how to get the output from windows form to a class? - c#

i want to get output from windows form to the calling application that is class library.
Form1 f=new Form1();
f.Show();
if(f.PropertyName!=null)
{
}
f.PropertyName is always null. After f.show() it straightaway runs if ()condition. is there any way to get the output from the form1?

Show() is non-blocking. Use ShowDialog(), or add a delegate to the FormClosing() event of your form and move your if() logic into it.
EDIT:
Here's an example of a lambda "delegate" for the closing event:
f.FormClosing += (sender, e) => { /* your code here */ };
EDIT 2: Whether you handle FormClosed() or FormClosing() depends on your specific needs. If you want to cancel the form close on a "bad" value, FormClosing() lets you cancel the form close.

You probably want to use ShowDialog() instead of Show().

Form1 f=new Form1();
if(f.ShowDialog() == DialogResult.OK)
{
if(f.PropertyName!=null)
{
}
}

Related

Disallowing interaction with background form

On my application's first run, two forms open. The topmost form needs to take priority, and disallow any interaction with the form in the background. I have tried ShowDialog() as referenced here, however this hides the form in the background which I do not wish to do. Is there a method of accomplishing this?
public Form1()
{
InitializeComponent();
if (!fileexists(#"c:\Management Tools\Absence Tracker\bin\data\tbase.skf"))
{ firstrunactions(); }
}
void firstrunactions()
{
//open the get-started form and invite user to populate serialisable objects
firstrun frwindow = new firstrun();
frwindow.ShowDialog();
}
When you are using .ShowDialog() the execution of the containing method is paused until you close the newly opened window. So make sure to do everthing else before you call .ShowDialog(). Otherwise your program gets stuck in this method. If you are calling .ShowDialog() before the background window is shown will cause problems.
But using .ShowDialog() here is totally correct and has the right functionality.
Example how not to do it (causes the same behavior like in your problem):
public Form1()
{
InitializeComponent();
//this is the wrong place for showing a child window because it "hides" its parent
Form frwindow = new Form();
frwindow.ShowDialog(this);
}
The magical place where it works:
private void Form1_Shown(object sender, EventArgs e)
{
Form frwindow = new Form();
frwindow.ShowDialog(this);
}
Edit: In your case it is enough moving if(!fileexistst...) into the Form1_Shown()-event.
Try with frwindow.ShowDialog(this);
Or instead "this" pass the other form as parameter.
Also move this part if (!fileexists(#"c:\Management Tools\Absence Tracker\bin\data\tbase.skf"))
{ firstrunactions(); }
}
in OnLoad override.

Managing the dialog form in C#

On click of a button I have this code with is should show a dialog on top of the current form and display text, wait for one second, change the text and then finally close it:
Form p = new Form();
p.ShowDialog();
p.Text = "Start.";
Thread.Sleep(1000);
p.Text = "Counting.";
Thread.Sleep(1000);
p.Text = "End.";
Thread.Sleep(1000);
p.Close();
However once it executes p.ShowDialog(); it stops the code until the form p is closed and it doesn't work as I intended it to. Can I get some guidance on this? Not necessarily the solution, but at least maybe some keywords I could google on?
UPDATE: due to the difficulties I am facing trying to access business logic, which is irrelevant to the problem, I am delaying providing the working example. Stay tuned and sorry :)
SOLUTION: what I did is in fact used Show() instead of ShowDialog(). Since i was impossible to access form from business logic, BackgroundWorker came in handy and was being used between them. I cannot share any code or the layout of the project structure, but in conclusion, the accepted answer's main statement was the key to the solution :)
That is the point of ShowDialog(). It creates a modal form and does not return control to the calling function until you are done. If it doesn't need to be modal, then use .Show(). If it does need to be modal, then put code in the Form Load method to update the text as needed.
http://msdn.microsoft.com/en-us/library/c7ykbedk.aspx
taken from the link above:
When this method is called, the code following it is not executed until after the dialog box is closed.
if you want to form to display whatever it is you want to display you should write the code inside the the form itself, do that in an eventhandler of the form show event.
As you have found, ShowDialog is a blocking method that does not return until the dialog is closed. Your code to change the text and handle the delay needs to be within the dialogue itself.
However, it's worth noting the next problem that you'll find: if you call Thread.Sleep(1000) from the UI thread, your application will become unresponsive for 1 second at a time. This is probably not what you're aiming for! I'd suggest you look into the Timer or BackgroundWorker classes to handle this more smoothly.
Check this out:
public partial class Form2 : Form
{
delegate void SetTextCallback(string text);
delegate void CloseFormCallback();
public Form2()
{
InitializeComponent();
new Thread(DoMagic).Start();
}
public void DoMagic()
{
this.SetText("Start.");
Thread.Sleep(1000);
this.SetText("Counting.");
Thread.Sleep(1000);
this.SetText("End");
Thread.Sleep(1000);
this.CloseForm();
}
private void CloseForm()
{
if (this.InvokeRequired)
{
CloseFormCallback c = new CloseFormCallback(CloseForm);
this.Invoke(c);
}
else
{
this.Close();
}
}
private void SetText(string text)
{
if (this.label1.InvokeRequired)
{
SetTextCallback d = new SetTextCallback(SetText);
this.Invoke(d, new object[] { text });
}
else
{
this.label1.Text = text;
}
}
}

