I am using DropNet. I have problem with upload file into DropBox.
I am sure the connection with dropbox in fine. when I changed the method of upload to create file and delete file method that works fine.
I really can not see any problem that why is not uploading? I use exactly same API as DropNet.
protected void Btn_upload_Click(object sender, EventArgs e)
{
if (FileUpload1.HasFile)
{
if (Session["DropNetUserLogin"] != null)
{
try
{
_client.UseSandbox = true;
_client.UploadFile("/", FileUpload1.FileName, FileUpload1.FileBytes);
}
catch (Exception ex)
{
litOutput.Text = "Error in upload user login in session " + ex.Message;
}
}
else
{
litOutput.Text = "Session expired...";
}
}
else
{
litOutput.Text = "You did not specify a file to upload.";
}
}
}
Here is code which worked for me, hoping that this may help you:
private void button1_Click(object sender, RoutedEventArgs e)
{
var dlg = new OpenFileDialog();
dlg.Filter = "Text documents (.txt)|*.txt";
Nullable<bool> result = dlg.ShowDialog();
if (result == true)
{
string filename = dlg.FileName;
FileNameTextBox.Text = filename;
}
var x = #"/" + Path.GetFileName(FileNameTextBox.Text);
_client.UploadFile("/", Path.GetFileName(FileNameTextBox.Text), File.ReadAllBytes(#"" + FileNameTextBox.Text));
}
Related
My point is to create a save button like we have in Microsoft Word, for example. I know that there is already a post about "Save As" button but here is a difference. You click "Save" and if your file has not been saved earlier, you will get a window with possibility to set a name, directory etc. But if you have already saved the file, you will not get that window (unlike with "Save As"), changes will be saved for the file and this is exactly what I need
So I have this event, can somebody help me what's next?
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
}
P.S. Already tried this:
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.InitialDirectory = #"C:\Documents";
saveFileDialog1.Title = "Saving files";
saveFileDialog1.CheckFileExists = true;
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.DefaultExt = "";
saveFileDialog1.Filter = "All files (*.*)|*.*";
saveFileDialog1.FilterIndex = 1;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
System.IO.StreamWriter file = new System.IO.StreamWriter(saveFileDialog1.FileName.ToString());
file.WriteLine(richTextBox1.Text);
file.Close();
}
}
It seems to me that you'd just need to track whether or not they've already saved the document, by capturing the file path in a variable. This way, if the value is not set you can show the dialog, and if it is set you just use the path to save the content.
You'd also want to update this variable in the SaveAs and Open events if you have them.
Here's an example:
// Stores the name and path of the current file
private string filePath = null;
// Enum to enable us to easily reuse the same method for getting a file path
// while still showing the appropriate dialog title (see 'UpdateFilePath')
private enum DialogType
{
Open,
Save,
SaveAs
}
// Shows a dialog (based on 'dialogType') and captures the path in our variable
private bool UpdateFilePath(DialogType dialogType)
{
FileDialog dialog;
if (dialogType == DialogType.Open)
{
dialog = new OpenFileDialog();
}
else
{
dialog = new SaveFileDialog();
}
dialog.Filter = "All Files (*.*)|*.*";
dialog.Title = dialogType == DialogType.SaveAs
? "Save File As"
: dialogType + " File";
if (dialog.ShowDialog() == DialogResult.OK && dialog.FileName.Length > 0)
{
filePath = dialog.FileName;
return true;
}
return false;
}
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
var originalPath = filePath;
if (UpdateFilePath(DialogType.Open))
{
try
{
richTextBox1.LoadFile(filePath);
}
catch
{
MessageBox.Show("Unable to load specified file.");
filePath = originalPath;
}
}
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
if (string.IsNullOrEmpty(filePath))
{
if (UpdateFilePath(DialogType.Save))
{
richTextBox1.SaveFile(filePath);
}
}
else
{
richTextBox1.SaveFile(filePath);
}
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
if (UpdateFilePath(DialogType.SaveAs))
{
richTextBox1.SaveFile(filePath);
}
}
I am having a problem with a with a code that I used for my C# application. When I click on the browse button and select the file dialogue box opens twice.
