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Is there a way to reduce the number of figures of a number?
Example:
double d = 222222222222222224444444444444.0
I want to "serialize" it like 17[2]13[4] for example.
The idea is to reduce the number of "chars" used by the number.
double d = 222222222222222224444444444444.0
You can't have a double that big in the first place.
I want to "serialize" it like 17[2]13[4] for example.
The idea is to reduce the number of "chars" used by the number.
A double only takes 8 bytes regardless of its value. There doesn't seem to be any actual point to this.
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So I created an array with 100 variables using Enumerable.Range. The data type is limited to Int32.
Problem
How can I create the same array with SByte?
Am I right in thinking I would need to use a loop to create and index the variables?
I have looked around online and most results touch on declaring counting variables for the loop but not using a loop to declare variables
Just cast them:
SByte[] array = Enumerable.Range(0, 100).Select(i => (SByte) i).ToArray();
note that SByte is not cls compliant, you might want to use short instead.
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I have a method that pseudo-randomly encrypts a byte array. I would like to convert the encrypted byte-array to a C# int (4 bytes), while observing a user-specified lower and upper bound (e.g. give me a number between 1 and 10)
What is the most secure and performant way of achieving this?
You could use System.ByteConverter.ToInt32(arr, start_index).
From your description of the array, the start index would likely be zero.
I am not sure what you mean by upper and lower bound, but if you mean you want a random number, you could use a variety of functions to get a value in between the two numbers. If you have semi-uniform distribution, the modulus function would work nicely. In that case, your random number would simply be lowerBound + (System.ByteConverter.ToInt32(arr, start_index) % (upperBound - lowerBound)).
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I want to generate number as format above and I try to use UUID() and GUID() but it is not what I want(difference format and it is hexadecimal not number)
anyone have any idea or logic to do it?
The simplest way to generate 1000000000000 unique numbers is just an ever-increasing sequence:
long i = 42; // whatever
string key = $"{i / 100000000:0000}-{(i / 10000) % 10000:0000}-{i % 10000:0000}";
The next time, increase i before generating the key.
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I have decimal values in the database. I want to show the decimal value in it. How to convert decimal values into it.
int vatprice;
dt.Load(cmd.ExecuteReader());
vatprice = Convert.ToInt32(dt.Rows[0][5].ToString());//getting error here
As per your requirement, round decimal up to 2 place using following way :
1) Use Math.Round().
var vatprice= Convert.ToDecimal(Math.Round(dt.Rows[0][5], 2));
2) second way is
var vatprice=Convert.ToDecimal(dt.Rows[0][5].ToString ("#.##"));
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How to write a regular expression to scan whether input is a signed decimal or not?
e.g:
-1.234567
-.1234567
123456789
1.2345678
1234567.8
-1234.567
Input length must be 9.
Why are you using RegEx? There are better methods to determine if a string is signed or not.
Use decimal.TryParse() and Math.Sign() to get your answer.
string input = "-1.2342";
decimal decValue;
bool isDecimal = decimal.TryParse(input, out decValue);
if (isDecimal)
{
int signValue = Math.Sign(decValue);
}
else
{
throw new Exception("Not a valid decimal!");
}
You could do it the hard way:
([-\d]\d\.\d\d\d\d\d\d|[-\d]\d\d\.\d\d\d\d\d|[-\d]\d\d.\d\d\d\d|...)
Basically this is any of the forms you listed OR-ed. This is quite tedious, but right now I can't think of any other way that will work for all possible inputs.