I want to change the radiobutton location and make it move up while i am clicking button
tried this
private void up_MouseDown(object sender, MouseEventArgs e)
{
while(P.Location.Y>0)
P.Location = new System.Drawing.Point(P.Location.X, P.Location.Y - 1);
}
P is a radiobutton
I want it to keep moving up while I'm pressing, but it's just jumping up to the up of the form.
it's working good in debugging but it's really moving fast
I want to slow the movement of the radiobutton and make it visible
Actually you are starting a while loop that will not exit until your RadioButton is at the top of your Form wether you are still pressing the Button or not. You can slow it down by putting a Thread.Sleep in your loop that way it is slowed down visible.
private void up_MouseDown(object sender, MouseEventArgs e)
{
while (P.Location.Y > 0)
{
P.Location = new System.Drawing.Point(P.Location.X, P.Location.Y - 1);
System.Threading.Thread.Sleep(10);
}
}
If you want to have better control I would use a Timer. In this example the Interval is set to 10.
private void up_MouseDown(object sender, MouseEventArgs e)
{
timer1.Start();
}
private void up_MouseUp(object sender, MouseEventArgs e)
{
timer1.Stop();
}
private void timer1_Tick(object sender, EventArgs e)
{
if (P.Location.Y > 0)
{
P.Location = new System.Drawing.Point(P.Location.X, P.Location.Y - 1);
}
}
You can use timer. Add a timer from the toolbox, say its name was timer1, then add following method:
private void P_MouseUp(object sender, MouseEventArgs e) {
timer1.Enabled=false;
}
private void P_MouseDown(object sender, MouseEventArgs e) {
timer1.Enabled=true;
}
private void timer1_Tick(object sender, EventArgs e) {
if(P.Location.Y>0)
P.Location=new System.Drawing.Point(P.Location.X, P.Location.Y-1);
}
You can change the interval of timer1 in properties window. I guess you write this for fun; so, have fun!
Related
private void Form1_Load(object sender, EventArgs e)
{
if (MouseMove == button1;)
{
button1.Size= 100;70;
}
}
}
}
I couldn't find how to write code
Use the MouseEnter event to capture the mouse cursor hovering over the button borders,
and the MouseLeave event to detect when the cursor leaves the button borders, in order to return it to its original size.
Here is one way to implement such functionality:
private Size OriginalButtonSize;
private Size HoveredSize;
private void Form1_Load(object sender, EventArgs e)
{
OriginalButtonSize = this.button1.Size;
HoveredSize = new Size(OriginalButtonSize.Width + 30, OriginalButtonSize.Height + 30);
}
private void button1_MouseEnter(object sender, EventArgs e)
{
button1.Size = HoveredSize;
}
private void button1_MouseLeave(object sender, EventArgs e)
{
button1.Size = OriginalButtonSize;
}
Output:
You can use this code:
private void button1_MouseHover(object sender, EventArgs e)
{
button1.Width = 100;
button1.Height = 70;
}
if you want to set size to the previous size after leaving the mouse, you can use this (for example it was 60 and 30 at first place):
private void button1_MouseLeave(object sender, EventArgs e)
{
button1.Width = 60;
button1.Height = 30;
}
It seems like my script is not being executed. I created my own exit button, pressed on "view code" and added this line:
public void leaveButton_Click ( object sender, EventArgs e )
{
this.Close();
}
I tried the same with:
Application.Exit();
I thought that it might just not work on an image (which it actually should?) so I created a button with the same function... The same result; nothing.
I ignored it for the first part and looked for some different lines to add. My borders are set to none but I still wanted it to be movable. So I added this:
private bool mouseDown;
private Point lastLocation;
private void Form1_MouseDown(object sender, MouseEventArgs e)
{
mouseDown = true;
lastLocation = e.Location;
}
private void Form1_MouseMove(object sender, MouseEventArgs e)
{
if (mouseDown)
{
this.Location = new Point(
(this.Location.X - lastLocation.X) + e.X, (this.Location.Y - lastLocation.Y) + e.Y);
this.Update();
}
}
private void Form1_MouseUp(object sender, MouseEventArgs e)
{
mouseDown = false;
}
I do not truly understand it so there might be an error in it. It does nothing.
I use this code to refresh my from it work good for one time after that the timer stopped with me
private void Button1_Click(object sender, EventArgs e)
{
System.Windows.Forms.Timer timer1 = new System.Windows.Forms.Timer();
timer1.Interval = 900000;//5 minutes
timer1.Tick += new System.EventHandler(Timer1_Tick);
timer1.Start();
}
private void Timer1_Tick(object sender, EventArgs e)
{
//do whatever you want
RefreshMyForm();
}
private void RefreshMyForm()
{
this.Hide();
Graph1 graph = new Graph1();
graph.Show();
}
i don't know what i miss in this code
it hide the from and didn't open again
start refresh that what i looking form
You need to move the timer deceleration out of the button click and make it "global" to the class. Also, set it up on the Form_Load (make sure you wire up the Form_Load method to your Form_Load event.