private void txt_location_TextChanged(object sender, EventArgs e)
{
string folderPath = "";
FolderBrowserDialog folderBrowserDialog1 = new FolderBrowserDialog();
if (folderBrowserDialog1.ShowDialog() == DialogResult.OK) {
folderPath = folderBrowserDialog1.SelectedPath;
}
}
private void Button21_Click(object sender, EventArgs e)
{
using(var fbd = new FolderBrowserDialog()) {
DialogResult result = fbd.ShowDialog();
if (result == DialogResult.OK && !string.IsNullOrWhiteSpace(fbd.SelectedPath)) {
selectedPath = fbd.SelectedPath;
txt_location.Text = selectedPath;
}
}
}
private void bunifuThinButton21_Click_1(object sender, EventArgs e)
{
System.IO.StreamWriter file;
bool isvalid = ValidateInputs();
try {
file = new System.IO.StreamWriter(selectedPath + # "\dred.txt");
catch (Exception ex) {
MessageBox.Show("Please, Select valid Path..");
return;
}
try {
if (isvalid) {
WriteLines(file);
}
}
catch (Exception ex2) {
MessageBox.Show(ex2.Message);
}
finally {
file.Close();
}
}
}
Obviously, it is only meant to open once to enable me to read the selected file. This works, but only once I have selected the file twice.
Thanks in advance for your help.
You have FolderBrowserDialog being instantiated and shown on two different events:
txt_location_TextChanged
and
Button21_Click
You're having two popups because each one is firing once separately.
You should probably remove the event txt_location_TextChanged entirely unless you need it for another thing that isn't popping the FolderBrowserDialog again.
I am saving (uploading) file to FTP server using file upload control and .SaveAs method. But after 1st post back session values are lost. Not sure why and any work around this.
protected void Page_Load(object sender, EventArgs e)
{
if (Session["TheUser"] != null)
{
aUser = (clsUser)Session["TheUser"];
}
}
protected void Button1_Click(object sender, EventArgs e)
{
if (FileUpload1.HasFile)//continue only if the file control has the file
{
if (Get_and_Show_FileInformation())//if the file information was retrived and loaded into the textboxes
{
//continue with the execution
}
else
{
//error message displyed
}
}
}
protected bool Get_and_Show_FileInformation()
{
if (FileUpload1.HasFile)
{
string fName = FileUpload1.PostedFile.FileName;
string extension = Path.GetExtension(fName);
string FileName = fName.Substring(0, fName.Length - extension.Length);
string dir = uname;
string appPath = Server.MapPath("Uploads/") + dir;
FileInfo MyFileInfo = new FileInfo(appPath);
DirectoryInfo newDirectoryInfo = new DirectoryInfo(appPath);
if (!Directory.Exists(appPath))//if user is uploading to FTP_Upload first time, create a new directory for him/her
{
try
{
FileUpload1.SaveAs(Server.MapPath("~/Uploads/" + dir + "/" + FileName)); // ERROR here, call to this .SaveAs method causes loss of session values (Session["TheUser"])
Image2.ImageUrl = "~/Uploads/" + dir + "/" + FileName;
return true;
}
catch (Exception ex)
{
lbl_Err.Text = "<br/>Error: Error creating and saving into your space!(Error Code:XF05)";
return false;
}
}
else
{
//same code but don't create the directory
}
}
}
If I set path = "C:\\MSREAD.txt"; and Click on SaveAs Menu Item ,it saves Filetext,But If I dont give the String path and save it from saveFD.FileName it doesnt work.Please help me with this issue.
Thanks a lot
public void SaveToFile()
{
String SavedFile = "";
saveFD.InitialDirectory = #"C:";
saveFD.Title = "Save a Text File";
saveFD.FileName = "";
RichTextBox richTextBox1 = new RichTextBox();
saveFD.Filter = "Text Files|*.txt|All Files|*.*";
try
{
if (saveFD.ShowDialog() != DialogResult.Cancel)
{
SavedFile = saveFD.FileName;
path = SavedFile.ToString();
//path = "C:\\MSREAD.txt";
MessageBox.Show(path);
richTextBox1.SaveFile(path, RichTextBoxStreamType.PlainText);
SaveMyTextBoxContents(path);
}
}
catch(Exception e)
{
MessageBox.Show(e.ToString());
}
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveToFile();
}
public void SaveMyTextBoxContents(string path)
{
if (listBoxItems.SelectedIndex == -1)
{
if (rdBtnSlow.Checked && rdBtnNo.Checked)
{
using (StreamWriter outputFile = new StreamWriter(path))
{
foreach (string item in listBoxItems.Items)
{
saveAllText = slowNo + " " + item;
outputFile.WriteLine(saveAllText);
}
}
}
}
}
Here is your problem:
richTextBox1.SaveFile(path, RichTextBoxStreamType.PlainText);
SaveMyTextBoxContents(path);
You first save the richTextBox text to file, but then override the same file with SaveMyTextBoxContents, However the file is empty because of SaveMyTextBoxContents method will only save something if some conditions are true "not selected item and both check boxes are checked", and the listBoxItems.Items.Count > 0 which apparently not the case
Hey Everyone,
Sorry to bother you with this, but I'm having an issue with selecting multiple xlsx files through a file browser window in a winforms application when debugging and can't figure out what I did wrong.
