Declaring interface on abstract base class - c#

I am currently implementing the Quartz timer to allow scheduling of some data files. I have a abstract DataOutput class and then implementations to cover the different types of output (http, file, etc). I have implemented the interface on both specialisations but I am having compilation errors when I try and declare this on the abstract base in order to create objects of type DataOutput so I can deal with these at runtime.
Is this possible?

You'll need to at least abstractly implement the interface:
public interface IExample
{
string Word { get; set; }
void DoIt();
}
public abstract class ExampleClass : IExample
{
public string Word { get; set; }
public abstract void DoIt();
}
I'm not sure if you've done this since you didn't post any code or errors.

Related

Using an Interface as a Parameter Type For Method, Can this work?

my question is, if you have a method of the form:
public bool ProcessAggregation(IAggregatePoint point) { #do stuff }
And a class, NetworkAggregation, implementing IAggregatePoint. Can you call the method like:
ProcessAggregation(point) where point here is a NetworkAggregation instance?
Also, if not possible with interfaces, could inheritance of an abstract base class work? Meaning any object inheriting from the abstract base class would be passible into the method?
I am reluctant to alter the classes with inheritance as they are database schemas for a MySql database/ used with EntityFramework.
Thanks!
Network aggregation is implemented like:
public class NetworkAggregation : IAggregatePoint
{
public DateTime? AssessmentDate {get; set;}
public int Id {get; set;}
public string DUPValue {get; set;}
//And so on, other properties not specified in IAggregatePoint
}
and IAggregatePoint is implemented like:
public interface IAggregatePoint
{
public DateTime? AssessmentDate {get; set;}
}
Yes, this will work. As long as a class implements the IAggregatePoint interface, an instance of that class can be provided to ProcessAggregation without any issues. You'll get a compiler error if you make a mistake (like trying to use a method that is from NetworkAggregation but not part of IAggregatePoint within ProcessAggregation).
You could also do the same thing with an abstract base class, as you mentioned.
It might be worthwhile to review the C# language specification's documentation on interfaces.
Edit - here's a simple, working example:
public interface IAggregatePoint
{
}
public class NetworkAggregation : IAggregatePoint
{
}
public class AnotherAggregation
{
}
public void Test()
{
// works because NetworkAggregation implements IAggregatePoint
ProcessAggregation(new NetworkAggregation());
// fails to compile (as expected) because AnotherAggregation
// doesn't implement IAggregatePoint
ProcessAggregation(new AnotherAggregation());
}

Force derived class to implement method with Generics - C# [duplicate]

This question already has answers here:
Adding different type of generic objects into generic list
(4 answers)
Closed 4 years ago.
Is it possible to have an abstract base class force its derived classes to implement a specific method with generics while still being able to use the abstract base class elsewhere? Here's what I mean:
public abstract class BaseFieldValue<ToutputType,TinputType>
{
public abstract ToutputType DoStuff(TinputType input);
}
public class StringField:BaseFieldValue<string,string>
{
public string StringValue { get; set; }
public override string DoStuff(string input)
{
//Custom implementation for this class
}
}
public class Project
{
public string ProjectName { get; set; }
public List<BaseFieldValue> ProjectFields {get;set;} //ERROR
}
The inheritance of BaseFieldValue -> StringField compiles fine, but when I try to use List<BaseFieldValue> on Project it doesn't like the syntax because it wants the generic types defined. Is what I'm trying to do even possible or is there a better approach?
I'm currently implementing an interface on all these derived classes, but this forces me to remember it needs to go on each of them. I'd like the generic contract to be enforced on any class that derives form BaseFieldValue.
Just make your generic base class inherit a non-generic base class or interface:
public abstract class BaseFieldValue
{
}
public abstract class BaseFieldValue<ToutputType,TinputType> : BaseFieldValue
{
public abstract ToutputType DoStuff(TinputType input);
}
I'm currently implementing an interface on all these derived classes...
In that case, you might consider just using this interface instead of an abstract base class.
public abstract class BaseFieldValue<ToutputType,TinputType> : IFieldValue
{
...
}
public class Project
{
public string ProjectName { get; set; }
public List<IFieldValue> ProjectFields {get;set;}
}

