First time asking a question on here;
I am looking for a way to be able to use a search algorithm, or a built in method to dynamically search for repeating sequences within a string, or other variable.
The reason I say dynamic, is because I want it to be able to search through the string and locate repeating sequences on its own. I am not going to be able to supply a constructor of a sequence to look for.
I am unsure if this is even possible, but if it is, all help would be appreciated!
Here is a basic visual representation of what I am looking for (mind you, this is not code, just a for instance of a string)
This is going to be a long string that will have sequences throughout it. This may have matching characters side by side or it may not, but regardless, this is going to be a long string. If this is going to be a long string, I need it to find these sequences throughout it on its own!
As you can see by the above example, there are 2 sets of matching sequences throughout the single string. If there is any way to identify these programatically, along with being able to be searched through very fast for these different patterns, it would help me significantly!
The matches will most likely be stored in a List / array for later use as well.
Thank you for any help you are able to provide!
Edit:
As this question was asked, case sensitivity will not be an issue.
When I was mentioning there were 2 matches, I meant that 2 particular sequences, had a duplicate. One of which, had 2 duplicates.
#HenkHolterman You are correct that this is going to be a compression algorithm, however, I was not sure where to start for looking for the sequences that I will be matching.
I had been doing multiple searches regarding something similar to this, but was coming up short with the answers I were looking for. That is why my question was posed here the way it was.
Thank you for all the responses I have gotten so far though!
Here's the basic brute force idea
first you find all repeating sequences of size 1(you can change the minimum size to whatever you want).
To do this, you essentially go down the line, and use a regex to find all of the Ts and then all the hs, etc...
Then you find all sequences of size 2, so you'd find all the Ths and the his and the iss
you repeat this until you have found all of the sequences.
The runtime would be
the time complexity to find a particular sequence with regex: O(n)
times the number of different sequences of a particular size: O(n)
times the number of sizes: O(n)
the total time complexity would be O(n3)
Use a suffix tree to do this in O(n) time. I am adding this extraneous sentence to keep this from being converted into a comment.
Related
I have a need to check if a list of items contains a string...so kind of like the list gets filtered as the user types in a search box. So, on the text changed event, I am checking if the entered text is contained in one of the listox items and filtering out...so
something like:
value.Contains(enteredText)
I was wondering if this is the fastest and most efficient way to filter out listbox items?
Is Contains() method the best way to search for substrings in C#?
I'd say that in all but very exceptional circumstances, it's fast and efficient enough, and even in such exceptional circumstances it's likely to be a purely academical problem. If you use it and come across any bottlenecks in your logic related to this then I'd be surprised, but only then would it be worth looking at, then chances are you'll be looking elsewhere.
Contains is one of the cheapest methods in my code completion filtering algorithm (Part 6 #6, where #7 and the fuzzy logic matching described in the footnote are vastly more expensive), which doesn't have problems keeping up with even a fast typing user and thousands of items in the dropdown.
I highly doubt it will cause you problems.
Although this is not the fastest option globally, it is the fastest one for which you do not need to code anything. It should be sufficient for filtering drop-down items.
For longer texts, you may want to go with the KMP Algorithm, which has a linear timing complexity. Note, however, that it would not make any difference for very short search strings.
For searches that have lots of matches (e.g. ones that you get for the first one to two characters) you may want to precompute a table that maps single letters and letter pairs to the rows in your drop-down list for a much faster look-up at the expense of using more memory (a pretty standard tradeoff in programming in general).
I need to compare a set of strings to another set of strings and find which strings are similar (fuzzy-string matching).
For example:
{ "A.B. Mann Incorporated", "Mr. Enrique Bellini", "Park Management Systems" }
and
{ "Park", "AB Mann Inc.", "E. Bellini" }
Assuming a zero-based index, the matches would be 0-1, 1-2, 2-0. Obviously, no algorithm can be perfect at this type of thing.
I have a working implementation of the Levenshtein-distance algorithm, but using it to find similar strings from each set necessitates looping through both sets of strings to do the comparison, resulting in an O(n^2) algorithm. This runs unacceptably slow even with modestly sized sets.
I've also tried a clustering algorithm that uses shingling and the Jaccard coefficient. Unfortunately, this too runs in O(n^2), which ends up being too slow, even with bit-level optimizations.
Does anyone know of a more efficient algorithm (faster than O(n^2)), or better yet, a library already written in C#, for accomplishing this?
Not a direct answer to the O(N^2) but a comment on the N1 algorithm.