Problem: I set Multiselect=true under the OpenFileDialog but I still cannot select more than one file.
What do I need to change to get the multiSelect feature to work?
Do I need to add anything under sourceFileOpenFileDialog method?
Do I need to add anything under listBoxSourceFiles_SelectedIndexChanged method to get the filenames to load correclty in the listbox?
// When the user clicks on Select Files Button, this happens
private void sourceFiles_Click(object sender, EventArgs e)
{
Stream myStream;
int i = 0;
OpenFileDialog sourceFileOpenFileDialog = new OpenFileDialog();
this.sourceFileOpenFileDialog.InitialDirectory = "i:\\CommissisionReconciliation\\Review\\";
this.sourceFileOpenFileDialog.Filter = "Excel Files (*.xls;*.xlsx;)|*.xls;*.xlsx;|" + "All Files (*.*)|*.*";
this.sourceFileOpenFileDialog.FilterIndex = 2;
this.sourceFileOpenFileDialog.RestoreDirectory = true;
this.sourceFileOpenFileDialog.Multiselect = true;
this.sourceFileOpenFileDialog.Title = "Please Select Excel Source File(s) for Consolidation";
if (sourceFileOpenFileDialog.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = sourceFileOpenFileDialog.OpenFile()) != null)
{
using (myStream)
{
foreach (string FileName in sourceFileOpenFileDialog.FileNames)
{
sourceFileOpenFileDialog.FileNames[i] = FileName;
listBoxSourceFiles.Items.Add(FileName);
Log("Source Files: " + sourceFileOpenFileDialog.FileNames[i]);
i++;
}
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
//method for the listbox. Do I need anything here?
private void listBoxSourceFiles_SelectedIndexChanged(object sender, EventArgs e)
{
}
//method for the sourceFileOpenFileDialog. Do I need anything here?
private void sourceFileOpenFileDialog_FileOk(object sender, CancelEventArgs e)
{
}
I updated the code to reflect sourceFileOpenFileDialog and the MultiSelect or Title doesn't work... Perhaps I'm referencing the onfiledialog wrong? is this the proper prefix to use?
Thanks for looking!
You are using two OpenFileDialogs. You display sourceFilesList but you initialized sourceFileOpenFileDialog. Using consistent naming rules religiously is a great way to avoid bugs like these btw.
Next problem, what is OpenFile() supposed to do when you selected more than one file? What is myStream actually used for?
You are setting up sourceFileOpenFileDialog but then use sourceFileList!!! Make up your mind and only use one.
Fixed the non-working MultiSelect by:
Updating the code to only use one variable sourceFileOpenFileDialog throughout the method and the MultiSelect or Title didnt work...
Removing all references to myStream. myStream was used in an example which i based my code off but i took it out and the multiSelect works!
Here's the working code:
// When the user clicks on Select Files Button, this happens
private void sourceFiles_Click(object sender, EventArgs e)
{
Stream myStream;
int i = 0;
OpenFileDialog sourceFileOpenFileDialog = new OpenFileDialog();
this.sourceFileOpenFileDialog.InitialDirectory = "i:\\CommissisionReconciliation\\Review\\";
this.sourceFileOpenFileDialog.Filter = "Excel Files (*.xls;*.xlsx;)|*.xls;*.xlsx;|" + "All Files (*.*)|*.*";
this.sourceFileOpenFileDialog.FilterIndex = 2;
this.sourceFileOpenFileDialog.RestoreDirectory = true;
this.sourceFileOpenFileDialog.Multiselect = true;
this.sourceFileOpenFileDialog.Title = "Please Select Excel Source File(s) for Consolidation";
if (sourceFileOpenFileDialog.ShowDialog() == DialogResult.OK)
{
try
{
string tempFolder = System.IO.Path.GetTempPath();
foreach (string FileName in this.sourceFileOpenFileDialog.FileNames)
{
this.sourceFileOpenFileDialog.FileNames[i] = FileName;
listBoxSourceFiles.Items.Add(FileName);
Log("Source Files: " + sourceFileOpenFileDialog.FileNames[i]);
i++;
System.IO.File.Copy(FileName, tempFolder + #"\" + FileName);
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
//method for the listbox. Do I need anything here?
private void listBoxSourceFiles_SelectedIndexChanged(object sender, EventArgs e)
{
}
//method for the sourceFileOpenFileDialog. Do I need anything here?
private void sourceFileOpenFileDialog_FileOk(object sender, CancelEventArgs e)
{
}