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C# How remove single xml parent element node without removing the contents inside the parent node

I am new to C#, kindly help me. How to remove the single xml element node 'PaymentRecord' and content inside that should not get deleted.
<Payments>
<PaymentRecord>
<PayId>2031</PayId>
<Reference>Policy03</Reference>
<StatusCode>ACV</StatusCode>
<MethodDetail>
<PaymentMethodDetail>
<CardPaymentDetails>
<CardHolderName>abcded</CardHolderName>
<CardTransactionDetails>
<StoredCard>N</StoredCard>
</CardTransactionDetails>
</CardPaymentDetails>
</PaymentMethodDetail>
</MethodDetail>
<CurrencyCode>USD</CurrencyCode>
</PaymentRecord>
</Payments>
I need to remove "PaymentRecord" element from the XML. I need like below
<Payments>
<PayId>2031</PayId>
<Reference>Policy03</Reference>
<StatusCode>ACV</StatusCode>
<MethodDetail>
<PaymentMethodDetail>
<CardPaymentDetails>
<CardHolderName>abcded</CardHolderName>
<CardTransactionDetails>
<StoredCard>N</StoredCard>
</CardTransactionDetails>
</CardPaymentDetails>
</PaymentMethodDetail>
</MethodDetail>
<CurrencyCode>USD</CurrencyCode>
</Payments>
I have tried my below code, but its deleting the complete node which I don't want to do :- here 'queuePayload' is the xml element
XmlNodeList payloadRecordList = queuePayload.SelectNodes("//Payments/PaymentRecord");
foreach (XmlElement singleNode in payloadRecordList)
{
XmlHelper.removeElem((XmlElement)singleNode.ParentNode, "//PaymentRecord");
XmlDocument xmlDoc = singleNode.OuterXml;
// my remaining logic goes based on "xmldoc" value - I will inserting this data to table
}

You can use System.Xml.Linq with its XDocument to achiev this. Load the input and create a new document out of it like:
XDocument inputDoc = XDocument.Load(inputFile, LoadOptions.None);
XDocument outputDoc = new XDocument();
var elements = inputDoc.Element("Payments").Elements().Select(pr => pr.Elements());
XElement newElement = new XElement("Payments");
foreach (var element in elements)
{
newElement.Add(element);
}
outputDoc.Add(newElement);
Console.WriteLine(outputDoc.ToString());

I think #Fructzwerg is slightly overcomplicating it.
You can remove the PaymentRecord node and add all its children to the root in one go.
var xDoc = XDocument.Load(filePath);
var paymentRecord = xDoc.Root.Element("PaymentRecord");
var nodes = xDoc.Root.Element("PaymentRecord").Elements();
paymentRecord.Remove();
xDoc.Root.Add(nodes);
Console.WriteLine(xDoc.ToString());
dotnetfiddle

How to get nodes from XML file without its attribute and put to a List of string

I would like to display the tag names of child nodes without its attributes. Then those tag names (nodes) should be put in a List of string. Here's example of my XML file:
<?xml version="1.0" encoding="UTF-8"?>
<ROOT>
<CAR>
<ID>21</ID>
<MANUFACTURER>Ford</MANUFACTURER>
<MODEL>Fiesta</MODEL>
</CAR>
<CAR>
<ID>22</ID>
<MANUFACTURER>Peugeot</MANUFACTURER>
<MODEL>508</MODEL>
</CAR>
</ROOT>
So, the effect I want to get in a console output is shown below:
ID
MANUFACTURER
MODEL
Then I would like to store that ID, MANUFACTURER and MODEL tag names in a List of strings.
This is the code that I tried so far:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.PreserveWhitespace = true;
try
{
xmlDocument.Load("XMLFile.xml");
}
catch (FileNotFoundException ex)
{
Console.WriteLine(ex);
}
Console.WriteLine(xmlDocument.OuterXml);
XmlNodeList nodeList = xmlDocument.SelectNodes("ROOT/CAR");
foreach(XmlNode node in nodeList)
{
Console.WriteLine(node.ChildNodes);
xmlNodes.Add(node.ChildNodes.ToString());
}
The problem is that it's not displaying the way I want to. As a result I only get two System.Xml.XmlChildNodes which seems to be corresponding to two <CAR> nodes, instead of its three child nodes, such as ID, MANUFACTURER and MODEL.
System.Xml.XmlChildNodes
System.Xml.XmlChildNodes
Adding items to a List basically adds the same thing as shown above.
What am I doing wrong?

If you have to use XmlDocument, then you can -
List<string> elements = new List<string>();
XmlNodeList CarNodes = xml.SelectNodes("Root/Car");
foreach(XmlNode c in CarNodes)
{
foreach(XmlNode n in c.ChildNodes)
{
if (!elements.Contains(n.Name))
{
elements.Add(n.Name);
}
}
}
But I find XDocument to be much simpler and better readability.
XDocument xdoc = XDocument.Parse(yourXmlString);
List<string> elements = xdoc.Descendants("Car")
.DescendantNodes().OfType<XElement>()
.Select(x => x.Name).Distinct().ToList();
And thats all you'll need. Easy to read as well, get all the descendants of "Car" Node and get all distinct names of XElements within it.
Another way to do it -
List<string> elements = xdoc.Descendants("Car").First()
.DescendantNodes().OfType<XElement>()
.Select(x => x.Name).ToList();
In this case I have removed the "distinct" and rather got just the first Car node ONLY. You can see the difference - if by any case some other Car node has an extra element, you'll miss getting that information by doing it this way.

