I need to be able to grab specific elements out of a string that start and end with curly brackets. If I had a string:
"asjfaieprnv{1}oiuwehern{0}oaiwefn"
How could I grab just the 1 followed by the 0.
Regex is very useful for this.
What you want to match is:
\{ # a curly bracket
# - we need to escape this with \ as it is a special character in regex
[^}] # then anything that is not a curly bracket
# - this is a 'negated character class'
+ # (at least one time)
\} # then a closing curly bracket
# - this also needs to be escaped as it is special
We can collapse this to one line:
\{[^}]+\}
Next, you can capture and extract the inner contents by surrounding the part you want to extract with parentheses to form a group:
\{([^}]+)\}
In C# you'd do:
var matches = Regex.Matches(input, #"\{([^}]+)\}");
foreach (Match match in matches)
{
var groupContents = match.Groups[1].Value;
}
Group 0 is the whole match (in this case including the { and }), group 1 the first parenthesized part, and so on.
A full example:
var input = "asjfaieprnv{1}oiuwehern{0}oaiwef";
var matches = Regex.Matches(input, #"\{([^}]+)\}");
foreach (Match match in matches)
{
var groupContents = match.Groups[1].Value;
Console.WriteLine(groupContents);
}
Outputs:
1
0
Use the Indexof method:
int openBracePos = yourstring.Indexof ("{");
int closeBracePos = yourstring.Indexof ("}");
string stringIWant = yourstring.Substring(openBracePos, yourstring.Len() - closeBracePos + 1);
That will get your first occurrence. You need to slice your string so that the first occurrence is no longer there, then repeat the above procedure to find your 2nd occurrence:
yourstring = yourstring.Substring(closeBracePos + 1);
Note: You MAY need to escape the curly braces: "{" - not sure about this; have never dealt with them in C#
This looks like a job for regular expressions
using System.Text.RegularExpressions;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string str = "asjfaieprnv{1}oiuwe{}hern{0}oaiwefn";
Regex regex = new Regex(#"\{(.*?)\}");
foreach( Match match in regex.Matches(str))
{
Console.WriteLine(match.Groups[1].Value);
}
}
}
}
Related
I have string like
"Augustin Ralf (050288)"
"45 Max Müller (4563)"
"Hans (Adam) Meider (056754)"
I am searching for a regex to extract the last part in the brackets, for example this results for the strings above:
"050288"
"4563"
"056754"
I have tried with
var match = Regex.Match(string, #".*(\(\d*\))");
But I get also the brackets with the result. Is there a way to extract the strings and get it without the brackets?
Taking your requirements precisely, you are looking for
\(([^()]+)\)$
This will capture anything between the parentheses (not nested!), may it be digits or anything else and anchors them to the end of the string. If you happen to have whitespace at the end, use
\(([^()]+)\)\s*$
In C# this could be
using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = #"\(([^()]+)\)$";
string input = #"Augustin Ralf (050288)
45 Max Müller (4563)
Hans (Adam) Meider (056754)
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
See a demo on regex101.com.
please use regex - \(([^)]*)\)[^(]*$. This is working as expected. I have tested here
You can extract the number between the parantheses without worring about extracting the capturing groups with following regex.
(?<=\()\d+(?=\)$)
demo
Explanation:
(?<=\() : positive look behind for ( meaning that match will start after a ( without capturing it to the result.
\d+ : captures all digits in a row until non digit character found
(?=\)$) : positive look ahead for ) with line end meaning that match will end before a ) with line ending without capturing ) and line ending to the result.
Edit: If the number can be within parantheses that is not at the end of the line, remove $ from the regex to fix the match.
var match = Regex.Match(string, #".*\((\d*)\)");
https://regex101.com/r/Wk9asY/1
Here are three options for you.
The first one uses the simplest pattern and in addition the Trim method.
The second one uses capturing the desired value to the group and then getting it from the group.
The third one uses Lookbehind and Lookahead.
var inputs = new string[] {
"Augustin Ralf (050288)", "45 Max Müller (4563)", "Hans (Adam) Meider (056754)"
};
foreach (var input in inputs)
{
var match = Regex.Match(input, #"\(\d+\)");
Console.WriteLine(match.Value.Trim('(', ')'));
}
Console.WriteLine();
foreach (var input in inputs)
{
var match = Regex.Match(input, #"\((\d+)\)");
Console.WriteLine(match.Groups[1]);
}
Console.WriteLine();
foreach (var input in inputs)
{
var match = Regex.Match(input, #"(?<=\()\d+(?=\))");
Console.WriteLine(match.Value);
}
Console.WriteLine();
How to check the following text in C# with Regex:
key_in-get { 43243225543543543 };
or
key_in_set { password123 : 34980430943834 };
I tried to build a regular expression, but I failed after few hours.
