Increment character in string - c#

I have the following code:
string str="A";
I want to get the next alphabetical character programmatically (so B, C, D, E etc.)
Can anyone suggest a way of doing this?

Instead of whole strings, use Char.
char aChar = 'A';
aChar++; // After this line executes, `aChar` is `B`

If you are looking for something like "A".. "Z"..."AA", "AB"..."ZZ"..."AAA"...
, here is the code,
public static string IncrementString(this string input)
{
string rtn = "A";
if (!string.IsNullOrWhiteSpace(input))
{
bool prependNew = false;
var sb = new StringBuilder(input.ToUpper());
for (int i = (sb.Length - 1); i >= 0; i--)
{
if (i == sb.Length - 1)
{
var nextChar = Convert.ToUInt16(sb[i]) + 1;
if (nextChar > 90)
{
sb[i] = 'A';
if ((i - 1) >= 0)
{
sb[i - 1] = (char)(Convert.ToUInt16(sb[i - 1]) + 1);
}
else
{
prependNew = true;
}
}
else
{
sb[i] = (char)(nextChar);
break;
}
}
else
{
if (Convert.ToUInt16(sb[i]) > 90)
{
sb[i] = 'A';
if ((i - 1) >= 0)
{
sb[i - 1] = (char)(Convert.ToUInt16(sb[i - 1]) + 1);
}
else
{
prependNew = true;
}
}
else
{
break;
}
}
}
rtn = sb.ToString();
if (prependNew)
{
rtn = "A" + rtn;
}
}
return rtn.ToUpper();
}

var str = "A";
char firstChar = str[0];
char nextChar = (char)((int)firstChar + 1);
var newStr = nextChar.ToString();

I am looking for the same thing, and I am using string so I need to cast it.
You can do this if your variable is string:
string foo = "b";
char result = Convert.ToChar(foo[0] + 1); //Will result to 'c'

Related

if an string has Arabic words then it must be write from "RTL" in wpf ie orientation of the string

input:string arabicStr = "inrr أربعة عشر anp خمسين paisle";
but my desire output is: "paisle. خمسين anp عشر أربعة inrr "
class ReverseString
{
static void Main(string[] args)
{
int i;
string Temp = string.Empty;
string Str;
Console.WriteLine("Enter string");
Str = Console.ReadLine();
int Prev = Str.Length - 1;
for (i = Str.Length - 1; i >= 0; i--)
{
if (Str[i] == ' ' || i == 0)
{
if (i == 0)
Temp += Str[i];
for (int j = i + 1; j <= Prev; j++)
{
Temp += Str[j];
}
Temp += ' ';
Prev = i - 1;
}
else
{
continue;
}
}
Console.WriteLine(Temp);
}
}
}
Just split it with Spaces, Reverse it and then again join it with Spaces:
string result = string.Join(" ", input.Split(' ').Reverse());