Pass in parent form to ShowDialog that is called from a class instance

I have a form.
In that form I create an instance of a class on a new thread because it runs some long running logic. The form also gives the user the ability to cancel this logic/thread.
That class opens a new form if input is required.
The new form sometimes appears behind the other form.
I set a property on the class:
public Form ParentForm{get;set;}
I can now do:
MyForm form = new MyForm();
form.ShowDialog(ParentForm);
However I get a cross thread exception when calling ShowDialog(ParentForm).
I know I can use InvokeRequired somehow but not sure how on a property.
Thanks
UPDATE: Have tried doing this but still get exception:
MyForm form = new MyForm();
form.ShowDialog(GetParentForm());
private Form GetParentForm()
{
//You have to Invoke() so you can wait for the function to return and obtain its return value.
if (ParentForm.InvokeRequired)
{
return (Form)ParentForm.Invoke(new Func<Form>(() => GetParentForm()));
}
else
{
return ParentForm;
}
}
Your updated method (GetParentForm) won't work because you're wrapping the task of getting the reference to ParentForm in an InvokeRequired block. You could try wrapping the ShowDialog call in such a block instead, but I think you would still get the cross-threading error.
Your simplest fix would be to move the code that creates and shows the second form out of your class and into ParentForm. So instead of this:
MyForm form = new MyForm();
form.ShowDialog(ParentForm);
you would do this:
ParentForm.showMyNewForm();
and in ParentForm you would have this:
public void showMyNewForm()
{
MyForm form = new MyForm();
form.ShowDialog(this);
}
If MyForm needs to have a reference to the class on the other thread, you would just add a parameter to showMyNewForm() so that the reference to it can be passed in.
What you're trying to do here (creating and showing related, connected forms that are created on different threads) is really going against the grain of how forms are meant to be used in .NET.
you can add async method to a form.
Let's say like this:
public class MyForm : Form
{
public void ShowModalAsync()
{
this.Invoke(new Action(()=> {
ShowDilaog(..);
}));
}
}
and use this, like:
MyForm form = new MyForm();
form.ShowModalAsync(...);
Should work for you.
By the way, if your problem is only the fact that the window appears on bihind of others, try to make use of Form.TopMost property setting it to true. Having in mind that it, yes, will bring it infront of other forms, but not necessary infront of other topmost forms.

c# Windows form application forms problem

I have a c# windows form app which contains several forms.
Generally, for example, in form1, I create a instance of form2 and then
form1.hide();
form2.show();
But sometimes I want the previous form to show and dispose current form. How can I call the previous form?
Thanks in advance.
To answer your question, you need to maintain references in your views to each other. While this might work it's messy and error prone. It sounds like all your control logic is probably contained within your form class code and I would suggest moving away from that and separate your concerns.
Solving your form management issues becomes very simple if you create a controller class that, at a minimum, manages the creation and disposal of your forms in whatever way you see fit.
So your code sample would actually be launched from a controller class as something like:
public class FormsController
{
private Form form1 = new Form();
private Form form2 = new Form();
public void SwitchForms()
{
form1.hide();
form2.show();
}
}
For further edification checkout the MVC architectural pattern for cleanly working with data, biz logic and UI.
You might consider extending Form to include some properties/fields that allow you to access other forms. the Form class can be inherited from just like most other .Net classes.
You may also consider doing some of that management in the Program.cs file that is part of you project, if neither form is really supposed to be a child of the other.
If you inherit a new class for your form1 from Form and add a method like closeSecondForm you can have it close and dispose the second form.
There are probably a bunch of different ways to solve the issue. These are just a few.
If you set the new form's Owner to a reference to the current form, you can reference that Owner from the new form. You could also subscribe to the new form's Closed() event from the old form, with code to dispose it (though the form can dispose itself by overriding OnClosed, if it doesn't happen there anyway).
This logic should be handled in Program.cs. The Main() method initializes Form1. You want to take control there instead of passing control to the form.
Example:
static class Program
{
internal static Form1 MyForm1;
internal static Form2 MyForm2;
///
/// The main entry point for the application.
///
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
//Application.Run(new Form1());
// Initialize Form1
MyForm1 = new Form1();
MyForm1.FormClosing += new FormClosingEventHandler(MyForm1_FormClosing);
// You may want to initialize Form2 on-demand instead of up front like here.
MyForm2 = new Form1();
MyForm2.FormClosing += new FormClosingEventHandler(MyForm2_FormClosing);
// Show Form1 first
MyForm1.Show();
// Now we need to occupy the thread so it won't exit the app. This is normally the job of Application.Run.
// An alternative to this is to have a third form you pass on control to.
while (true)
{
Application.DoEvents();
System.Threading.Thread.Sleep(10);
}
}
static void MyForm1_FormClosing(object sender, FormClosingEventArgs e)
{
// Do something, for example show Form2
MyForm2.Show();
// EXAMPLE: We only want to hide it?
e.Cancel = true;
MyForm1.Visible = false;
}
static void MyForm2_FormClosing(object sender, FormClosingEventArgs e)
{
// Do something, for example show Form1
MyForm1.Show();
// EXAMPLE: We only want to hide it?
e.Cancel = true;
MyForm2.Visible = false;
}
}
Since Program is static you can access MyForm1 and MyForm2 anywhere in that project by:
Program.MyForm1.Show();
Program.MyForm2.Hide();
If you plan to have many forms/complex logic I suggest moving this to a separate class. Also consider using a single form and rotate user controls inside it instead.
Form2 myform = new Form2();
myform.show();
this.hide();
You could do this in form1:
...
var form2 = new form2();
form2.Closing += (form2_Closing);
this.hide();
form2.show();
...
private void form2_Closing(object sender, System.EventArgs e)
{
this.show();
}