Also, your hide logic is a bit faulty. You hide the form, then create a graph (but don't attach it to the Form) then show it. Added some comments below to help you navigate these issues.
private System.Windows.Forms.Timer timer1;
private void Form_Load(object sender, EventArgs e)
{
timer1 = new System.Windows.Forms.Timer();
timer1.Interval = 900000;//5 minutes
timer1.Tick += new System.EventHandler(Timer1_Tick);
}
private void Button1_Click(object sender, EventArgs e)
{
if (!timer1.Enabled)
timer1.Start();
}
private void Timer1_Tick(object sender, EventArgs e)
{
//do whatever you want
RefreshMyForm();
}
private void RefreshMyForm()
{
// Do your data update logic here
this.Refresh();
}
I have an PictureBox that I want to move up on the y axis after a button click. The problem is that the PictureBox simply appears there after the button click. I want it to move to the new position, not teleport. What do I do?
public partial class Form1 : Form
{
Point stageplus1 = new Point(164, 325);
public Form1()
{
InitializeComponent();
}
private void button2_Click(object sender, EventArgs e)
{
pictureBox5.Location = stageplus1;
}
private void pictureBox5_Click(object sender, EventArgs e)
{
}
}
Expanding on BJ Myers comment this is how you can implement that:
private void button2_Click(object sender, EventArgs e)
{
this.timer1.Enabled = true;
}
private void timer1_Tick(object sender, EventArgs e)
{
// calculate new position
this.pictureBox1.Top++;
this.pictureBox1.Left++;
// when to stop
if (this.pictureBox1.Top > (this.Height - (2 * this.pictureBox1.Height)))
{
this.timer1.Enabled = false;
}
}
I used the default Timer control that raises a Tick at an interval. The Tick event gets executed on the UI thread so you don't have to be bothered by cross thread errors.
If added to your form this is what you'll get:
If you need to animate more stuff you might want to look into using a Background worker and helper classes like I show in this answer of mine
Is this possible to display button on Windows Form only when focus is on specific textbox?
Tried that with this approach:
private void button3_Click(object sender, EventArgs e)
{
MessageBox.Show("OK");
}
private void textBox2_Enter(object sender, EventArgs e)
{
button3.Visible = true;
}
private void textBox2_Leave(object sender, EventArgs e)
{
button3.Visible = false;
}
No luck, because button click does not work then, because button is hidden immediately after textbox lost focus, preventing it from firing button3_Click(/*...*/) { /*...*/ } event.
Now I'm doing it like that:
private void button3_Click(object sender, EventArgs e)
{
MessageBox.Show("OK");
}
private void textBox2_Enter(object sender, EventArgs e)
{
button3.Visible = true;
}
private void textBox2_Leave(object sender, EventArgs e)
{
//button3.Visible = false;
DoAfter(() => button3.Visible = false);
}
private async void DoAfter(Action action, int seconds = 1)
{
await Task.Delay(seconds*1000);
action();
}
Form now waits for a second and only then hides button3.
Is there any better approach?
I think you want to display the button only when focus is on specific textbox or the focus is on the button.
To do this you can check the Focused property of button3 in the Leave event of textBox2 and only hide the button if the button doesn't have focus. Note that the button will get focus before the Leave event of textBox2 fires.
You will then need to hide the button in the scenario where button3 loses focus and the focus moves to somewhere other than textBox2. You can use exactly the same technique here by handling the Leave event of button3 and only hiding button3 if textBox2 does not have focus.
The following code should fit your requirements:
private void textBox2_Leave(object sender, EventArgs e)
{
if (!button3.Focused)
{
button3.Visible = false;
}
}
private void button3_Leave(object sender, EventArgs e)
{
if (!textBox2.Focused)
{
button3.Visible = false;
}
}
private void textBox2_Enter(object sender, EventArgs e)
{
button3.Visible = true;
}
private void button3_Click(object sender, EventArgs e)
{
MessageBox.Show("Button clicked");
}
Why not work with the GotFocus and LostFocus event of the TextBox?
private void textBox2_GotFocus(object sender, EventArgs e)
{
button3.Visible = true;
}
Then hide the button on the click event.
private void button3_Click(object sender, EventArgs e)
{
MessageBox.Show("OK");
button3.Visible = false;
}
How about you add a Panel and place the button and text boxes in that panel and when user MouseHovers that Panel then display the button...
This way user would be able to click on the button...
This is the event you are looking for, I think...
http://msdn.microsoft.com/en-us/library/system.windows.forms.control.mousehover(v=vs.110).aspx
UPDATE:
var textboxFocussed = false;
private void textBox2_Enter(object sender, EventArgs e)
{
textboxFocussed = true;
}
private void textBox2_Leave(object sender, EventArgs e)
{
textboxFocussed = false;
}
UPDATE 2
private void Panel_GotFocus(object sender, EventArgs e)
{
button3.Visible = textboxFocussed;
}
private void Panel_LostFocus(object sender, EventArgs e)
{
button3.Visible = false;
}
Here are the details of the Panel Events
you can add Enter event handler for all controls on form at Load. Just make sure to skip the controls on which you want to show the button.
List<string> strControlException = new List<string>();
public Form1()
{
InitializeComponent();
strControlException.Add("btnMain");
strControlException.Add("txtMain");
}
private void Form1_Load(object sender, EventArgs e)
{
for (int i = 0; i < this.Controls.Count;i++ )
{
if (!strControlException.Contains(Controls[i].Name))
{
Controls[i].Enter += new EventHandler(hideButton);
}
}
}
private void txtMain_Enter(object sender, EventArgs e)
{
btnMain.Visible = true;
}
private void hideButton(object sender, EventArgs e)
{
btnMain.Visible = false;
}
btnMain (Button you want to Manipulate) and txtMain (Which controls the vibility of the button) are the controls in contention here
Add more controls on the form to test.
Explanation for the above code :
First initialize a list with the names of controls that should show the Button
On Form Load add an Event handler to all controls (except the one in our list)
In the handler function hide the button. (You might want to perform more logic here based on the control that called this function)
Button is hidden by default and only on textbox Enter event we show the button.