Adding exponentials

I made an expression evaluator but I only included: addition and substraction and multiply and division and a brackets resolver and I want to add exponential "^" and after that trigonometric functions: sine, cosine and tangent but I don't know where to start... this is what I did for now:
public static string RemoveBrackets(string text)
{
while (text.Contains('(') && text.Contains(')'))
{
int openIndex = 0;
int closeIndex = 0;
for(int i = 0; i < text.Length; ++i)
{
if(text[i] == '(')
{
openIndex = i;
}
if(text[i] == ')')
{
closeIndex = i;
text = text.Remove(openIndex, closeIndex - openIndex + 1).Insert(openIndex, ResolveBrackets(openIndex, closeIndex, text));
break;
}
}
}
for(int i = 1; i < text.Length; ++i)
{
if(text[i] == '-' && (text[i - 1] == '*' || text[i - 1] == '/'))
{
for(int j = i - 1; j >= 0; --j)
{
if(text[j] == '+')
{
StringBuilder text1 = new StringBuilder(text);
text1[j] = '-';
text = text1.ToString();
text = text.Remove(i, 1);
break;
}
else if(text[j] == '-')
{
StringBuilder text1 = new StringBuilder(text);
text1[j] = '+';
text = text1.ToString();
text = text.Remove(i, 1);
break;
}
}
}
}
for (int i = 0; i < text.Length; ++i)
{
if (text[i] == '-' && (text[i - 1] == '-' || text[i - 1] == '+'))
{
if(text[i - 1] == '-')
{
StringBuilder text1 = new StringBuilder(text);
text1[i] = '+';
text = text1.ToString();
text = text.Remove(i - 1, 1);
}
else
{
StringBuilder text1 = new StringBuilder(text);
text1[i] = '-';
text = text1.ToString();
text = text.Remove(i - 1, 1);
}
}
else if (text[i] == '+' && (text[i - 1] == '-' || text[i - 1] == '+'))
{
if (text[i - 1] == '-')
{
StringBuilder text1 = new StringBuilder(text);
text1[i] = '-';
text = text1.ToString();
text = text.Remove(i - 1, 1);
}
else
{
StringBuilder text1 = new StringBuilder(text);
text1[i] = '+';
text = text1.ToString();
text = text.Remove(i - 1, 1);
}
}
}
if (text[0] == '-')
{
text = '0' + text;
}
return Calculate(text);
}
public static string ResolveBrackets(int openindex, int closeindex, string text)
{
string BracketAnswer = evaluate(text.Substring(openindex + 1, closeindex - openindex - 1));
return BracketAnswer;
}
public static double DivideAndMultiply(string text)
{
string[] expr = text.Split('*');
List<string> textList = new List<string>();
for (int i = 0; i < expr.Length; ++i)
{
textList.Add(expr[i]);
if (i != expr.Length - 1)
{
textList.Add("*");
}
}
for (int i = 0; i < textList.Count; ++i)
{
if (textList[i].Contains('/') && textList[i].Length > 1)
{
string[] textPart = textList[i].Split('/');
textList.RemoveAt(i);
for (int j = textPart.Length - 1; j >= 0; --j)
{
textList.Insert(i, textPart[j]);
if (j != 0)
{
textList.Insert(i, "/");
}
}
}
}
double total;
if (textList[0].Contains('*') || textList[0].Contains('/'))
{
total = textList[0] == "" ? 0 : DivideAndMultiply(textList[0]);
}
else
{
total = Convert.ToDouble(textList[0]);
}
/// 7:30 min tutorial
for (int i = 2; i < textList.Count; i += 2)
{
if (textList[i - 1] == "/")
{
total /= Convert.ToDouble(textList[i]);
}
else if (textList[i - 1] == "*")
{
total *= Convert.ToDouble(textList[i]);
}
}
return total;
}
public static double AddAndSubstract(string text)
{
string[] expr = text.Split('-');
List<string> textList = new List<string>();
for(int i = 0; i < expr.Length; ++i)
{
textList.Add(expr[i]);
if(i != expr.Length - 1)
{
textList.Add("-");
}
}
for(int i = 0; i < textList.Count; ++i)
{
if (textList[i].Contains('+') && textList[i].Length > 1)
{
string[] textPart = textList[i].Split('+');
textList.RemoveAt(i);
for (int j = textPart.Length - 1; j >= 0; --j)
{
textList.Insert(i, textPart[j]);
if (j != 0)
{
textList.Insert(i, "+");
}
}
}
}
//double total = Add(expr[0]);
double total = expr[0] == "" ? 0 : DivideAndMultiply(textList[0]);
for (int i = 2; i < textList.Count; i += 2)
{
if(textList[i - 1] == "-")
{
total -= DivideAndMultiply(textList[i]);
}
else if(textList[i - 1] == "+")
{
total += DivideAndMultiply(textList[i]);
}
}
return total;
}
Any suggestions on what should I read?
Use system.math to do this, it is easier
read about programmatic part - of math class
https://msdn.microsoft.com/en-us/library/system.math(v=vs.110).aspx
And find some tuturial about scientific calculator. That should give a insights.