injecting an generic interface

ok I'm little lost with generics in C#
I have this generic interface
interface IInvoiceStorage<T>
where T : class
{
void Persist(T Invoice);
}
with two classes implementing the interface
public class FacturaStorageForSQLServer:IInvoiceStorage<EVT>
{
public void Persist(EVT Invoice)
{
/*Implementation*/
}
}
public class FacturaStorageForMySQLServer:IInvoiceStorage<EVTFruit>
{
public void Persist(EVTFruit Invoice)
{
/*Implementation*/
}
}
The problem comes when I want to declare this in my service class
public class invoice_service
{
IInvoiceStorage Storage;
public invoice_service(IInvoiceStorage storage)
{
Storage=_storage;
}
}
C# tells me that I have to declare de type of the interface but if I do that then my service class is going to depend from the implementation and not from the interface.
Suggestions??
UPDATE 1:
Sorry If I declare the type the interface is going to depend only from the implementations using that type but what happens if I have two implementations using two different types for example EVT and EVTFruit.
I was thinking to use another interface to establish a relationship between EVT and EVTFruit but they can be two totally different objects so I'm not sure if it is a good idea.
You could change your class a little bit:
public class invoice_service<T> where T : class
{
IInvoiceStorage<T> Storage;
public invoice_service(IInvoiceStorage<T> storage)
{
Storage=_storage;
}
}
Which would allow you to use the interface correctly and keep it generic.
Depending on your needs, you could also defined non-generic version of that interface:
public interface IInvoiceStorage
{
...
}
And make classes inherit from this interface, too.
public class FacturaStorageForSQLServer : IInvoiceStorage, IInvoiceStorage<EVT>
public class FacturaStorageForMySQLServer : IInvoiceStorage, IInvoiceStorage<EVTFruit>
That way you can use non-generic version of interface in invoice_service class.
But, as I said, depending on your needs if you can make functionality of that interface independent of type (for example, List<T> also implements IList for list functionalities, without type).
After trying your suggestions and reading some blogs here is what I did and is fulfilling my requeriments at least for now. The problem was resolved when I realized that I shouldn't use the generic repository pattern as a repository itself but as a helper of the repository! At the end what I'm doing is wrapping the generic interfaces inside of another layer of non-generic interfaces.
a Service class calling for an IInvoiceRepositoryService implementation
public class InvoiceService
{
private IInvoiceRepositoryService RepositoryService;
public SQLInvoiceService(IInvoiceRepositoryService _RS)
{
RepositoryService=_RS;
}
}
and their respective implementation for EVT and EVTFruit.
public class EVTRepository:IInvoiceRepositoryService
{
private IInvoiceStorage<EVT> EVTStorage;
public EVTInvoiceRepository(IInvoice<EVT> _EVT)
{
EVTStorage=_EVT;
}
}
public class EVTStorageForSQLServer: IInvoiceStorage<EVT>
{
/*Implementation*/
}
public class EVTStorageForMySQLServer: IInvoiceStorage<EVT>
{
/*Implementation*/
}
public class EVTFruitRepository:IInvoiceRepositoryService
{
private IInvoiceStorage<EVT> EVTFruitStorage;
public EVTFruitInvoiceRepository(IInvoice<EVTFruit> _EVTFruit)
{
EVTFruitStorage=_EVTFruit;
}
}
public class EVTFruitStorageForSQLServer: IInvoiceStorage<EVTFruit>
{
/*Implementation*/
}
public class EVTFruitStorageForMySQLServer: IInvoiceStorage<EVTFruit>
{
/*Implementation*/
}
At the end this was just a design problem I think. I'm going to mark Ron Beyer's response as the answer because is valid and it was really straightforward

Child use of interface

I have a user control that will handle images on a form. But depending on what the source is (web cam or ID scan or other video source) the user control is different.
But they share some common features so I want to create a base class.
My other controls all have some interface items that I need. I would like to declare the interface at the base level though and just implement at the class level. But virtual and override seems to be the closest way to get what I want. Is there any to do it, force the new class to implement the interface assigned at the base class? Looking around it look like making the class abstract (which I don't fully understand) might be a start. If it was just methods that might be alright, but I am also using properties. In that area I have hit a dead end in my searches for answers. Here is what I have so far. Am I on the right track? I just have not worked with abstract classes at all and only limited exposure to interfaces. From the research I think I have the method correct just not sure about the property.
public interface RequiredAnswer
{
void LabelRequiredFieldEmpty();
bool AnswerRequired{ get;}
}
public abstract partial class ExtImage : UserControl, RequiredAnswer
{
public virtual bool AnswerRequired
{
get
{
throw new NotImplementedException ("Answer Required");
}
}
public abstract void LabelRequiredFieldEmpty ()
{
//checkBox_AgreementAcceptedText.ForeColor = Color.Red;
}
So I would have a class
public partial class ExtImageWebCam : ExtImage
{
public override bool AnswerRequired
{
get
{
return valueFromThisClassThatMeansAnAnswerIsRequired;
}
}
public override void LabelRequiredFieldEmpty ()
{
// do something
}
}
When you declare a method abstract, you are basically saying that a child class must supply the definition of the method. You can make properties abstract. This sounds like it is exactly what you need.
Here is the MSDN article for further reference.
From MSDN
Properties
Abstract properties behave like abstract methods, except for the differences in declaration and invocation syntax.
It is an error to use the abstract modifier on a static property.
An abstract inherited property can be overridden in a derived class by including a property declaration that uses the override modifier.
Continuing later
In this example, the class DerivedClass is derived from an abstract class BaseClass. The abstract class contains an abstract method, AbstractMethod, and two abstract properties, X and Y.
abstract class BaseClass // Abstract class
{
protected int _x = 100;
protected int _y = 150;
public abstract void AbstractMethod(); // Abstract method
public abstract int X { get; }
public abstract int Y { get; }
}
Abstract base class with an Interface
An abstract class must provide implementation for all interface members.
An abstract class that implements an interface might map the interface methods onto abstract methods. For example:
interface I
{
void M();
}
abstract class C : I
{
public abstract void M();
}
First of all, interfaces should start with an I by convention, so your interface would be IRequiredAnswer.
Second, if you want to force the inherited classes to implement their own methods rather than inheriting them, just make them abstract in the base class:
public abstract class ExtImage : UserControl, IRequiredAnswer
{
public abstract bool AnswerRequired { get; }
public abstract void LabelRequiredFieldEmpty ();
}
Your child classes would then have to implement the method and property.
You're on the right track. Here's a simple example of what you could do. Making the Bar() method abstract forces the inheritors to implement it.
public interface IFoo{
void Bar();
}
public abstract class BaseFoo : IFoo
{
public abstract void Bar();
public void Implemented(){
Debug.WriteLine("this is a shared implementation");
}
}
public class KungFoo : BaseFoo{
public override void Bar()
{
}
}
You are on the right track for the creation of an interface and then defining an abstract class for your purpose.
Standard naming conventions for an interface has been broken however, interfaces are usually prefixed with an I to help identify them
public interface IRequiresAnswer
{
void LabelRequiredFieldEmpty();
bool AnswerRequired { get; }
}
I would also suggest changing the AnswerRequired property to a function as your concrete class says "do somthing to find result". Properties are usually meant to be quick, so performing any calculation within a property is masking that real work takes place when you call the property. With a function it is more apparent to callers that the result will not be achieved immediately.