C# Winforms Threading - Delay Child form event until form is closed

I have an interesting problem..
I have a Form that launches another Form (2) through a Button. Before Form2 Closes, it sometimes fires an Event which Invalidates Form 1 and forces Form 1 to refresh it's data. The problem I have is After Form 2 fires the event, Form 1 seems to get it and handles it, and refreshes it's data and Only then Form 2 Closes. I want Form 2 to Fire the event and Close, BEFORE Form1's event handler catches and processes the event.
I have a feeling it is related to BackgroundWorker (sort of like SwingUtilities.InvokeLater in Java) .. but I am not that experienced with it ..
public class Frm1{
void LaunchForm2(){
Frm2 form2 = new Frm2();
form2.dataChanged += new DataChangeListener(myListener);
form2.showDialog();
}
private void myListener(){
//get my data again
}
}
public class Frm2{
private void Close(){
if(myDataHasChanged){
if(dataChanged != null) {
dataChanged();
}
this.Close();
}
}
}
Is there a specific reason why you're using events in this situation?
Expose a property on Form2 that allows you to check whether the data has changed. After the ShowDialog() call returns, check the value of the property and do your update if necessary.
(Edited to remove my now-useless code sample.)
You can do this in OnHandleDestroyed as it it done after final destruction of the window handle. You can be certain that:
No more processing will be done by Frm2
The call will always be fired when the form closes
Thus do something like the following:
public class Frm2 : Form
{
protected override void OnHandleDestroyed(EventArgs e)
{
base.OnHandleDestroyed(e);
if (myDataHasChanged)
{
if (dataChanged != null)
dataChanged();
}
}
private void Close()
{
if (myDataHasChanged)
this.Close();
}
}
UPDATE:
Test to verify that HandleDisposed is called prior to returning from ShowDialog():
bool called = false;
Form test = new Form();
test.Shown += delegate (Object o, EventArgs e) { test.Close(); };
test.HandleDestroyed += delegate(Object o, EventArgs e) { called = true; };
test.ShowDialog();
Assert.IsTrue(called);
You can raise the event after calling Close - calling Form.Close will not exit the method that called it.
EDIT: Try using BeginInvoke to wait for the next message loop before handling the event, like this:
form2.dataChanged += delegate { BeginInvoke(new DataChangeListener(myListener)); };
2nd EDIT: To give Form1 a chance to repaint, call BeginInvoke twice to wait two message loops before updating (One to close Form2, and a second to repaint Form1), like this:
form2.dataChanged += delegate(parameters) {
BeginInvoke(new Action(delegate {
BeginInvoke(new DataChangeListener(myListener), parameters);
}));
//Or,
BeginInvoke(new Func<Delegate, object[], IAsyncResult>(BeginInvoke),
new object[] { parameters }
);
};
Why don't you raise DataChanged Event in Closed event of form2?
Try changing the event call to:
public class Frm2{
private void Close(){
if(myDataHasChanged){
if(dataChanged != null) {
dataChanged.BeginInvoke();
}
this.Close();
}
}
}
This won't guarantee that the form closes before myListener() completes. However, it should allow the form to close without waiting for myListener() to complete.

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