You could loop through for children nodes:
1- You can define xmlNodes like a HashSet to avoid multiple tags like :
HashSet<string> xmlNodes = new HashSet<string>();
2 - Change little the code like :
....
XmlNodeList nodeList = xmlDocument.SelectNodes("ROOT/CAR");
foreach (XmlNode node in nodeList)
{
foreach(XmlNode element in node.ChildNodes)
{
if (element.NodeType == XmlNodeType.Element)
xmlNodes.Add(element.Name);
}
}
Demo
Console.WriteLine(string.Join(", ", xmlNodes));
Result
ID, MANUFACTURER, MODEL
I hope you find this helpful.

Read particular xml node using condition c#

I want to read particular node in XML like if any "Log"(root node) node contain "Message" node the it should read all the node under the "Log" node.
Note : Log node is root node and there are many node under "log" node.
for Example :
<TestLogDataSet>
<Log>
<Assembly>TestCase</Assembly>
<TestMethod>Application</TestMethod>
<Status>Passed</Status>
<Trace />
</Log>
<Log>
<Assembly>TestCase</Assembly>
<TestMethod>Application</TestMethod>
<Status>Failed</Status>
<Message>
<pre><![CDATA[ Error while deleting the Project]]>
</pre>
</Message>
<Trace />
</Log>
</TestLogDataSet>
Code :
string xmlFile = File.ReadAllText(#"D:\demo.xml");
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlFile);
foreach (XmlNode lognode in xmlDoc.SelectNodes("/TestLogDataSet/Log[Message]"))
{
foreach (XmlNode node in lognode.ChildNodes)
{
string n1 = node.InnerText;
textBox1.Text = n1 + "\r\n";
}
}

You can use XPath for this.
StringBuilder nodeText = new StringBuilder();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(<your xml here>);
foreach (XmlNode lognode in xmlDoc.SelectNodes("/TestLogDataSet/Log[Message]")) //select all log nodes with Message as child tag
{
string status = lognode.SelectSingleNode("./Status").InnerText;
if (!string.Equals(status,"failed",StringComparison.OrdinalIgnoreCase))
{
continue;
}
foreach (XmlNode node in lognode.ChildNodes)
{
nodeText.Append(node.LocalName);
nodeText.Append(":");
nodeText.Append(node.InnerText);//read inner text of node here
nodeText.Append("\n");
}
}
Console.WriteLine(nodeText.ToString());

If you want the Log nodes then this should suffice:
var nodes =
xd
.Root
.Elements("Log")
.Where(x => x.Element("Message") != null);
That gives:
If you want a list of all of the child nodes (which is what I understand you want from your question, but it seems a bit odd) then this works:
var nodes =
xd
.Root
.Elements("Log")
.Where(x => x.Element("Message") != null)
.SelectMany(x => x.Elements());
This gives:

How to create a path to xml element in C#

I want to create a routing(path) to xml element and assign it to a variable so i can access it
fast in the future.
The element, which is a child of other elements, can change its position in the document
so i cant use methods like first child or indexing that rely on position.
The path to the element will always stay constant and there is no other path like it.
If we look at a short example so i want a path to level4 value(header4) so i can modify it.
<level1>
<level2>
<level3>header3</level3>
<level4>header4</level4>
<level3>header31</level31>
</level2>
<level2>
<level3>nnn</level3>
<level3>nnnnn</level31>
</level2>
</level1>

You've got to use XPath in that case.
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load("Path of the xml");
XmlNode titleNode = xmlDoc.SelectSingleNode("//level1/level2/level3");

You can use XPath for this.
XmlDocument doc; // assuming the xml is already in doc
XmlNode node = doc.SelectSingleNode("/level1/level2/level3/level4");
if(node != null)
{
node.InnerText = "New value";
}
If there could be more than one level4 then you could do this:
XmlDocument doc; // assuming the xml is already in doc
XmlNodeList nodes = doc.SelectNodes("/level1/level2/level3/level4");
if(nodes != null)
{
foreach(XmlNode node in nodes)
{
node.InnerText = "New value";
}
}

How to find child dynamically inside XML

how to check whether child node is there for the product node in the following xml:
<product>
<SysSectionName>Processors</SysSectionName>
<section>
<subsection>
<SysSectionName>CPU#1</SysSectionName>
</subsection>
</section>
</product>
I have tried this:
foreach (XmlNode xn1 in sectionNode)
{
XmlNode node = xn1.FirstChild;
if (xn1.HasChildNodes)
{
//do something..
}
}

XmlNodeList snode = xmldoc.SelectNodes("/product/section/subsection");
foreach (XmlNode xn2 in snode)
{
//it comes inside if there will be a child node.
}

Try to use this piece of code to get the product nodes from XML:
XDocument doc = XDocument.Parse("Your Xml String");
var products = doc.Descendants("product");
foreach (var product in products)
{
//... do something ...
}

You mean you want to find whether product node has any child node?
If yes,
XmlNodeList productNodes = xmlDoc.SelectNodes("Product");
foreach(XmlNode pNode in productNodes)
{
if(pNode.ChildNodes.count >0)
{
}
}

I think XLinq (Linq for Xml) is what you're looking for.
Then you should load the Xml using XDocument, and for any XElement you have the "Descendants()" method, which returns list of child XElements. If there are no child elements, the list will have no elements as well.