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Icomparer c# List

I have a list of image name like this {"1.jpg", "10.jpg", "2.jpg"}.
I would like to sort like this {"1.jpg", "2.jpg", "10.jpg"}.
I created this comparer. That means if x or y == "DSC_10.jpg", so if list is {"DSC_1.jpg", "DSC_10.jpg", "DSC_2.jpg", ...} don't sort and keep the list.
var comparer = new CompareImageName();
imageUrls.Sort(comparer);
return imageUrls;
public class CompareImageName : IComparer<string>
{
public int Compare(string x, string y)
{
if (x == null || y == null) return 0;
var l = x.Split('/');
var l1 = y.Split('/');
int a, b;
var rs = int.TryParse(l[l.Length - 1].Split('.')[0], out a);
var rs2 = int.TryParse(l1[l1.Length - 1].Split('.')[0], out b);
if (!rs || !rs2) return 0;
if (a == b || a == 0 && b == 0) return 0;
return a > b ? 1 : -1;
}
}
This sort correctly with name {"1.jpg", "10.jpg", "2.jpg"}, but incorrectly if list is {"DSC_1.jpg", "DSC_10.jpg", "DSC_2.jpg", ...}.
I read in MSDN:
What wrong with my code?

I think you're better off doing a bit of Regex for this. Try this solution:
public class CompareImageName : IComparer<string>
{
public int Compare(string x, string y)
{
if (x == null || y == null) return 0;
var regex = new Regex(#"/(((?<prefix>\w*)_)|)((?<number>\d+))\.jpg$");
var mx = regex.Match(x);
var my = regex.Match(y);
var r = mx.Groups["prefix"].Value.CompareTo(my.Groups["prefix"].Value);
if (r == 0)
{
r = int.Parse(mx.Groups["number"].Value).CompareTo(int.Parse(my.Groups["number"].Value));
}
return r;
}
}
Apart from the Regex string itself this is easier to follow the logic.

Here is your solution check this example, following class will do the comparison
public class NumericCompare : IComparer<string>
{
public int Compare(string x, string y)
{
int input1,input2;
input1=int.Parse(x.Substring(x.IndexOf('_')+1).Split('.')[0]);
input2= int.Parse(y.Substring(y.IndexOf('_')+1).Split('.')[0]);
return Comparer<int>.Default.Compare(input1,input2);
}
}
You can make use of this class like the following:
var imageUrls = new List<string>() { "DSC_1.jpg", "DSC_10.jpg", "DSC_2.jpg" };
var comparer = new NumericCompare();
imageUrls.Sort(comparer);
Console.WriteLine(String.Join("\n",imageUrls));
Try this with simple OrderBy
var SortedList = imageUrls.OrderBy(
x=>int.Parse(
x.Substring(x.IndexOf('_')+1).Split('.')[0])
).ToList();

Basically what you want to do is sort by the numeric part within the string. You are almost there. You just have to handle the part when you split a case like this DSC_2.jpg using a . then the first part is not all digits. So you need to get digits and then compare those. Here is the code. Please note I have made the assumption you will have backslash and if that is not the case then please handle it:
public int Compare(string x, string y)
{
if (x == null || y == null) return 0;
var nameX = x.Substring(x.LastIndexOf('/'));
var nameY = y.Substring(y.LastIndexOf('/'));
var nameXParts = nameX.Split('.');
var nameYParts = nameY.Split('.');
int a, b;
var rs = int.TryParse(nameXParts[0], out a);
var rs2 = int.TryParse(nameYParts[0], out b);
var nameXDigits = string.Empty;
if (!rs)
{
for (int i = 0; i < nameXParts[0].Length; i++)
{
if (Char.IsDigit(nameXParts[0][i]))
nameXDigits += nameXParts[0][i];
}
}
var nameYDigits = string.Empty;
if (!rs2)
{
for (int i = 0; i < nameYParts[0].Length; i++)
{
if (Char.IsDigit(nameYParts[0][i]))
nameYDigits += nameYParts[0][i];
}
}
int.TryParse(nameXDigits, out a);
int.TryParse(nameYDigits, out b);
if (a == b || a == 0 && b == 0) return 0;
return a > b ? 1 : -1;
}