How to generate a Alphanumeric sequence number in c#

I wrote below code for generating my 8 digit character number, increment should happen from left to right.
suppose my starting Number is ABC00001 the next increment number will be ABC00002
number will increment up to 9 and after 9 it will change to A .
eg: ABC00009 -- >ABC00000A --> ABC00000B --> .... -->ABC00000Z
after Z it will change last second digit number as ABC0000A1 --> ABC0000A2 ...
public static string GeneratedNextevcPrimakryKey()
{
System.Text.StringBuilder sb = new System.Text.StringBuilder();
string str = string.Empty;
var maxNumber = "ONC0BJKZ";
string splitnumber = maxNumber.Substring(3, 5);
char[] temp = splitnumber.ToCharArray();
//find last index number/character
for (int i = splitnumber.Length - 1; i >= 0; i--)
{
if (char.IsNumber(splitnumber[i]))
{
int fifthvalue = Convert.ToInt32(splitnumber[i].ToString());
//increment 5th digit character
if (fifthvalue == 9)
{
temp[i] = 'A';
break;
}
else
{
fifthvalue = fifthvalue + 1;
string f = Convert.ToString(fifthvalue);
temp[i] = Convert.ToChar(f);
//sb.Append(fifthvalue);
break;
}
}
else
{
char letter = splitnumber[i];
char nextChar = new char();
if (letter == 'z')
{
string strvalue = Convert.ToString(1);
temp[i] = Convert.ToChar(strvalue);
}
else if (letter == 'Z')
{
//last digit character
string strvalue = Convert.ToString(1);
temp[i] = Convert.ToChar(strvalue);
str = new string(temp);
break;
}
else
nextChar = (char)(((int)letter) + 1);
temp[i] = nextChar;
str = new string(temp);
break;
}
}
return str;
}
You can try to implement Base36
void Main()
{
// 17 would be the number you want to convert to your ABC format
var result = ToBase36(17);
Console.WriteLine(result);
// Will print "ABC00000H"
}
private static string ToBase36(ulong value)
{
const string base36 = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
var sb = new StringBuilder(9);
do
{
sb.Insert(0, base36[(byte)(value % 36)]);
value /= 36;
} while (value != 0);
var paddedString = "ABC" + sb.ToString().PadLeft(6, '0');
return paddedString;
}

How to get output to be a continuous string rather than it being stacked on top of each letter - c#

public class LetterArray
{
internal static string[] Alphabet()
{
var letterValues = new string[26];
letterValues[0] = "A";
letterValues[1] = "B";
letterValues[2] = "C";
letterValues[3] = "D";
letterValues[4] = "E";
letterValues[5] = "F";
letterValues[6] = "G";
letterValues[7] = "H";
letterValues[8] = "I";
letterValues[9] = "J";
letterValues[10] = "K";
letterValues[11] = "L";
letterValues[12] = "M";
letterValues[13] = "N";
letterValues[14] = "O";
letterValues[15] = "P";
letterValues[16] = "Q";
letterValues[17] = "R";
letterValues[18] = "S";
letterValues[19] = "T";
letterValues[20] = "U";
letterValues[21] = "V";
letterValues[22] = "W";
letterValues[23] = "X";
letterValues[24] = "Y";
letterValues[25] = "Z";
return letterValues;
}
}
public class decrypt
{
public static void Main() //Main method
{
int res = 34;
string[] letterValues = LetterArray.Alphabet();
//Create for loop that runs through every possible shift value
for (int shift = 0; shift <= 25; shift++)
{
Console.WriteLine("\nShift Value = " + shift + ": ");
// For each character in the text file
foreach (var ch in ReadText.cipherTxt()) {
if (ch == ' ')
{ }
else
{
for (int i = 0; i <= 25; i++)
{
if ((ch.ToString().ToUpper()) == letterValues[i])
{
res = i;
}
}
if (shift > res)
{
Console.WriteLine(letterValues[26 - (shift - res)][0]);
}
else
{
Console.WriteLine(letterValues[res - shift][0]);
}
}
}
}
}
}
Not sure how to output the following so be a continuous string instead of each letter being stacked on top of each other. I have tried to change the Console.WriteLine values but it seems to mess the program up and throw an error instead.
Use Console.Write if you don't want each value in a new line.
Console.Write(letterValues[res - shift]);
You can also use a StringBuilder and Append characters to it. Then print it once after the loop.

How to add or subtract very large numbers without bigint in C#?