Here is my code:
string text1 = "key_in-get { 322389238237 };";
string text2 = "key_in-set { password123 : 322389238237 };";
string pattern = "key_in-(get|set) { .* };";
var result1 = Regex.IsMatch(text, pattern);
Console.Write("Is valid: {0} ", result1);
var result2 = Regex.IsMatch(text, pattern);
Console.Write("Is valid: {0} ", result2);
I have to check if there is "set" or "get".
If the pattern finds "set" then it can only accept following pattern "text123 : 123456789", and if it finds "get" then should accept only "123456789".
You can use
key_in-(?:get|(set)) {(?(1) \w+ :) \w+ };
key_in-(?:get|(set))\s*{(?(1)\s*\w+\s*:)\s*\w+\s*};
key_in-(?:get|(set))\s*{(?(1)\s*\w+\s*:)\s*\d+\s*};
See the regex demo. The second one allows any amount of any whitespace between the elements and the third one allows only digits after : or as part of the get expression.
If the whole string must match, add ^ at the start and $ at the end of the pattern.
Details:
key_in- - a substring
(?:get|(set)) - get or set (the latter is captured into Group 1)
\s* - zero or more whitespaces
{ - a { char
(?(1)\s*\w+\s*:) - a conditional construct: if Group 1 matched, match one or more word chars enclosed with zero or more whitespaces and then a colon
\s*\w+\s* - one or more word chars enclosed with zero or more whitespaces
}; - a literal substring.
In the pattern that you tried key_in-(get|set) { .* }; you are matching either get or set followed by { until the last occurrence of } which could possibly also match key_in-get { }; };
As an alternative solution, you could use an alternation | specifying each of the accepted parts for the get and the set.
key_in-(?:get\s*{\s*\w+|set\s*{\s*\w+\s*:\s*\w+)\s*};
The pattern matches
key_in- Match literally
(?: Non capture group
get\s*{\s*\w+ Match get, { between optional whitespace chars and 1+ word chars
| Or
set\s*{\s*\w+\s*:\s*\w+ Match set, { between optional whitespace chars and word chars on either side with : in between.
) Close non capture group
\s*}; Match optional whitespace chars and };
Regex demo
I'm trying to define a regular expression for the Split function in order to obtain all substring split by a whitespace omitting those whitespaces that are into single quotation marks.
Example:
key1:value1 key2:'value2 value3'
i Need these separated values:
key1:value1
key2:'value2 value3'
I'm tried to perform this in different ways:
Regex.Split(q, #"(\s)^('\s')").ToList();
Regex.Split(q, #"(\s)(^'.\s.')").ToList();
Regex.Split(q, #"(?=.*\s)").ToList();
What i am wrong with this code?
Could you please help me with this?
Thanks in advance
A working example:
(\w+):(?:(\w+)|'([^']+)')
(\w+) # key: 1 or more word chars (captured)
: # literal
(?: # non-captured grouped alternatives
(\w+) # value: 1 or more word chars (captured)
| # or
'([^']+)' # 1 or more not "'" enclosed by "'" (captured)
) # end of group
Demo
Your try:
(\s)^('\s')
^ means beginning of line, \s is a white-space characters. If you want to use the not-operator, this only works in a character class [^\s] -> 1 character not a white-space.
var st = "key1:value1 key2:'value2 value3'";
var result = Regex.Matches(st, #"\w+:\w+|\w+:\'[^']+\'");
foreach (var item in result)
Console.WriteLine(item);
The result should be:
key1:value1
key2:'value2 value3'
Try following :
static void Main(string[] args)
{
string input = "key1:value1 key2:'value2 value3'";
string pattern = #"\s*(?'key'[^:]+):((?'value'[^'][^\s]+)|'(?'value'[^']+))";
MatchCollection matches = Regex.Matches(input, pattern);
foreach (Match match in matches)
{
Console.WriteLine("Key : '{0}', Value : '{1}'", match.Groups["key"].Value, match.Groups["value"].Value);
}
Console.ReadLine();
}
I'm looking for a way to search a string for everything before a set of characters in C#. For Example, if this is my string value:
This is is a test.... 12345
I want build a new string with all of the characters before "12345".