Don't use imageUrls.Sort(comparer); on List because it doesn't accept 0 value as keeping the order of elements.
Reason:
The Sort performs an unstable sort; that is, if two elements are equal, their order might not be preserved. In contrast, a stable sort preserves the order of elements that are equal.
Link: https://msdn.microsoft.com/en-gb/library/w56d4y5z.aspx
Solution: Let's try to use OrderBy with your compare
var imageUrls1 = new List<string>() { "1.jpg", "10.jpg", "2.jpg" };
var imageUrls2 = new List<string>() { "DSC_1.jpg", "DSC_10.jpg", "DSC_2.jpg" };
var comparer = new CompareImageName();
//Sort normally
imageUrls1 = imageUrls1.OrderBy(p=>p, comparer).ToList();
//Keep the order as your expectation
imageUrls2 = imageUrls2.OrderBy(p=>p, comparer).ToList();

Maybe you can try doing this in a function instead of writing a comparator. I can't think of a good way to implement this logic as a comparator since there are different rules based on the contents (don't sort if the file name is not numeric).
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
namespace sortinglists
{
public class MainProgram
{
public static void Main()
{
var imageUrlsNumbers = new List<string>();
imageUrlsNumbers.Add("c:/a/b/1.jpg");
imageUrlsNumbers.Add("c:/a/b/10.jpg");
imageUrlsNumbers.Add("c:/a/b/2.jpg");
CustomSort(ref imageUrlsNumbers);
foreach (var imageUrl in imageUrlsNumbers)
{
Console.WriteLine(imageUrl);
}
var imageUrlsText = new List<string>();
imageUrlsText.Add("c:/a/b/DSC_1.jpg");
imageUrlsText.Add("c:/a/b/DSC_10.jpg");
imageUrlsText.Add("c:/a/b/DSC_2.jpg");
CustomSort(ref imageUrlsText);
foreach (var imageUrl in imageUrlsText)
{
Console.WriteLine(imageUrl);
}
}
public static void CustomSort(ref List<string> imageUrls)
{
if (imageUrls
.Select(s => s.Substring(s.LastIndexOf("/", StringComparison.OrdinalIgnoreCase) + 1))
.Select(t => t.Substring(0, t.IndexOf(".", StringComparison.OrdinalIgnoreCase)))
.Where(u => new Regex("[A-Za-z_]").Match(u).Success)
.Any())
{
imageUrls = imageUrls
.Select(x => x.Substring(x.LastIndexOf("/", StringComparison.OrdinalIgnoreCase) + 1))
.ToList();
}
else
{
imageUrls = imageUrls
.Select(v => v.Substring(v.LastIndexOf("/", StringComparison.OrdinalIgnoreCase) + 1))
.OrderBy(w => Convert.ToInt32(w.Substring(0, w.LastIndexOf(".", StringComparison.OrdinalIgnoreCase))))
.ToList();
}
}
}
}
The output for imageUrlsNumbers after sorting is:
1.jpg
2.jpg
10.jpg
And the output for imageUrlsText after sorting is:
DSC_1.jpg
DSC_10.jpg
DSC_2.jpg

Create a list of all permutation from different lists [duplicate]

This one should not be too hard but my mind seems to be having a stack overflow (huehue). I have a series of Lists and I want to find all permutations they can be ordered in. All of the lists have different lengths.
For example:
List 1: 1
List 2: 1, 2
All permutations would be:
1, 1
1, 2
In my case I don't switch the numbers around. (For example 2, 1)
What is the easiest way to write this?