So let me start by saying that I'm a newbie with little to moderate knowledge about C#.
Coming to the topic: I need to make a program that is able to add/subtract very large integers. Initially, used BigInt only to find out it's not allowed. There should be a logical workaround for this? I have an idea which is using "elementary school method" where you add each digit starting from right to left.
I made a string which I split into char array and added each digit from right to left(GetUpperBound-i). But it doesn't seem to work.
My Code:
string s, s2;
char[] c_arr, c_arr2;
int i, erg;
s = "1234";
s2 = "5678";
c_arr = s.ToCharArray();
c_arr2 = s2.ToCharArray();
for (i = 0; i <= c_arr.GetUpperBound(0); i++)
{
erg = c_arr[c_arr.GetUpperBound(0)-i]+c_arr2[c_arr2.GetUpperBound(0)-i];
Console.Write(erg);
}
Console.ReadKey();
There are a few things wrong with your code for the 'elementary school method'. You don't account for carry, you're adding up ascii values rather than actual values between 0-9, and you're outputting the results in the wrong order.
The code below, whilst not very elegant, does produce the correct results:
var s1 = "12345";
var s2 = "5678";
var carry = false;
var result = String.Empty;
if(s1.Length != s2.Length)
{
var diff = Math.Abs(s1.Length - s2.Length);
if(s1.Length < s2.Length)
{
s1 = String.Join("", Enumerable.Repeat("0", diff)) + s1;
}
else
{
s2 = String.Join("", Enumerable.Repeat("0", diff)) + s2;
}
}
for(int i = s1.Length-1;i >= 0; i--)
{
var augend = Convert.ToInt32(s1.Substring(i,1));
var addend = Convert.ToInt32(s2.Substring(i,1));
var sum = augend + addend;
sum += (carry ? 1 : 0);
carry = false;
if(sum > 9)
{
carry = true;
sum -= 10;
}
result = sum.ToString() + result;
}
if(carry)
{
result = "1" + result;
}
Console.WriteLine(result);
The following program can be used to add two large numbers, I have used string builder to store the result. You can add numbers containing digits upto '2,147,483,647'.
Using System;
using System.Text;
using System.Linq;
public class Test
{
public static void Main()
{
string term1="15245142151235123512352362362352351236";
string term2="1522135123612646436143613461344";
StringBuilder sum=new StringBuilder();
int n1=term1.Length;
int n2=term2.Length;
int carry=0;
int n=(n1>n2)?n1:n2;
if(n1>n2)
term2=term2.PadLeft(n1,'0');
else
term1=term1.PadLeft(n2,'0');
for(int i=n-1;i>=0;i--)
{
int value=(carry+term1[i]-48+term2[i]-48)%10;
sum.Append(value);
carry=(carry+term1[i]-48+term2[i]-48)/10;
}
char[] c=sum.ToString().ToCharArray();
Array.Reverse(c);
Console.WriteLine(c);
}
}
string Add(string s1, string s2)
{
bool carry = false;
string result = string.Empty;
if(s1[0] != '-' && s2[0] != '-')
{
if (s1.Length < s2.Length)
s1 = s1.PadLeft(s2.Length, '0');
if(s2.Length < s1.Length)
s2 = s2.PadLeft(s1.Length, '0');
for(int i = s1.Length-1; i >= 0; i--)
{
var augend = Convert.ToInt64(s1.Substring(i,1));
var addend = Convert.ToInt64(s2.Substring(i,1));
var sum = augend + addend;
sum += (carry ? 1 : 0);
carry = false;
if(sum > 9)
{
carry = true;
sum -= 10;
}
result = sum.ToString() + result;
}
if(carry)
{
result = "1" + result;
}
}
else if(s1[0] == '-' || s2[0] == '-')
{
long sum = 0;
if(s2[0] == '-')
{
//Removing negative sign
char[] MyChar = {'-'};
string NewString = s2.TrimStart(MyChar);
s2 = NewString;
if(s2.Length < s1.Length)
s2 = s2.PadLeft(s1.Length, '0');
for (int i = s1.Length - 1; i >= 0; i--)
{
var augend = Convert.ToInt64(s1.Substring(i,1));
var addend = Convert.ToInt64(s2.Substring(i,1));
if(augend >= addend)
{
sum = augend - addend;
}
else
{
int temp = i - 1;
long numberNext = Convert.ToInt64(s1.Substring(temp,1));
//if number before is 0
while(numberNext == 0)
{
temp--;
numberNext = Convert.ToInt64(s1.Substring(temp,1));
}
//taking one from the neighbor number
int a = int.Parse(s1[temp].ToString());
a--;
StringBuilder tempString = new StringBuilder(s1);
string aString = a.ToString();
tempString[temp] = Convert.ToChar(aString);
s1 = tempString.ToString();