That is sample data but it is all clean. That is not data that I would use Levenstien on. Incriminate would have closer distance to Incorporated than Inc. E. would not match well to Enrique.
Levenshtein-distance is good at catching key entry errors.
It is also good for matching OCR.
If you have clean data I would go with stemming and other custom rules.
Porter stemmer is available for C# and if you have clean data
E.G.
remove . and other punctuation
remove stop words (the)
stem
parse each list once and assign an int value for each unique stem
do the match on int
still N^2 but now N1 is faster
you might add in a single cap the matches a word that start with cap gets a partial score
also need to account for number of words
two groups of 5 that match of 3 should score higher then two groups of 10 that match on 4
I would create Int hashsets for each phrase and then intersect and count.
Not sure you can get out of N^2.
But I am suggesting you look at N1.
Lucene is a library with phrase matching but it is not really set up for batches.
Create the index with the intent it is used many time so index search speed is optimized over index creation time.
In the given examples at least one word is always matching. A possible approach could use a multimap (a dictionary being able to store multiple entries per key) or a Dictionary<TKey,List<TVlaue>>. Each string from the first set would be splitted into single words. These words would be used as key in the multimap and the whole string would be stored as value.
Now you can split strings from the second set into single words and do an O(1) lookup for each word, i.e. an O(N) lookup for all the words. This yields a first raw result, where each match contains at least one matching word. Finally you would have to refine this raw result by applying other rules (like searching for initials or abbreviated words).
This problem, called "string similarity join," has been studied a lot recently in the research community. We released a source code package in C++ called Flamingo that implements such an algorithm http://flamingo.ics.uci.edu/releases/4.1/src/partenum/. We also have a Hadoop-based implementation at http://asterix.ics.uci.edu/fuzzyjoin/ if your data set is too large for a single machine.
Okay so I'm trying to make a basic malware scanner in C# my question is say I have the Hex signature for a particular bit of code
For example
{
System.IO.File.Delete(#"C:\Users\Public\DeleteTest\test.txt");
}
//Which will have a hex of 53797374656d2e494f2e46696c652e44656c657465284022433a5c55736572735c5075626c69635c44656c657465546573745c746573742e74787422293b
Gets Changed to -
{
System.IO.File.Delete(#"C:\Users\Public\DeleteTest\notatest.txt");
}
//Which will have a hex of 53797374656d2e494f2e46696c652e44656c657465284022433a5c55736572735c5075626c69635c44656c657465546573745c6e6f7461746573742e74787422293b
Keep in mind these bits will be within the entire Hex of the program - How could I go about taking my base signature and looking for partial matches that say have a 90% match therefore gets flagged.
I would do a wildcard but that wouldn't work for slightly more complex things where it might be coded slightly different but the majority would be the same. So is there a way I can do a percent match for a substring? I was looking into the Levenshtein Distance but I don't see how I'd apply it into this given scenario.
Thanks in advance for any input
Using an edit distance would be fine. You can take two strings and calculate the edit distance, which will be an integer value denoting how many operations are needed to take one string to the other. You set your own threshold based off that number.
For example, you may statically set that if the distance is less than five edits, the change is relevant.
You could also take the length of string you are comparing and take a percentage of that. Your example is 36 characters long, so (int)(input.Length * 0.88m) would be a valid threashold.
First, your program bits should match EXACTLY or else it has been modified or is corrupt. Generally, you will store an MD5 hash on the original binary and check the MD5 against new versions to see if they are 'the same enough' (MD5 can't guarantee a 100% match).
Beyond this, in order to detect malware in a random binary, you must know what sort of patterns to look for. For example, if I know a piece of malware injects code with some binary XYZ, I will look for XYZ in the bits of the executable. Patterns get much more complex than that, of course, as the malware bits can be spread out in chuncks. What is more interesting is that some viruses are self-morphing. This means that each time it runs, it modifies itself, meaning the scanner does not know an exact pattern to find. In these cases, the scanner must know the types of derivatives can be produced and look for all of them.
In terms of finding a % match, this operation is very time consuming unless you have constraints. By comparing 2 strings, you cannot tell which pieces were removed, added, or replaced. For instance, if I have a starting string 'ABCD', is 'AABCDD' a 100% match or less since content has been added? What about 'ABCDABCD'; here it matches twice. How about 'AXBXCXD'? What about 'CDAB'?