I can't say if the following is the easiest way, but IMO it's the most efficient way. It's basically a generalized version of the my answer to the Looking at each combination in jagged array:
public static class Algorithms
{
public static IEnumerable<T[]> GenerateCombinations<T>(this IReadOnlyList<IReadOnlyList<T>> input)
{
var result = new T[input.Count];
var indices = new int[input.Count];
for (int pos = 0, index = 0; ;)
{
for (; pos < result.Length; pos++, index = 0)
{
indices[pos] = index;
result[pos] = input[pos][index];
}
yield return result;
do
{
if (pos == 0) yield break;
index = indices[--pos] + 1;
}
while (index >= input[pos].Count);
}
}
}
You can see the explanation in the linked answer (shortly it's emulating nested loops). Also since for performace reasons it yields the internal buffer w/o cloning it, you need to clone it if you want store the result for later processing.
Sample usage:
var list1 = new List<int> { 1 };
var list2 = new List<int> { 1, 2 };
var lists = new[] { list1, list2 };
// Non caching usage
foreach (var combination in lists.GenerateCombinations())
{
// do something with the combination
}
// Caching usage
var combinations = lists.GenerateCombinations().Select(c => c.ToList()).ToList();
UPDATE: The GenerateCombinations is a standard C# iterator method, and the implementation basically emulates N nested loops (where N is the input.Count) like this (in pseudo code):
for (int i0 = 0; i0 < input[0].Count; i0++)
for (int i1 = 0; i1 < input[1].Count; i1++)
for (int i2 = 0; i2 < input[2].Count; i2++)
...
for (int iN-1 = 0; iN-1 < input[N-1].Count; iN-1++)
yield { input[0][i0], input[1][i1], input[2][i2], ..., input[N-1][iN-1] }
or showing it differently:
for (indices[0] = 0; indices[0] < input[0].Count; indices[0]++)
{
result[0] = input[0][indices[0]];
for (indices[1] = 0; indices[1] < input[1].Count; indices[1]++)
{
result[1] = input[1][indices[1]];
// ...
for (indices[N-1] = 0; indices[N-1] < input[N-1].Count; indices[N-1]++)
{
result[N-1] = input[N-1][indices[N-1]];
yield return result;
}
}
}

Nested loops:
List<int> listA = (whatever), listB = (whatever);
var answers = new List<Tuple<int,int>>;
for(int a in listA)
for(int b in listB)
answers.add(Tuple.create(a,b));
// do whatever with answers

Try this:
Func<IEnumerable<string>, IEnumerable<string>> combine = null;
combine = xs =>
xs.Skip(1).Any()
? xs.First().SelectMany(x => combine(xs.Skip(1)), (x, y) => String.Format("{0}{1}", x, y))
: xs.First().Select(x => x.ToString());
var strings = new [] { "AB", "12", "$%" };
foreach (var x in combine(strings))
{
Console.WriteLine(x);
}
That gives me:
A1$
A1%
A2$
A2%
B1$
B1%
B2$
B2%

I made the following IEnumerable<IEnumerable<TValue>> class to solve this problem which allows use of generic IEnumerable's and whose enumerator returns all permutations of the values, one from each inner list. It can be conventiently used directly in a foreach loop.
It's a variant of Michael Liu's answer to IEnumerable and Recursion using yield return
I've modified it to return lists with the permutations instead of the single values.
using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
namespace Permutation
{
public class ListOfListsPermuter<TValue> : IEnumerable<IEnumerable<TValue>>
{
private int count;
private IEnumerable<TValue>[] listOfLists;
public ListOfListsPermuter(IEnumerable<IEnumerable<TValue>> listOfLists_)
{
if (object.ReferenceEquals(listOfLists_, null))
{
throw new ArgumentNullException(nameof(listOfLists_));
}
listOfLists =listOfLists_.ToArray();
count = listOfLists.Count();
for (int i = 0; i < count; i++)
{
if (object.ReferenceEquals(listOfLists[i], null))
{
throw new NullReferenceException(string.Format("{0}[{1}] is null.", nameof(listOfLists_), i));
}
}
}
// A variant of Michael Liu's answer in StackOverflow
// https://stackoverflow.com/questions/2055927/ienumerable-and-recursion-using-yield-return
public IEnumerator<IEnumerable<TValue>> GetEnumerator()
{
TValue[] currentList = new TValue[count];
int level = 0;
var enumerators = new Stack<IEnumerator<TValue>>();
IEnumerator<TValue> enumerator = listOfLists[level].GetEnumerator();
try
{
while (true)
{
if (enumerator.MoveNext())
{
currentList[level] = enumerator.Current;
level++;
if (level >= count)
{
level--;
yield return currentList;
}
else
{
enumerators.Push(enumerator);
enumerator = listOfLists[level].GetEnumerator();
}
}
else
{
if (level == 0)
{
yield break;
}
else
{
enumerator.Dispose();
enumerator = enumerators.Pop();
level--;
}
}
}
}
finally
{
// Clean up in case of an exception.
enumerator?.Dispose();
while (enumerators.Count > 0)
{
enumerator = enumerators.Pop();
enumerator.Dispose();
}
}
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
}
You can use it directly in a foreach like this:
public static void Main(string[] args)
{
var listOfLists = new List<List<string>>()
{
{ new List<string>() { "A", "B" } },
{ new List<string>() { "C", "D" } }
};
var permuter = new ListOfListsPermuter<string>(listOfLists);
foreach (IEnumerable<string> item in permuter)
{
Console.WriteLine("{ \"" + string.Join("\", \"", item) + "\" }");
}
}
The output:
{ "A", "C" }
{ "A", "D" }
{ "B", "C" }
{ "B", "D" }

