So ive tried following a load of different tutorials on Stack and the internet on how to do this, but i'm getting nowhere.
this is the closest ive gotten:
private void button1_Click(object sender, EventArgs e)
{
Image image1 = Image.FromFile("S:\\Software\\C#\\Project\\WindowsFormsApplication1\\1.png");
Image image2 = Image.FromFile("S:\\Software\\C#\\Project\\WindowsFormsApplication1\\2.png");
using (Graphics g = Graphics.FromImage(image1))
{
g.DrawImageUnscaled(image2, 0, 0);
}
}
And when i click my button, it executes the code but literally nothing happens, why is this?
You have to do something with your image object afterwards. You have at least two possibilities:
Either save it back to a file using the Image.Save method, e.g.
image1.Save("S:\\Test.jpg");
or place a PictureBox on your Form and put it in there
PictureBox1.Image = image1;
...to place it in a new Window:
Form imgForm = new Form();
imgForm.BackgroundImage = image1;
imgForm.Show();
Related
I want to be ale to add an image to a form in runtime using a click from the left mouse button. When I tried the code below, nothing happens. I don't get an error message and the picture doesn't appear where I click. I'm not sure if I'm on the right track or not. I don't know how to start if this isn't how I go about doing this operations.
private void button7_Click(object sender, EventArgs e)
{
Floors floors = new Floors();
floors.ShowDialog();
if(Mouse.LeftButton == MouseButtonState.Pressed)
{
var picture = new PictureBox
{
Name = "pictureBox",
Size = new Size(16, 16),
Location = new Point(100, 100),
Image = Final_Project_1_.Properties.Resources.fire_icon,
};
this.Controls.Add(picture);
}
}
So I tried the following code:
private void button1_Click(object sender, EventArgs e)
{
var picture = new PictureBox
{
Name = "pictureBox",
Size = new Size(16, 16),
Location = new Point(100, 100),
Image = WinFormsTestApp.Properties.Resources.Copy,
SizeMode = PictureBoxSizeMode.StretchImage
};
this.Controls.Add(picture);
}
and this worked perfectly fine. If this doesn't work on your machine, your image link may be corrupted or something else is overlapping the image.
However, if this works, I guess it's currently not working because of the if statement with the mouse button. It could be, that the click event will only be raised, if the mouse button is up again so the if statement can never be true. If you want to achieve, that the image is created the moment the mouse button goes down, you should be able to do so with the MouseDown Event.
I started developing Windows Forms Applications recently. I'm working with PictureBox and I'm facing an issue with it. It is losing the image as shown in below pictures when I navigate out or if I minimize it and open it back. Any help is greatly appreciated.
private void button1_Click(object sender, EventArgs e) {
try {
using (FileStream fs = new FileStream("C:\\Users\\Public\\Pictures\\Sample Pictures\\Penguins.jpg", FileMode.Open, FileAccess.Read)) {
using (Image original = Image.FromStream(fs)) {
Bitmap image1 = (Bitmap)original;
pictureBox1.Image = image1;
pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage;
pictureBox1.Refresh();
}
}
}
catch (System.IO.FileNotFoundException) {
MessageBox.Show("There was an error opening the bitmap." +
"Please check the path.");
}
}
Forms Application before Navigating
Forms Application after Navigating to another app or minimizing it
This is because you are disposing the image
using (Image original = ....
{
Bitmap image1 = (Bitmap)original;
// ...
}
image1 is the same object as original, just cast to Bitmap, and gets disposed right after being painted on the screen (with Refresh method).
To fix the problem, use the following instead
Bitmap image1 = new Bitmap(original);
// ...
I have a win form where i have some label,a datagridview and some textbox.I want to print all of my items in my form in exact format it shows in the form. I have tried it using taking snap of my form then print it. But in this way i can't have my full form as my form is large enough.It only shows half portion of my form.I don't know is it the best practice on not.Is there any other way of doing this please mention
My Sample code:
private void btnPrint_Click(object sender, EventArgs e)
{
CaptureScreen();
printDocument1.Print();
}
private void CaptureScreen()
{
Graphics myGraphics = this.CreateGraphics();
Size s = this.Size;
memoryImage = new Bitmap(s.Width, s.Height, myGraphics);
Graphics memoryGraphics = Graphics.FromImage(memoryImage);
memoryGraphics.CopyFromScreen(this.Location.X, this.Location.Y, 0, 0, s);
}
private void printDocument1_PrintPage_1(object sender, PrintPageEventArgs e)
{
e.Graphics.DrawImage(memoryImage, 0, 0);
}
As i am new in C#,it will be great help if anyone help me with some sample code.
I think you should emulate your form layout in a page or text description language like PDF or RTF. Taking a screenshot programmatically is in a way elegant but also crude at the same time, and runs into limitations of which you encountered just one.
One thing to consider is whether you should serialize your data e.g. as XML first, and only then export to data formats suitable for printing or displaying, like PDF or HTML.
I have a browse button, and two empty images (image1, image2). I want to first click the browse button and load an image to (image1). On the second click I want to load the image to (image2).
I'm very new to WPF and C# in general. I guess I need some method to control the clicks of the button? Does anyone have any idea about this? I would highly appreciate it.
This is my code behind attempt:
private void button1_Click(object sender, RoutedEventArgs e)
{
OpenFileDialog fd = new OpenFileDialog();
fd.DefaultExt = ".tif";
fd.Filter = "(*.tif,*.tiff)|*.tif;*.tiff";
fd.ShowDialog();
string fname = fd.FileName;
textBox1.Text = fname;
image1.Source = new BitmapImage(new Uri(fd.FileName));
}
After this, the first image is displayed in image1, but when I browse for another image it comes on top of image 1, and not in image2. How can I make the second image that I browse display in image2? maybe something like, if the button is already clicked one time, then the image should load into image2? or if image1 is already full then load to image2? I'm not sure!
Oh and the purpose of this is to create an interface that lets the user browse different images shown in a listbox, and when the user clicks each image, it displays in another window and the user can zoom in and out and so on.
But right now I'm just stuck with this small part of my project!
While I question the why you want to do such a thing, you could use the following. Also, please show some effort next time. This is a relatively easy solution!
private bool _ImageOneSet;
public MainWindow()
{
InitializeComponent();
_ImageOneSet = false;
}
private void Button_Click(object sender, RoutedEventArgs e)
{
if (!_ImageOneSet)
{
// set image one
_ImageOneSet = true;
}
else
{
// set image two
}
}
I use a private field that is set to false. The first time the button_click event gets triggered, _ImageOneSet is still false, so you can set the first image.
The second (and third, fourth etc...), _ImageOneSet is true so you will set the second image.
I'm using Winforms and have a picturebox. When the user clicks on it, I want to load a image from my computer. But its not working. Any ideas why?
private void pictureBox1_Click(object sender, EventArgs e)
{
pictureBox1.Image = Image.FromFile("C:/wamp/www/cyber.jpeg");
pictureBox1.Image = new Bitmap(#"C:\wamp\www\cyber.jpeg");
}
If I click on it, I get the error "FileNotFoundException was unhandled". If I remove the Image.FromFile and use the Bitmap instead, I get the error "Parameter is not valid"
try this
pictureBox1.Image = Image.FromFile(#"C:\wamp\www\cyber.jpeg");
Assuming your filepath is correct , I think You have .jpg as extension for your image but you are trying to access with extension .jpeg
Try This:
pictureBox1.Image = Image.FromFile("C:/wamp/www/cyber.jpg");