There are many DIFF tools in existence that can tell you what pieces of a file have been changed (which can lead to a %). Unfortunately, none of them are perfect because of the issues that I described above. You will find that you have false negatives, false positives, etc. This may be 'good enough' for you.
Before you can identify a specific algorithm that will work for you, you will have to decide what the restrictions of your search will be. Otherwise, your scan will be NP-hard, which leads to unreasonable running times (your scanner may run all day just to check one file).
I suggest you look into Levenshtein distance and Damerau-Levenshtein distance.
The former tells you how many add/delete operations are needed to turn one string into another; and the latter tells you how many add/delete/replace operations are needed to turn one string into another.
I use these quite a lot when writing programs where users can search for things, but they may not know the exact spelling.
There are code examples on both articles.
This question already has answers here:
How to find the index of an element in an array in Java?
(15 answers)
Closed 6 years ago.
I was asked this question in an interview. Although the interview was for dot net position, he asked me this question in context to java, because I had mentioned java also in my resume.
How to find the index of an element having value X in an array ?
I said iterating from the first element till last and checking whether the value is X would give the result. He asked about a method involving less number of iterations, I said using binary search but that is only possible for sorted array. I tried saying using IndexOf function in the Array class. But nothing from my side answered that question.
Is there any fast way of getting the index of an element having value X in an array ?
As long as there is no knowledge about the array (is it sorted? ascending or descending? etc etc), there is no way of finding an element without inspecting each one.
Also, that is exactly what indexOf does (when using lists).
How to find the index of an element having value X in an array ?
This would be fast:
int getXIndex(int x){
myArray[0] = x;
return 0;
}
A practical way of finding it faster is by parallel processing.
Just divide the array in N parts and assign every part to a thread that iterates through the elements of its part until value is found. N should preferably be the processor's number of cores.
If a binary search isn't possible (beacuse the array isn't sorted) and you don't have some kind of advanced search index, the only way I could think of that isn't O(n) is if the item's position in the array is a function of the item itself (like, if the array is [10, 20, 30, 40], the position of an element n is (n / 10) - 1).
Maybe he wants to test your knowledge about Java.
There is Utility Class called Arrays, this class contains various methods for manipulating arrays (such as sorting and searching)
http://download.oracle.com/javase/6/docs/api/java/util/Arrays.html
In 2 lines you can have a O(n * log n) result:
Arrays.sort(list); //O(n * log n)
Arrays.binarySearch(list, 88)); //O(log n)
Puneet - in .net its:
string[] testArray = {"fred", "bill"};
var indexOffset = Array.IndexOf(testArray, "fred");
[edit] - having read the question properly now, :) an alternative in linq would be:
string[] testArray = { "cat", "dog", "banana", "orange" };
int firstItem = testArray.Select((item, index) => new
{
ItemName = item,
Position = index
}).Where(i => i.ItemName == "banana")
.First()
.Position;
this of course would find the FIRST occurence of the string. subsequent duplicates would require additional logic. but then so would a looped approach.
jim
It's a question about data structures and algorithms (altough a very simple data structure). It goes beyond the language you are using.
If the array is ordered you can get O(log n) using binary search and a modified version of it for border cases (not using always (a+b)/2 as the pivot point, but it's a pretty sophisticated quirk).
If the array is not ordered then... good luck.
He can be asking you about what methods you have in order to find an item in Java. But anyway they're not faster. They can be olny simpler to use (than a for-each - compare - return).
There's another solution that's creating an auxiliary structure to do a faster search (like a hashmap) but, OF COURSE, it's more expensive to create it and use it once than to do a simple linear search.
Take a perfectly unsorted array, just a list of numbers in memory. All the machine can do is look at individual numbers in memory, and check if they are the right number. This is the "password cracker problem". There is no faster way than to search from the beginning until the correct value is hit.
Are you sure about the question? I have got a questions somewhat similar to your question.
Given a sorted array, there is one element "x" whose value is same as its index find the index of that element.
For example:
//0,1,2,3,4,5,6,7,8,9, 10
int a[10]={1,3,5,5,6,6,6,8,9,10,11};
at index 6 that value and index are same.
for this array a, answer should be 6.
This is not an answer, in case there was something missed in the original question this would clarify that.
If the only information you have is the fact that it's an unsorted array, with no reletionship between the index and value, and with no auxiliary data structures, then you have to potentially examine every element to see if it holds the information you want.
However, interviews are meant to separate the wheat from the chaff so it's important to realise that they want to see how you approach problems. Hence the idea is to ask questions to see if any more information is (or could be made) available, information that can make your search more efficient.