Sort Array on on Value Difference

I Have An Array,for example
string[] stArr= new string[5] { "1#3", "19#24", "10#12", "13#18", "20#21" };
i want to sort this array on
3-1=2;
24-19=5;
12-10=2;
18-13=5;
21-20=1;
and the sorting result should be like
string[] stArr= new string[5] { "20#21", "1#3", "10#12", "13#18", "20#21" };
I have to find the solution for all possible cases.
1>length of the array is not fixed(element in the array)
2>y always greater than x e.g x#y
3> i can not use list

You can use LINQ:
var sorted = stArr.OrderBy(s => s.Split('#')
.Select(n => Int32.Parse(n))
.Reverse()
.Aggregate((first,second) => first - second));
For Your Case:
stArr = stArr.OrderBy(s => s.Split('#')
.Select(n => Int32.Parse(n))
.Reverse()
.Aggregate((first,second) => first - second)).ToArray();

try this
string[] stArr = new string[5] { "1#3", "19#24", "10#12", "13#18", "20#21" };
Array.Sort(stArr, new Comparison<string>(compare));
int compare(string z, string t)
{
var xarr = z.Split('#');
var yarr = t.Split('#');
var x1 = int.Parse(xarr[0]);
var y1 = int.Parse(xarr[1]);
var x2 = int.Parse(yarr[0]);
var y2 = int.Parse(yarr[1]);
return (y1 - x1).CompareTo(y2 - x2);
}

Solving this problem is identical to solving any other sorting problem where the order is to be specified by your code - you have to write a custom comparison method, and pass it to the built-in sorter.
In your situation, it means writing something like this:
private static int FindDiff(string s) {
// Split the string at #
// Parse both sides as int
// return rightSide-leftSide
}
private static int CompareDiff(string a, string b) {
return FindDiff(a).CompareTo(FindDiff(b));
}
public static void Main() {
... // Prepare your array
string[] stArr = ...
Array.Sort(stArr, CompareDiff);
}
This approach uses Array.Sort overload with the Comparison<T> delegate implemented in the CompareDiff method. The heart of the solution is the FindDiff method, which takes a string, and produces a numeric value which must be used for comparison.

you can try the following ( using traditional way)
public class Program
{
public static void Main()
{
string[] strArr= new string[5] { "1#3", "19#24", "10#12", "13#18", "20#21" };
var list = new List<Item>();
foreach(var item in strArr){
list.Add(new Item(item));
}
strArr = list.OrderBy(t=>t.Sort).Select(t=>t.Value).ToArray();
foreach(var item in strArr)
Console.WriteLine(item);
}
}
public class Item
{
public Item(string str)
{
var split = str.Split('#');
A = Convert.ToInt32(split[0]);
B = Convert.ToInt32(split[1]);
}
public int A{get; set;}
public int B{get; set;}
public int Sort { get { return Math.Abs(B - A);}}
public string Value { get { return string.Format("{0}#{1}",B,A); }}
}
here a working demo
hope it will help you