So my new string would equal "This is is a test.... "
Is there a way to do this?
I've found Regex examples where you can focus on one character but not a sequence of characters.
You don't need to use a Regex:
public string GetBitBefore(string text, string end)
{
var index = text.IndexOf(end);
if (index == -1) return text;
return text.Substring(0, index);
}
You can use a lazy quantifier to match anything, followed by a lookahead:
var match = Regex.Match("This is is a test.... 12345", #".*?(?=\d{5})");
where:
.*? lazily matches everything (up to the lookahead)
(?=…) is a positive lookahead: the pattern must be matched, but is not included in the result
\d{5} matches exactly five digits. I'm assuming this is your lookahead; you can replace it
You can do so with help of regex lookahead.
.*(?=12345)
Example:
var data = "This is is a test.... 12345";
var rxStr = ".*(?=12345)";
var rx = new System.Text.RegularExpressions.Regex (rxStr,
System.Text.RegularExpressions.RegexOptions.IgnoreCase);
var match = rx.Match(data);
if (match.Success) {
Console.WriteLine (match.Value);
}
Above code snippet will print every thing upto 12345:
This is is a test....
For more detail about see regex positive lookahead
This should get you started:
var reg = new Regex("^(.+)12345$");
var match = reg.Match("This is is a test.... 12345");
var group = match.Groups[1]; // This is is a test....
Of course you'd want to do some additional validation, but this is the basic idea.
^ means start of string
$ means end of string
The asterisk tells the engine to attempt to match the preceding token zero or more times. The plus tells the engine to attempt to match the preceding token once or more
{min,max} indicate the minimum/maximum number of matches.
\d matches a single character that is a digit, \w matches a "word character" (alphanumeric characters plus underscore), and \s matches a whitespace character (includes tabs and line breaks).
[^a] means not so exclude a
The dot matches a single character, except line break characters
In your case there many way to accomplish the task.
Eg excluding digit: ^[^\d]*
If you know the set of characters and they are not only digit, don't use regex but IndexOf(). If you know the separator between first and second part as "..." you can use Split()
Take a look at this snippet:
class Program
{
static void Main(string[] args)
{
string input = "This is is a test.... 12345";
// Here we call Regex.Match.
MatchCollection matches = Regex.Matches(input, #"(?<MySentence>(\w+\s*)*)(?<MyNumberPart>\d*)");
foreach (Match item in matches)
{
Console.WriteLine(item.Groups["MySentence"]);
Console.WriteLine("******");
Console.WriteLine(item.Groups["MyNumberPart"]);
}
Console.ReadKey();
}
}
You could just split, not as optimal as the indexOf solution
string value = "oiasjdoiasj12345";
string end = "12345";
string result = value.Split(new string[] { end }, StringSplitOptions.None)[0] //Take first part of the result, not the quickest but fairly simple
I need to match the following strings and returns the values as groups:
abctic
abctac
xyztic
xyztac
ghhtic
ghhtac
Pattern is wrote with grouping is as follows:
(?<arch>[abc,xyz,ghh])(?<flavor>[tic,tac]$)
The above returns only parts of group names. (meaning match is not correct).
If I use * in each sub pattern instead of $ at the end, groups are correct, but that would mean that abcticff will also match.
Please let me know what my correct regex should be.
Your pattern is incorrect because a pipe symbol | is used to specify alternate matches, not a comma in brackets as you were using, i.e., [x,y].
Your pattern should be: ^(?<arch>abc|xyz|ghh)(?<flavor>tic|tac)$
The ^ and $ metacharacters ensures the string matches from start to end. If you need to match text in a larger string you could replace them with \b to match on a word boundary.
Try this approach:
string[] inputs = { "abctic", "abctac", "xyztic", "xyztac", "ghhtic", "ghhtac" };
string pattern = #"^(?<arch>abc|xyz|ghh)(?<flavor>tic|tac)$";
foreach (var input in inputs)
{
var match = Regex.Match(input, pattern);
if (match.Success)
{
Console.WriteLine("Arch: {0} - Flavor: {1}",
match.Groups["arch"].Value,
match.Groups["flavor"].Value);
}
else
Console.WriteLine("No match for: " + input);
}