Questions like:
1/ Does the data change very often?
If not, then you can use an extra data structure.
For example, maintain a dirty flag which is initially true. When you want to find an item and it's true, build that extra structure (sorted array, tree, hash or whatever) which will greatly speed up searches, then set the dirty flag to false, then use that structure to find the item.
If you want to find an item and the dirty flag is false, just use the structure, no need to rebuild it.
Of course, any changes to the data should set the dirty flag to true so that the next search rebuilds the structure.
This will greatly speed up (through amortisation) queries for data that's read far more often than written.
In other words, the first search after a change will be relatively slow but subsequent searches can be much faster.
You'll probably want to wrap the array inside a class so that you can control the dirty flag correctly.
2/ Are we allowed to use a different data structure than a raw array?
This will be similar to the first point given above. If we modify the data structure from an array into an arbitrary class containing the array, you can still get all the advantages such as quick random access to each element.
But we gain the ability to update extra information within the data structure whenever the data changes.
So, rather than using a dirty flag and doing a large update on the next search, we can make small changes to the extra information whenever the array is changed.
This gets rid of the slow response of the first search after a change by amortising the cost across all changes (each change having a small cost).
3. How many items will typically be in the list?
This is actually more important than most people realise.
All talk of optimisation tends to be useless unless your data sets are relatively large and performance is actually important.
For example, if you have a 100-item array, it's quite acceptable to use even the brain-dead bubble sort since the difference in timings between that and the fastest sort you can find tend to be irrelevant (unless you need to do it thousands of times per second of course).
For this case, finding the first index for a given value, it's probably perfectly acceptable to do a sequential search as long as your array stays under a certain size.
The bottom line is that you're there to prove your worth, and the interviewer is (usually) there to guide you. Unless they're sadistic, they're quite happy for you to ask them questions to try an narrow down the scope of the problem.
Ask the questions (as you have for the possibility the data may be sorted. They should be impressed with your approach even if you can't come up with a solution.
In fact (and I've done this in the past), they may reject all your possibile approaches (no, it's not sorted, no, no other data structures are allowed, and so on) just to see how far you get.
And maybe, just maybe, like the Kobayashi Maru, it may not be about winning, it may be how you deal with failure :-)
I'm currently working on a project that requires me to match our database of Bands and venues with a number of external services.
Basically I'm looking for some direction on the best method for determining if two names are the same. For Example:
Our database venue name - "The Pig and Whistle"
service 1 - "Pig and Whistle"
service 2 - "The Pig & Whistle"
etc etc
I think the main differences are going to be things like missing "the" or using "&" instead of "and" but there could also be things like slightly different spelling and words in different orders.
What algorithms/techniques are commonly used in this situation, do I need to filter noise words or do some sort of spell check type match?
Have you seen any examples of something simlar in c#?
UPDATE: In case anyone is interested in a c# example there is a heap you can access by doing a google code search for Levenshtein distance
The canonical (and probably the easiest) way to do this is to measure the Levenshtein distance between the two strings. If the distance is small relative to the size of the string, it's probably the same string. Note that if you have to compare a lot of very small strings it'll be harder to tell whether they're the same or not. It works better with longer strings.
A smarter approach might be to compare the Levenshtein distance between the two strings but to assign a distance of zero to the more obvious transformations, like "and"/"&", "Snoop Doggy Dogg"/"Snoop", etc.
I did something like this a while ago, I used the the Discogs database (which is public domain), which also tracks artist aliases;
You can either:
Use an API call (namevariations field).
Download the monthly data dumps (*_artists.xml.gz) & import it in your database. This contains the same data, but is obviously a lot faster.
One advantage of this over the Levenshtein distance) solution is that you'll get a lot less false matches.
For example, Ryan Adams and Bryan Adams have a score of 2, which is quite good (lower is better matches, Pig and Whistle and Pig & Whistle has a score of 3), yet they're obviously different people.
While you could make a smarter algorithm (which also looks at string length, for example), using the alias DB is a lot simpler & less error-phone; after implementing this, I could completely remove the solution that was suggested in the other answer & had better matches.
soundex may also be useful
In bioinformatics we use this to compare DNA- or protein sequences all the time.
There are plenty of algorithms, you probably want to look at global alignments.
In this respect the Needleman-Wunsch algorithm is probably what you seek.
If you have particularly long recurring strings to compare you might also want to consider heuristic searches like BLAST.