while(temp < i)
{
temp++;
StringBuilder copyS1 = new StringBuilder(s1);
string nine = "9";
tempString[temp] = Convert.ToChar(nine);
s1 = tempString.ToString();
}
augend += 10;
sum = augend - addend;
}
result = sum.ToString() + result;
}
//Removing the zero infront of the answer
char[] zeroChar = {'0'};
string tempResult = result.TrimStart(zeroChar);
result = tempResult;
}
}
return result;
}
string Multiply(string s1, string s2)
{
string result = string.Empty;
//For multipication
bool Negative = false;
if(s1[0] == '-' && s2[0] == '-')
Negative = false;
else if(s1[0] == '-' || s2[0] == '-')
Negative = true;
char[] minusChar = {'-'};
string NewString;
NewString = s2.TrimStart(minusChar);
s2 = NewString;
NewString = s1.TrimStart(minusChar);
s1 = NewString;
List<string> resultList = new List<string>();
for(int i = s2.Length - 1; i >= 0; i--)
{
string multiplycation = string.Empty;
for (int j = s1.Length - 1; j >= 0; j--)
{
var augend = Convert.ToInt64(s1.Substring(j,1));
var addend = Convert.ToInt64(s2.Substring(i,1));
long multiply = augend * addend;
// print(multiply);
multiplycation = multiply.ToString() + multiplycation;
}
//Adding zero at the end of the multiplication
for (int k = s2.Length - 1 - i; k > 0; k--)
{
multiplycation += "0";
}
resultList.Add(multiplycation);
}
for (int i = 1; i < resultList.Count; i++)
{
resultList[0] = Add(resultList[0],resultList[i]);
}
//Finally assigning if negative negative sign in front of the number
if(Negative)
result = resultList[0].Insert(0,"-");
else
result = resultList[0];
return result;
}
string Divide(string dividend, string divisor)
{
string result = string.Empty;
int remainder = 0;
int intNumberstoGet = divisor.Length;
int currentInt = 0;
int dividing = int.Parse(dividend.Substring(currentInt,intNumberstoGet));
int intDivisor = int.Parse(divisor);
while(currentInt < dividend.Length)
{
if(dividing == 0)
{
currentInt++;
result += "0";
}
else
{
while(dividing < intDivisor)
{
intNumberstoGet++;
dividing = int.Parse(dividend.Substring(currentInt,intNumberstoGet));
}
if (dividing > 0)
{
remainder = dividing % intDivisor;
result += ((dividing - remainder) / intDivisor).ToString();
intNumberstoGet = 1;
if(currentInt < dividend.Length - 2)
currentInt += 2;
else
currentInt++;
if(currentInt != dividend.Length)
{
dividing = int.Parse(dividend.Substring(currentInt,intNumberstoGet));
remainder *= 10;
dividing += remainder;
}
}
}
}
return result;
}
Here you go. Another example. It's 10 to 30 times faster than the accepted answer.
static string AddNumStr(string v1, string v2)
{
var v1Len = v1.Length;
var v2Len = v2.Length;
var count = Math.Max(v1Len, v2Len);
var answ = new char[count + 1];
while (count >= 0) answ[count--] = (char)((v1Len > 0 ? v1[--v1Len] & 0xF:0) + (v2Len>0 ? v2[--v2Len]&0xF : 0));
for (var i = answ.Length - 1; i >= 0; i--)
{
if (answ[i] > 9)
{
answ[i - 1]++;
answ[i] -= (char)10;
}
answ[i] = (char)(answ[i] | 48);
}
return new string(answ).TrimStart('0');
}
Below SO question has some interesting approaches. Though the answer is in Java, but you will surely get to know what needs to be done.
How to handle very large numbers in Java without using java.math.BigInteger
public static int[] addTwoNumbers(string s1, string s2)
{
char[] num1 = s1.ToCharArray();
char[] num2 = s2.ToCharArray();
int sum = 0;
int carry = 0;
int size = (s1.Length > s2.Length) ? s1.Length + 1 : s2.Length + 1;
int[] result = new int[size];
int index = size - 1;
int num1index = num1.Length - 1;
int num2index = num2.Length - 1;
while (true)
{
if (num1index >= 0 && num2index >= 0)
{
sum = (num1[num1index]-'0') + (num2[num2index]-'0') + carry;
}
else if(num1index< 0 && num2index >= 0)
{
sum = (num2[num2index]-'0') + carry;
}
else if (num1index >= 0 && num2index < 0)
{
sum = (num1[num1index]-'0') + carry;
}
else { break; }
carry = sum /10;
result[index] = sum % 10;
index--;
num1index--;
num2index--;
}
if(carry>0)
{
result[index] = carry;
}
return result;
}

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