Without LINQ and Lists :) Old School.
static void Sort(string [] strArray)
{
try
{
string[] order = new string[strArray.Length];
string[] sortedarray = new string[strArray.Length];
for (int i = 0; i < strArray.Length; i++)
{
string[] values = strArray[i].ToString().Split('#');
int index=int.Parse(values[1].ToString()) - int.Parse(values[0].ToString());
order[i] = strArray[i].ToString() + "," + index;
}
for (int i = 0; i < order.Length; i++)
{
string[] values2 = order[i].ToString().Split(',');
if (sortedarray[int.Parse(values2[1].ToString())-1] == null)
{
sortedarray[int.Parse(values2[1].ToString())-1] = values2[0].ToString();
}
else
{
if ((int.Parse(values2[1].ToString())) >= sortedarray.Length)
{
sortedarray[(int.Parse(values2[1].ToString())-1) - 1] = values2[0].ToString();
}
else if ((int.Parse(values2[1].ToString())) < sortedarray.Length)
{
sortedarray[(int.Parse(values2[1].ToString())-1) + 1] = values2[0].ToString();
}
}
}
for (int i = 0; i < sortedarray.Length; i++)
{
Console.WriteLine(sortedarray[i]);
}
Console.Read();
}
catch (Exception ex)
{
throw;
}
finally
{
}

Query for values

Declarations and entries in two_Dict dictionary is created as given:
Dictionary<string, List<string>>two_Dict = new Dictionary<string, List<string>>();
List<string> list;
if (!two_Dict.TryGetValue(d.ToString(), out list))
{
two_Dict.Add( d.ToString(), list = new List<string>());
list.Add(possibility_cell_list[0]);
list.Add(possibility_cell_list[1]);
}
Sample entries in two_Dict:
two_Dict["5"] Count = 2 [0]: "A2" [1]: "D2"
two_Dict["6"] Count = 2 [0]: "A2" [1]: "D2"
I am looking to form a linq query to get the keys which have the same list entries in the dictionary two_Dict. Any help will be appreciated.

You can use a fairly simple expression with linq:
var keys = from kvp1 in two_dict
where two_dict.Any(kvp2 => kvp2.Key != kvp1.Key
&& kvp2.Value.SequenceEqual(kvp1.Value))
select kvp1.Key;
However, this does not give the best performance as it will search through the entire dictionary n times, where n is the number of entries in the dictionary.
You can get slightly better performance if you only look at the items that have already been looked at so far. This way, on average you only go through half of the dictionary n times, so it's theoretically twice as fast. Unfortunately, I don't think there is a good way to do this purely using linq.
public static IEnumerable GetDuplicates(IDictionary<string, List<string>> dict)
{
var previousItems = new List<KeyValuePair<string, List<string>>>(dict.Count);
var matchedItems = new List<bool>();
foreach (var kvp in dict)
{
var match = previousItems.Select((kvp2, i) => Tuple.Create(kvp2.Key, kvp2.Value, i)).FirstOrDefault(t => kvp.Value.SequenceEqual(t.Item2));
if (match != null)
{
var index = match.Item3;
if (!matchedItems[index])
{
yield return match.Item1;
matchedItems[index] = true;
}
yield return kvp.Key;
}
else
{
previousItems.Add(kvp);
matchedItems.Add(false);
}
}
}
You would call the function like this:
var keys = GetDuplicates(two_dict);

All linq, no duplicate result but also, be careful, no null checks:
var res = from k1 in dict.Keys
from k2 in dict.Keys
where string.Compare(k1, k2) == -1 &&
dict[k1].Count == dict[k2].Count && !dict[k1].Any(x => !dict[k2].Contains(x)) && !dict[k2].Any(x => !dict[k1].Contains(x))
select new { k1, k2 };

