoo xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Foo>
<Val>Data1</Val>
</Foo>
<Foo>
<Val>Data2</Val>
</Foo>
</ArrayOfFoo>
If you can remove the inital line
<?xml version="1.0" encoding="ISO-8859-1"?>
And minipulate the string into
string s = "<ArrayOfFoo><Foo> <Val>Data1</Val></Foo><Foo> <Val>Data2</Val></Foo></ArrayOfFoo>";
var s2 = new XmlSerializer(typeof(List<Foo>));
StringReader sr = new StringReader(s);
List<Foo> list = (List<Foo>)s2.Deserialize(sr);
That could work.

That isn't valid Xml. There needs to be a core root element for it to work properly.

this is not a valid xml so you can not deserialize it like a valid xml. You need some kind of hack to make this work. i'd suggest to insert at beginning of the xml and inserting at the end of xml. then you can deserialize it, since you cant make this change at xml side, do it in your code.
String ss;
// lets assume this holds your xml data in string.
ss.append("</ArrayOfFoo>");
ss.replace("<?xml version=\"1.0\" encoding=\"utf-16\"?>", "<?xml version=\"1.0\" encoding=\"utf-16\"?> <ArrayOfFoo>")
var s2 = new XmlSerializer(typeof(List<Foo>));
StringReader sr = new StringReader(ss);
List<Foo> returnList = (List<Foo>)s2.Deserialize(sr);
now this shall return you the correct list.

As the other posters say, this XML that the hardware device produces is not compatible to the way .NET serializes/deserializes object. Valid XML, and .NET requires valid XML, has a root element.
I suggest:
either you modify your obtained XML to match the way astander presents in his xml code snippet.
or you write a simple xml parser for your file that deserializes the file like you need
br, Marcel

Technically, what you have there is not a well-formed XML document (which has exactly one root element), but rather an well-formed external parsed entity (which can have any number of elements not contained in other elements, as well as text not contained in any elements). Therefore, it should parse if your XML parser has an entry point for parsing EPEs rather than documents. You could also create a stub document which includes by reference your EPE and parse that document.

Xstream for .Net could be a useful API