I've been all up and down this tutorial.
I can't for the life of me figure out how when my app loads to have 1 screen, then when a menu item is clicked to show another screen. I get the idea of having multiple forms, but is that the solution I need here?
From what I've read I understand new forms to be essentially new windows. If that's right, that doesn't sound like what I need.
My users start off with a blank window other than a menu (I'm gonna fill it in later), but I want for File -> Settings to load a settings form. Ideally not in a new window.
Its a MDI window. They are window containers of other windows.
You create a parent form, and then you change which child form is the active form on the menu item click events. This requires you make a parent MDI form, and a child MDI form for each of the different views you want of your document. The menu items then switch which child MDI form is the active one.
Related
I'm creating a new winforms application.
I want to simulate MDI functionality with a flowlayoutpanel that will host "many" panels that will have a form embedded into it.
So the workflow would work like this:
User click on navigation menu to open a module (the module is a winform that will be embedded into a panel and this panel will expand to fill its container)
The user will se the module filled in order to work but has option to minimize it so he can work on other module.
When the user click on the minimize icon "custom icon added to the panel", the panel will minimize like a title into the flowcontainerpanel.
The user then can click on other module or double click the existing current opened modules "tiles" to open it again.
Here are some images so I can explain it better.
Once the "tile" is double clicked the panel should expand and fill:
How can I do this?
I am using an MDI form in which I have given option tool strip menu item as a call to a new child form. On the child form I have some buttons and DataGridView. But when I click the child form option the buttons and DataGridView are not displaying correctly. Provided I have already set the isMdiContainer property to true of MDI form.
The scenario runs successfully when I simply show a form, but the problem occurs when I use the form as a child form. Here is the code which I wrote in a tool strip menu item click:
frm_bank_master myfrm = new frm_bank_master();
myfrm.MdiParent =this;
myfrm.Show();
I have an application using C# wherein I have a form which is MdiContainer form named parentmdiform in which all my child form gets open.
From submenu of this parentmdiform a form named studentmasterform gets open.from this form on a click of a button a new form named existingstudent form gets open.
When I want go back to studentmasterform again from Existingstudentform, a click of a button on which studentmasterform gets open.But the problem is my earlier opened studentmasterform from parent form does not get focused or disposed off.That means I get two separate object of same form that is Studentmasterform which exists in my parentmdiform.
What I want is ,that same form object should get either focused or disposed of when i click on any other forms within my MDI application to access earlier form.
Can anyone tell me how?
You need to track the creation of studentmasterform. And if it is there, created, don't create new one, do Keyboard.Focus(oldOne);
P.S. There is studentmasterform.Closed event to help you keep the track.
I hope I understand what are you want to do.
First, if you want that a Form closes if it loses focus, take a look at the "Deactivate" event of the Form class. [MSDN Deactive Event]: http://msdn.microsoft.com/en-us/library/system.windows.forms.form.deactivate.aspx
When you need a Form as only once opened, you can check "parentmdiform.MdiChildren" to get all the children of your MDI From. You can give your Forms an unique name, so it's easier to focus the right.
regards, C#er
I have a user control in my SplitContainer's right panel. A form opens below the user control. Now if i click a button in the user control, that current form should close and a new form should open. How to do this?
You can implement below logic in your app easily:
splitContainer.Panel2.Controls.Remove(myPanel);
splitContainer.Panel2.Controls.Add(myOtherPanel);
which will remove the existing panel from the container and place the other panel. You can extend the same logic to place forms, or separate controls on the container easily.
I couldn't find a right term to search about this in the feature.
I have a control that will load a very heavy data that embedding within a tab of of my MainWindow.
Test Case:
For testing I have a window, within this windows there are 2 tab. the first tab contain notthing. 2nd tab contain this user control.
In the 2nd tab I have a MessageBox.
Run this program and MessageBox popup right after the MainWindow was loaded.
How can I delay load this usercontrol/page until the tab is active?
Have you tried calling your load code only when the user control is visible?
The other suggestion would be to create you own tab control that only loads the content when the tab is visible. This would also allow you to create animations when a tab becomes hidden before the new tab is visible.