How about this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
Dictionary<string, List<string>> two_Dict = new Dictionary<string, List<string>>();
var keyIndex = two_Dict.Keys.AsEnumerable()
.Select((x, i) => new { index = i, value = x })
.ToList();
var result = (from key1 in keyIndex
from key2 in keyIndex
where key1.index > key2.index
where AreEqual(two_Dict[key1.value],two_Dict[key2.value])
select new {key1 = key1.value, key2 = key2.value}).ToList();
}
static bool AreEqual<T>(List<T> x, List<T> y)
{
// same list or both are null
if (x == y)
{
return true;
}
// one is null (but not the other)
if (x == null || y == null)
{
return false;
}
// count differs; they are not equal
if (x.Count != y.Count)
{
return false;
}
x.Sort();
y.Sort();
for (int i = 0; i < x.Count; i++)
{
if (!x[i].Equals(y[i]))
{
return false;
}
}
return true;
}
}
}
​

string sorting in C#

I have an array of strings like the following:
"access"
"Addition"
"account"
"base"
"Brick"
"zammer"
"Zilon"
I want them to sort them witht the following rules"
Capital letters for a given character should come first.
The capital and small letters should be sorted in their own groups.
Thus, the output should be:
"Addition"
"access"
"account"
"Brick"
"base"
"Zilon"
"zammer"
The language I am using is C# and .Net 4.0.

Proper set of OrderBy/ThenBy calls will do the trick.
Order by first letter lowercased, to get all as and As first, then bs and Bs, etc.
Then by IsLower(firstCharacter), which will get the uppercased items for each letter first.
Then by the entire string.
var sorted = source.OrderBy(s => char.ToLower(s[0]))
.ThenBy(s => char.IsLower(s[0]))
.ThenBy(s => s)
.ToList();

Try like this
List<string> list = new List<string>();
list.Add("access");
list.Add("Addition");
list.Add("account");
list.Add("base")
list.Add("Brick")
list.Add("zammer")
list.Add("Zilon")
list = list.Where(r => char.IsLower(r[0])).OrderBy(r => r)
.Concat(list.Where(r => char.IsUpper(r[0])).OrderBy(r => r)).ToList();
for (int i = 0; i < list.Count; i++)
Console.WriteLine(list[i]);

Below solution works for more than one Caps.
static void Main(string[] args)
{
var names = new List<String>() {
"access",
"Addition",
"ADDition",
"ADdition",
"account",
"base",
"Brick",
"zammer",
"Zilon"
};
names.Sort((one, two) =>
{
int result = 0;
var oneArray = one.ToCharArray();
var twoArray = two.ToCharArray();
var minLength = Math.Min(oneArray.Length, twoArray.Length) - 1;
var i = 0;
while (i < minLength)
{
//Diff Letter
if (Char.ToUpper(one[i]) != Char.ToUpper(two[i]))
{
result = Char.ToUpper(one[i]) - Char.ToUpper(two[i]);
break;
}
// Same Letter, same case
if (oneArray[i] == twoArray[i])
{
i++;
continue;
}
// Same Letter, diff case
result = one[i] - two[i];
break;
}
return result;
});
foreach (string s in names)
Console.WriteLine(s);
Console.WriteLine("done");

If you want to go beyond the first character, I should implement a comparer:
class MyComparer : IComparer<string>
{
public int Compare(string x, string y)
{
if ((x == null) && (y == null))
{
return 0;
}
if (x == null)
{
return 1;
}
if (y == null)
{
return -1;
}
var l = Math.Min(x.Length, y.Length);
for (var i = 0; i < l; i++)
{
var c = x[i];
var d = y[i];
if (c != d)
{
if (char.ToLowerInvariant(c) == char.ToLowerInvariant(d))
{
return StringComparer.Ordinal.Compare(new string(c, 1), new string(d, 1));
}
else
{
return StringComparer.OrdinalIgnoreCase.Compare(new string(c, 1), new string(d, 1));
}
}
}
return x.Length == y.Length ? 0 : x.Length > y.Length ? 1 : -1;
}
}
And then use it:
var myComparer = new MyComparer();
source.OrderBy(s => s, myComparer);