How to force multiple Interfaces to include the same properties?

I am trying to figure out a way to force all of my Interfaces to include properties of the same name/type.
For example: I have two Interfaces; IGetAlarms and IGetDiagnostics. Each of the Interfaces will contain properties that are specific to the Interface itself, however I want to force the two Interfaces (and all other Interfaces that may be added later) to include properties of the same name. So, the result may look something like the this:
interface IGetAlarms
{
string GetAlarms();
DateTime LastRuntime { get; set; }
}
interface IGetDiagnostics
{
string GetDiagnostics();
DateTime LastRuntime { get; set; }
}
Notice that both Interfaces include a DateTime property named LastRuntime.
I would like to know if there is some way I can force other Interfaces that will be added later to include the DateTime LastRuntime property. I have naively attempted to have all my Interfaces implement another Interface (IService) - which includes the LastRuntime property. However, that doesn't solve my problem as that simply forces the class to implement the property - not all the Interfaces.
Thanks.
An interface can inherit from other interfaces.
interface IDerived : IBase
{
string Foo { get; set; }
}
interface IBase
{
DateTime LastRunDate { get; set; }
}
Any class deriving from IDerived will have to implement the methods/properties of IBase as well.
class Derived : IDerived
{
#region IDerived Members
public string Foo { get; set; }
#endregion
#region IBase Members
public DateTime LastRunDate {get;set;}
#endregion
}
If I understand your question correctly, you want to force a class to implement a number of different interfaces, the list of interfaces will grow with time but will have some properties in common.
The common property part you have solved with your IService interface. Something like this, I presume
interface IService
{
DateTime LastRuntime { get; set; }
}
interface IGetAlarms : IService
{
string GetAlarms();
}
interface IGetDiagnostics : IService
{
string GetDiagnostics();
}
The growing list of interfaces that a class will have to implement you can also solve in a similar fashion. Create a "composite" interface which inherits from all the interfaces you wish your class to implement
interface IComposite : IGetAlarms, IGetDiagnostics {}
class MyClass : IComposite
{
...
}
When you let the IComposite interface inherit a new interface, the class will have implement the new interface too.
EDIT
In response to your clarification; in that case you should not share the specification of the LastRuntime property, but declare it in each individual interface. In the implementing class you can use Explicit interface member implementation
class MyClass : IComposite
{
DateTime IGetAlarms.LastRuntime { get; set; }
DateTime IGetDiagnostics.LastRuntime { get; set; }
...
}
However, AFAIK it is not possible to force the implementing class to explicitly implement each individual interface
It really depends on exactly what you need the interface for. You can use generics to enforce the implementation of a specified pattern, but you can't enforce the implementation of each individually if they all have identical signatures.
public interface IA<T> where T: class
{
void DoIt(T ignore = null);
}
public interface IB : IA<IB>
{
}
public interface IC : IA<IC>
{
}
That would force the following class to implement each separately:
public class D : IB, IC
{
public void DoIt(IB ignore = null) { }
public void DoIt(IC ignore = null) { }
}
It's the "T ignore" parameter that forces each one to be implemented separately, and since it has a default value, you can just ignore that parameter unless calling it using reflection.
But obviously this doesn't work with properties, so they would have to be implemented using getter/setter methods.

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